I use following find command to find and show all files having the input text pattern.
find . -type f -print|xargs grep -n "pattern"
I have many project folders each of which has its own makefile named as 'Makefile'.(no file extension, just 'Makefile')
How do i use above command to search for a certain pattern only in the files named Makefile which are present in all my project folders?
-AD.
-print is not required (at least by GNU find implementation). -name argument allows to specify filename pattern. Hence the command would be:
find . -name Makefile | xargs grep pattern
If you have spaces or odd characters in your directory paths youll need to use the null-terminated method:
find . -name Makefile -print0 | xargs -0 grep pattern
find . -type f -name 'Makefile' | xargs egrep -n "pattern"
use egrep if you have very long paths
Duplicate of : this
You can avoid the use of xargs by using -exec:
find . -type f -name 'Makefile' -exec egrep -Hn "pattern" {} \;
-H on egrep to output the full path to the matching files.
grep -R "string" /path
Please find this link
http://rulariteducation.blogspot.in/2016/03/how-to-check-particluar-string-in-linux.html
you can use ff command i.e ff -p .format. For eg ff -p *.txt
Find big files occupying large disk space
we need to combine multiple command .
find . -type f | xargs du -sk | sort -n | tail;
Related
I am now working with "Jenkinsfile".
I need to do a "find" by type of the file extension, to do a "sed -i", ignoring some hidden directories and other folders.
I don't know the correct syntax.
Example:
def replacePath() {
sh 'sed -i "s/A\\/B/C\\/D\\/E\\/F\\/G\\/A\\/B\\/opt\\/C/g" \$(find . -type f -name "*.json" not path ..... -print0) '
Try using xargs, like so:
find . -type f -name '*.json' ... -print0 | xargs -0 sed -i 's/pattern/replacement/g'
Using xargs has fewer problems than passing argument on the command line with $(...), particularly when used with -print0, as xargs can cope with filenames containing shell metacharacters.
I can do the find and replace a string in multiple files with the below command.
find . -name '*.py' | xargs sed -i 's/foo/faa/g'
Can we do the same by using Perl?
Try this command...:
find . -name '*.py' | xargs perl -p -i -e 's/foo/faa/g'
N.B.: If you want to make a backup copy of your files before changing them, provide -i flag with an extension... I.E.: -i.bak...
I'm using executing this bash commands inside a search script I've built with php:
find myFolder -type f -exec grep -r KEYWORD {} +
find myFolder -type f -exec grep -r KEYWORD {} + | wc -l
find myFolder -type f | wc -l
The first line gives me back the filenames where KEYWORD was found.
The second line gives me the number of occurrences and the third line the total number of files.
Is there a way to do this more elegantly and faster?
You can get more efficiency if you avoid -exec, which makes one fork per file match. xargs is a better choice here. So I would do something like this:
find myFolder -type f -print0 | xargs -0 grep KEYWORD
find myFolder -type f -print0 | xargs -0 grep KEYWORD | wc -l
The last one should be OK, at least with GNU find.
The -print0 and -0 ensure that filenames with spaces in them are handled correctly.
Note that grep -r` implies recursive grepping, but as you're only supplying one filename in each invocation it is redundant.
I'm new to sed, and need to grab just the filename from the output of find. I need to have find output the whole path for another part of my script, but I want to just print the filename without the path. I also need to match starting from the beginning of the line, not from the end. In english, I want to match, the first group of characters ending with ".txt" not containing a "/". Here's my attempt that doesn't work:
ryan#fizz:~$ find /home/ryan/Desktop/test/ -type f -name \*.txt
/home/ryan/Desktop/test/two.txt
/home/ryan/Desktop/test/one.txt
ryan#fizz:~$ find /home/ryan/Desktop/test/ -type f -name \*.txt | sed s:^.*/[^*.txt]::g
esktop/test/two.txt
ne.txt
Here's the output I want:
two.txt
one.txt
Ok, so the solutions offered answered my original question, but I guess I asked it wrong. I don't want to kill the rest of the line past the file suffix i'm searching for.
So, to be more clear, if the following:
bash$ new_mp3s=\`find mp3Dir -type f -name \*.mp3\` && cp -rfv $new_mp3s dest
`/mp3Dir/one.mp3' -> `/dest/one.mp3'
`/mp3Dir/two.mp3' -> `/dest/two.mp3'
What I want is:
bash$ new_mp3s=\`find mp3Dir -type f -name \*.mp3\` && cp -rfv $new_mp3s dest | sed ???
`one.mp3' -> `/dest'
`two.mp3' -> `/dest'
Sorry for the confusion. My original question just covered the first part of what I'm trying to do.
2nd edit:
here's what I've come up with:
DEST=/tmp && cp -rfv `find /mp3Dir -type f -name \*.mp3` $DEST | sed -e 's:[^\`].*/::' -e "s:$: -> $DEST:"
This isn't quite what I want though. Instead of setting the destination directory as a shell variable, I would like to change the first sed operation so it only changes the cp output before the "->" on each line, so that I still have the 2nd part of the cp output to operate on with another '-e'.
3rd edit:
I haven't figured this out using only sed regex's yet, but the following does the job using Perl:
cp -rfv `find /mp3Dir -type f -name \*.mp3` /tmp | perl -pe "s:.*/(.*.mp3).*\`(.*/).*.mp3\'$:\$1 -> \$2:"
I'd like to do it in sed though.
Something like this should do the trick:
find yourdir -type f -name \*.txt | sed 's/.*\///'
or, slightly clearer,
find yourdir -type f -name \*.txt | sed 's:.*/::'
Why don't you use basename instead?
find /mydir | xargs -I{} basename {}
No need external tools if using GNU find
find /path -name "*.txt" -printf "%f\n"
I landed on the question based on the title: using sed to grab filename from fullpath.
So, using sed, the following is what worked for me...
FILENAME=$(echo $FULLPATH | sed -n 's/^\(.*\/\)*\(.*\)/\2/p')
The first group captures any directories from the path. This is discarded.
The second group capture is the text following the last slash (/). This is returned.
Examples:
echo "/test/file.txt" | sed -n 's/^\(.*\/\)*\(.*\)/\2/p'
file.txt
echo "/test/asd/asd/entrypoint.sh" | sed -n 's/^\(.*\/\)*\(.*\)/\2/p'
entrypoint.sh
echo "/test/asd/asd/default.json" | sed -n 's/^\(.*\/\)*\(.*\)/\2/p'
default.json
find /mydir | awk -F'/' '{print $NF}'
path="parentdir2/parentdir1/parentdir0/dir/FileName"
name=${path##/*}
I am interested into getting into bash scripting and would like to know how you can traverse a unix directory and log the path to the file you are currently looking at if it matches a regex criteria.
It would go like this:
Traverse a large unix directory path file/folder structure.
If the current file's contents contained a string that matched one or more regex expressions,
Then append the file's full path to a results text file.
Bash or Perl scripts are fine, although I would prefer how you would do this using a bash script with grep, awk, etc commands.
find . -type f -print0 | xargs -0 grep -l -E 'some_regexp' > /tmp/list.of.files
Important parts:
-type f makes the find list only files
-print0 prints the files separated not by \n but by \0 - it is here to make sure it will work in case you have files with spaces in their names
xargs -0 - splits input on \0, and passes each element as argument to the command you provided (grep in this example)
The cool thing with using xargs is, that if your directory contains really a lot of files, you can speed up the process by paralleling it:
find . -type f -print0 | xargs -0 -P 5 -L 100 grep -l -E 'some_regexp' > /tmp/list.of.files
This will run the grep command in 5 separate copies, each scanning another set of up to 100 files
use find and grep
find . -exec grep -l -e 'myregex' {} \; >> outfile.txt
-l on the grep gets just the file name
-e on the grep specifies a regex
{} places each file found by the find command on the end of the grep command
>> outfile.txt appends to the text file
grep -l -R <regex> <location> should do the job.
If you wanted to do this from within Perl, you can take the find commands that people suggested and turn them into a Perl script with find2perl:
If you have:
$ find ...
make that
$ find2perl ...
That outputs a Perl program that does the same thing. From there, if you need to do something that easy in Perl but hard in shell, you just extend the Perl program.
find /path -type f -name "*.txt" | awk '
{
while((getline line<$0)>0){
if(line ~ /pattern/){
print $0":"line
#do some other things here
}
}
}'
similar thread
find /path -type f -name "outfile.txt" | awk '
{
while((getline line<$0)>0){
if(line ~ /pattern/){
print $0":"line
}
}
}'