powershell exchange 2003 : query ActiveDirectory for activesync, office, and description? - powershell

Question

I'm using powershell to pull a list of exchange 2003 users and based on the user's mailbox "LegacyDN", I was hoping to use an LDAP query to pull their activesyncenabled property (msExchOmaAdminWirelessEnable), description, and office; however, it doesn't seem to be coming up for me. any ideas?
here is how i'm querying for the AD attributes:
$allusers = get-wmiobject -class exchange_mailbox -namespace root\microsoftexchangev2 -computername srv02 | select mailboxdisplayname, legacyDN
foreach ($user in $allusers)
{
$obj = new-object psobject
$exchangever = "2003"
$tmp = [adsi]("LDAP://" + $user.legacydn)
$obj | add-member -membertype noteproperty -name "Display Name" -value $user.mailboxdisplayname
$obj | add-member -membertype noteproperty -name "Office" -value $tmp.physicaldeliveryofficename
$obj | add-member -membertype noteproperty -name "Description" -value $tmp.description
$obj | add-member -membertype noteproperty -name "Activesync" -value $tmp.msExchOmaAdminWirelessEnable
$allusersemail += $obj
}
$alluseremail | export-csv \\srv02\logs\test.csv

Answer 1

Here's one way:
$search = System.DirectoryServices.DirectorySearcher
$search.filter = "(&(homeMDB=*)(objectcategory=user)(objectclass=user))"
$props = "mailNickName","displayName","physicaldeliveryofficename","description","msExchOmaAdminWirelessEnable"
$props | foreach { [void]$search.PropertiesToLoad.Add($_) }
$users = $search.findAll()
foreach($u in $users)
{
$DisplayName = #{name="DisplayName";expression={$u.properties.item("DisplayName")}}
$Office = #{name="Office";expression={$u.properties.item("physicaldeliveryofficename")}}
$Description = #{name="Description";expression={$u.properties.item("Description")}}
$Activesync = #{name="Activesync";expression={$u.properties.item("msExchOmaAdminWirelessEnable")}}
$u | select $DisplayName,$Office,$Description,$Activesync
}