Is there anyway to have vim not count special characters as words? - macros

I'm using VIM do alot of work for me using the macros.
There's alot of text in columns and I want the macro to move between columns effortlessly by pressing the w key to "move to the beginning of the next word"
For example:
DataSourceName string ""
DetailFields []string
DynamicControlBorder boolean empty may be void
EscapeProcessing boolean True
FetchDirection long 1000
FetchSize long 12
Filter string ""
GroupBy string ""
HavingClause string ""
However when I do this, VIM only does this for letters; whenever it encounters a "[" or a " it interprets this as another word, messing up the macro because it now appears that there is an additional column.
Is there any setting I can change to make vim ignore the special characters and treat them just like the letters by skipping over them?
[Update]
I found an even better answer to this question over at superuser.com:
https://superuser.com/questions/12679/is-there-anyway-to-have-vim-not-count-special-characters-as-words/12828#12828

You could make the special characters a part of word, see the iskeyword option. In your case you could simply try the following commands:
:set iskeyword+=[
:set iskeyword+=]

The W command (Shift+W) moves to the next word delimited only by spaces, not whatever Vim is configured to consider a "word" (as unshifted w does).

Related

Find and replace all occurrences not in quotes

I'm in the middle of refactoring my Python code to use underscore notation as described in PEP8 and I am using VS Code's find-and-replace tool. The problem is occurrences of words in quotes are also being replaced. How can I replace all occurrences that aren't in quotes?
Example:
fooBar = df["fooBar"]
Desired after find and replace
foo_bar = df["fooBar"]
VS Code's Search functions supports regex, and you can use a negative lookbehind pattern to find "all fooBar strings that are not preceded by a quote": (?<!")fooBar.
(1) enables regex expressions when searching. As you can see, that ignores all the "fooBar" instances. Then you can also turn on (2) so that it enables whole word matching (so that it doesn't match "fooBar123").
As a side note, I hope you have automated tests you can run after doing all these renaming :)
open the find-and-replace vscode tool(ctrl+f and ctrl+h)
select the User Regular Expression(Alt+R)
select the Match Case (Alt+c)
Find = ([a-z]*)(?<!_)([A-Z])(?<!".*)
Replace = $1_\L$2
finaly press Enter
result is :

Multiline regular expression search in Visual Studio Code

Multiline regular expression search doesn't work in VS Code version 1.27.2 .
Theoretically aaa(\n|.)*bbb should find string starting from aaa and ending bbb but it doesn't work.
The solution mentioned here Multi-line regular expressions in Visual Studio Code doesn't work as well.
Multiline search is added in v1.29 released in November 2018. See multi-line search.
VS Code now supports multiline search! Same as in the editor, a regex
search executes in multiline mode only if it contains a \n literal.
The Search view shows a hint next to each multiline match, with the
number of additional match lines.
This feature is possible thanks to the work done in the ripgrep tool
to implement multiline search.
Multiline search is coming to the Find Widget with v1.38. See multiline find "pre-release" notes.
Multi Line search in Find Widget
The Find Widget now supports multiple line text search and replace. By
pressing Ctrl+Enter, you can insert new lines into the input box.
.
Odd that it is Ctrl+Enter in the Find Widget but Shift+Enter in the Search Panel (see Deepu's answer below). Shift+Enter has other functionality when the Find Widget is focused.
yes, you could use regex for mutliple line search in VScode.
To find a multi-line text block starting from aaa and ending with the first bbb (lazy qualifier)
aaa(.|\n)+?bbb
To find a multi-line text block starting from aaa and ending with the last bbb. (greedy qualifier)
aaa(.|\n)+bbb
I have been looking for a quick way to do this, and I have come to the following:
start_text.*?(.|[\n])*?end_text
with start_text and end_text being the bounds of your multiline search.
breaking down the regex ".?(.|[\n])?":
".?" will match any characters from your start text to the end of the line. The "?" is there to ensure that if your end_text is on the same line the . wont just keep going to the end of the line regardless (greedy vs lazy matching)
"(.|[\n])" means either a character\whitespace or a new line
"*?" specifies to match 0 or more of the expression in the parentheses without being greedy.
Examples:
<meta.*?(.|[\n])*?/> will match from the beginning of all meta tags to the end of the respective tags
<script.*?(.|[\n])*?</script> will match from the beginning of all script tags to the respective closing tags
Warning:
Using .*?(.|[\n])*? with improperly or partially filled in start_text or end_text might crash VS Code. I suggest either writing the whole expression out (which doesn't cause a problem) or writing the start and end text before pasting in the regex. In any case, when I tried to delete parts of the starting and ending text VS Code froze and forced me to reload the file. That being said, I honestly could not find something that worked better in VS Code.
Without using regex.
Multi-line search is now possible in vs code version 1.30 and above without using regex.
Type Shift+Enter in the search box to insert a newline, and the search box will grow to show your full multiline query. You can also copy and paste a multiline selection from the editor into the search box.
You can find and replace in multiple lines by using this simple regex : StringStart\r\nStringEnd
For example
public string MethodA(int x)
{
var user;
}
public string MethodB(string y)
{
var user;
}
public string MethodC(int x)
{
var user;
}
public string MethodD(float x)
{
var user;
}
If you want to replace the name of user variable with customer along with method parameter name to user but only for the int ones.
Then the regex to find will be : int x)\r\nEnterBlankSpacesHereToReachTheString{\r\nEnterBlankSpacesHereToReachTheStringvar user
and regex to replace will be : int user)\r\nEnterBlankSpacesHereToReachTheString{\r\nEnterBlankSpacesHereToReachTheStringvar customer
See for reference
I had a similar issue, this works better for me:
aaa[.\n\r\t\S\s]*bbb
This includes carriage return (\r), new line (\n), tab (\t), any whitespece (\s) and any non whitespace (\S). There seems to be some redundancy putting "." and "\S" together, but it doesn't work without both in my case.
No regex way: you can copy multiline text and paste it in "Find in files" form:
result of "Replace all":
(.|\n)+? or [\s\S\r]* or [.\n\r\t\S\s]* may be understandable when viewed in isolation, but in an already complex regex expression, they can add that extra layer of complexity that makes the whole thing unmanageable.
On Windows, for files on the local disk, I find the best solution is to switch to using Notepad++. Not only does it handle multi-line out of the box, it also has a pleasant interface for multi-file search and replace, handles macros gracefully, and is quite light-weight. You can switch back to VScode as soon you have finished your regex changes. Personally, I deleted Notepad++ when I found VScode, but reinstalled it later when I found some of what Notepad++ had to offer was missing in VScode. Both are free to use! I'm sure there's an equivalent on the Mac.
If you are willing to search JavaScript, TypeScript or JSON files I can recommend my VScode extension
It allows for formatting agnostic text search and structural code search
You can find it on codeque.co or at VSCode Marketplace
Your query could look like this
aaa$$mbbb
where $$m means optional multiline set of any characters
Make sure to use text mode for this query
CodeQue can make much more than that!
The reason on this behavior is very simple.
Multiple line search isn't implemented yet.
see: Support multi-line search for Global search

Scratch equals operator problems

I am using scratch.mit.edu version 2.0 on the internet and writing a program to evaluate a postfix expression. As I iterate through the input string such as: "23+" (postfix) letter by letter using the letter..of...block, it works fine.
I then add a letter.. of.. block to identify a spacebar character so the user can insert blanks in the expression eg "2 3 +"
However, there seems no way to recognize a blank character. I tried
1) Lookahead = ""
2) Lookahead =' '
3) Lookahead =''
None of which pick up that a space has been encountered.
Here is the project: https://scratch.mit.edu/projects/77653712/
In Scratch, the box is the string literal - no quotes, unless you're looking for literal quotes. Just put a space in the box.
Just set it to check <(Lookahead) = [ ]>: (brackets are the symbol for the box)
(That black line is me pressing ctrl+a to highlight and show that it exists.)
OK, I have found the solution. There is no character to represent a blank. You simply press space bar once!
You can see the letter nextChar of blanks is an empty space but, you must add space using the spacebar for it to work!!

Notepad++ newline in regex

Suppose you have this file:
x
a
b
c
x
x
a
b
c
x
x
and you want to find the sequence abc (and select the whole 3 lines) with Notepad++ . How to express the newline in regex, please?
Notepad++ can do that comfortably, you don't even need regexes
In the find dialogue box look in the bottom left and switch your search mode to Extended which allows \n etc.
As odds on you're working on a file in windows format you'll be looking for \r\n (carriage return, newline)
a\r\nb\r\nc
Will find the pattern over three lines
Update 18th June 2012
With the new Notepad++ v6, you can indeed search for newlines with regexes. So you can just use
a\r\nb\r\nc
even with regular expressions to accomplish what you want. Note \r\n is Windows encoding of line-breaks. In Unix files, its just \n.
Unfortunately, you can't do that in Notepad++ when using regex search. Notepad++ is based on the Scintilla editor component, which doesn't handle newlines in regex.
You can use extended search for newline searching, but I don't think that will help you search for 3 lines.
More info here.
Update: Robb and StartClass0830 were right about extended search. It does work, but not when using regular expressions search.
^a\x0D\x0Ab\x0D\x0Ac
This will work \x0D is newline and \x0A is carriage return. Assumption is that each line in your file ends with ascii 10 and 13.
I found a workaround for this.
Simply, in Extended mode replace all \r\n to a string that didn't exist in the rest of the document eg. ,,,newline,,, (watch out for special regexp chars like $, &, and *).
Then switch to Regexp mode, do some replacements (now newline is ,,,newline,,,).
Next, switch to Extended mode again and replace all ,,,newline,,, to \r\n.
For Notepad 6 and beyond, do this as a regular expression:
Select Search Mode > Regular expression (w/o . matches newline)
And in the Find what Textbox : a[\r\n]b[\r\n]+c[\r\n]
or if you are looking at the (Windows or Unix) file to see its line breaks as \r\n or \n then you may find it easier to use Extended Mode:
Select Search Mode > Extended (\n, \r, \t, \0, \x...)
And in the Find what Textbox for Windows: a\r\nb\r\nc\r\n
Or in the Find what Textbox for Unix: a\nb\nc\n
Wasn't clear if the OP intent is to select the trailing line return (after the 'c') as well, as would be necessary to remove the lines.
To not select the trailing line return, as appropriate for replacing with a non-empty string, simply remove the final line return from the matching statement.
Note that if there should be a match on the last line of the string, without a matching trailing line return, the match fails.
a\r\nb\r\nc works for me, but not ^a\x0D\x0Ab\x0D\x0Ac
Hmm, too bad that newline is not working with regular expressions. Now I have to go back to Textpad again. :(
Select Search Mode Which is
Extended (\n, \r, \t, \0, \x...)
\n is new line and such
This is Manuel
Find: "(^a.$)\r\n(b.)\r\n^(c.*)$" - pickup 3 whole lines, only storing data
Replace with: "\1\2\3" - Put down (replay) data
Works fine in Regex with Notepad++ v7.9.5
Place holders: ^ Start and $ End of line can be inside or out of ()store as shown, though clearly not necessary in given example. Note "[^x]" is different - here "^" is "NOT".
Advantage of storing and replay allows much more complicated pattern match without having to type in again what you want to end up with, and even change of replay: "\2\3\1" for "bca"
I have run accross this little issue when the document is windows CR/LF
If you click the box for . to match newlines you need .. to match CR/LF so if you have
<blah><blah>",
"<more><blah>
you need to use ",.." to match some string comma cr/lf another string
In Notepad++ you can also try highlighting the desired part of the text and then pressing CTRL+J.
That would justify the text and thus removing all line endings.

How to search for carriage return in eclipse

If I have the following text in my Eclipse editor:
Text Line 1
Text Line 2
I would like to concatenate the text into:
Text Line 1Text Line 2
My first idea was to search for carriage return character '\n' and replace it with '' to concatenate it.
I tried using the search function of Eclipse, but it does not recognize carriage return character.
Are there any other editor that can do this?
Eclipse does this if you:
turn on regular expression mode in search/replace
enter \R for the newline
Just use Edit -> Find/Replace, switch on the Regular Expressions checkbox, search for \n and replace it by space.
I tried it in Eclipse 3.4 and it worked well.
Short answer:
I decided to use \s++ as separator in multi-line search expressions (with regular expressions enabled) and \Qfoo\E to escape special characters if required.
Long answer:
As soru already answered, for any "Unicode linebreak sequence" a regular expression search with \R can be used.
A pure carriage return is represented by \r. Upper and lower case make a difference. \R represents any unicode linebreak sequence (for example \r\n).
I found this SO question because I wanted to search for a multi-line expression in Eclipse, including line breaks and tabs:
#Override
#Transient
In order to include the white spaces in my regular search expression I used (on Windows platform)
#Override\r\n\t*#Transient
Following expressions also work:
#Override\R\t*#Transient
#Override\s++#Transient
Please note that the second expression also matches #Override #Transient
without a line break, which is fine for me.
Following expressions did not! work for me:
#Override\r\t*#Transient
#Override\n\t*#Transient
Explanation of some regular expressions:
\R represents any unicode linebreak sequence (for example \r\n)
\s represents any white space
\t represents a tab
* matches zero or more occurrences
++ matches one ore more occurrences
\Q and \E escape wrapped content. Use them if your original multi line expression includes special regex characters, for example
\Q/**\E\s++\Q*\E
matches
/**
*
Also see:
Difference between \n and \r?
https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
Most find and replace tasks in editors (at least, TextPad) have the ability to replace via a regex. If you can find this option in eclipse, then just use that.
\r is the correct regular expression for carriage return. But Eclipse standard editor does not find it.
So use external editor, for example notepad++