if I have an app and open 2 pages with push navigator, is there any way to open the 3rd page in order to delete the second one (and the first page remain)?
I don't know if it went well to understand my doubt
I believe you want to navigate to the next screen without the way back.
You can refer to the question, Move to a new screen without providing navigate back to previous screen and use Navigator.pushReplacement
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I can go to my page PgMain by a lot of way (end of action, logout, button go to menu, button back, system back button, etc.). I want clear my routing every time, where I open PgMain page. How to do it inside PgMain class, for example inside build method? As I said previously, I have a lot of ways to go to PgMain, and not at every case I can use Get.offAll() method
Use
Get.offAll(PgMain()); Get.off(PgMain());
whenever you navigate to PgMain page.
I am building an IOS App and I have a flow that enables users to build and share a post. First they start on a home screen, where they select the media, then another screen to write the paragraph and another one to edit the media and so on. At the end they share the post and I want them to come back to the root view and start the whole flow all over again but without the ability to navigate back.
How do I achieve that? I could technically hack it by disabling the back button in the root view but that doesn't feel clean.
Ideally, I would need to delete the current navigation stack and start a new one when they navigate back to home. Is there a way to do that?
If not, what is the standard way of doing it?
There are 3 screens in my app. When I use popAndPushNamed() in the 2nd page, it pops the 2nd page and shows the 3rd page, but when It pops it shows the 1st page behind it in milliseconds. how to avoid that?
is Animation the way?
or are there any other methods just like push and show 3rd page, and pop 2nd page when the 3rd page visible to the user?
popAndPushNamed() as the documentation suggests, pushes the new route but pops the old route simultaneously, and hence, there is a small moment where you can see the first page even if your new routes are fully opaque. Replace the method with Navigator.of(context).pushReplacementNamed() and it should work as expected.
In my current app, it's possible to navigate through pages with a drawer. But if I go to a second page, and the click to go to the first page (making this route history [FirstPage, SecondPage, FirstPage]) it recreate a new FirstPage.
I don't want to it to be recreated because there is a lot of process and it can take few seconds. I was wondering if it's possible to go to the first instance of the FirstPage instead of recreating a new one, and still have the same route history.
I hope it's clear enough to understand.
I am trying to create a new page from an existing page with a back button. I have recreated the issue here in a plunkr. In the trip analytics option When I click the first card i.e. Enter Home address. I want the todayDetail .html page to come up with a back button. I have already tried two approaches
First approach The ng-click approach. In which I give $state.go(statename) to give that page. But then I wouldn't get a back button as the navigation stack is changed.
Second approach - If I keep the navigation stack i.e. keep the state name as initial.trips.today.todayDetail. The page doesn't load at all.
What is the issue? How should I go about it?