**loginServlet.java**
package com.anil.apps;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LoginServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out=response.getWriter();
String uid=request.getParameter("userid");
String password=request.getParameter("pwd");
if(uid.equals("Anil")&&password.equals("missinlx")){
//out.println("welcome "+uid);
response.sendRedirect("welcomeUser?userid="+uid);
}
else{
out.println("invalid username or password");
}
}
}
**WelcomeUserServlet.java**
package com.anil.apps;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class WelcomeUserServlet extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out=response.getWriter();
out.println("<html><body><h1>Welcome " +uid+ "</h1></body></html>");
}
}
what is wrong with my code?? I want to redirect the page to welcomeUser.java page using response.sendRedirect() method.
As I am new to servlet please help me out of it. please tell me the whole format for the page redirection in Servlets.
GET parameters are not turned in to variables automatically. You need to add this to the top of your doGet method in the WelcomeUserServlet:
String uid = request.getParameter("userId");
Making that class look like this:
public class WelcomeUserServlet extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String uid = request.getParameter("userId");
PrintWriter out=response.getWriter();
out.println("<html><body><h1>Welcome " +uid+ "</h1></body></html>");
}
}
You are using the wrong argument for the sendRedirect method
You should use a complete path like
response.sendRedirect("some/path/here/to/"+welcomeUser?userid="+uid)
Or better
response.sendRedirect(response.encodeURL(response.getContextPath()+"welcomeUser?userid="+uid))
Or use a request dispatcher which knows the structure of your project and does not need a full path
request.getRequestDispatcher("welcomeUser?userid="+uid).forward(request,response)
Related
i'm trying to solve this problem since 2 days, there are the same title of problems in many post on stackoverflow but it was all different, because they allways had an error in code, but in my case i have a sample servlet, and when i run the project i get this error
HTTP Status 405 - HTTP method GET is not supported by this URL
this is my class servlet
package web;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Controller extends HttpServlet{
/**
*
*/
private static final long serialVersionUID = 1L;
#Override
public void init() throws ServletException {
}
#Override
protected void doGet(HttpServletRequest requet, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html");
response.setCharacterEncoding("UTF-8");
PrintWriter out =response.getWriter();
out.println("hello");
}
}
and my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" id="WebApp_ID" version="3.1">
<display-name>test2</display-name>
<servlet>
<servlet-name>cs</servlet-name>
<servlet-class>web.Controller</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>cs</servlet-name>
<url-pattern>/hello</url-pattern>
</servlet-mapping>
</web-app>
please tell me how solve this problem, thanks ...
Simple doGet Servlet Or You Can add try catch blog to debug code
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
public class logout extends HttpServlet
{
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
try
{
PrintWriter out=response.getWriter();
response.setContentType("text/html;charset=UTF-8");
out.println("Hello");
}
catch(Exception e)
{
out.println(e.toString())
}
}
}
I think you probably have not add GAT method on form attribute Like this
<form action="web" method="GET"></form>
What can a JSP form action be?
I have a Login.jsp page for the user to end the details.
Can i give the servlet class in the form action?
here is the the servlet code.
package mybean;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
public class LoginServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public LoginServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
try
{
System.out.println("In the Login Servlet");
LoginBean user = new LoginBean();
user.setUemail(request.getParameter("uemail"));
user.setUpass(request.getParameter("upass"));
user = LoginDAO.login(user);
if(user.isValid())
{
HttpSession session = request.getSession(true);
session.setAttribute("currentSessionUser",user);
response.sendRedirect("LoginSuccess.jsp");
}else
response.sendRedirect("LoginFailed.jsp");
} catch (Throwable exc)
{
System.out.println(exc);
}
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
}
As per the specs , it can take any valid URI
This attribute specifies a form processing agent. User agent behavior for a value other than an HTTP URI is undefined.
Can i give the servlet class in the form action ?
Yes if the servlet class name resolves to a valid URL mapped in the web.xml or else you will encounter a 404 .
Let us consider your JSP is at the root of the application, then
<FORM action="someServletName" method="post">
Now this will be resolved as protocol://servername:port/context/someServletName .Now somewhere you should have a mapping for /someServletName , either in web.xml or through annotation to a Servlet or JSP.
<servlet>
<servlet-name>someServletName</servlet-name>
<servlet-path>packageName.servletName</servlet-path>
</servlet>
<servlet-mapping>
<servlet-name>someServletName</servlet-name>
<url-pattern>/someServletName</url-pattern>
</servlet-mapping>
I have written a simple HelloServlet as follows.
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class HelloServlet
*/
#WebServlet("/HelloServlet")
public class HelloServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* #see HttpServlet#HttpServlet()
*/
public HelloServlet() {
super();
// TODO Auto-generated constructor stub
}
/**
* #see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
response.setContentType("text/html");
PrintWriter out = response.getWriter();
String docType =
"<!DOCTYPE HTML PUBLIC \"-//W3C//DTD HTML 4.0 " +
"Transitional//EN\">\n";
out.println(docType +
"<HTML>\n" +
"<HEAD><TITLE>Hello</TITLE></HEAD>\n" +
"<BODY BGCOLOR=\"#FDF5E6\">\n" +
"<H1>Hello</H1>\n" +
"</BODY></HTML>");
}
/**
* #see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
I have GlassFish 3.1 installed in the Java EE perspective in Eclipse.
Whenever I try and run the servlet clicking on "run on server" on the server it comes up with the following message:
This domain requires an administrative password to be set before the
domain can be started. Please specify an administrative password. The
Master Password is required to start the domain. No console, no
prompting possible. You should either create the domain with
--savemasterpassword=true or provide a password file with the --passwordfile option.
Command start-domain failed.
There is always a default master password "changeit" for glassfish. Why is it prompting me with this message ?
Good Morning, please i don't know how to resolve that exception, i'm using ApcheTomcat 7 under eclipse and that exception is thrown everytime i run my servlet, here's my servlet for more clarity:
package servlets;
import java.util.*;
import java.io.IOException;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import dao.*;
#WebServlet("/AdminServlt")
public class AdminServlt extends HttpServlet {
private static final long serialVersionUID = 1L;
CarHome carDao;
public void init(ServletConfig config) throws ServletException{
carDao = new CarHome();
}
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
populateAdminView(request, response);
}
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
}
public void populateAdminView(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException{
ArrayList productsList = (ArrayList) carDao.extractAdminAttributes();
HttpSession session = request.getSession(true);
session.setAttribute("product_list",productsList);
RequestDispatcher rd = request.getRequestDispatcher("Admin.jsp");
rd.forward(request, response);
}
}
and here's CarHome.java
package dao;
import java.util.ArrayList;
import java.util.List;
import javax.naming.InitialContext;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import org.hibernate.LockMode;
import org.hibernate.SessionFactory;
import org.hibernate.criterion.*;
import entity.*;
public class CarHome {
private static final Log log = LogFactory.getLog(CarHome.class);
private final SessionFactory sessionFactory = getSessionFactory();
public List extractAdminAttributes() {
log.debug("Extracting car attributes for administrator view");
try {
ArrayList results = (ArrayList) sessionFactory
.getCurrentSession()
.createCriteria("pojo.Car")
.setProjection(
Projections.projectionList()
.add(Projections.property("carDesc"))
.add(Projections.property("price"))
.add(Projections.property("quantity")));
return results;
} catch (RuntimeException re) {
log.error("find by admin view failed");
throw re;
}
}
}
here's the stacktrace of the exception
java.lang.ClassNotFoundException: org.hibernate.criterion.Projection
org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1676)
org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1521)
servlets.AdminServlt.init(AdminServlt.java:31)
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:462)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:562)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:395)
org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:250)
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:188)
org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:166)
org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:302)
java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
java.lang.Thread.run(Unknown Source)
i have solved my problem it was very simple, the main reason is that the hibernate.cor.jar file wasn't in the lib folder under the web-content of the application when i put it there it works fine
I was facing the same issue but in my case i re-ordered the hibernate-cor.jar on the top using eclipse
chose the project --> right click -->build path -->order tab -->chose the hibernate-cor.jar click top
I'm trying to create a REST service defined as:
#POST
#Path("/path")
#Consumes(MediaType.APPLICATION_XML)
#Produces("multipart/mixed")
public MultipartOutput create(MyObject o) {}
First part of the output will be an XML, second part a text file. In the XML I have the status code that I need, but how can I use it to create the HTTP status code? Currently I receive 200, I need 201.
(For other services, without MultipartOutput, the response is created using ResponseBuilder).
You can use the #Context to access the HttpServletResponse.
Try changing your method signature and call setStatus:
public MultipartOutput create(MyObject o, #Context HttpServletResponse response) {
MultipartOutput mpo = ...
response.setStatus(201);
return mpo;
}
EDIT :
Try using org.jboss.resteasy.spi.HttpResponse instead together with a PostProcessInterceptor:
import org.jboss.resteasy.core.Dispatcher;
import org.jboss.resteasy.core.ServerResponse;
import org.jboss.resteasy.mock.MockDispatcherFactory;
import org.jboss.resteasy.mock.MockHttpRequest;
import org.jboss.resteasy.mock.MockHttpResponse;
import org.jboss.resteasy.plugins.providers.multipart.MultipartOutput;
import org.jboss.resteasy.spi.HttpResponse;
import org.jboss.resteasy.spi.interception.PostProcessInterceptor;
import org.junit.Assert;
import org.junit.Test;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.core.Context;
import javax.ws.rs.core.MediaType;
import javax.xml.bind.annotation.XmlRootElement;
public class MultipartTest {
#XmlRootElement(name = "MyObject")
static class MyObject {}
#Path("/")
public static class Service {
#Context HttpResponse response;
#GET
#Path("/mpo")
public MultipartOutput create() {
response.setStatus(201);
final MultipartOutput mpo = new MultipartOutput();
mpo.addPart(new MyObject(), MediaType.APPLICATION_XML_TYPE);
return mpo;
}
}
public static class Interceptor implements PostProcessInterceptor {
#Context HttpResponse response;
#Override
public void postProcess(ServerResponse serverResponse) {
serverResponse.setStatus(response.getStatus());
}
}
#Test
public void test() throws Exception {
Dispatcher dispatcher = MockDispatcherFactory.createDispatcher();
dispatcher.getRegistry().addSingletonResource(new Service());
dispatcher.getProviderFactory().getServerPostProcessInterceptorRegistry().register(new Interceptor());
MockHttpRequest request = MockHttpRequest.get("/mpo");
MockHttpResponse response = new MockHttpResponse();
dispatcher.invoke(request, response);
Assert.assertEquals(201, response.getStatus());
}
}