Automatically get loop index in foreach loop in Perl - perl

Question

If I have the following array in Perl:
#x = qw(a b c);
and I iterate over it with foreach, then $_ will refer to the current element in the array:
foreach (#x) {
print;
}
will print:
abc
Is there a similar way to get the index of the current element, without manually updating a counter? Something such as:
foreach (#x) {
print $index;
}
where $index is updated like $_ to yield the output:
012

Answer 1

Like codehead said, you'd have to iterate over the array indices instead of its elements. I prefer this variant over the C-style for loop:
for my $i (0 .. $#x) {
print "$i: $x[$i]\n";
}

Answer 2

In Perl prior to 5.10, you can say
#!/usr/bin/perl
use strict;
use warnings;
my #a = qw/a b c d e/;
my $index;
for my $elem (#a) {
print "At index ", $index++, ", I saw $elem\n";
}
#or
for my $index (0 .. $#a) {
print "At index $index I saw $a[$index]\n";
}
In Perl 5.10, you use state to declare a variable that never gets reinitialized (unlike ones created with my). This lets you keep the $index variable in a smaller scope, but it can lead to bugs (if you enter the loop a second time it will still have the last value):
#!/usr/bin/perl
use 5.010;
use strict;
use warnings;
my #a = qw/a b c d e/;
for my $elem (#a) {
state $index;
say "At index ", $index++, ", I saw $elem";
}
In Perl 5.12 you can say
#!/usr/bin/perl
use 5.012; # This enables strict
use warnings;
my #a = qw/a b c d e/;
while (my ($index, $elem) = each #a) {
say "At index $index I saw $elem";
}
But be warned: you there are restrictions to what you are allowed to do with #a while iterating over it with each.
It won't help you now, but in Perl 6 you will be able to say
#!/usr/bin/perl6
my #a = <a b c d e>;
for #a Z 0 .. Inf -> $elem, $index {
say "at index $index, I saw $elem"
}
The Z operator zips the two lists together (i.e. it takes one element from the first list, then one element from the second, then one element from the first, and so on). The second list is a lazy list that contains every integer from 0 to infinity (at least theoretically). The -> $elem, $index says that we are taking two values at a time from the result of the zip. The rest should look normal to you (unless you are not familiar with the say function from 5.10 yet).

Answer 3

perldoc perlvar does not seem to suggest any such variable.

Answer 4

It can be done with a while loop (foreach doesn't support this):
my #arr = (1111, 2222, 3333);
while (my ($index, $element) = each(#arr))
{
# You may need to "use feature 'say';"
say "Index: $index, Element: $element";
}
Output:
Index: 0, Element: 1111
Index: 1, Element: 2222
Index: 2, Element: 3333
Perl version: 5.14.4

Answer 5

Not with foreach.
If you definitely need the element cardinality in the array, use a 'for' iterator:
for ($i=0; $i<#x; ++$i) {
print "Element at index $i is " , $x[$i] , "\n";
}

Answer 6

No, you must make your own counter. Yet another example:
my $index;
foreach (#x) {
print $index++;
}
when used for indexing
my $index;
foreach (#x) {
print $x[$index]+$y[$index];
$index++;
}
And of course you can use local $index; instead my $index; and so and so.

Answer 7

autobox::Core provides, among many more things, a handy for method:
use autobox::Core;
['a'..'z']->for( sub{
my ($index, $value) = #_;
say "$index => $value";
});
Alternatively, have a look at an iterator module, for example: Array::Iterator
use Array::Iterator;
my $iter = Array::Iterator->new( ['a'..'z'] );
while ($iter->hasNext) {
$iter->getNext;
say $iter->currentIndex . ' => ' . $iter->current;
}
Also see:
each to their own (autobox)
perl5i

Answer 8

Yes. I have checked so many books and other blogs... The conclusion is, there isn't any system variable for the loop counter. We have to make our own counter. Correct me if I'm wrong.

Answer 9

Oh yes, you can! (sort of, but you shouldn't). each(#array) in a scalar context gives you the current index of the array.
#a = (a..z);
for (#a) {
print each(#a) . "\t" . $_ . "\n";
}
Here each(#a) is in a scalar context and returns only the index, not the value at that index. Since we're in a for loop, we have the value in $_ already. The same mechanism is often used in a while-each loop. Same problem.
The problem comes if you do for(#a) again. The index isn't back to 0 like you'd expect; it's undef followed by 0,1,2... one count off. The perldoc of each() says to avoid this issue. Use a for loop to track the index.
each
Basically:
for(my $i=0; $i<=$#a; $i++) {
print "The Element at $i is $a[$i]\n";
}
I'm a fan of the alternate method:
my $index=0;
for (#a) {
print "The Element at $index is $a[$index]\n";
$index++;
}

Answer 10

Please consider:
print "Element at index $_ is $x[$_]\n" for keys #x;

Answer 11

Well, there is this way:
use List::Rubyish;
$list = List::Rubyish->new( [ qw<a b c> ] );
$list->each_index( sub { say "\$_=$_" } );
See List::Rubyish.

Answer 12

You shouldn't need to know the index in most circumstances. You can do this:
my #arr = (1, 2, 3);
foreach (#arr) {
$_++;
}
print join(", ", #arr);
In this case, the output would be 2, 3, 4 as foreach sets an alias to the actual element, not just a copy.

Answer 13

I have tried like....
#array = qw /tomato banana papaya potato/; # Example array
my $count; # Local variable initial value will be 0.
print "\nBefore For loop value of counter is $count"; # Just printing value before entering the loop.
for (#array) { print "\n",$count++," $_" ; } # String and variable seperated by comma to
# execute the value and print.
undef $count; # Undefining so that later parts again it will
# be reset to 0.
print "\nAfter for loop value of counter is $count"; # Checking the counter value after for loop.
In short...
#array = qw /a b c d/;
my $count;
for (#array) { print "\n",$count++," $_"; }
undef $count;