I am trying to compare an encode_base64('test') to the string variable containing the base64 string of 'test'. The problem is it never validates!
use MIMI::Base64 qw(encode_base64);
if (encode_base64("test") eq "dGVzdA==")
{
print "true";
}
Am I forgetting anything?
Here's a link to a Perlmonks page which says "Beware of the newline at the end of the encode_base64() encoded strings".
So the simple 'eq' may fail.
To suppress the newline, say encode_base64("test", "") instead.
When you do a string comparison and it fails unexpectedly, print the strings to see what is actually in them. I put brackets around the value to see any extra whitespace:
use MIME::Base64;
$b64 = encode_base64("test");
print "b64 is [$b64]\n";
if ($b64 eq "dGVzdA==") {
print "true";
}
This is a basic debugging technique using the best debugger ever invented. Get used to using it a lot. :)
Also, sometimes you need to read the documentation for things a couple time to catch the important parts. In this case, MIME::Base64 tells you that encode_base64 takes two arguments. The second argument is the line ending and defaults to a newline. If you don't want a newline on the end of the string you need to give it another line ending, such as the empty string:
encode_base64("test", "")
Here's an interesting tip: use Perl's wonderful and well-loved testing modules for debugging. Not only will that give you a head start on testing, but sometimes they'll make your debugging output a lot faster. For example:
#!/usr/bin/perl
use strict;
use warnings;
use Test::More 0.88;
BEGIN { use_ok 'MIME::Base64' => qw(encode_base64) }
is( encode_base64("test", "dGVzdA==", q{"test" encodes okay} );
done_testing;
Run that script, with perl or with prove, and it won't just tell you that it didn't match, it will say:
# Failed test '"test" encodes okay'
# at testbase64.pl line 6.
# got: 'gGVzdA==
# '
# expected: 'dGVzdA=='
and sharp-eyed readers will notice that the difference between the two is indeed the newline. :)
Related
The environment I am working is on PCRE which supports Perl syntax.
I want to build a regular expression which supports all the charecters and special charecters.
I have tried
(.*)
But it does not work.
For example. I am trying to redirect
From
https://oldaddress.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8
To
https://newsite.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8
The old site oldaddress.com successfully redirects to newsite.com but the URI part select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8 does not remain in it.
I have used regEx =~ (^.*) to handle the URI part but the regex does not support all the special characters.
I would like to implement this regEx in Perl.
Your problem is almost certainly not with your regex. The query parameters don't change, so they shouldn't be included in the regex at all as this Perl code will demonstrate:
#!/usr/bin/perl
use strict;
use warnings;
use 5.010;
my $url = 'https://oldaddress.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8';
my $new_url = 'https://newsite.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8';
$url =~ s/oldaddress/newsite/;
if ($url eq $new_url) {
say "Looks like that worked";
} else {
say "Looks like you've got a problem";
}
I'm only changing the domain, so that's all I need to refer to in the regex.
If your query string isn't surviving the transformation, then that problem is down to some other problem in the technology that you are using. Without knowing more about what you're doing, we really can't be any more help.
Update: From Sawyer's comment
but how to handle special charecters ?, % using Regex using Perl
You don't seem to be reading what people are telling you.
Your regex doesn't need to handle ?, % or other special characters. Your regex only needs to deal with the bits of your string that are changing - that's the domain names and they don't include these characters.
% has no special meaning in Perl regular expressions.
? has a special meaning, you avoid that by escaping it with a backslash (so use \?).
A dot (.) in a Perl regular expression matches any character except a newline. It matches ? and % without any problems at all.
Your problem is not with your regex; it is somewhere else in your system. But because you are being so mysterious about what you're doing and how you're doing it, we really can't be any more help.
Update2: Here's another version of my program which demonstrates (.*) matching ? and %. But I can't emphasise enough that you don't need to do this.
#!/usr/bin/perl
use strict;
use warnings;
use 5.010;
my $url = 'https://oldaddress.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8';
my $new_url = 'https://newsite.com/select.do?cyuf=err%3Errt.com%3fsfds%4A222-3424234&p=66&j=8';
$url =~ s/(.*)oldaddress(.)/${1}newsite${2}/;
if ($url eq $new_url) {
say "Looks like that worked";
} else {
say "Looks like you've got a problem";
}
Is there a way in Perl to preserve and print all backslashes in a string variable?
For example:
$str = 'a\\b';
The output is
a\b
but I need
a\\b
The problem is can't process the string in any way to escape the backslashes because
I have to read complex regular expressions from a database and don't know in which combination and number they appear and have to print them exactly as they are on a web page.
I tried with template toolkit and html and html_entity filters. The only way it works so far is to use a single quoted here document:
print <<'XYZ';
a\\b
XYZ
But then I can't interpolate variables which makes this solution useless.
I tried to write a string to a web page, into file and on the shell, but no luck, always one backslash disappears. Maybe I am totally on the wrong track, but what is the correct way to print complex regular expressions including backslashes in all combinations and numbers without any changes?
In other words:
I have a database containing hundreds of regular expressions as string data. I want to read them with perl and print them on a web page exatly as they are in the database.
There are all the time changes to these regular expressions by many administrators so I don't know in advance how and what to escape.
A typical example would look like this:
'C:\\test\\file \S+'
but it could change the next day to
'\S+ C:\\test\\file'
Maybe a correct conclusion would be to escape every backslash exactly one time no matter in which combination and in which number it appears? This would mean it works to double them up. Then the problem isn't as big as I feared. I tested it on the bash and it works with two and even three backslashes in a row (4 backslaches print 2 ones and 6 backslashes print 3 ones).
The backslash only has significance to Perl when it occurs in Perl source code, e.g.: your assignment of a literal string to a variable:
my $str = 'a\\b';
However, if you read data from a file (or a database or socket etc) any backslashes in the data you read will be preserved without you needing to take any special steps.
my $str = 'a\\b';
print $str;
This prints a\\b.
Use
my $str = 'a\\\\b';
instead
It's a PITA, but you will just have to double up the backslashes, e.g.
a\\\\b
Otherwise, you could store the backslash in another variable, and interpolate that.
The minimum to get two slashes is (unfortunately) three slashes:
use 5.016;
my $a = 'a\\\b';
say $a;
The problem I tried to solve does not exist. I confused initializing a string directly in the code with using the html forms. Using a string inside the code preserving all backslashes is only possible either with a here document or by reading a textfile containing the string. But if I just use the html form on a web page to insert a string and use escapeHTML() from the CGI module it takes care of all and you can insert the most wired combinations of special characters. They all get displayed and preserved exactly as inserted. So I should have started directly with html and database operations instead of trying to examine things first
by using strings directly in the code. Anyway, thanks for your help.
You can use the following regular expression to form your string correctly:
my $str = 'a\\b';
$str =~ s/\\/\\\\/g;
print "$str\n";
This prints a\\b.
EDIT:
You can use non-interpolating here-document instead:
my $str = <<'EOF';
a\\b
EOF
print "$str\n";
This still prints a\\b.
Grant's answer provided the hint I needed. Some of the other answers did not match Perl's operation on my system so ...
#!/usr/bin/perl
use warnings;
use strict;
my $var = 'content';
print "\'\"\N{U+0050}\\\\\\$var\n";
print <<END;
\'\"\N{U+0050}\\\\\\$var\n
END
print '\'\"\N{U+0050}\\\\\\$var\n'.$/;
my $str = '\'\"\N{U+0050}\\\\\\$var\n';
print $str.$/;
print #ARGV;
print $/;
Called from bash ... using the bash means of escaping in quotes which changes \' to '\''.
jamie#debian:~$ ./ft.pl '\'\''\"\N{U+0050}\\\\\\$var\n'
'"P\\\content
'"P\\\content
'\"\N{U+0050}\\\$var\n
'\"\N{U+0050}\\\$var\n
\'\"\N{U+0050}\\\\\\$var\n
The final line, with six backslashes in the middle, was what I had expected. Reality differed.
So:
"in here \" is interpolated
in HEREDOC \ is interpolated
'in single quotes only \' is interpolated and only for \ and ' (are there more?)
my $str = 'same limited \ interpolation';
perl.pl 'escape using bash rules' with #ARGV is not interpolated
How do I get rid of use of an uninitialized value within an if construct using a Perl regex?
When using the code below, I get use of uninitialized value messages.
if($arrayOld[$i] =~ /-(.*)/ || $arrayOld[$i] =~ /\#(.*)/)
When using the code below, I get no output.
if(defined($arrayOld[$i]) =~ /-(.*)/ || defined($arrayOld[$i]) =~ /\#(.*)/)
What is the proper way to check if a variable has a value given the code above?
Try:
if($arrayOld[$i] && $arrayOld[$i] =~ /-|\#(.*)/)
This first checks $arrayOld[$i] for a value before running a regx against it.
(Have also combined the || into the regex.)
From the error message in your comment, you're accessing an element of #arrayOld that isn't defined. Without seeing the rest of the code, this could indicate a bug in your program, or it could just be expected behavior.
If you understand why $arrayOld[$i] is undef, and you want to allow that without getting a warning, there's a couple of things you can do. Perl 5.10.0 introduced the defined-or operator //, which you can use to substitute the empty string for undef:
use 5.010;
...
if(($arrayOld[$i] // '') =~ /-(.*)/ || ($arrayOld[$i] // '') =~ /\#(.*)/)
Or, you can just turn off the warning:
if (do { no warnings 'uninitalized';
$arrayOld[$i] =~ /-(.*)/ || $arrayOld[$i] =~ /\#(.*)/ })
Here, I'm using do to limit the time the warning is disabled. However, turning off the warning also suppresses the warning you'd get if $i were undef. Using // allows you to specify exactly what is allowed to be undef, and exactly what value should be used instead of undef.
Note: defined($arrayOld[$i]) =~ /-(.*)/ is running a pattern match on the result of the defined function, which is just going to be a true/false value; not the string you want to test.
To answer your question narrowly, you can prevent undefined-value warnings in that line of code with
if (defined $i && defined $arrayOld[$i]
&& ($arrayOld[$i] =~ /-(.*)/ || $arrayOld[$i] =~ /\#(.*)/))
{
...;
}
That is, evaluating either $i or the expression $arrayOld[$i] may result in an undefined value. Note the additional layer of parentheses that are necessary as written above because of the difference in precedence between && and ||, with the former binding more tightly. For the particular patterns in your question, you could sidestep this precedence issue by combining your patterns into one regex, but this can be tricky to do in the general case.
I recommend against using the unpleasing code above. Read on to see an elegant solution to your problem that has Perl do the work for you and is much easier to read.
Looking back
From the slightly broader context of your earlier question, $i is a loop variable and by construction will certainly be defined, so testing $i is overkill. Your code blindly pulls elements from #arrayOld, and Perl happily obliges. In cases where nothing is there, you get the undefined value.
This sort of one-by-one peeking and poking is common in C programs, but in Perl, it is almost always a red flag that you could express your algorithm more elegantly. Consider the complete, working example below.
Working demonstration
#! /usr/bin/env perl
use strict;
use warnings;
use 5.10.0; # given/when
*FILEREAD = *DATA; # for demo only
my #interesting_line = (qr/-(.*)/, qr/\#(.*)/);
$/ = ""; # paragraph mode
while(<FILEREAD>) {
chomp;
my #arrayOld = split /\n/;
my #arrayNewLines;
for (1 .. #arrayOld) {
given (shift #arrayOld) {
push #arrayNewLines, $_ when #interesting_line;
push #arrayOld, $_;
}
}
print "\#arrayOld:\n", map("$_\n", #arrayOld), "\n",
"\#arrayNewLines:\n", map("$_\n", #arrayNewLines);
}
__DATA__
#SCSI_test # put this line into #arrayNewLines
kdkdkdkdkdkdkdkd
dkdkdkdkdkdkdkdkd
- ccccccccccccccc # put this line into #arrayNewLines
Front matter
The line
use 5.10.0;
enables Perl’s given/when switch statement, and this makes for a nice way to decide which array gets a given line of input.
As the comment indicates
*FILEREAD = *DATA; # for demo only
is for the purpose of this Stack Overflow demonstration. In your real code, you have open FILEREAD, .... Placing the input from your question into Perl’s DATA filehandle allows presenting code and input in one self-contained unit, and then we alias FILEREAD to DATA so the rest of the code will drop into yours with no fuss.
The main event
The core of the processing is
for (1 .. #arrayOld) {
given (shift #arrayOld) {
push #arrayNewLines, $_ when #interesting_line;
push #arrayOld, $_;
}
}
Notice that there are no defined checks or even explicit regex matches! There’s no $i or $arrayOld[$i]! What’s going on?
You start with #arrayOld containing all the lines from the current paragraph and want to end with the interesting lines in #arrayNewLines and everything else staying in #arrayOld. The code above takes the next line out of #arrayOld with shift. If the line is interesting, we push it onto the end of #arrayNewLines. Otherwise, we put it back on the end of #arrayOld.
The statement modifier when #interesting_line performs an implicit smart-match with the topic from given. As explained in “Smart matching in detail,” when smart matching against an array, Perl implicitly loops over it and stops on the first match. In this case, the array #interesting_line contains compiled regexes that match lines you want to move to #arrayNewLines. If the current line (in $_ thanks to given) does not match any of those patterns, it goes back in #arrayOld.
We do the preceding process exactly scalar #arrayOld times, that is, once for each line in the current paragraph. This way, we process everything exactly once and do not have to worry about fussy bookkeeping over where the current array index is. Whatever is left in #arrayOld after that many shifts must be the lines we pushed back onto it, which are the uninteresting lines in the order that the occurred in the input.
Sample output
For the input in your question, the output is
#arrayOld:
kdkdkdkdkdkdkdkd
dkdkdkdkdkdkdkdkd
#arrayNewLines:
#SCSI_test # put this line into #arrayNewLines
- ccccccccccccccc # put this line into #arrayNewLines
In Perl, is there any reason to encapsulate a single variable in double quotes (no concatenation) ?
I often find this in the source of the program I am working on (writen 10 years ago by people that don't work here anymore):
my $sql_host = "something";
my $sql_user = "somethingelse";
# a few lines down
my $db = sub_for_sql_conection("$sql_host", "$sql_user", "$sql_pass", "$sql_db");
As far as I know there is no reason to do this. When I work in an old script I usualy remove the quotes so my editor colors them as variables not as strings.
I think they saw this somewhere and copied the style without understanding why it is so. Am I missing something ?
Thank you.
All this does is explicitly stringify the variables. In 99.9% of cases, it is a newbie error of some sort.
There are things that may happen as a side effect of this calling style:
my $foo = "1234";
sub bar { $_[0] =~ s/2/two/ }
print "Foo is $foo\n";
bar( "$foo" );
print "Foo is $foo\n";
bar( $foo );
print "Foo is $foo\n";
Here, stringification created a copy and passed that to the subroutine, circumventing Perl's pass by reference semantics. It's generally considered to be bad manners to munge calling variables, so you are probably okay.
You can also stringify an object or other value here. For example, undef stringifies to the empty string. Objects may specify arbitrary code to run when stringified. It is possible to have dual valued scalars that have distinct numerical and string values. This is a way to specify that you want the string form.
There is also one deep spooky thing that could be going on. If you are working with XS code that looks at the flags that are set on scalar arguments to a function, stringifying the scalar is a straight forward way to say to perl, "Make me a nice clean new string value" with only stringy flags and no numeric flags.
I am sure there are other odd exceptions to the 99.9% rule. These are a few. Before removing the quotes, take a second to check for weird crap like this. If you do happen upon a legit usage, please add a comment that identifies the quotes as a workable kludge, and give their reason for existence.
In this case the double quotes are unnecessary. Moreover, using them is inefficient as this causes the original strings to be copied.
However, sometimes you may want to use this style to "stringify" an object. For example, URI ojects support stringification:
my $uri = URI->new("http://www.perl.com");
my $str = "$uri";
I don't know why, but it's a pattern commonly used by newcomers to Perl. It's usually a waste (as it is in the snippet you posted), but I can think of two uses.
It has the effect of creating a new string with the same value as the original, and that could be useful in very rare circumstances.
In the following example, an explicit copy is done to protect $x from modification by the sub because the sub modifies its argument.
$ perl -E'
sub f { $_[0] =~ tr/a/A/; say $_[0]; }
my $x = "abc";
f($x);
say $x;
'
Abc
Abc
$ perl -E'
sub f { $_[0] =~ tr/a/A/; say $_[0]; }
my $x = "abc";
f("$x");
say $x;
'
Abc
abc
By virtue of creating a copy of the string, it stringifies objects. This could be useful when dealing with code that alters its behaviour based on whether its argument is a reference or not.
In the following example, explicit stringification is done because require handles references in #INC differently than strings.
$ perl -MPath::Class=file -E'
BEGIN { $lib = file($0)->dir; }
use lib $lib;
use DBI;
say "ok";
'
Can't locate object method "INC" via package "Path::Class::Dir" at -e line 4.
BEGIN failed--compilation aborted at -e line 4.
$ perl -MPath::Class=file -E'
BEGIN { $lib = file($0)->dir; }
use lib "$lib";
use DBI;
say "ok";
'
ok
In your case quotes are completely useless. We can even says that it is wrong because this is not idiomatic, as others wrote.
However quoting a variable may sometime be necessary: this explicitely triggers stringification of the value of the variable. Stringification may give a different result for some values if thoses values are dual vars or if they are blessed values with overloaded stringification.
Here is an example with dual vars:
use 5.010;
use strict;
use Scalar::Util 'dualvar';
my $x = dualvar 1, "2";
say 0+$x;
say 0+"$x";
Output:
1
2
My theory has always been that it's people coming over from other languages with bad habits. It's not that they're thinking "I will use double quotes all the time", but that they're just not thinking!
I'll be honest and say that I used to fall into this trap because I came to Perl from Java, so the muscle memory was there, and just kept firing.
PerlCritic finally got me out of the habit!
It definitely makes your code more efficient, but if you're not thinking about whether or not you want your strings interpolated, you are very likely to make silly mistakes, so I'd go further and say that it's dangerous.
A common 'Perlism' is generating a list as something to loop over in this form:
for($str=~/./g) { print "the next character from \"$str\"=$_\n"; }
In this case the global match regex returns a list that is one character in turn from the string $str, and assigns that value to $_
Instead of a regex, split can be used in the same way or 'a'..'z', map, etc.
I am investigating unpack to generate a field by field interpretation of a string. I have always found unpack to be less straightforward to the way my brain works, and I have never really dug that deeply into it.
As a simple case, I want to generate a list that is one character in each element from a string using unpack (yes -- I know I can do it with split(//,$str) and /./g but I really want to see if unpack can be used this way...)
Obviously, I can use a field list for unpack that is unpack("A1" x length($str), $str) but is there some other way that kinda looks like globbing? ie, can I call unpack(some_format,$str) either in list context or in a loop such that unpack will return the next group of character in the format group until $str is exausted?
I have read The Perl 5.12 Pack pod and the Perl 5.12 pack tutorial and the Perkmonks tutorial
Here is the sample code:
#!/usr/bin/perl
use warnings;
use strict;
my $str=join('',('a'..'z', 'A'..'Z')); #the alphabet...
$str=~s/(.{1,3})/$1 /g; #...in groups of three
print "str=$str\n\n";
for ($str=~/./g) {
print "regex: = $_\n";
}
for(split(//,$str)) {
print "split: \$_=$_\n";
}
for(unpack("A1" x length($str), $str)) {
print "unpack: \$_=$_\n";
}
pack and unpack templates can use parentheses to group things much like regexps can. The group can be followed by a repeat count. * as a repeat count means "repeat until you run out of things to pack/unpack".
for(unpack("(A1)*", $str)) {
print "unpack: \$_=$_\n";
}
You'd have to run a benchmark to find out which of these is the fastest.