Is there any way using diff to show differences only in lines that include an specific word?
You can specify the option '-I regexp' to ignore the lines which match the specified regular expression. If you inverse the regex, you can ignore all lines NOT containing the word you're looking for.
See the diff manpage for more info or here for a specific example.
Related
I saw a SO post that says you can search using regex or an actual literal text on it to search multiline texts. But what if you want to (quickly) search two or three of words within a specified lines of text content?
For example, what if you want to search for multiline text area that contains "ruby" and "regex" (assuming you want to know where you took a note on your txt (or markdown or rich text format) file. you may want to search for "how to use regex in ruby" or "the ruby regex tutorial", right? )
Now you can use a simple (but redundant) regex like ruby(.*\n)+regex|regex(.*\n)+ruby. But to me it doesn't look beautiful. For three or more words, this kind of regex workaround increases its redundancy exponentially also, not good.
So is there a smarter way to do this? Thanks.
I have been researching this for quite some time but cannot seem to find an answer. Perhaps someone here can help.
I am trying to use sed to replace words in yml / yaml files. Since some of the words are included in the names I want to only replace words that appear after the colon (':').
For example. If the .yml file includes:
en:
label_some_tracker: A tracker
label_all_tracker: All trackers
label_attachment_type_trackers: Select trackers.
tracker_plural: trackers
and I want to replace all occurrences of tracker with issue in all values. The pattern:
s/tracker/issue/
also changes the names of the fields, which breaks my code.
I can reduce the size of the problem somewhat by including terms for all possible variants of a word. For example:
s/trackers/issues/
s/tracker/issue/
but that doesn't deal with all situations.
I have tried inserting a space before the search term:
s/ tracker/ issue/
but that matches names where the search term is at the beginning of the line.
If I search for whole words then it still seems to pick up the names because ':' and '_' are 'non word' characters.
If I try to put spaces at the beginning and end of the search term but then it misses words that are at the end of a line or words patterns with punctuation marks before the training space.
The only sure way seems to be to only replace words after a colon (':') but I cannot seem to figure out how to do that with sed.
Does anyone here know how?
With GNU sed:
sed -E 's/(:.*)tracker/\1issue/g' file
Output:
en:
label_some_tracker: A issue
label_all_tracker: All issues
label_attachment_type_trackers: Select issues.
tracker_plural: issues
Replace second occurance:
sed 's/tracker/issue/2' file
I want to search strings like "number 1" or "number 152" or "number 36985".
In all above strings "number " will be constant but digits will change and can have any length.
I tried Search option using wildcard but it doesn't seem to work.
basic regEx operators like + seem to not work.
I tried 'number*[1-9]*' and 'number*[1-9]+' but no luck.
This regular expression only selects upto one digit. e.g. If the string is 'number 12345' it only matches number 12345 (the part which is in bold).
Does anyone know how to do this?
Word doesn't use regular expressions in its search (Find) functionality. It has its own set of wildcard rules. These are very similar to RegEx, but not identical and not as powerful.
Using Word's wildcards, the search text below locates the examples given in the question. (Note that the semicolon separator in 1;100 may be soemthing else, depending on the list separator set in Windows (or on the Mac). My European locale uses a semicolon; the United States would use a comma, for example.
"number [0-9]{1;100}"
The 100 is an arbitrary number I chose for the maximum number of repeats of the search term just before it. Depending on how long you expect a number to be, this can be much smaller...
The logic of the search text is: number is a literal; the valid range of characters following the literal are 0 through 9; there may be one to one hundred of these characters - anything in that range is a match.
The only way RegEx can be used in Word is to extract a string and run the search on the string. But this dissociates the string from the document, meaning Word-specific content (formatting, fields, etc.) will be lost.
Try putting < and > on the ends of your search string to indicate the beginning and ending of the desired strings. This works for me: '<number [1-9]*>'. So does '<number [1-9]#>' which is probably what you want. Note that in Word wildcards the # is used where + is used in other RegEx systems.
Suppose I have 5000 images with following metadata in the LABEL field.
0001 ELEPHANT
0002 ELEPHANT
0003 ELEPHANT
...
4999 ELEPHANT
5000 ELEPHANT
I wish to change the format to:
ELEPHANT-0001
ELEPHANT-0002
ELEPHANT-0003
…
ELEPHANT-4999
ELEPHANT-5000
In other words, I want to do the following for a metadata field of multiple images:
#### NAME —> NAME-####
From what I can gather there could be two ways of doing this
Ignore the current metadata in the images, and reference a (plain text? csv?) file that I prepare separately; or
Read the file's metadata as a string, identify the space and the number preceding the space, save that number, and finally make a new string by concatenating the number and space, and adding a hyphen in between!
Any suggestions?
Expanding upon the answer I gave in the exiftool forums.
The basic command would be
exiftool "-LABEL<${LABEL;s/(\d{4}) (.*)/$2-$1/}" <FileOrDir>
You basically want to copy a tag into the same tag, with some modifications. The option to copy a tag is the less than (or greater than) symbol < or >. A common mistake is to use the equal sign = which is used to assign a static value to a tag.
To do the modification to the tag, it takes the Advance Formatting option, which is actually some in-line perl code. In this example, the tag is treated as a perl string and a regex substitution is used. It matches and captures the first four digits (\d{4}), matches the space (but doesn't capture it), then matches and captures the rest of the tag (.*). The two captures are assigned to the variables $1 and $2, respectively. In the replace half of the substitution $2-$1, the two captures are reversed with the hyphen between them.
To take full advantage of the advance formatting, some basic perl and regex knowledge is helpful.
Once you are sure of the command, you can add -overwrite_original to suppress the generation of backup files and -r to recurse into subdirectories.
How can I apply multiple search criteria to the document for obtaining a refined result/search? I 'tried' using wildcards -> ?[!a-z][!0-9][!^s] <- to find a character except from range a-z, range 0-9, and the non breaking space(^s). i.e. I do not want to find any character, any number or a space, but tabs, operators, special characters, etc. At least that's what I think it does. How can I use multiple "find what" criteria together in a document?
As a starting point, use wildcards and
[!0-9,a-z,A-Z, ]
should help. It may be possible to refine that further, but if not, VBA or equivalent and either a character-by-character check or multiple find loops are your options.