Variable classname in javascript - class

Is there a way to make a variable classname in javascript. In php the next is allowed:
$classname = "klasse";
$class = new $classname();
Tom

Use square bracket notation:
some_object["string_containing_method_name"]();
If you want to play with globals, then just remember they are all properties of the window object.
… but don't play with globals.
Your particular example:
var $classname = "klasse";
var $class = new window[$classname]();
(Obviously, the usual conventions for only using $ in machine generated code should apply too)

Bear in mind that "eval is evil", but if you are aware of this, then:
var classname= "klasse";
eval( "var obj = new " + classname + "();");

If you want to call something like
new acme.tools.Hammer();
Then do
var $toolName = "Hammer";
var myObject = new window['acme']['tools'][$toolName]();

Related

pointer to constructor to a class in perl6

I am trying to write some classes with Perl 6 just for testing out Perl 6 classes and methods.
Here is the code:
class human1 {
method fn1() {
print "#from human1.fn1\n";
}
}
class human2 {
method fn1() {
print "#from human2.fn1\n";
}
}
my $a = human1.new();
my $b = human2.new();
$a.fn1();
$b.fn1();
print "now trying more complex stuff\n";
my $hum1_const = &human1.new;
my $hum2_const = &human2.new;
my $c = $hum2_const();
$c.fn1();
Essentially I want to be able to use either the human1 constructor or human2 constructor to be able to build $c object dynamically. But I'm getting the following error:
Error while compiling /usr/bhaskars/code/perl/./a.pl6
Illegally post-declared types:
human1 used at line 23
human2 used at line 24
How do I create $c using the function pointers to choose which constructor I use?
I think this is a case of an LTA error. What I understand you want to achieve, is a lambda that will create a new human1 or human2 object for you. The way you do that is not correct, and the error it causes is confusing.
my $hum1_const = -> { human1.new };
my $hum2_const = -> { human2.new };
would be a correct way of doing this. Although, I would consider this a bit of an obfuscation. Since human1 and human2 are already constants, you can assign them to a variable, and then just call new on that:
my $the_human = $condition ?? human1 !! human2;
my $c = $the_human.new;
$c.fn1;
Does that make sense?
To get a “reference” to .new you have to use the meta object protocol.
Either .^lookup, or .^find_method.
my $hum1-create = human1.^find_method('new');
That is still not quite what you are looking for, as methods require either a class object or an instance, as their first argument.
my $c = $hum1-create( human1 );
So you would probably want to curry the class as the first argument to the method.
my $hum1-create = human1.^find_method('new').assuming(human1);
my $c = $hum1-create();
Note that .assuming in this case basically does the same thing as
-> |capture { human1.^find_method('new').( human1, |capture ) }
So you could just write:
my $hum1-create = -> |capture { human1.new( |capture ) }
Or if you are never going to give it an argument
my $hum1-create = -> { human1.new }
Also you can store it in a & sigiled variable, so you can use it as if it were a normal subroutine.
my &hum1-create = human1.^find_method('new').assuming(human1);
my $c = hum1-create;

How to make a clone of DateTime object

I have some code as follow:
my $d1 = $start_date;
$c->log->debug(Dumper($start_date));
my #date_range;
while($d1 <= $end_date){
push #date_range, $d1->day();
$d1->add(days => 1);
}
How can I do to prevent $start_date changed?
You can use clone method:
my $date = new DateTime();
my $temp_date = $date->clone();
It will be a copy and not a reference. If instead you do the below:
my $temp_date = $date;
then both will refer to the same object.
In perl, objects are scalar references. When you do "my $d1 = $start_date" you are making $d1 a referemce which refers to the same object as $start_date.
You probably want to modify a copy of $start_date. I don't know what class $start_date is, but see if that class provides a copy constructor for you to use.

What am I doing wrong with this Python class? AttributeError: 'NoneType' object has no attribute 'usernames'

Hey there I am trying to make my first class my code is as follows:
class Twitt:
def __init__(self):
self.usernames = []
self.names = []
self.tweet = []
self.imageurl = []
def twitter_lookup(self, coordinents, radius):
twitter = Twitter(auth=auth)
coordinents = coordinents + "," + radius
print coordinents
query = twitter.search.tweets(q="", geocode='33.520661,-86.80249,50mi', rpp=10)
print query
for result in query["statuses"]:
self.usernames.append(result["user"]["screen_name"])
self.names.append(result['user']["name"])
self.tweet.append(h.unescape(result["text"]))
self.imageurl.append(result['user']["profile_image_url_https"])
What I am trying to be able to do is then use my class like so:
test = Twitt()
hello = test.twitter_lookup("38.5815720,-121.4944000","1m")
print hello.usernames
This does not work and I keep getting: "AttributeError: 'NoneType' object has no attribute 'usernames'"
Maybe I just misunderstood the tutorial or am trying to use this wrong. Any help would be appreciated thanks.
I see the error is test.twitter_lookup("38.5815720,-121.4944000","1m") return nothing. If you want the usernames, you need to do
test = Twitt()
test.twitter_lookup("38.5815720,-121.4944000","1m")
test.usernames
Your function twitter_lookup is modifying the Twitt object in-place. You didn't make it return any kind of value, so when you call hello = test.twitter_lookup(), there's no return value to assign to hello, and it ends up as None. Try test.usernames instead.
Alternatively, have the twitter_lookup function put its results in some new object (perhaps a dictionary?) and return it. This is probably the more sensible solution.
Also, the function accepts a coordinents (it's 'coordinates') argument, but then throws it away and uses a hard-coded value instead.

Dynamically generate new named class from string with coffeescript

I have looked around and have found a number of questions which approach using-a-string-to-define-the-class-name and dynamic-class-generation-in-coffeescript> but neither of them exactly address my problem, so I am wondering whether I making some fundamental mistake in my approach to the problem.
In the loop below I am looping through some data parsed from JSON. For each set of data I want to extend my class Robot with string = new Robot where string is a string.
Currently my code does not produce any errors, and successfully creates new Robots but since their name is a string, trying to access them with robot1.move() or robot2.doSomeOtherClassyThing() does not work and tells me they are undefined.
This seems like it should not require a verbose helper function to make it work. What am I missing here?
createRobots: -> # process robot commands
createXcoord = missionData.xCoord
createYcoord = missionData.yCoord
createOrient = missionData.orientation
createInstru = missionData.robotInstructions
for command in createOrient
robot = 'robot' + (_i + 1)
name = robot
robot = new Robot \ # create named Robot
name
, createXcoord[_i]
, createYcoord[_i]
, createOrient[_i]
, createInstru[_i]
console.log(robot)
I think what is happening is that the variable "robot = 'string' is written over when the robot = new Robot is declared.
The outcome I am hoping for is string1 = new Robot, "string2 = new Robot". Does that make sense? jsfiddle.net/7EN5y/1
You need to add them to a context. If you want them to be global, create a variable like this:
# Either the browser root, or the CommonJS (e.g. Node) module root
root = window or exports
If you want an object that holds robots, add such an object to the root.
root.robots = []
Then when creating robots, add them to such an object.
robot = 'robot' + (_i + 1)
name = robot
robot = new Robot # ...
root[name] = robot # or robots[name] = robot
You may then use code like robot1.move(), or robots.robot1.move() (depending on if you attached them to the root or not).

Call TYPO3 plugin from other plugin's body

I need to call typo3 plugin from other plugin's body and pass its result to template. This is pseudo-code that describes what I want to achieve doing this:
$data['###SOME_VARIABLE###'] = $someOtherPlugin->main();
$this->cObj->substituteMarkerArray($someTemplate, $data);
Is it possible?
Thanks!
It doenst work if you use the whole pi construct, e.g. for links, marker function etc, and the TSFE Data can be corrupted.
Dmitry said:
http://lists.typo3.org/pipermail/typo3-english/2008-August/052259.html
$cObjType = $GLOBALS['TSFE']->tmpl->setup['plugin.']['tx_rgsmoothgallery_pi1'];
$conf = $GLOBALS['TSFE']->tmpl->setup['plugin.']['tx_rgsmoothgallery_pi1.'];
$cObj = t3lib_div::makeInstance('tslib_cObj');
$cObj->start(array(), '_NO_TABLE');
$conf['val'] = 1;
$content = $cObj->cObjGetSingle($cObjType, $conf); //calling the main method
You should use t3lib_div:makeInstance method.
There is a working example from TYPO3's "powermail" extension.
function getGeo() {
// use geo ip if loaded
if (t3lib_extMgm::isLoaded('geoip')) {
require_once( t3lib_extMgm::extPath('geoip').'/pi1/class.tx_geoip_pi1.php');
$this->media = t3lib_div::makeInstance('tx_geoip_pi1');
if ($this->conf['geoip.']['file']) { // only if file for geoip is set
$this->media->init($this->conf['geoip.']['file']); // Initialize the geoip Ext
$this->GEOinfos = $this->media->getGeoIP($this->ipOverride ? $this->ipOverride : t3lib_div::getIndpEnv('REMOTE_ADDR')); // get all the infos of current user ip
}
}
}
The answer of #mitchiru is nice and basically correct.
If you have created your outer extension with Kickstarter and you are using pi_base then there is already an instance of tslib_cObj and the whole construct becomes simpler:
// get type of inner extension, eg. USER or USER_INT
$cObjType = $GLOBALS['TSFE']->tmpl->setup['plugin.']['tx_innerextension_pi1'];
// get configuration array of inner extension
$cObjConf = $GLOBALS['TSFE']->tmpl->setup['plugin.']['tx_innerextension_pi1.'];
// add own parameters to configuration array if needed - otherwise skip this line
$cObjConf['myparam'] = 'myvalue';
// call main method of inner extension, using cObj of outer extension
$content = $this->cObj->cObjGetSingle($cObjType, $cObjConf);
Firstly, you have to include your plugin class, before using, or outside your class:
include_once(t3lib_extMgm::extPath('myext').'pi1/class.tx_myext_pi1.php');
Secondly in your code (in the main as example)
$res = tx_myext_pi1::myMethod();
This will work for sure (I've checked this): http://lists.typo3.org/pipermail/typo3-english/2008-August/052259.html.
Probably Fedir's answer is correct too but I didn't have a chance to try it.
Cheers!