Hi I have a scenario to add a all previous values ...
Input is this of a column of a table
Col
3
5
4
6
9
7
8
And I need output in this manner:
Col Col2
3 3
5 8
4 12
6 18
9 27
7 34
8 42
Kindly reply asap
Regards,
Neeraj
As long as you have a field to order by, you can use SUM ... OVER to do the running sum;
SELECT Col, SUM(Col) OVER (ORDER BY id) Col2
FROM Table1
ORDER BY id;
An SQLfiddle to test with.
Related
Its an example of a table from PostgreSQL.
I learning the SQL query and cant find anything to help me pass this.
What I`m working to achieve is:
Return UNIQ(DISTINCT) values of WNR WHEN tdate >='2020-01-13 00:00:01.757000'
WNR tdate T1 T2 T3
2 '2020-01-06 00:05:23.229000' 8 18 15
2 '2020-01-06 00:05:23.725000' 11 4 7
2 '2020-01-06 00:05:31.578000' 19 12 6
3 '2020-01-13 00:00:01.655000' 9 9 3
3 '2020-01-13 00:00:01.757000' 5 11 16
3 '2020-01-13 00:00:05.778000' 16 17 16
4 '2020-01-20 00:00:11.925000' 18 13 4
4 '2020-01-20 00:00:12.177000' 18 3 15
4 '2020-01-20 00:00:12.694000' 7 12 7
5 '2020-01-27 00:00:04.860000' 19 3 14
5 '2020-01-27 00:00:05.056000' 14 18 8
5 '2020-01-27 00:00:05.107000' 18 7 14
Result expected should be 3,4,5
Thank you!
To select distinct values in Postgresql you can use DISTINCT clause.
From Postgresql documentation: SELECT DISTINCT eliminates duplicate rows from the result. SELECT DISTINCT ON eliminates rows that match on all the specified expressions. SELECT ALL (the default) will return all candidate rows, including duplicates. (See DISTINCT Clause below.)
SELECT DISTINCT WNR
FROM table_name
WHERE tdate >='2020-01-13 00:00:01.757000';
I am working on the output of a postgres subquery and have the table with 20 columns(generated using WITH clause).
The table looks something like this
col1 col2 col3 --- col20
4 4 24
6 6 45
5 5 66
5 5 12
I want to write a write a query that remove the duplicated column. I tried by select all the columns except the 2nd. But I could not find a better way to do that.
The expected output is:
col1 col3 ------ col20
4 24
6 45
5 66
5 12
Thanks
I have column like below : I have applied orderby percentileno Dec then it gives like below but I need proper order : 1,2,3,--10.
PercentileNo
1 (0.1-12.6)
10 (113.5-126)
2 (12.7-25.2)
3 (25.3-37.8)
4 (37.9-50.4)
5 (50.5-63)
6 (63.1-75.6)
7 (75.7-88.2)
8 (88.3-100.8)
9 (100.9-113.4)
I need order
1 (0.1-12.6)
2 (12.7-25.2)
3 (25.3-37.8)
4 (37.9-50.4)
5 (50.5-63)
6 (63.1-75.6)
7 (75.7-88.2)
8 (88.3-100.8)
9 (100.9-113.4)
10 (113.5-126)
Please help me Thanks in advance
Your question is not completely clear to me, but if you want to order your list you can do the following:
SELECT col_1, col_2
FROM table_1
ORDER BY col_1 DESC
So if you have a column called PercentileNo you could do:
SELECT PrecentileNo
FROM yourTable
ORDER BY PercentileNo DESC
Hope this helps.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Calculate a Running Total in SqlServer
I need to use values from previous row inorder to generate a cumulative value as shown below. Always for each Code for the year 2000 the starting Base is 100.
I need to ahieve this using tsql code.
id Code Yr Rate Base
1 4 2000 5 100
2 4 2001 7 107 (100+7)
3 4 2002 4 111 (107+4)
4 4 2003 8 119 (111+8)
5 4 2004 10 129 (119+10)
6 5 2000 2 100
7 5 2001 3 103 (100+3)
8 5 2002 8 111 (103+8)
9 5 2003 5 116 (111+5)
10 5 2004 4 120 (116+4)
OK. We have table like this
CREATE Table MyTbl(id INT PRIMARY KEY IDENTITY(1,1), Code INT, Yr INT, Rate INT)
And we would like to calculate cumulative value by Code.
So we can use query like this:
1) recursion (requires more resources, but outputs the result as in the example)
with cte as
(SELECT *, ROW_NUMBER()OVER(PARTITION BY Code ORDER BY Yr ASC) rn
FROM MyTbl),
recursion as
(SELECT id,Code,Yr,Rate,rn, CAST(NULL as int) as Tmp_base, CAST('100' as varchar(25)) AS Base FROM cte
WHERE rn=1
UNION ALL
SELECT cte.id,cte.Code,cte.Yr,cte.Rate,cte.rn,
CAST(recursion.Base as int),
CAST(recursion.Base+cte.Rate as varchar(25))
FROM recursion JOIN cte ON recursion.Code=cte.Code AND recursion.rn+1=cte.rn
)
SELECT id,Code,Yr,Rate,
CAST(Base as varchar(10))+ISNULL(' ('+ CAST(Tmp_base as varchar(10))+'+'+CAST(Rate as varchar(10))+')','') AS Base
FROM recursion
ORDER BY 1
OPTION(MAXRECURSION 0)
2) or we can use a faster query without using recursion. but the result is impossible to generate the strings like '107 (100+7)' (only strings like '107')
SELECT *,
100 +
(SELECT ISNULL(SUM(rate),0) /*we need to calculate only the sum in subquery*/
FROM MyTbl AS a
WHERE
a.Code=b.Code /*the year in subquery equals the year in main query*/
AND a.Yr<b.Yr /*main feature in our subquery*/
) AS base
FROM MyTbl AS b
I have a table like this
UserID Score Date
5 6 2010-1-1
7 8 2010-1-2
5 4 2010-1-3
6 3 2010-1-4
7 4 2010-1-5
6 1 2010-1-6
I would like to get a table like this
UserID Score RunningTotal Date
5 6 6 2010-1-1
5 4 10 2010-1-3
6 3 3 2010-1-4
6 1 4 2010-1-6
7 8 8 2010-1-2
7 4 12 2010-1-5
Thanks!
Unlike Oracle, PostgreSQL and even MySQL, SQL Server has no efficient way to calculate running totals.
If you have few scores per UserID, you can use this:
SELECT userId,
(
SELECT SUM(score)
FROM scores si
WHERE si.UserID = so.UserID
AND si.rn <= so.rn
)
FROM (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY UserID) AS rn
FROM scores
) so
, however, this will be very inefficient for larger tables.
For larger tables, you could benefit from using (God help me) a cursor.
Would something like this work for you...?
SELECT UserID, Score,
(SELECT SUM(Score)
FROM TableName innerTable
WHERE innerTable.UserID = outerTable.userID
AND innerTable.Date <= outerTable.date) AS RunningTotal
FROM TableName outerTable
This assumes, though, that a user cannot have more than one score per day. (What is your PK?)