NSString *col1 = [aBook.name stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#" \n\t"]];
NSLog(#"column1: %#", col1); //output:- ABC+Company
This is my xml data output.
It comes with '+' mark. How can i decode this?
Could you please help me?
You mean get the parts that are seperated by the '+' sign? You can do that with:
NSArray *stringArray = [col1 componentsSeparatedByString:#"+"];
[stringArray objectAtIndex:0]; //ABC
[stringArray objectAtIndex:1]; //Company
If you want to remove/replace the '+' sign you can do this:
NSString* string = [col1 stringByReplacingOccurrencesOfString:#"+" withString:#""]; //last string can be empty or have a string value
Hope this helped you!
You can also replace the plus signs with spaces, if that’s what you’re after:
NSString *name = [col1 stringByReplacingOccurrencesOfString:#"+" withString:#" "];
Currently I am using stringByReplacingOccuranceOfString... to replace " with \", but is there any smarter way?
Thanks!
You can do like this,
NSString *str = #"hello";
NSString *escape = #"\\\””; // this adds ***//*** & then ***/"***
NSString *newStr = [NSString stringWithFormat:#"%#%#%#", escape, str, escape];
NSLog(#"%#", newStr);
I have a string say "Allentown, pa"
How to remove the white space in between , and pa using objective c?
This will remove all space from myString.
NSString *newString = [myString stringByReplacingOccurrencesOfString:#" " withString:#""];
Here is a proper and documented way of removing white spaces from your string.
whitespaceCharacterSet Apple Documentation for iOS says:
Returns a character set containing only the in-line whitespace characters space (U+0020) and tab (U+0009).
+ (id)whitespaceCharacterSet
Return Value
A character set containing only the in-line whitespace characters space (U+0020) and tab (U+0009).
Discussion
This set doesn’t contain the newline or carriage return characters.
Availability
Available in iOS 2.0 and later.
You can use this documented way:
[yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
Hope this helps you.
If you need any more help then please let me know on this.
Probably the solution in one of the answers in Collapse sequences of white space into a single character and trim string:
NSString *whitespaceString = #" String with whitespaces ";
NSString *trimmedString = [whitespaceString stringByReplacingOccurrencesOfString:#" " withString:#""];
If you want to white-space and new-line character as well then use "whitespaceAndNewlineCharacterSet" instead of "whitespaceCharacterSet"
NSCharacterSet *whitespace = [NSCharacterSet whitespaceCharacterSet];
NSString *trimmedString = [temp.text stringByTrimmingCharactersInSet:whitespace];
NSLog(#"Value of the text field is %#",trimmedString);
myStr = [myStr stringByReplacingOccurrencesOfString:#" " withString:#""];
NSString *sample = #" string with whitespaces";
NSString *escapeWhiteSpaces = [sample stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
- (NSString *)removeWhitespaces {
return [[self componentsSeparatedByCharactersInSet:
[NSCharacterSet whitespaceCharacterSet]]
componentsJoinedByString:#""];
}
In my case NSString was added Zero Width Space(i i used some library). so solution worked for me.
NSMutableString *newString=[[newString stringByReplacingOccurrencesOfString:#"\u200B" withString:#""] mutableCopy];
#"\u200B" is Zero width space character value.
Here is the proper way to remove extra whitespaces from string which is coming in between.
NSString *yourString = #"Allentown, pa";
NSCharacterSet *whitespaces = [NSCharacterSet whitespaceCharacterSet];
NSPredicate *noEmptyStrings = [NSPredicate predicateWithFormat:#"SELF != ''"];
NSArray *parts = [yourString componentsSeparatedByCharactersInSet:whitespaces];
NSArray *filteredArray = [parts filteredArrayUsingPredicate:noEmptyStrings];
yourString = [filteredArray componentsJoinedByString:#" "];
you can use remove function to remove any substring from the string
- (NSString*)remove:(NSString*)textToRemove fromString:(NSString*)input {
return [input stringByReplacingOccurrencesOfString:textToRemove withString:#""];
}
I have tried all the solutions here, none of them could remove the whitespace generated by the Chinese PinYin Input method.
After some debugging, I found this working:
NSString *newString = [myString stringByReplacingOccurrencesOfString:#"\342\200\206" withString:#""];
I have googled what the '\342\200\206' is, but failed.
Whatever, it works for me.
Hi there is the swift version of the solution with extension :
extension String{
func deleteSpaces() -> String{
return self.stringByReplacingOccurrencesOfString(" ", withString: "")
}
}
And Just call
(yourString as! String).deleteSpaces()
Swift 3:
var word: String = "Hello world"
let removeWhiteSpace = word.stringByRemovingWhitespaces
word = "Helloworld"
it's me again. I've asked a question similar to this just awhile ago but this question is a bit more complex. I was planning on using RegexKitLite to do what I needed to do but I believe this can be done with out it. I have a NSString that has some words with spaces/blanks in it and I'm wanting to get the very last space in the string that is to the left of the last word. Example String below:
NSString *string = #"Here is an example string HELLO ";
As you can see in the string above there is a space/blank at the very end of the string. I'm wanting to be able to get the space/blank to the left of HELLO and replace it with my own text/string. I'm working on using the NSString's NSBackwardsSearch but it's not working.
NSString *spaceReplacement = #"text that i want";
NSString *replaced = [snipet [string rangeOfString:substring options:NSBackwardsSearch].location:#" " withString:spaceReplacement];
NSLog(#"%#", replaced);
Any help would help, I'm just tired of trying to fix this thing, it's driving me bonkers. I thought I could do this with RegexKitLite but the learning curve for that is too steep for me considering my timeframe I'm working with. I'm glad Jacob R. referred me to use NSString's methods :-)
This solution assumes you always have a space at the end of your string... it should convert
Here is an example string HELLO
... to:
Here is an example stringtext that i wantHELLO
... since that's what I understood you wanted to do.
Here's the code:
NSString *string = #"Here is an example string HELLO ";
NSRange rangeToSearch = NSMakeRange(0, [string length] - 1); // get a range without the space character
NSRange rangeOfSecondToLastSpace = [string rangeOfString:#" " options:NSBackwardsSearch range:rangeToSearch];
NSString *spaceReplacement = #"text that i want";
NSString *result = [string stringByReplacingCharactersInRange:rangeOfSecondToLastSpace withString:spaceReplacement];
The trick is to use the [NSString rangeOfString:options:range:] method.
Note: If the string doesn't always contain a space at the end, this code will probably fail, and you would need code that is a bit more complicated. If that is the case, let me know and I'll update the answer.
Disclaimer: I haven't tested the code, but it should compile and work just fine.
Something like this should work:
NSString *string = #"Here is an example string HELLO ";
if ([string hasSuffix:#" "]) {
NSString *spaceReplacement = #"text that i want";
NSString *replacedString = [[string substringToIndex:
[string length]] stringByAppendingString:spaceReplacement];
NSLog(#"replacedString == %#", replacedString);
}
To solve #Senseful note
If the string doesn't always contain a space at the end, this code will probably fail, and you would need code that is a bit more complicated. If that is the case, let me know and I'll update the answer.
I had added one line into code that helps in such situations and make code more universal:
// Some income sting
NSString * string = #"Here is an example string HELLO ";
// clear string from whitespace in end on string
[string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSRange rangeToSearch = NSMakeRange(0, [string length]);
NSRange rangeOfSecondToLastSpace = [string rangeOfString:#" "
options:NSBackwardsSearch
range:rangeToSearch];
// Replaed with String
NSString * spaceReplacement = #"text that i want";
NSString * result = [string stringByReplacingCharactersInRange:rangeOfSecondToLastSpace
withString:spaceReplacement];
if i have an NSString eg->
string(102)"?xml etc
How to remove all chars upto and including the double quote. I want to remove the string(102)"
Doing this NSString* newString = [str substringFromIndex:13] works but is not ideal
NSRange range = [str rangeOfString:#"\""];
NSString *newString = [str substringFromIndex:range.location + range.length];
Is one way.