Capturing Non-Zero Elements, Counts and Indexes of Sparse Matrix - perl

Question

I have the following sparse matrix A.
2 3 0 0 0
3 0 4 0 6
0 -1 -3 2 0
0 0 1 0 0
0 4 2 0 1
Then I would like to capture the following information from there:
cumulative count of entries, as matrix is scanned columnwise.
Yielding:
Ap = [ 0, 2, 5, 9, 10, 12 ];
row indices of entries, as matrix is scanned columnwise.
Yielding:
Ai = [0, 1, 0, 2, 4, 1, 2, 3, 4, 2, 1, 4 ];
Non-zero matrix entries, as matrix is scanned columnwise.
Yielding:
Ax = [2, 3, 3, -1, 4, 4, -3, 1, 2, 2, 6, 1];
Since the actual matrix A is potentially very2 large, is there any efficient way
in Perl that can capture those elements? Especially without slurping all matrix A
into RAM.
I am stuck with the following code. Which doesn't give what I want.
use strict;
use warnings;
my (#Ax, #Ai, #Ap) = ();
while (<>) {
chomp;
my #elements = split /\s+/;
my $i = 0;
my $new_line = 1;
while (defined(my $element = shift #elements)) {
$i++;
if ($element) {
push #Ax, 0 + $element;
if ($new_line) {
push #Ai, scalar #Ax;
$new_line = 0;
}
push #Ap, $i;
}
}
}
push #Ai, 1 + #Ax;
print('#Ax = [', join(" ", #Ax), "]\n");
print('#Ai = [', join(" ", #Ai), "]\n");
print('#Ap = [', join(" ", #Ap), "]\n");

Answer 1

A common strategy for storing sparse data is to drop the values you don't care about (the zeroes) and to store the row and column indexes with each value that you do care about, thus preserving their positional information:
[VALUE, ROW, COLUMN]
In your case, you can economize further since all of your needs can be met by processing the data column-by-column, which means we don't have to repeat COLUMN for every value.
use strict;
use warnings;
use Data::Dumper;
my ($r, $c, #dataC, #Ap, #Ai, #Ax, $cumul);
# Read data row by row, storing non-zero values by column.
# $dataC[COLUMN] = [
# [VALUE, ROW],
# [VALUE, ROW],
# etc.
# ]
$r = -1;
while (<DATA>) {
chomp;
$r ++;
$c = -1;
for my $v ( split '\s+', $_ ){
$c ++;
push #{$dataC[$c]}, [$v, $r] if $v;
}
}
# Iterate through the data column by column
# to compute the three result arrays.
$cumul = 0;
#Ap = ($cumul);
$c = -1;
for my $column (#dataC){
$c ++;
$cumul += #$column;
push #Ap, $cumul;
for my $value (#$column){
push #Ax, $value->[0];
push #Ai, $value->[1];
}
}
__DATA__
2 3 0 0 0
3 0 4 0 6
0 -1 -3 2 0
0 0 1 0 0
0 4 2 0 1

Answer 2

This is what you are looking for, I guess:
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper::Simple;
my #matrix;
# Populate #matrix
while (<>) {
push #matrix, [ split /\s+/ ];
}
my $columns = #{ $matrix[0] };
my $rows = #matrix;
my ( #Ap, #Ai, #Ax );
my $ap = 0;
for ( my $j = 0 ; $j <= $rows ; $j++ ) {
for ( my $i = 0 ; $i <= $columns ; $i++ ) {
if ( $matrix[$i]->[$j] ) {
$ap++;
push #Ai, $i;
push #Ax, $matrix[$i]->[$j];
}
}
push #Ap, $ap;
}
print Dumper #Ap;
print Dumper #Ai;
print Dumper #Ax;

Answer 3

Updated based on FM's comment. If you do not want to store any of the original data:
#!/usr/bin/perl
use strict;
use warnings;
my %matrix_info;
while ( <DATA> ) {
chomp;
last unless /[0-9]/;
my #v = map {0 + $_ } split;
for (my $i = 0; $i < #v; ++$i) {
if ( $v[$i] ) {
push #{ $matrix_info{$i}->{indices} }, $. - 1;
push #{ $matrix_info{$i}->{nonzero} }, $v[$i];
}
}
}
my #cum_count = (0);
my #row_indices;
my #nonzero;
for my $i ( sort {$a <=> $b } keys %matrix_info ) {
my $mi = $matrix_info{$i};
push #nonzero, #{ $mi->{nonzero} };
my #i = #{ $mi->{indices} };
push #cum_count, $cum_count[-1] + #i;
push #row_indices, #i;
}
print(
"\#Ap = [#cum_count]\n",
"\#Ai = [#row_indices]\n",
"\#Ax = [#nonzero]\n",
);
__DATA__
2 3 0 0 0
3 0 4 0 6
0 -1 -3 2 0
0 0 1 0 0
0 4 2 0 1
Output:
C:\Temp> m
#Ap = [0 2 5 9 10 12]
#Ai = [0 1 0 2 4 1 2 3 4 2 1 4]
#Ax = [2 3 3 -1 4 4 -3 1 2 2 6 1]

Answer 4

Ap is easy: simply start with zeroes and increment each time you meet a nonzero number. I don't see you trying to write anything into #Ap, so it's no surprise it doesn't end up as you wish.
Ai and Ax are trickier: you want a columnwise ordering while you're scanning rowwise. You won't be able to do anything in-place since you don't know yet how many elements the columns will yield, so you can't know in advance the elements' position.
Obviously, it would be a hell lot easier if you could just alter the requirement to have a rowwise ordering instead. Failing that, you could get complex and collect (i, j, x) triplets. While collecting, they'd naturally be ordered by (i, j). Post-collection, you'd just want to sort them by (j, i).

Answer 5

The code you provided works on a row-by-row basis. To get results sequential by columns you have to accumulate your values into separate arrays, one for each column:
# will look like ([], [], [] ...), one [] for each column.
my #columns;
while (<MATRIX>) {
my #row = split qr'\s+';
for (my $col = 0; $col < #row; $col++) {
# push each non-zero value into its column
push #{$columns[$col]}, $row[$col] if $row[$col] > 0;
}
}
# now you only need to flatten it to get the desired kind of output:
use List::Flatten;
#non_zero = flat #columns;
See also List::Flatten.