I'm looking for a command that will compress every folder within a directory separately with the name of each archive reflecting the original folder name. I know that
tar czvf example.tar.gz example/
will compress an entire folder. However, I have not found a command to bulk archive. Is there such a command?
for f in `find -mindepth 1 -maxdepth 1 -type d`; do
tar -czf $f.tar.gz $f
done
find -mindepth 1 -maxdepth 1 -type d -exec tar czf {}.tar.gz {} \;
Note that I used -maxdepth 1.
Consider the directory structure:
.
|-- a
| `-- x
|-- b
`-- c
Without -maxdepth 1 you would get a.tar.gz and a/x.tar.gz. a.tar.gz would contain x and all of the files within; and a/x.tar.gz would contain x and its files. But this stores the items within x twice, assuming that isn't the goal.
Updated to use -mindepth 1 as well, because when run outside of example/ an example.tar.gz would be created as well.
Update ... and for bzip2:
find -mindepth 1 -maxdepth 1 -type d -exec tar cjf {}.tar.bz2 {} \;
Okay, here's the final command I came up with to archive then compress with bzip2 for maximum compression
find -mindepth 1 -maxdepth 1 -type d -exec tar cjf '{}'.tar.bz2 '{}' \;
thanks everyone!
Related
I tried to copy Copy directories and their subdirectories created a day ago as follows:
find /application/work/ -type d -mtime -1 -exec cp -r {} /tmp/backup \;
But it is copying all directories (Not only the ones created a day ago).
Would you please advise?
find is also finding the working directory /application/work/ and is copying it, see How to exclude this / current / dot folder from find "type d". Since you're executing cp -r, it recursively copies everything in . before also copying the subset of directories you've found via -mtime. You need to set the -mindepth to exclude the working directory from the paths on which find will operate.
Modify your command to:
find /application/work -mindepth 1 -type d -mtime -1 -exec cp -r {} /tmp/backup \;
I am trying to copy a folder containing a subfolder structure, while excluding a specified subfolder by using the find -exec cp command. I have managed to use multiple working excluding options when I am using the find command alone, but once I add the '-exec cp' command, the excluding terms work no longer.
Imagine the directory of interest containing multiple files and subfolders, with one subfolder named "exclusion_string"
This find command works properly when used alone:
find ~/directory/of/interest/ -maxdepth 2 ! -name "*exclusion_string*"
... while this command negates the exclusion criterium:
find ~/directory/of/interest/ -maxdepth 2 ! -name "*exclusion_string*" -exec cp -r '{}' . \;
Likewise, when using other criteria or arguments, the exclusion of a subdirectory is lost, E.g:
find ~/directory/of/interest/ -maxdepth 2 -name "*" -size -100k -exec cp -r '{}' . \;
find ~/directory/of/interest/ -maxdepth 2 -name "*exclusion_string*" | xargs cp -rt .
What am I missing here?
I tried to rename files ending with ".txt" to ".abc" using the find command as below. Now the files are not available on my disk.
find ./ -type f -iname '*.txt' -exec sh -c 'mv "$0" "$1.abc"' {} \;
can someone explain me the above command in detail what is did with the files.
Is there any possibility to retrive those, if yes how ?
You used the wrong variable and most of the files cannot be retrieved.
find ./ -type f -iname '*.txt' -exec sh -c 'mv "$0" "$1.abc"' {} \;
will rename every .txt file to a file called .abc. So if you files named bar.txt and foo.txt it will rename bar.txt to .abc and then rename foo.txt to .abc which will overwrite the original contents of bar.txt. You cannot see the file because it is .abc and is hidden under a normal list. If you run 'ls -a' you will see a file named ".abc" which will have the contents of the last .txt file that was renamed.
I am not sure how to do exactly what you wanted but running
find ./ -type f -iname '*.txt' -exec sh -c 'mv "$0" "$0.abc"' {} \;
will rename each .txt file to a .txt.abc file. So you would have bar.txt.abc and foo.txt.abc
The explanation of rondo is correct.
But what are the solutions for your problem?
If you want to replace the suffix .txt with .abc you can use rename
You will have success, if you use rename and find like this:
find . -type f -iname '*.txt' -print0 | xargs -0 rename .txt .abc
For all files found by find like x.txt or a/b.txt the appropriate command will execute, e.g.
rename .txt .abc x.txt
rename .txt .abc a/b.txt
so x.txt -> x.abc, and a/b.txt -> a/b.abc
If you only want to add the suffix .abc to all files you can still use mv
find . -type f -iname '*.txt' -print0 | xargs -0 mv {} {}.abc
With xargs for each file the command mv is executed.
BTW: with the find option "-print0" and the xargs option "-0" the commands work also with filenames which includes spaces.
As specified in title I am looking for a way how to create links to all subfolders containing specified text in their names, so for example for all subfolders of root directory containing ".app" in their names an link will be created to "/AppLinks" directory. I would like to use it in bash script (open source, free).
Does anyone know how to do that?
I searched it by google with no luck.
find yourdir -type d -name '*.app' -exec ln -s {} /AppLinks \;
Find all directories named something.app in yourdir, and create a symlink to them in /AppLinks.
single line bash-fu
function FUNCsymlink() { echo "$1"; fileName=`basename "$1"`; ln -s "$1" "/AppLinks/$fileName"; }; export -f FUNCsymlink; find `pwd`/ -maxdepth 1 -type d -iname "*.app" -exec bash -c "FUNCsymlink '{}'" \;
to easy reading:
function FUNCsymlink() {
echo "$1";
fileName=`basename "$1"`;
ln -s "$1" "/AppLinks/$fileName";
};
export -f FUNCsymlink;
find `pwd`/ -maxdepth 1 -type d -iname "*.app" -exec bash -c "FUNCsymlink '{}'" \;
you may have to adjust it a bit for your specific solution.
wherever you run it, it will create the symlinks to /AppLinks
it will only look for direct subfolders, not subfolders of subfolders, thats what I believe you need..
Say with a directory structure such as:
toplev/
file2.txt
file5.txt
midlev/
test.txt
anotherdirec/
other.dat
myfile.txt
furtherdown/
morefiles.txt
otherdirec/
myfile4.txt
file7.txt
How would you delete all files (not directories and not recursively) from the 'anotherdirec'? In this example it would delete 2 files (other.dat, myfile.txt)
I have tried the below command from within the 'midlev' directory but it gives this error (find: bad option -maxdepth find: [-H | -L] path-list predicate-list):
find anotherdirec/ -type f -maxdepth 1
I'm running SunOS 5.10.
rm anotherdirec/*
should work for you.
Rob's answer (rm anotherdirec/*) will probably work, but it is a bit verbose and generates a bunch of error messages. The problem is that you are using a version of find that does not support the -maxdepth option. If you want to avoid the error messages that 'rm anotherdirec/*' gives, you can just do:
for i in anotherdirec/*; do test -f $i && rm $i; done
Note that neither of these solutions will work if any of the files contain spaces or other special characters. You can put double quotes around $i if that is an issue.
Find is sensitive to options order. Try this:
find anotherdirec/ -maxdepth 1 -type f -exec rm {} \;
rm toplev/midlev/anotherdirec/* if you want to delete only files.
rm -rf toplev/midlev/anotherdirec/* if you want to delete files and lower directories