Take the following string, for example:
some random text*
- sed is actually not that easy.*
other text
How can I search for lines containing both - and *, then replace the asterisk in that line with a string?
(For Example) Using the string "test" to replace the asterik in matched lines, the output would look this:
some random text*
- sed is actually not that easy.test
other text
I tried
sed -i '' 's/\- .*\*/\n\n:::\n/g';
But the problem with that is that it replaces the whole line, instead of just the asterisk.
If you want to match and keep the hyphen at the start of the line, and replace the asterix at the end of the line, you can use a capture group \(...\) for what you want to keep and use that group in the replacement with \1
sed -i 's/^\(- .*\)\*$/\1test/' file
The contents of file will be:
some random text*
- sed is actually not that easy.test
other text
If the characters are not directly at the start or end of the string, you can remove the anchors ^ and $
Related
I have a .yaml in which:-
value: "this is the whole line with this text -Djavax.net.ssl.keyStorePassword and the line continuous"
I want to delete only -Djavax.net.ssl.keyStorePassword but it removes whole value: section
You can use sed to find and replace a string in your file.
See also: https://unix.stackexchange.com/questions/159367/using-sed-to-find-and-replace#159369
The code your your case would look like:
sed -i -e 's/-Djavax.net.ssl.keyStorePassword//g' filename.yaml
This makes sed to replace your string with an empty string.
The /s option is used to find a substring in a file. Place the string to replace it with after the next /. /g in the end makes sed to copy that string to your file.
See https://linux.die.net/man/1/sed
I have the following content in a file
dhcp_option_domain:
- test.domain
And what I need to do is this:
whenever the value 'dhcp_option_domain:' followed by a newline and then ANY string, replace it with 'dhcp_option_domain:' followed by a newline and a variable.
ie if I set a variable of dhcp_domain="different.com" then then string above would convert to:
dhcp_option_domain:
- different.com
Note that both lines have and need to maintain leading 2 spaces.
I do not want to just do a search and replace on 'test.domain' as I have a few cases to use this and the values could be different each time the sed command is run.
I have tried a few methods such as:
dhcp_domain="something.com"
sed -i 's|dhcp_option_domain:\n.*|dhcp_option_domain:\n - $dhcp_domain|g' filename
however cannot get it to work.
Thanks.
As the manual explains:
sed operates by performing the following cycle on each line of input: first, sed reads one line from the input stream, removes any trailing newline, and places it in the pattern space. Then commands are executed
Your regex (dhcp_option_domain:\n.*) does not match because there is no \n in the pattern space in the first place.
A possible solution:
sed '/dhcp_option_domain:$/{n;c\
- '"$dhcp_domain"'
}'
The /dhcp_option_domain:$/ part is an address. The following command is only executed on lines matching that pattern.
The { } command groups multiple commands into a single block.
The n command prints out the current pattern space and replaces it by the next line of input.
The c\ command replaces the current pattern space by whatever follows in the script. Here it gets a bit tricky. We have:
a literal newline in the sed program (required after c\), then
- (placing those characters in the pattern space literally, then
' (part of shell syntax, terminating the single-quoted part started by sed '...), then
" (starting a double-quoted part), then
$dhcp_domain (which, because it's in a double-quoted part, interpolates the contents of the dhcp_domain shell variable), then
" (terminating the double-quoted part), then
' (starting another single-quoted part), then
a literal newline again (terminating the text after c\), then
} (closing the block started by {).
By default, sed works line by line (using newline character to distinguish newlines)
$ cat ip.txt
foo baz
dhcp_option_domain:
- test.domain
123
dhcp_option_domain:
$ dhcp_domain='something.com'
$ sed '/^ dhcp_option_domain:/{n; s/.*/ - '"$dhcp_domain"'/}' ip.txt
foo baz
dhcp_option_domain:
- something.com
123
dhcp_option_domain:
/^ dhcp_option_domain:/ condition to match
{} to group more than one command to be executed when this condition is satisfied
n get next line
s/.*/ - '"$dhcp_domain"'/ replace it as required - note that shell variables won't be expanded inside single quotes, see sed substitution with bash variables
for details
note that last line in the file didn't trigger the change as there was no further line
tested on GNU sed, syntax might vary for other implementations
From GNU sed manual
n
If auto-print is not disabled, print the pattern space, then,
regardless, replace the pattern space with the next line of input. If
there is no more input then sed exits without processing any more
commands.
This might work for you (GNU sed):
sed '/dhcp_option_domain:$/{p;s// - '"${var}"'/;n;d}' file
Match on dhcp_option_domain:, print it, substitute the new domain name (maintaining indent), print the current line and fetch the next (n) and delete it.
I know this should be straight forward but I'm stuck, sorry.
I have two files both contain the same parameters but with different values. I'm trying to read one file line at a time, get the parameter name, use this to match in the second file and replace the whole line with that from file 1.
e.g. rw_2.core.fvbCore.Param.isEnable 1 (FVB_Params)
becomes
rw_2.core.fvbCore.Param.isEnable true (FVB_Boolean)
The lines are not always the same length but I always want to replace the whole line.
The code I have is as follows but it doesn't make the substitutions and I can't work out why not.
while read line; do
ParamName=`awk '{print $1}'`
sed -i 's/$ParamName.*/$line/g' FVB_Params.txt
done < FVB_Boolean.txt
You need your sed command within double quotes if you want those variables to be replaced with their values. You have single quotes, so sed is actually looking for strings with dollar signs to replace with the string '$line', not whatever your shell has in the $line variable.
In short, sed's not seeing the values you want. Switch to double quotes.
I have text file input.txt which has
april,december,month.gmail.com
lion,tiger,animal.gmail.com
Using sed change first and second columns to uppercase? Is there a way to do it?
With GNU sed:
sed 's/^[a-z]*,[a-z]*,/\U&/' file
s: substitute command
[a-z]*,: search for zero ore more lowercase letter followed by a ,. The pattern is repeated for second field
the \U sequence turns the replacement to uppercase
\U is applied to & which reference the matched string
or if there is only three comma separated fields:
sed 's/^[a-z].*,/\U&/' file
output:
APRIL,DECEMBER,month.gmail.com
LION,TIGER,animal.gmail.com
As #Sundeep suggests, the second sed can be shortened to:
s/^.*,/\U&/
which converts all characters until last , is found
For more on GNU sed substitution command, see this article
Input-
X's Score 1725 and Y's Score 6248 in the match number 576
I want sed to ouput-
1725
6248
My code-
sed 's/Score[[:space:]]\([0-9]+\)/\1/g'
The above code outputs -
1725 and Y's 6248 in the match
You could try the following sed commands
#!/bin/sed f
s/Score\s*/\
/g
s/\n\([0-9]\+\)[^\n]*/\
\1/g
s/^[^\n]*\n//
The first command replaces all "Score"s with newlines, so now all numbers are at the beginning of a line. To insert a newline character, we must write a backslash followed by an actual line break. That's why the command spawns two lines.
The second command will remove everything after the numbers that are on the beginning of a line. It will match a newline character followed by a number (this is how we now that this number was prefixed by a "Score" string). The number will be captured into variable \1. Then it will skip all characters up to the newline character. When writing the replacement, we must restore the newline character and the number that was captured into \1.
Because the first line contains text before the first "Score", we must remove it. That's what the last command does, it matches all characters up to the first newline, starting from the beginning of the contents of the pattern space (ie. our working buffer).
In a single command:
sed -e 's/Score\s*/\
/g;s/\n\([0-9]\+\)[^\n]*/\
\1/g;s/^[^\n]*\n//'
Hope this helps =)
One way using GNU sed because \b that matches a word boundary is an extension.
echo "X's Score 1725 and Y's Score 6248 in the match number 576" | sed -e '
## Surround searched numbers (preceded by "Score") with newline characters.
s/\bScore \([0-9]\+\)\b/\n\1\n/g;
## Delete all numbers not preceded by a newline character.
s/\([^\n0-9]\)[0-9]\+/\1/g;
## Remove all other characters but numbers and newlines.
s/[^0-9\n]\+//g;
## Remove extra newlines.
s/\n\([0-9]\)/\1/g;
s/\n$//
' infile
It yields:
1725
6248
You could AND two egreps:
<infile egrep -o 'Score [0-9]+' | egrep -o '[0-9]+$'