Is there a way to stop the use of more than 1 space in a row in a textfield?.
Currently I am using this code to deal with a single space, but I don't want to end up with an infinitely long list of exceptions like the second image.
I do want to use spaces, just not at the start of my text or multiple spaces in a row.
Thank you in advance.
You could use trimRight() to strip all leading whitespace from your value.
If you want to deal with trailing whitespace as well, you could just use trim()
Either way, both of these would catch all the exceptions you listed, whether there is an empty value, or a value with only whitespace.
I'm unsure if you are asking how to also replace multiple spaces inside the string with just single space? To do that you can use a regex, like this:
value = value.trim();
var singleSpaces = value.replaceAll(RegExp(r"\s+"), " ");
Related
As stated in the title, I have two tables I'm attempting to link. Both Strings appear to be a match, however Crystal Reports is not picking it up. The only thing I can think is that that length of the field is different, even though the strings are the same. could that cause a discrepancy? If so how can I correct for it? Thank you
Length of the string will prevent a match. If you are using the Trim(string) function, that only removes spaces found at the beginning or end of your string, so the two strings could still be of different lengths after using this function. You will need to use another function to capture a substring of the original string. To do this you can use the Left(string, length) function to ensure both strings are the same length.
If they still do not match then you may have non-printable characters in one or both of your strings. Carriage Return and Line Feed tend to be the most commonly found non-printable characters. A Carriage Return is represented as Chr(10), while a Line Feed is represented as Chr(13). These are Built In Constants similar to those found in VBA and Visual Basic.
You can use a find and replace to remove them with the following formula. Its not a bad idea to also include the trim and left functions in this as well to ensure you get the best match possible.
Replace(Replace(Left(Trim({YourStringField}), 10),Chr(10), ""),Chr(13), "")
There are a few additional Built In Constants you may need to check for if this doesn't work. A Tab is represented as Chr(9) for example. Its very rare for strings to contain the other Built In Constants though. In most cases Carriage Return and Line Feed are the only ones that are typically found in Plain Text. Tabs and the other constants should only be found in Rich Text and are very rare in string data.
I'm working to build an import tool that utilizes a quoted CSV file. However, several of the fields in the CSV file are reported as such:
"=""38000"""
Where 38000 is the data I need. The data integration software I use (Talend 6.11) already strips the leading and trailing double quotes for me (so, "38000" becomes 38000), but I can't find a way to get rid of those others.
So, essentially, I need "=""38000""" to become "38000" where the leading "=" is removed and the trailing "" is removed.
Is there a TRIM function that can accomplish this for me? Perhaps there is a method in Talend that can do this?
As the other answer stated, you could do that operation in SQL. Or, you could do it in Java, Groovy, etc, within Talend. However, if there is an existing Talend component which does the job, my preference is to use it. That leads to faster development, potentially less testing, and easier maintenance. Having said that, it is important to review all the components which are available, so you know what's available to you.
You can use the Talend component tReplace, to inspect each of the input columns you want to trim of quotes and equal signs. A single tReplace component can do search and replace operations on multiple input columns. If all the of the replaces are related to each other, I would keep them within a single tReplace. When it gets to the point of doing unrelated replacements, I might place those within a new tReplace so that logical operations are organized and grouped together.
tReplace
For a given Input Column
search for "=", replace with ""
search for "\"", replace with ""
Something like that:
SELECT format( '"%s"', trim( both '"=' from '"=""38000"""' ) );
-[ RECORD 1 ]---
format | "38000"
1st: trim() function removes all " and = chars. Result is simply 38000
2nd: with format can add double quote back to get wishful end result
Alternatively, can use regexp and other Postgres string functions.
See more:
https://www.postgresql.org/docs/current/static/functions-string.html
I asked a question earlier today and got a really quick answer from llbrink. I really should have asked that question before I spent several hours trying to find an answer.
So - here's another question that I have never found an answer for (although I have created a work-around which seems very cludgy).
My AHK program asks the user for a login name. The program then compares the login name with an existing list of names in a file.
The login name in the file may contain spaces, but there are never spaces at the beginning of the name. When the user enters the name, he may include spaces at the beginning. This means that when my program compares the name with those in the file, it can not find a match (because of the extra spaces).
I want to find a way of stripping the spaces from the beginning of the input.
My work-round has been to split the input string into an array (which does ignore leading spaces) and then use the first element of the array. This is my code :
name := DoStrip(name)
DoStrip(xyz) ; strip leading and trailing spaces from string
{
StringSplit, out, xyz, `,, %A_Space%
Return out1
}
This seems to be a very laboured way to do it - is there a better way ?
I don't see a problem with your example if it works on all cases.
There is a much simpler way; just use Autotrim which works like this.
AutoTrim, On ; not required it is on by default
my_variable = %my_variable%
There are also many other different ways to trim string in autohotkey,
which you can combine into something useful.
You can also use #LTrim and #RTrim to remove white spaces at the beginning and at the end of the string.
I have a field with multiple words in it. I want to separate the words onto different lines rather than have them separated by spaces.
So for example “Not Great”, I want to put “Not” on 1st line and “Great” on 2nd line, like so:
Not
Great
There could be words with “/” character in between i.e. “Great / Good” where I want to put everything after 1st word in 2nd line and everything after “/” in 3rd line i.e.
Great
/
Good
Basically, whenever there is space, I want split that string into multiple lines. How do I do that in SSRS?
Ok, you want the string broken up into different lines.
Do you mean on separate lines within the same tablix cell?
Thats straightfoward see
http://www.kodyaz.com/articles/reporting-services-add-line-break-between-words-custom-code.aspx
If you mean to split the string so the words are on different Tablix cells one approach would be to use a sub report on a list.
Set the list data set to the original data set containing the multiple word string, pass the string to the sub report as a parameter.
On the sub report pass the parameter to a data set that splits the string into individual lines.
Losts of suggestions for how to do that here
Turning a Comma Separated string into individual rows
Simply replace the space with a carriage return and line feed:
=Replace(Fields!SomeWords.Value, " ", vbCrLf)
=Fields!SomeFields.Value.Replace(Space(1), vbCrLf)
I've developed a workaround since crystal reports doesn't seem to have a substring function with the following formula:
right({_v_hardware.groupname},
truncate(instr(replace({_v_hardware.groupname},".",
","), ","))
What I'm trying to do is search for the period (".") in a string and replace it with a comma. Then find the comma position in the string and print all characters following after the comma. This is assuming the string will only have 1 period in the entire string.
Now when I attempt to do this, I get some weird characters which look like wingdings. Any ideas?
thanks in advance.
I don't know the entire issue that you are attempting to accomplish, but for this question alone, the step of replacing the period with a comma seems to be unnecessary. If you know that there is only one period in the string and you only want the characters right of the period then you should be able to do something like the following (this is #first_formula):
right({_v_hardware.groupname}, len({_v_hardware.groupname}) - instr({_v_hardware.groupname},"."))
If for some reason you want to show the comma then I'd do that in a separate formula. If you need the entire screen with the comma replaced then just do:
replace({_v_hardware.groupname},".",",")
And if you need the comma plus included in the string then it might just be easier to do something like:
"," + {#first_formula}
Hope this helps.