Dart is replacing "&" with "\u0026" in a URL - flutter

Question

I am using flutter to process a link and download it to the device using dio package.
But the problem is dart is replacing all '&' with '\u0026' and making the link unusable. is there a way to avoid this problem? Thanks in advance.
Here's the code:
const uuid = Uuid();
final Dio dio = Dio();
// * create random id for naming downloaded file
final String randid = uuid.v4();
// * create a local instance of state all media
List<MediaModel> allMedia = state.allMedia;
// * create an instance of IGDownloader utility class from ~/lib/utilities
final IGDownloader igd = IGDownloader();
// * make a download link from provided link from the GetNewMedia event
final link = await igd.getPost(event.link);
link.replaceAll('\u0026', '&');
print(await link);
Output:
// expected : "http://www.example.com/example&examples/"
// result: "http://www.example.com/example\u0026example"

Answer 1

Pass your url to cleanContent function and don't forget to add imports
import 'package:html/parser.dart';
import 'package:html_unescape/html_unescape.dart';
static String cleanContent(String content, {bool decodeComponent = false}) {
if (content.contains("<p>")) {
content = content.replaceAll("<p>", "").trim();
}
if (content.contains("</p>")) {
content = content.replaceAll("</p>", "").trim();
}
var unescape = HtmlUnescape();
content = unescape.convert(content).toString();
if (content.contains("\\<.*?\\>")) {
content = content.replaceAll("\\<.*?\\>", "").trim();
}
content = parseHtmlString(content,decodeComponent: decodeComponent);
return content;
}
static String parseHtmlString(String htmlString,{bool decodeComponent = false}) {
final document = parse(htmlString);
String parsedString = parse(document.body!.text).documentElement!.text;
if(parsedString.contains("%3A")){
parsedString = parsedString.replaceAll("%3A", ":");
}
if(parsedString.contains("%2F")){
parsedString = parsedString.replaceAll("%2F", "/");
}
if(decodeComponent){
parsedString = Uri.decodeComponent(parsedString);
}
return parsedString;
}

Answer 2

replaceAll returns the modified string, but leaves original String untouched.
Try:
print(await link.replaceAll('\u0026', '&'));
or
newLink = link.replaceAll('\u0026', '&');
print(await newLink);