Reading/Capturing DOS input for use in MsBuild - command-line

How do I capture/read DOS input for use in MsBuild?
EDITED for clarification
Currently I have 2 files. One batch file, the other is the core.msbuild file which contains the msbuild stuff. I want to be able to capture an extra user input e.g. an output directory, from the windows command prompt (when the build file is executed) and send it to the msbuild file (and set it to a PropertyGroup). %1 is already taken so I'm thinking to use %2.
Like the following:
build.bat param1 param2
param2 is the one im trying to capture and do the above.
Thanks.

Got it...
In the build.bat file, append this to a build string:
... /p:customOutputDir="%1"
In MsBuild file:
<PropertyGroup>
<OutputDir>$(customOutputDir)</OutputDir>
</PropertyGroup>
Then OutputDir can be used in Targets.
Thanks.

Isn't the idea of an automated build that the build is repeateable and without user input?
But, i would guess that powershell has some better options for getting input from a user for this than standard dos.

Would it also be possible to query the user input before executing the build file and pass it as a param?

Related

Powershell call a script from another scipt as if in a different folder

I use the video transcoding tools made by Don Melton over on GitHub to compress self filmed videos. Now I would like to automate this task by using a PowerShell script to loop over the contents of a folder as input arguments for the tool and have the output put into a seperate folder. My problem is that the tool is written in a way that it has no option to provide an output location, instead it always places the output files in the directory where it is called in. So when I cd into an "output" directory "next to" the one where my input files are, I then can call
other-transcode ../input/file.mp4
and the output file of the same name as the input file will be placed in the output directory.
Now when I want to use the command in a script, how do I tell PowerShell to run the command as if it was typed manually into a shell that was in the output directory at the moment?
For context, this is my end goal, but I think it is easier to split the complicated question into multiple ones.

Display a nicely formatted path in PowerShell have code how to format for profile

I found a snippet of code that if I paste in PowerShell It displays all of my windows path variables on one line. What would the syntax be for adding this code to my profile?
Push-Location env:
(ls path).value.split(";")
Pop-Location
Put this function in your PowerShell profile:
function Get-Path {
$env:Path.Split(";")
}
After this function is defined, you can type Get-Path to see the list of directories in your Path.
If you don't already have a profile script, run the command help about_Profiles for more information.
Not sure why you'd prefer to see PATH variable on one line, but here's the code to do it.
C:>(ls Env:\Path).value
I prefer separate lines:
C:>(ls Env:\Path).value.split(';')
As far as your PowerShell Profile goes, open PowerShell and run:
C:>$profile
It will tell you the path to your profile (make the file and directory if it doesn't exist).
Then, copy + paste the code above into it.
It will run whenever you open powershell.

Powershell Pre-Build script failing from msbuild

I have a Powershell script that executes as a pre-build call for a Xamarin mobile app. The script changes the package name to match the build type e.g. Debug, Release.
To enable different "flavours" of the app to be created, I have written a batch file to replace the config file of the app with one matching the requested build type.
When I build from within Visual Studio, the powershell script runs as I expect and changes what I expected. However when the batch file runs I get an error message appearing:
Here is the content of the batch file, this was my first attempt at writing a batch file to build a code project:
#ECHO OFF
set buildVer=%1
set path=XamarinTestApp\XamarinTestApp
set msBuildDir=%WINDIR%\Microsoft.NET\Framework\v4.0.30319
echo %buildVer%
IF "%buildVer%"=="Release" (
goto :releaseBuild)
IF "%buildVer%"=="Test" (
goto :testBuild)
IF "%buildVer%"=="Dev" (
goto :devBuild)
:releaseBuild
set buildType=Release
copy /-y %path%\app.Release.config %path%\app.Config
goto :builder
:testBuild
set buildType=Release
copy /-y %path%\app.Test.config %path%\app.Config
goto :builder
:devBuild
set buildType=Debug
copy /-y %path%\app.Debug.config %path%\app.Config
goto :builder
:builder
call %msBuildDir%\msbuild.exe
C:\Projects\%path%\XamarinTestApp.Droid\XamarinTestApp.Droid.csproj /property:Configuration=%buildType% /target:SignAndroidPackage /verbosity:diag
I'm looking for any advice on either the error message I am getting, or some advice on how to get configurable information into my app.
Thanks.
Do not use path as user-variable. It is predefined by the system to locate executables.
Change that name to mypath - almost anything other than path.
from the prompt, use the command
set
to see a partial list of the names of variables that are set by the system

Run script file from other script file in Octave

I have several Octave script files that run tests, named test_1, test_2, etc. I want to have a script file that will run all the tests, without having to switch all the test_n files to function files. I've tried several variations on this:
#!/path/to/octave -q
addpath('/path/to/directory/containing/all/scripts/');
source(test_1.m);
source(test_2.m);
but I always get "error: invalid call to script /path/to/directory/containing/all/scripts/test_1.m".
(I've tried source_file(), run(), and just having the filename alone on the line.)
Is there any way to run script files from a script file in Octave?
Try
source test_1.m
or
source('test_1.m')
instead.
Your syntax implies test_1 is a struct variable and you're trying to access a field called m
Same with the run command (in fact, run simply calls source under the hood).
You can also call the script directly, if it's on the path. You just have to make sure you don't include the .m extension, i.e.
test_1
test_2
Just put the name of the included script, without .m extension on a separate line.
Lets have for example script 1: 'enclosed.m'
and script 2: 'included.m'. Then enclosed.m should look like:
% begin enclosed.m
included; % sources included.m
% end encluded.m

finding a files path in the command line

I am doing a batch scripting assignment where I have to call one script from inside another. I need the script to run the second script no matter where my lecturer saves these scripts. How would I do this. Is there some way to find the path of script inside the script and use that to execute the file. Any help would be great. I think I need to use %'s but i'm not sure.
The name of the script is Hello World.bat.
How would I copy Hello World.bat to the C:\ if I don't know which directory the lecturer has placed it in. what command/s would I use so that the copy would work regardless of the scripts location.
I don't see the "DOS" tag, but I'll assume that it is for now. If you want the entire path, you can get it by doing this:
echo %cd%
If you want just the last folder, this works (inside a .bat file):
for %%* in (.) do #echo %%~n*
Note that from the command line, the above command will work with single %'s:
for %* in (.) do #echo %~n*
If the script you are executing is calling other scripts in the SAME folder location, you can prefix the path statement with "%~dp0" or "%~dps0" but do not put a backslash between that and the name of the script you are calling. In other words, if script1.bat is calling script2.bat in the same folder, the statement in script1.bat would refer to "%~dp0script2.bat"
sorry about batch files, am not familiar, but in nix shell, there is the locate command which can return the path of the file , if you know the filename exactly and the name is unique.
like
name=$(locate filname)