In my Iphone App I have created this query:
"SELECT * FROM visuel where id_visuel = 1"
And so I have this function that works very well:
- (void)getVisuel {
visuelArray = [[NSMutableArray alloc] init];
sqlite3 *database;
if(sqlite3_open([self.databasePath UTF8String], &database) == SQLITE_OK) {
sqlite3_reset(getVisuelStatement);
while(sqlite3_step(getVisuelParcStatement) == SQLITE_ROW) {
NSString *aTitle = [NSString stringWithUTF8String:(char *)sqlite3_column_text(getVisuelStatement , 2)];
NSString *aLpath = [NSString stringWithUTF8String:(char *)sqlite3_column_text(getVisuelStatement , 3)];
Visuel *aVisuel = [[Visuel alloc] initWithName:aTitle lpath:aLpath];
[visuelArray addObject:aVisuel];
}
}
sqlite3_close(database);
}
What I want is to change the query like this: "SELECT * FROM visuel where id_visuel = ?"
I don't want to have a static id, but I don't know how to do that.
Thanks,
Well, first change your query to your parameterized query like you have there. Then, just before you call sqlite3_step bind the right id to the parameter:
sqlite3_reset(getVisuelStatement);
//Add these two lines
int visuelId = 1; //Put whatever id you want in here.
sqlite3_bind_int(getVisuelParcStatement, 1, visuelId);
while(sqlite3_step(getVisuelParcStatement) == SQLITE_ROW) {
Related
I have a simple program that update a record of a table
The table is "person" with two columns "name" and "age";
some records have been inserted, as follows:
name age
tom 20
andy 30
han 25
Now I am writing a program to update a row in the table:
NSString *database=[[NSBundle mainBundle] pathForResource:#"mytable" ofType:#"sqlite"];
sqlite3_open([database UTF8String],&contactDB);
NSString *text=#"andy";
NSString *query=[NSString stringWithFormat:#"UPDATE person SET age=%d WHERE name='%#'",30,text];
sqlite3_stmt *statement;
sqlite3_prepare_v2(contactDB,[query UTF8String],-1,&statement,NULL);
sqlite3_finalize(statement);
sqlite3_close(contactDB);
The program works fine, but the database is not updated (I am using SQLite Manager to browser the database)
When I try reading from database, it works well:
NSString *database=[[NSBundle mainBundle] pathForResource:#"mytable" ofType:#"sqlite"];
sqlite3_open([database UTF8String],&contactDB);
NSString *query1=[NSString stringWithFormat:#"SELECT * FROM person WHERE age=%d;",30];
sqlite3_stmt *statement;
sqlite3_prepare_v2(contactDB,[query1 UTF8String],-1,&statement,NULL);
sqlite3_step(statement);
NSString *result=[[NSString alloc] initWithUTF8String:(const char *)sqlite3_column_text(statement, 0)];
label.text=result;
sqlite3_finalize(statement);
sqlite3_close(contactDB);
-(void)updateSetting:(NSArray *)arr
{
if(sqlite3_open([databasePath UTF8String],&myDatabase)==SQLITE_OK)
{
sqlite3_stmt *compiledStmt;
NSString *sqlStmt=[NSString stringWithFormat:#"UPDATE setting SET flow='%#',formate='%#' WHERE primaryKey=%i;",[arr objectAtIndex:0],[arr objectAtIndex:1],1];
if(sqlite3_prepare_v2(myDatabase, [sqlStmt UTF8String],-1,&compiledStmt, NULL)==SQLITE_OK)
{
NSLog(#"Successful update");
}
sqlite3_step(compiledStmt);
sqlite3_close(myDatabase);
}
}
I already faced this issues. Whats the problem behind this is you passed the query as a string format so you have to use the ; at the end of the query statement.
NSString *query=[NSString stringWithFormat:#"UPDATE questionbank SET age=%d WHERE name='%#';",30,text];
Please make a checking like below before you perform your sqlite3_step method.
const char *sqlQuery = "UPDATE SETTINGS SET someFlag = 0";
sqlite3_stmt *insertStatement = nil;
int success = 0;
if(sqlite3_prepare_v2(sqliteDatabase, sqlQuery, -1, &insertStatement, NULL) == SQLITE_OK)
{
success = sqlite3_step(insertStatement);
if(insertStatement)
{
sqlite3_finalize(insertStatement);
}
if(success == SQLITE_ERROR)
{
return NO;
}
return YES;
}
return NO;
So that you can figure out, where the problem is.
You need to check whether you could access and open the database or not. Simply place your update segment in a if-statement like this: if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK).
Also try to add NSLog(#"%s", sqlite3_errmsg(database)); after your prepare to see if there was any errors.
The answer for this problem is that the database in the main bundle is read-only
I can not insert data into sqlite3 file on XCode
I was able to get a list of title of the books (tableview) and when i select the book i would like to push to the new view of the details of the books. Do i do it in titleView class 'didSelectRow' or in DetailView class 'viewWillAppear' and if so what exactly do I have to put to get the statement, 3 or contentInfo?
Database Class
(NSArray *) itemsByAuthorID:(NSInteger)authorID {
NSMutableArray *retval = [[NSMutableArray alloc] init];
NSString *query;
code....
query = [NSString stringWithFormat:#"select * from books where books.author_id = '%i'", authorID];
}
code...
sqlite3_stmt *statement;
if (sqlite3_prepare_v2(_database, [query UTF8String], -1, &statement, nil) == SQLITE_OK){
while (sqlite3_step(statement) == SQLITE_ROW) {
int itemID = sqlite3_column_int(statement, 0);
int authorID = sqlite3_column_int(statement, 1);
char *nameChars = (char *) sqlite3_column_text(statement, 2);
char *itemContent = (char *) sqlite3_column_text(statement, 3);
NSString *contentTitle = [[NSString alloc] initWithUTF8String:nameChars];
NSString *contentInfo = [[NSString alloc] initWithUTF8String:itemContent];
Item *info = [[Item alloc] initWithItemID:itemID authorID:authorID contentTitle:(NSString *)contentTitle contentInfo:contentInfo];
[retval addObject:info];
}
sqlite3_finalize(statement);
}
return retval;
You can create a private class for Book and retrive data from database for all books in array of Book.
Then after when didSelectRow is called only pass object of Book as parameter and show details in Detail view.
I have a very odd problem. My sqlite use in my project which has been working for a while has now stopped working on Xcode 4 compiled code, but only on devices with iOS3.1.3. It fails to return records, but if I turn off code optimization it works perfectly.
Does anyone know what may be the cause of this or has experienced similar issues.
Thanks
Rael
// get word from database
NSString *query = [[NSString alloc] initWithFormat:#"select kana_word, kanji_word, word_type_name, word_subtype_name, custom_category_name, kana_index, dictionary_id from dictionary join word_type on word_type.word_type_id=dictionary.word_type_id join word_subtype on word_subtype.word_subtype_id=dictionary.word_subtype_id join custom_category on custom_category.custom_category_id=dictionary.custom_category_id where kana_index=%d", inKanaIndex];
sqlite3_stmt *statement;
NSLog(#"%#", query);
const char *cQuery = [query UTF8String];
if (sqlite3_prepare_v2(jmwDb, cQuery, -1, &statement, nil) != SQLITE_OK) {
char *errMessage;
errMessage = (char*)sqlite3_errmsg(jmwDb);
sqlite3_finalize(statement);
[query release];
return nil;
}
// build a word object
int kanji_key;
if (sqlite3_step(statement) == SQLITE_ROW) {
// create new word
self.kana = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 0)];
self.kanji = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 1)];
self.wordType = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 2)];
self.wordSubType = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 3)];
self.customCategory = [NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, 4)];
self.kanaIndex = sqlite3_column_int(statement, 5);
kanji_key = sqlite3_column_int(statement, 6);
self.dictionaryId = kanji_key;
}
else {
sqlite3_finalize(statement);
[query release];
return nil;
}
small clarification is this possible to open two tables from one sqlite db in one iphone class??? but i can't open it please give me the solution i'm a beginner
here i tried coding
- (void)viewDidLoad {
[super viewDidLoad];
list = [[NSMutableArray alloc] init];
if ([material isEqualToString:#"Derlin"]) {
[self sel1];
}
else if([material isEqualToString:#"Helers"]){
[self sel2];
}
}
-(void)sel1 {
[self createEditableCopyOfDatabaseIfNeeded];
NSLog(#"numberOfRowsInSection");
sqlite3_stmt *statement = nil; // create a statement
const char *sql = "Select * from material"; //create a query to display in the tableView
if(sqlite3_open([writableDBPath UTF8String], &database) == SQLITE_OK)
{
NSLog(#"sqlite3_open");
if(sqlite3_prepare_v2(database, sql,-1, &statement, NULL)!=SQLITE_OK)
NSAssert1(0,#"Error Preparing Statement",sqlite3_errcode(database));
else
{
while(sqlite3_step(statement) == SQLITE_ROW) // if the connection exists return the row of the query table
{
achemical = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,0)];
arates = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,1)];
anotes = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,2)];
Chemical * chemic = [[Chemical alloc] initWithName:achemical rates:arates notes:anotes];
[list addObject:chemic];
[chemic release];
}
}
}
sqlite3_finalize(statement);
}
-(void)sel2 {
[self createEditableCopyOfDatabaseIfNeeded];
NSLog(#"numberOfRowsInSection");
sqlite3_stmt *statement = nil; // create a statement
const char *sql = "Select * from material1"; //create a query to display in the tableView
if(sqlite3_open([writableDBPath UTF8String], &database) == SQLITE_OK)
{
NSLog(#"sqlite3_open");
if(sqlite3_prepare_v2(database, sql,-1, &statement, NULL)!=SQLITE_OK)
NSAssert1(0,#"Error Preparing Statement",sqlite3_errcode(database));
else
{
while(sqlite3_step(statement) == SQLITE_ROW) // if the connection exists return the row of the query table
{
achemical = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,0)];
arates = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,1)];
anotes = [NSString stringWithFormat:#"%s",(char *)sqlite3_column_text(statement,2)];
Chemical * chemic = [[Chemical alloc] initWithName:achemical rates:arates notes:anotes];
[list addObject:chemic];
[chemic release];
}
}
}
sqlite3_finalize(statement);
}
thanks in advance
Sure, it's easy. Download FMDB, add it to your project, and add two FMResultSet objects in your class, one for each (query against each) table.
i try to get a connection my server, with the sqlite3_open command!
my question...is it possible to that? i got the following code...
// Get the path to the documents directory and append the databaseName
databaseName = #"AnimalDatabase.sql";
NSString *serverpath = #"http://localhost/app/";
databasePath = [serverpath stringByAppendingPathComponent:databaseName];
and then this here
-(void) readAnimalsFromDatabase {
// Setup the database object
sqlite3 *database;
// Init the animals Array
animals = [[NSMutableArray alloc] init];
// Open the database from the users filessytem
if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {
// Setup the SQL Statement and compile it for faster access
const char *sqlStatement = "select * from animals";
sqlite3_stmt *compiledStatement;
if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
// Loop through the results and add them to the feeds array
while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
// Read the data from the result row
NSString *aName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)];
NSString *aDescription = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)];
NSString *aImageUrl = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 3)];
// Create a new animal object with the data from the database
Animal *animal = [[Animal alloc] initWithName:aName description:aDescription url:aImageUrl];
// Add the animal object to the animals Array
[animals addObject:animal];
[animal release];
}
}
// Release the compiled statement from memory
sqlite3_finalize(compiledStatement);
}
sqlite3_close(database);
}
any suggestion??
Where you get the idea that SQLite can open database from URL??
It can open files only (or, create temporary db in memory).
The answer is just NO, there are lot of mistakes in your code anyway. For example:
databaseName = #"AnimalDatabase.sql";
Where did you get this. iPhone is working with sqlite database, it has nothing in common with sql files:)