I have a .yaml in which:-
value: "this is the whole line with this text -Djavax.net.ssl.keyStorePassword and the line continuous"
I want to delete only -Djavax.net.ssl.keyStorePassword but it removes whole value: section
You can use sed to find and replace a string in your file.
See also: https://unix.stackexchange.com/questions/159367/using-sed-to-find-and-replace#159369
The code your your case would look like:
sed -i -e 's/-Djavax.net.ssl.keyStorePassword//g' filename.yaml
This makes sed to replace your string with an empty string.
The /s option is used to find a substring in a file. Place the string to replace it with after the next /. /g in the end makes sed to copy that string to your file.
See https://linux.die.net/man/1/sed
Related
I have a file with a string log.txt and inside the file i have multiple lines
line 1 text
line2/random/string/version:0.0.30
line 3 randome stuff
http://someurl:8550/
So currently I use sed to find and replace 0.0.30 to a new value like 0.0.31
with
sed -i s/0.0.30/0.0.31/g log.txt
The problem with this is I need to know the previous value.
Is there a way to always remove 0.0.30 from the string in the file and replace it with a new value ?
Maybe a indexof or a substring.
You can use a regex definition to match 0.0.30 and replace it with 0.0.31 as below. The --posix flag is to ensure no GNU dialects are applied and plain BRE (Basic Regular Expressions) library is used. Since \{2\} is a BRE syntax to match 2 occurrences of the digit.
sed -i --posix 's/[[:digit:]]\.[[:digit:]]\.[[:digit:]]\{2\}/0.0.31/' file
See explanation for regex here.
I am trying to add multiple lines to a file, all with a leading a tab. The lines should be inserted on the first line after matching a string.
Assume a file with only one line, called "my-file.txt" as follows:
foo
I have tried the following sed command:
sed "/^foo\$/a \tinsert1\n\tinsert2" my-file.txt
This produces the following output:
foo
tinsert1
insert2
Notice how the the tab that should be on the first (inserted) line is omitted. Instead it prints an extra leading 't'.
Why? And how can I change my command to print the tab on the first line, as expected?
With GNU sed:
sed '/^foo$/a \\tinsert1\n\tinsert2' file
<---- single quotes! --->
Produces:
foo
insert1
insert2
From the manual:
a \
text Append text, which has each embedded newline preceded by a backslash.
Since the text to be append itself has to to be preceded by a backslash, it needs to be \\t at the beginning.
PS: If you need to use double quotes around the sed command because you want to inject shell variables, you need to escape the \ which precedes the text to be appended:
ins1="foo"
ins2="bar"
sed "/^foo\$/a \\\t${ins1}\n\t${ins2}" file
sed is for doing s/old/new on individual strings, that is all. Just use awk:
$ awk '{print} $0=="foo"{print "\tinsert1\n\tinsert2"}' file
foo
insert1
insert2
The above will work using any awk in any shell on every UNIX box and is trivial to modify to do anything else you might want to do in future.
I am trying to replace a list of words found in a csv file with index markup (docbook). The csv is in this format:
testword[ -?],testword<indexterm><primary>testword</primary></indexterm>
This finds all occurrences of the testword with punctuation at the end. This part works. However, I need the final punctuation mark to be included in the replace part of the sed command.
sed -e 's/\(.*\)/s,\1,g/' index.csv > index.sed
sed -i -f index.sed file.xml
So e.g. This is a testword, in a test.
Would get replaced with This is a testword,<indexterm><primary>testword</primary></indexterm> in a test.
Problem is the string in the csv file that steers the proces, here you loose the punctuation.
Replacing the:
testword[ -?],testword<indexterm><primary>testword</primary></indexterm>
by:
testword\([ -?]\),testword\1<indexterm><primary>testword</primary></indexterm>
Would already solve your problem.
I want to replace ignore_broadcast_ssid=1 with ignore_broadcast_ssid=0
inside the file /var/run/hostapd-phy0.conf.
This would be my first guess:
sed 's/ignore_broadcast_ssid=1/ignore_broadcast_ssid=0/g' /var/run/hostapd-phy0.conf
But this replaces this option globally, How can I only replace this in one of the sections, starting with bss=wlan0-2 inside the file?
...
bss=wlan0-2
ctrl_interface=/var/run/hostapd
ap_isolate=1
disassoc_low_ack=1
preamble=1
wmm_enabled=1
ignore_broadcast_ssid=0
uapsd_advertisement_enabled=1
auth_algs=1
wpa=0
ssid=temp_wifi
bridge=br-client
bssid=a0:f3:c1:d8:b7:7c
interface=client0
ctrl_interface=/var/run/hostapd
ap_isolate=1
disassoc_low_ack=1
preamble=1
wmm_enabled=1
...
You can first find out the line number of the first text as the starting search index:
grep -n "bss=wlan0-2"
Let assume it is at Line 10. Then apply your sed command at follow:
sed '10s/ignore_broadcast_ssid=1/ignore_broadcast_ssid=0/' /var/run/hostapd-phy0.conf
Make sure you don't have the keyword g at the end of the command as it indicates to replace the matching pattern globally.
sed '/bss=wlan0-2/,/ignore_broadcast_ssid/{s/ignore_broadcast_ssid=1/ignore_broadcast_ssid=0/}' file
I'm struggling to find a sed command to remove all lines in a text file that do not contain punctuation (of any kind) without doing each manually.
For example:
111.222.123.234
222.11.34.54
word # To remove
www.facebook.com
www.stackoverflow.com
another # To remove
random#email.com
Does such a command exist?
You can use the [:punct:] character class, which corresponds to
[!"#$%&'()*+,-./:;<=>?#[\]^_`{|}~]
and negate it:
$ sed '/[[:punct:]]/!d' infile
111.222.123.234
222.11.34.54
www.facebook.com
www.stackoverflow.com
random#email.com
Or, instead of the negated match, negate the character class directly:
sed '/[^[:punct:]]/d'
Or don't print anything unless a line does contain a punctuation character:
sed -n '/[[:punct:]]/p'
Or use grep instead of sed:
grep '[[:punct:]]' infile