I have a NSString which is passed from an xml feed........
NSString *strDate =#"Thu, 22 Apr 2010 10.30 am CEST";
I'm currently using this code to format the date........
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy hh:mm a vvvv"];
NSDate *myDate = [dateFormatter dateFromString:date];
[dateFormatter setDateFormat:#"HH"];
NSLog(#"%#", [dateFormatter stringFromDate:myDate]);
I want to format my string only to display only hours and currently I'm getting value like this.
strDate =#"2010-04-10 14:00:00 +0530";
Can anyone please help me with this?......
I'm sorry.It's my mistake.It should be like this.
NSString *strDate =#"Thu, 22 Apr 2010 10:30 am CEST";
What my requirement is to get hour part only from above string using NSDateFormatter. How can I achieve that. Sorry for the earlier mistake.
Thanks.
If you want to get the 10 of 10:30 (if its ur requirement) then you can do it like:
strDate = #"Thu, 22 Apr 2010 10:30 am CEST";
NSArray *dateComponents = [strDate componentsSeparatedByString:#" "];
NSString *requiredString = [dateComponents objectAtIndex:4];
dateComponents = [requiredString componentsSeparatedByString:#":"];
requiredString = [dateComponents objectAtIndex:0];
and when you do:
NSLog(rquiredString);
Output : 10;
This is just a workaround, for better approach you should go through the NSDateComponents class.
Hope this helps.
Thanks,
Madhup
change to
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy hh.mm a vvvv"];
(. instead of : in hh:mm)
You want to do this:
NSString *strDate =#"Thu, 22 Apr 2010 10:30 am CEST";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy hh:mm a"];
NSDate *myDate = [dateFormatter dateFromString:strDate];
[dateFormatter setDateFormat:#"hh"];
strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
(Firstly your original formatter was wrong, you had a: instead of a .) EDIT no longer the case
Secondly, you want to ignore the CEST bit as this will cause your timezone being changed
Related
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
NSString to NSDate
I have a date in format Mon Jan 14 14:00:00 CET 2013 I try to convert it to NSDate:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE MMM dd HH:mm:ss zzz y"];
NSString *dateString = #"Mon Jan 14 14:00:00 CET 2013"
NSDate *date = [df dateFromString:dateString];
but it doesn't work and my date is nil
Input data is in en-GB locale, my device's locale is nb-NO
Any suggestions?
You're missing day in your format:
[df setDateFormat:#"EEE MMM dd HH:mm:ss zzz y"];
If it was not a typo, then next thing is to set proper locale so formatter will recognise CET timezone, for example en-GB will fix that:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
// that will fix the problem with not recognized CET timezone
[df setLocale:[[NSLocale alloc] initWithLocaleIdentifier:#"en-GB"]];
[df setDateFormat:#"EEE MMM dd HH:mm:ss zzz y"];
NSString *dateString = #"Mon Jan 14 14:00:00 CET 2013"
NSDate *date = [df dateFromString:dateString];
Try to use this function
- (NSDate*) dateFromString:(NSString*)aStr
{
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setLocale:[[[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"] autorelease]];
//[dateFormatter setDateFormat:#"YYYY-MM-dd HH:mm:ss a"];
[dateFormatter setDateFormat:#"MM/dd/yyyy HH:mm:ss a"];
[dateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSLog(#"%#", aStr);
NSDate *aDate = [dateFormatter dateFromString:aStr];
[dateFormatter release];
return aDate;
}
I hope this will helps u.
I think your Time Zone is wrong. Just use this code , it will work Perfectly :
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE MMM dd HH:mm:ss zzz y"];
NSString *dateString = #"Mon Jan 14 14:00:00 EDT 2013";
NSDate *date = [df dateFromString:dateString];
NSLog(#"date :: %#",date);
It will log Output as :
date :: 2013-01-14 18:00:00 +0000
EDIT :
I found Something for you : NSDateFormatter doesn't parse some timezones
You can solve this by using en_GB Locale , as stated : "These abbreviations do still work with the en_GB locale" in Working with Date and Time in Cocoa .
CET is not recognised
Try this :-
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE MMM dd HH:mm:ss yyyy"];
NSString *dateString = #"Mon Jan 14 14:00:00 2013";
NSDate *date = [df dateFromString:dateString];
NSLog(#"%#",date);
Hope it helps you
Simply "CET" is not a recognized time zone by NSDateFormatter.
Also the date/tine is over specified, best to not try include the day or week (Mon).
Here is an example that demonstrates working code with a recognized timezone:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE MMM dd HH:mm:ss zzz yyyy"];
NSString *dateString = #"Mon Jan 14 14:00:00 EST 2013";
NSDate *date = [df dateFromString:dateString];
NSLog(#"date: %#", date);
NSLog output
date: 2013-01-14 19:00:00 +0000
NSLog(#"abbreviationDictionary: %#", [NSTimeZone abbreviationDictionary]);
does show
CET = "Europe/Paris";
so this looks like an Apple bug in NSDateFormatter.
Report the bug at: Apple Bug Reporter
You can use:
[dateFormatter setDateStyle:NSDateFormatterShortStyle];
If you still want to custom your date format try this one:
yyyy-MM-dd HH:mm:ss ZZZ
Because can't invent your own formatted string syntax and expect it to work; you need to actually use a documented format as the documentation points it out : Formatters in OS X v10.8 and iOS 6.0 use version tr35-25.
-> https://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/DataFormatting/Articles/dfDateFormatting10_4.html
If you are curious: http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns
One simple thing on conversion from NSString to NSDate. How can I convert Mon, 27 August 2012 01:30 AM to NSDate in this same format. I tried with NSDateFormatter. But I am not getting it in this required format. Can anyone help? This is what I tried.
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEEE,dd MM yyyy HH:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
NSDateFormatter is to specify the format that will appear in the date-string when extracting string from date or the format that is in the date-string when extracting date from string
So whenever you extract NSDate from a NSString, NSDate is always obtained in default date format(eg 2012-08-27 00:30:00 +0000)... only the when you extract NSString from NSDate, NSString can be obtained in desired(custom) format that you set in NSDateFormatter.
I hope this will help you sure!
NSDateFormatter *dateformater=[[[NSDateFormatter alloc] init]autorelease];
[dateformater setDateFormat:#"EEEE,dd MMMM yyyy HH:mm a"];
NSDate *todayTmp=[NSDate date];
NSString *conversionDate=[dateformater stringFromDate:todayTmp];
Note : (Upper case) HH for 24h time format, (Lower case) hh for 12h time format
NSString *myDateAsAStringValue = #"Mon, 27 August 2012 01:30 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSDate *myDate = [[NSDate alloc]init];
myDate = [df dateFromString:myDateAsAStringValue];
[df release];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSString *strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
[dateFormatter release];
please use below code
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
your formatter is wrong
check this one
NSLog will return NSDate in a fixed format, i guess.
If we need Date in different format, we should have to format it via NSDateFormatter and get it as NSString.
Just a guess.
Don't forget to set the correct locale! If your device does not use an english locale NSDateFormatter can have problems to convert Mon and August into useful information because Mon is not the correct abbreviation for Monday in your language. For example in Germany the correct three letter abbreviation for Monday is Mon..
If you parse dates that have words in it you have to set the correct locale.
This should work:
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSLocale *posixLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[df setLocale:posixLocale];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
EEE is the dateformatter code for a three letter weekday abbreviation.
hh is the dateformatter code for Hours between 1 and 12. HH means 0-23
MMMM is the full month, MM would be the numeric value (= 08) of the month.
I am trying this since last two hours and finaly left it out for you guys :P
I need to convert this String Mon, 14 May 2012, 12:00:55 +0200
into Date dd/mm/yyyy hh:ss format..
Any kind of help towards the goal will be really appreciated.
What I have tried
I have tried using NSDateFormatter but I am unable to figure out the exact format of the above date.
This [dateFormatter setDateFormat:#"EEEddMM,yyyy HH:mm:ss"]; is how I have tried and many other formats too
Eg:
NSString *finalDate = #"Tue, 29 May 2012, 14:24:56 +0200";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEEddMM,yyyy HH:mm:ss"];
NSDate *date = [dateFormatter dateFromString:finalDate];
Here the date alwasys comes as nil
The most important part of date formatting is often forgotten, tell the NSDateFormatter the input language:
NSDateFormatter *dateFormatter = [NSDateFormatter new];
[dateFormatter setDateFormat:#"EEE, dd MMMM yyyy, HH:mm:ss Z"];
dateFormatter.locale = [[NSLocale alloc] initWithLocaleIdentifier:#"EN"];
NSDate *date = [dateFormatter dateFromString:#"Mon, 14 May 2012, 12:00:55 +0200"];
NSLog(#"date: %#", date);
I've checked the output: date: 2012-05-14 10:00:55 +0000
Be aware that the HH in the date formatter is for 24hr.
Now I would suggest not to use a fixed output scheme, but use one of the NSDateFormatterStyle:
[dateFormatter setDateStyle:NSDateFormatterShortStyle];
[dateFormatter setTimeStyle:NSDateFormatterShortStyle];
NSString *dateString = [dateFormatter stringFromDate:date];
NSLog(#"date: %#", dateString);
Which in american english will output: 5/14/12 12:00 PM
This code is valid for ARC if you are not using ARC add autorelease to the NSLocale and release the NSDateFormatter after you are done with it.
NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init];
[inputFormatter setDateFormat:#"dd/mm/yyyy hh:ss"];
NSString *formatterDate = [inputFormatter stringFromDate:inDate];
[inputFormatter release];
get inforamtion about all Date Formate
my Blog Link is http://parasjoshi3.blogspot.in/2012/01/date-formate-info-for-iphone-sdk.html
and also small function is bellow.....
-(NSString *) dateInFormat:(NSString*) stringFormat {
char buffer[80];
const char *format = [stringFormat UTF8String];
time_t rawtime;
struct tm * timeinfo;
time(&rawtime);
timeinfo = localtime(&rawtime);
strftime(buffer, 80, format, timeinfo);
return [NSString stringWithCString:buffer encoding:NSUTF8StringEncoding];
}
////////Like.......
NSString *mydate = [self dateInFormat:#"%Y%m%d-%H%M%S"];
hope,this help you....
I am converting an NSString like #"12:25 AM May 27 2011" into NSDate.But as I convert it using the following code
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"hh:mm a MMM dd YYYY"];
NSDate *date = [[dateFormatter dateFromString:#"12:25 AM May 27 2011"] copy];
[dateFormatter release];
I get the wrong Date as 2010-12-25 19:25:00 +0000
Can anyone please help me around here
It's not a wrong date, the time is displayed GMT hance (+0000) if you set the correct timezone very thing will be oke.
I want to convert this ,
NSString *result1=#"Mon, 28 Sep 2009 06:35:42 PDT";
to nsdate using NSDateFormatter in iphone....
Can anyone help me?
Thanks in advance.....
I believe you want this:
NSString* dateString = #"Mon, 28 Sep 2009 06:35:42 PDT";
NSDateFormatter* newFormatter = [[[NSDateFormatter alloc] init] autorelease];
// Use this format to parse the string
[newFormatter setDateFormat:#"EEE, dd MMM yyyy hh:mm:ss zzz"];
NSDate* aDate = [newFormatter dateFromString:dateString];
// Now change the format to that desired for printing
[newFormatter setDateFormat:#"MMM dd,yyyy HH:mm:ss aaa"];
NSLog(#"%#", [newFormatter stringFromDate:aDate]);
// Result:
// 2009-09-29 23:50:09.440 test[15396:903] Sep 28,2009 06:35:42 AM
You can find these codes here (as referenced in the NSDateFormatter documentation): http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns
That's what I do in my program:
NSString *dateString = #"Mon, 28 Sep 2009 06:35:42 PDT";
NSDateFormatter *newFormatter = [[NSDateFormatter alloc] init];
[newFormatter setDateStyle:NSDateFormatterMediumStyle];
[newFormatter setTimeStyle:NSDateFormatterMediumStyle];
I'm using medium style, but there are more styles, you probably should use kCFDateFormatterLongStyle or kCFDateFormatterFullStyle, and then:
NSDate *aDate = [newFormatter dateFromString: dateString];
[newFormatter release];
Hope this helps