I am writing a T-SQL function that returns an account number from a block of text. The text is generated by the system, and has 3 colons so I need to try to find a way to use SUBSTR() on the row containing "Account:" and not just the colon itself:
Amount: $10.00
Date: 12/5/2022
Account: Mr. John Doe 83850
What would be the cleanest way to select only the line containing the account number to my function for parsing into an integer?
I'll probably mess this up on my phone but something like this should help:
SUBSTRING(TEXT,(PATINDEX('%ACCOUNT:%',TEXT)+9),LEN(TEXT)-(PATINDEX('%ACCOUNT:%',TEXT)+9))
Edit:
You could find the third line by finding your 3rd carriage return and line feed using char(10)+char(13), but that could look messy going 3 levels deep so I wont attempt it on my phone
Related
I have a list, and I need to take only first words including numbers of every row without anything after numbers. How can I achieve that?
A pic is provided
For example:
I have a row like this:
ЛУ 344 ул.Яссауй в районе дома №163 северном направление
As a result I want to get:
ЛУ 344
Left, right won't help because the number of characters can change.
You can use a regex based substring() variant:
substring(the_column from '\w+\s+[0-9]+')
This will extract the first "word characters" followed by one or more spaces followed by one or more numbers
Online example
Maybe split_part() will help.
Or the string_to_array()
Or the substring()
Depends on the use you want and the way you want to get the substring.
I've run into an interesting problem I'm hoping someone can shed some light on.
I'm trying to pull a unique list of names from an MS SQL Database - but the company has been sloppy with their names. They were tacking on a code to the end of last name for some users. I need to remove that code.
Example:
firstname lastname
John Doe
Mary Smith AST
Mike Jackson AST
Brian Astor
Jackie Masterson
In the example, "AST" is the code they tack on. It's not tacked on to all last names either. I need to get an output of just the last names without the code.
I would have expected this is a simple use of REPLACE. I tried:
select REPLACE(lastname, ' AST', '') from table
Note the leading space in the quotes for the search phrase... this does work to remove the "AST" appended to the last names.
However - my problem is that it will also remove anywhere AST appears at the BEGINNING of the field. So Brian Astor comes out as "Brian or" since the field started with AST. However... it correctly does not remove ast from the middle, so Jackie Masterson is fine.
Any ideas why it is ignoring the leading space in my search phrase for the beginning of the field? I've tried ltrim to eliminate the possibility the field has leading spaces.
Thanks!
Replace with an empty string will eliminate the searched string anywhere in your source string. So the behaviour is as expected.
If you only need to replace ' ast' at the end of your searched string, try something like this:
select replace(lastname + '$$$', ' AST$$$', '') from table
Of course you need to be sure that the $$$ appended don't appear by chance in your source string (lastname). Which I guess is not that likely.
A web form collects data on students in a band organization at school. The form data is fed into a google sheet that then populates a merge template and the merged forms are emailed to the recipient. A parent needs to print, sign and turn in the forms. There are hundreds of kids in this band and at registration time when the forms are turned in it is easier to sort all the papers in the stack if you have a short sort number in the corner... Volunteer kids don't apply alphabetization well. I'm trying to create a formula that will give me that sorting number to merge onto the header of each page of the PDF they receive after submitting the form. I want it based on last name and then first name and be able to create that number (in the google sheet) on the fly because the merging happens almost instantly when the user submits the form. Hence, an excel type formula is desired that will result in a number representing the kids name. I'd like for each number to be unique but some names are the same for the first few letters, also some names are only 2 characters long. I tried making A=10, B=11, z=35 etc. (so all are 2 digits) So, using only the first 3 characters, Bob Jones would = 192423112411 - hardly easy to sort the paper at a glance and it doesn't really differentiate between Bob Janes either. 4 digits is preferable. I also looked at =code() formula and it came out with long numbers too. Any advice is appreciated. Thanks!
Side note: What method do spreadsheets use to sort text? Do they weight the characters or what? Before I got the automerge thing to work I assigned each kid in the list a number higher than the one below and lower than above (on the sheet), then did the merge.
One option is to:
sort the name list alphabetically
add a sort number column, and put a =TEXT(row(),"0000") formula to generate a unique ID
on the merge spreadsheet, use a VLOOKUP function to retrieve the unique ID for that specific name.
First off, that wall of text was kind of hard to read through. Please try and do a little formatting so the people trying to help you can easily follow what you're trying to convey.
Personally I would suggest a hyphenated system. First initial of last name converted to a number, followed by a hyphen, followed by the first two letters of their first name converted to numbers.
Bob Jones becomes 11-1956 assuming you differentiate between upper and lower case, or 11-1924 if you convert everything to upper case, which I guess makes more sense.
You could use this VBA function to convert names to a system like that:
Function ConvertToIndex(strInput As String) As String
Dim strLast As String
Dim arrName() As String
Dim strFirst1 As String
Dim strFirst2 As String
arrName = Split(strInput, " ")
strLast = Mid(arrName(1), 1, 1)
strFirst1 = Mid(arrName(0), 1, 1)
strFirst2 = Mid(arrName(0), 2, 1)
ConvertToIndex = Asc(UCase(strLast)) - 55 & "-" & Asc(UCase(strFirst1)) - 55 & Asc(UCase(strFirst2)) - 55
'MsgBox ConvertToIndex
End Function
Thank you Tim, Nutsch and Mad Tech for your responses. I appreciate your input. Sorry the paragraph was so long, I get wordy. Because the members get their merged PDF sheet immediately after submitting I need the number to be based on the name as soon as it's entered, not after the fact; so I was looking for a formula that would reside in the sheet. Interesting VBA function too though. I'll settle for numbering them afterwards, maybe when the sheets are turned in. By then I'll know all who are in the band and can assign numbers like before. Thanks again!
I've prepared a macro in Notepad++ to transform a ldif file in a csv file with a few fields. Everything is OK but I have a final problem: I have to have 2 fields with a specific length and in this moment I cannot ensure that length because in the source file they are not coming so
For instance, I generate this line:
12345,namenamename,123456
And I have to ensure that the 2nd and 3rd fields have 30 (filling with spaces at right side) and 9 (filling with zeros at left) characters, so in this case I should generate:
12345,namenamename ,000123456
I haven't found how Notepad++ could match a pattern in order to add spaces/zeros, so I have though in to add 1 space/zero to the proper field and repeat this step so many times as needed to ensure the lengths (this is, 29 and 8, because they cannot come empty) and search with the length in the regex (for instance: \d{1,8} for the third field)
My question is: can I repeat only one step of the macro several times (and the rest of the macro only 1 repetition)?
I've read the wiki related to this point (http://sourceforge.net/apps/mediawiki/notepad-plus/index.php?title=Editing_Configuration_Files#.3CMacros.3E) and I don't found anything neither
If not possible, how could be a good solution? Create another 2 different macros and after execute the main one, execute this new 2 macros several times?
Thanks in advance!
A two pass solution with Notepad++ is possible. Find a pair of characters or two short sequence of characters that never occurs in your data file. I will use =#<= and =>#= here.
First pass, generate or convert the input text into the form 12345,=#<=namenamename______________________________,000000000123456=>#=. Ie add 30 spaces after the name and nine zeroes before the number (underscores used here just to make things clearer).
Second pass, do a regular expression search for =#<=(.{30})_*,0*(\d{9})=>#= and replace with \1,\2.
I have just suggested a similar solution in special timestamp format of csv
I've developed a workaround since crystal reports doesn't seem to have a substring function with the following formula:
right({_v_hardware.groupname},
truncate(instr(replace({_v_hardware.groupname},".",
","), ","))
What I'm trying to do is search for the period (".") in a string and replace it with a comma. Then find the comma position in the string and print all characters following after the comma. This is assuming the string will only have 1 period in the entire string.
Now when I attempt to do this, I get some weird characters which look like wingdings. Any ideas?
thanks in advance.
I don't know the entire issue that you are attempting to accomplish, but for this question alone, the step of replacing the period with a comma seems to be unnecessary. If you know that there is only one period in the string and you only want the characters right of the period then you should be able to do something like the following (this is #first_formula):
right({_v_hardware.groupname}, len({_v_hardware.groupname}) - instr({_v_hardware.groupname},"."))
If for some reason you want to show the comma then I'd do that in a separate formula. If you need the entire screen with the comma replaced then just do:
replace({_v_hardware.groupname},".",",")
And if you need the comma plus included in the string then it might just be easier to do something like:
"," + {#first_formula}
Hope this helps.