The type or namespace name 'Forms' does not exist in the namespace 'System.Windows' FIX - unity3d

Can someone please help me with this, am trying to use OpenFileDialog class from System.Windows.Forms to open a file dialog and read the selected file. Then, this error showed up. I've referenced it but still the same, below is the code.
`using UnityEngine
using UnityEngine.UI
using System.Windows.Forms;
public class OpenFileButtonScript : MonoBehaviour
{
public TextFieldScript textFieldScript;
public void OpenFile()
{
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*";
openFileDialog.FilterIndex = 1;
openFileDialog.Multiselect = false;
if (openFileDialog.ShowDialog() == DialogResult.OK)
{
string filePath = openFileDialog.FileName;
string text = System.IO.File.ReadAllText(filePath);
textFieldScript.inputField.text = text;
}
}
}`

It may look like you have access to all of the native Window system libraries, but it just looks like it. In actuality, a lot of the time you're simply given stubs, or shims, that look like the full Window libraries, because there's a certain element that Unity wants to use from those namespaces. If you think about it, the code you present above, what do you think it should do on Android or Nintendo devices? The simple answer is, it simply won't work.
Generally in cases like this, you have to gain access to the native operating system, and perform those calls directly. For example, there is a file browser asset on the Asset Store, that does this for you. It's not free, because the process isn't trivial.
Depending on how much effort you want to put in, you CAN read files from the local file stores (to varying degrees based on platform). It's possible to read the list of files in a location, and use either uGUI or UIToolkit to create your own File Open Dialogue box. Again, this isn't a trivial task either. So you have to be sure that you'd want to go down that path.

Related

How to exclude UnityEditor reference from asmdef?

How to exclude UnityEditor reference from asmdef?
Why I need it:
I have an asmdef file. For example, it is MyAssembly/MyAssembly.asmdef. The MyAssembly contains a lot of features and each feature staff is placed in its own folder. And some of these features has a code that is needed only in editor, and it refers to UnityEditor namespace. Such editor code is placed into an Editor folder.
But as you know, Editor folder name means nothing in terms of asmdef usage. So I add AssemblyDefenitionReference in each folder and refer it to the MyAssemblyEditor.asmdef assembly definition. So the paths looks like this:
MyAssembly/MyAssembly.asmdef
MyAssembly/Editor/MyAssemblyEditor.asmdef - this folder contains no code. It's needed just to place asmdef, because it's not allowed to place two asmdefs in a single folder.
MyAssembly/SomeFeature/Editor/*feature editor staff*
MyAssembly/SomeFeature/Editor/Editor.asmref - refers to MyAssemblyEditor.asmdef
MyAssembly/SomeFeature/*feature staff*
All this works good. But the problem is that, when some developer adds a new feature, he can forget to add a reference to the MyAssemblyEditor.asmdef in the editor folder. And there are no any errors will be shown in this case. This mistake will be revealed only when the build will be cooked. But I'd like that using of UnityEditor in MyAssembly will be instantly marked as an error.
Feel free to suggest other solution for this problem.
This thread got me thinking I can use CsprojPostprocessor to remove all references to UnityEditor from my csproj file. I wrote such class:
using System.Text.RegularExpressions;
using UnityEditor;
// ReSharper disable once CheckNamespace
public class CsprojPostprocessor : AssetPostprocessor
{
public static string OnGeneratedCSProject(string path, string content)
{
if (!path.EndsWith("Editor.csproj") && !path.EndsWith("Tests.csproj"))
{
var newContent =
Regex.Replace(content, "<Reference Include=\"UnityEditor(.|\n)*?</Reference>", "");
return newContent;
}
return content;
}
}
It also can be done with an xml parser or something.
The only thing, that confuse me is that this mechanism is badly documented and doesn't look like something simple users should use. So I use it at my own risk, but looks like there is no guarantee it will be strongly supported in future.

Is it possible on monogame to load content files to the Content Manager at run time?

The reason I want to do this is that I'd like users to be able to create their own racetrack and save it as an image. Users would then be able to select their image and race on their track.
I'm thinking of using the following code to test if the file exists
using System.IO;
public static bool TrackExists(string fileName)
{
return File.Exists($#"Content\Tracks\{fileName}.xnb");
}
If it doesn't exist in the pipeline, I'd like it to be added and built so it can then be used in the project.
How should I go about doing this?
if (File.Exists(path))
{
tex.FromFile(_graphicsDevice, path);
_game.ChangeState(new RaceState(_game, _graphicsDevice, _content, tex));
}
If you need to load an image file as a Texture2D, you need to use the static method Texture2D.FromFile() as follows
myTex2D = Texture2D.FromFile(GraphicsDevice, "path/to/file");
As a rule of thumb, you cannot use the pipeline to load files dynamically. Nevertheless, it is not necessary that you have to use it. AFAIK the pipeline is the best and fastest way to load the static content of your game. There will be methods to import your custom files as content dynamically, so don't worry just because you're not using the pipeline. There are many types in Monogame (like Texture2D) that support dynamic loading from files.
EDIT:
Just to clarify, The method is a static member of Texture2D class, so you should be using it as follows:
if (File.Exists(path))
{
tex = Texture2D.FromFile(_graphicsDevice, path);
//...Rest of your code
}

How to customize addContentItemDialog to restrict files over 10mb upload in IBM Content Navigator

I am customizing ICN (IBM Content Navigator) 2.0.3 and my requirement is to restrict user to upload files over 10mb and only allowed files are .pdf or .docx.
I know I have to extend / customize the AddContentItemDialog but there is very less detail on exactly how to do it, or any video on it. I'd appreciate if someone could guide.
Thanks
I installed the development environment but I am not sure how to extend the AddContentItemDialog.
public void applicationInit(HttpServletRequest request,
PluginServiceCallbacks callbacks) throws Exception {
}
I want to also know how to roll out the changes to ICN.
This can be easily extended. I would suggest to read the ICN red book for the details on how to do it. But it is pretty standard code.
Regarding rollout the code to ICN, there are two ways:
- If you are using plugin: just replace the Jar file on the server location and restart WAS.
- If you are using EDS: you need to redeploy the web service and restart WAS.
Hope this helps.
thanks
Although there are many ways to do this, one way indeed is tot extend, or augment the AddContentItemDialog as you qouted. After looking at the (rather poor IBM documentation) i figured you could probably use the onAdd event/method
Dojo/Aspect#around allows you to do exactly that, example:
require(["dojo/aspect", "ecm/widget/dialog/AddContentItemDialog"], function(aspect, AddContentItemDialog) {
aspect.around(AddContentItemDialog.prototype, "onAdd", function advisor(original) {
return function around() {
var files = this.addContentItemGeneralPane.getFileInputFiles();
var containsInvalidFiles = dojo.some(files, function isInvalid(file) {
var fileName = file.name.toLowerCase();
var extensionOK = fileName.endsWith(".pdf") || fileName.endsWith(".docx");
var fileSizeOK = file.size <= 10 * 1024 * 1024;
return !(extensionOK && fileSizeOK);
});
if (containsInvalidFiles) {
alert("You can't add that :)");
}else{
original.apply(this, arguments);
}
}
});
});
Just make sure this code gets executed before the actual dialog is opened. The best way to achieve this, is by wrapping this code in a new plugin.
Now on creating/deploying plugins -> The easiest way is this wizard for Eclipse (see also a repackaged version for newer eclipse versions). Just create a new arbitrary plugin, and paste this javascript code in the generated .js file.
Additionally it might be good to note that you're only limiting "this specific dialog" to upload specific files. It would probably be a good idea to also create a requestFilter to limit all possible uses of the addContent api...

Changing working directory in Scala [duplicate]

How can I change the current working directory from within a Java program? Everything I've been able to find about the issue claims that you simply can't do it, but I can't believe that that's really the case.
I have a piece of code that opens a file using a hard-coded relative file path from the directory it's normally started in, and I just want to be able to use that code from within a different Java program without having to start it from within a particular directory. It seems like you should just be able to call System.setProperty( "user.dir", "/path/to/dir" ), but as far as I can figure out, calling that line just silently fails and does nothing.
I would understand if Java didn't allow you to do this, if it weren't for the fact that it allows you to get the current working directory, and even allows you to open files using relative file paths....
There is no reliable way to do this in pure Java. Setting the user.dir property via System.setProperty() or java -Duser.dir=... does seem to affect subsequent creations of Files, but not e.g. FileOutputStreams.
The File(String parent, String child) constructor can help if you build up your directory path separately from your file path, allowing easier swapping.
An alternative is to set up a script to run Java from a different directory, or use JNI native code as suggested below.
The relevant OpenJDK bug was closed in 2008 as "will not fix".
If you run your legacy program with ProcessBuilder, you will be able to specify its working directory.
There is a way to do this using the system property "user.dir". The key part to understand is that getAbsoluteFile() must be called (as shown below) or else relative paths will be resolved against the default "user.dir" value.
import java.io.*;
public class FileUtils
{
public static boolean setCurrentDirectory(String directory_name)
{
boolean result = false; // Boolean indicating whether directory was set
File directory; // Desired current working directory
directory = new File(directory_name).getAbsoluteFile();
if (directory.exists() || directory.mkdirs())
{
result = (System.setProperty("user.dir", directory.getAbsolutePath()) != null);
}
return result;
}
public static PrintWriter openOutputFile(String file_name)
{
PrintWriter output = null; // File to open for writing
try
{
output = new PrintWriter(new File(file_name).getAbsoluteFile());
}
catch (Exception exception) {}
return output;
}
public static void main(String[] args) throws Exception
{
FileUtils.openOutputFile("DefaultDirectoryFile.txt");
FileUtils.setCurrentDirectory("NewCurrentDirectory");
FileUtils.openOutputFile("CurrentDirectoryFile.txt");
}
}
It is possible to change the PWD, using JNA/JNI to make calls to libc. The JRuby guys have a handy java library for making POSIX calls called jnr-posix. Here's the maven info
As mentioned you can't change the CWD of the JVM but if you were to launch another process using Runtime.exec() you can use the overloaded method that lets you specify the working directory. This is not really for running your Java program in another directory but for many cases when one needs to launch another program like a Perl script for example, you can specify the working directory of that script while leaving the working dir of the JVM unchanged.
See Runtime.exec javadocs
Specifically,
public Process exec(String[] cmdarray,String[] envp, File dir) throws IOException
where dir is the working directory to run the subprocess in
If I understand correctly, a Java program starts with a copy of the current environment variables. Any changes via System.setProperty(String, String) are modifying the copy, not the original environment variables. Not that this provides a thorough reason as to why Sun chose this behavior, but perhaps it sheds a little light...
The working directory is a operating system feature (set when the process starts).
Why don't you just pass your own System property (-Dsomeprop=/my/path) and use that in your code as the parent of your File:
File f = new File ( System.getProperty("someprop"), myFilename)
The smarter/easier thing to do here is to just change your code so that instead of opening the file assuming that it exists in the current working directory (I assume you are doing something like new File("blah.txt"), just build the path to the file yourself.
Let the user pass in the base directory, read it from a config file, fall back to user.dir if the other properties can't be found, etc. But it's a whole lot easier to improve the logic in your program than it is to change how environment variables work.
I have tried to invoke
String oldDir = System.setProperty("user.dir", currdir.getAbsolutePath());
It seems to work. But
File myFile = new File("localpath.ext");
InputStream openit = new FileInputStream(myFile);
throws a FileNotFoundException though
myFile.getAbsolutePath()
shows the correct path.
I have read this. I think the problem is:
Java knows the current directory with the new setting.
But the file handling is done by the operation system. It does not know the new set current directory, unfortunately.
The solution may be:
File myFile = new File(System.getPropety("user.dir"), "localpath.ext");
It creates a file Object as absolute one with the current directory which is known by the JVM. But that code should be existing in a used class, it needs changing of reused codes.
~~~~JcHartmut
You can use
new File("relative/path").getAbsoluteFile()
after
System.setProperty("user.dir", "/some/directory")
System.setProperty("user.dir", "C:/OtherProject");
File file = new File("data/data.csv").getAbsoluteFile();
System.out.println(file.getPath());
Will print
C:\OtherProject\data\data.csv
You can change the process's actual working directory using JNI or JNA.
With JNI, you can use native functions to set the directory. The POSIX method is chdir(). On Windows, you can use SetCurrentDirectory().
With JNA, you can wrap the native functions in Java binders.
For Windows:
private static interface MyKernel32 extends Library {
public MyKernel32 INSTANCE = (MyKernel32) Native.loadLibrary("Kernel32", MyKernel32.class);
/** BOOL SetCurrentDirectory( LPCTSTR lpPathName ); */
int SetCurrentDirectoryW(char[] pathName);
}
For POSIX systems:
private interface MyCLibrary extends Library {
MyCLibrary INSTANCE = (MyCLibrary) Native.loadLibrary("c", MyCLibrary.class);
/** int chdir(const char *path); */
int chdir( String path );
}
The other possible answer to this question may depend on the reason you are opening the file. Is this a property file or a file that has some configuration related to your application?
If this is the case you may consider trying to load the file through the classpath loader, this way you can load any file Java has access to.
If you run your commands in a shell you can write something like "java -cp" and add any directories you want separated by ":" if java doesnt find something in one directory it will go try and find them in the other directories, that is what I do.
Use FileSystemView
private FileSystemView fileSystemView;
fileSystemView = FileSystemView.getFileSystemView();
currentDirectory = new File(".");
//listing currentDirectory
File[] filesAndDirs = fileSystemView.getFiles(currentDirectory, false);
fileList = new ArrayList<File>();
dirList = new ArrayList<File>();
for (File file : filesAndDirs) {
if (file.isDirectory())
dirList.add(file);
else
fileList.add(file);
}
Collections.sort(dirList);
if (!fileSystemView.isFileSystemRoot(currentDirectory))
dirList.add(0, new File(".."));
Collections.sort(fileList);
//change
currentDirectory = fileSystemView.getParentDirectory(currentDirectory);

Access images or doc outside public folder in zend framework

I developing an application in zend framework. I want to store certain secure images and pdf documents outside public folder like /project/data/uploads or /projects/application/data/uploads.
I am not able to access the images/pdf documents other than public folder.
Can someone suggest a way to do it.
thank you
You have to have a separate action that knows how to fetch and deliver all that stuff. Something like this:
public function viewpdfAction()
{
$id = (int) $this->_getParam('id', 0);
// You implement some function - either here in your controller
// or someplace else - to get the pdf name from the passed id.
// Alternatively, you can pass the name itself. Up to you, of course.
// The key is that the request somehow identifies the file requested.
$pdfName = $this->_mapPdfIdToName($id);
// The path to the real pdf
$pdfFile = '/project/data/uploads/pdf/' . $pdfName;
// Disable rendering
$this->_helper->viewRenderer->setNoRender(true);
// Send the right mime headers for the content type
$this->getResponse()
->setBody('')
->setHeader('Cache-control', 'public') // needed for IE, I have read
->setHeader('Content-type', 'application/pdf')
->setHeader('Content-Disposition', sprintf('attachment; filename="%s"', $pdfName));
// Send the content
readfile($pdfFile);
}
Of course, some of this can be pushed down into service classes to keep the controller as thin as possible. Everyone has different tastes in this regard.
I confess that this code not completely tested, mostly trying to give the basic idea. If I have made a total bonehead error in here, please let me know.
Hope it helps!