How can i simplify UIScreen width? - iphone

how can i simplify that code in one line?
CGRect screen = [[UIScreen mainScreen] bounds];
NSLog(#"%#", screen.size.width);
Thanks for your time.

This statement will cause an exception, or should:
NSLog(#"%#", screen.size.width);
The width property returns a CGFloat. You would need to change your log statement to:
NSLog(#"%f", screen.size.width);
If you want everything on one line:
NSLog(#"%f", [[[[UIScreen mainScreen] bounds] size] width]);

I would suggest:
NSLog(#"%1.0f", [UIScreen mainScreen].bounds.size.width);
To get both height and width you can use NSStringFromCGSize:
NSLog(#"%#", NSStringFromCGSize([UIScreen mainScreen].bounds.size));

Related

EXC_BAD_ACCESS when trying to get iPhone screen dimensions

I'm trying to make certain elements resize according to the screen dimensions when the interface orientation changes. I've read in various places (including a few answers on here) that the way to get the bounds of the screen is to use [[UIScreen] mainScreen] bounds]. So I've added this code to see how it behaves:
- (void) willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration
{
NSLog(#"view dimensions: (%#, %#)", [[UIScreen mainScreen] bounds].size.width, [[UIScreen mainScreen] bounds].size.height);
}
But when running it, as soon as I rotate the screen I get an EXC_BAD_ACCESS message. Is there something about the scope of the willRotateToInterfaceOrientation function that doesn't allow me to call for the screen bounds? If so, how would I go about it?
%# format specifier expects format parameter to be objective-c object, while what you provide is plain float. To print float numbers use %f specifier:
NSLog(#"view dimensions: (%f, %f)", [[UIScreen mainScreen] bounds].size.width, [[UIScreen mainScreen] bounds].size.height);

Defining constant for screen width

I have a constant defined with screen width to 320. This is being used at multiple places in my code. I have to change this to take value from current device and I do not want to touch all these places. So, I want to define a constant for this with value:
[[UIScreen mainScreen] bounds].size.width
#define kScreenWidth [[UIScreen mainScreen] bounds].size.width
But it is giving me lot of compilation errors. Any clue?
[[UIScreen mainScreen] applicationFrame].size.width

why would [[UIScreen mainScreen] scale] return 0?

I thought I was doing something relatively simple, but I guess not.
Running:
NSLog(#"%f",[[UIScreen mainScreen] scale];
returns 0.000000
The problem is that I am trying to check for a retina display and the:
if([UIScreen respondsToSelector:#selector(scale)] &&
[[UIScreen mainScreen] scale] == 2.0) {
// does not get called on an iPhone 4
}
Doesnt get called. I have tried this both in the simulator as well as on the device.
I guess the answer is How to call [[UIScreen mainScreen] scale] in a universal app for the iphone and ipad

IPhone/IPad: How to get screen width programmatically?

Hi I'm wondering if there's a way to get the width programmatically.
I'm looking for something general enough to accomodate iphone 3gs, iphone 4, ipad. Also, the width should change based on if the device is portrait or landscape (for ipad).
Anybody know how to do this?? I've been looking for a while... thanks!
Take a look at UIScreen.
eg.
CGFloat width = [UIScreen mainScreen].bounds.size.width;
Take a look at the applicationFrame property if you don't want the status bar included (won't affect the width).
UPDATE: It turns out UIScreen (-bounds or -applicationFrame) doesn't take into account the current interface orientation. A more correct approach would be to ask your UIView for its bounds -- assuming this UIView has been auto-rotated by it's View controller.
- (void)didRotateFromInterfaceOrientation:(UIInterfaceOrientation)fromInterfaceOrientation
{
CGFloat width = CGRectGetWidth(self.view.bounds);
}
If the view is not being auto-rotated by the View Controller then you will need to check the interface orientation to determine which part of the view bounds represents the 'width' and the 'height'. Note that the frame property will give you the rect of the view in the UIWindow's coordinate space which (by default) won't be taking the interface orientation into account.
CGRect screen = [[UIScreen mainScreen] bounds];
CGFloat width = CGRectGetWidth(screen);
//Bonus height.
CGFloat height = CGRectGetHeight(screen);
This can be done in in 3 lines of code:
// grab the window frame and adjust it for orientation
UIView *rootView = [[[UIApplication sharedApplication] keyWindow]
rootViewController].view;
CGRect originalFrame = [[UIScreen mainScreen] bounds];
CGRect adjustedFrame = [rootView convertRect:originalFrame fromView:nil];
use:
NSLog(#"%f",[[UIScreen mainScreen] bounds].size.width) ;
As of iOS 9.0 there's no way to get the orientation reliably. This is the code I used for an app I design for only portrait mode, so if the app is opened in landscape mode it will still be accurate:
screenHeight = [[UIScreen mainScreen] bounds].size.height;
screenWidth = [[UIScreen mainScreen] bounds].size.width;
if (screenWidth > screenHeight) {
float tempHeight = screenWidth;
screenWidth = screenHeight;
screenHeight = tempHeight;
}
Use this code it will help
[[UIScreen mainScreen] bounds].size.height
[[UIScreen mainScreen] bounds].size.width
Here is a Swift way to get screen sizes, this also takes current interface orientation into account:
var screenWidth: CGFloat {
if UIInterfaceOrientationIsPortrait(screenOrientation) {
return UIScreen.mainScreen().bounds.size.width
} else {
return UIScreen.mainScreen().bounds.size.height
}
}
var screenHeight: CGFloat {
if UIInterfaceOrientationIsPortrait(screenOrientation) {
return UIScreen.mainScreen().bounds.size.height
} else {
return UIScreen.mainScreen().bounds.size.width
}
}
var screenOrientation: UIInterfaceOrientation {
return UIApplication.sharedApplication().statusBarOrientation
}
These are included as a standard function in:
https://github.com/goktugyil/EZSwiftExtensions

iPhone SDK screen size returns different results using similar syntax

I'm new to Objective C for iPhone. I tried the following code to get the screen size, however the code below returns two different result:
CGRect screenRect = [UIScreen mainScreen].bounds;
NSLog(#"width: %d", screenRect.size.width);
NSUInteger width = [UIScreen mainScreen].bounds.size.width;
NSUInteger height = [UIScreen mainScreen].bounds.size.height;
NSLog(#"width: %d", width);
The first NSLog outputs 0, while the last one outputs 320. Why are they different? Does it have something to do with pointers? Please help.
%d is for decimal and you're trying to print a float. Try
CGRect screenRect = [UIScreen mainScreen].bounds;
NSLog(#"width: %f", screenRect.size.width);
float width = [UIScreen mainScreen].bounds.size.width;
NSLog(#"width: %f", width);
CGRect.size.width is a CGFloat. If you use %f in your format string, you will get 320.
The bounds property is a structure of type CGRect. I think since NSLog doesn't know how to print this, it prints a 0. The size member is a structure of type CGSize. You can print CGSize's members because they are simply CGFLoats, or floats.
EDIT: Oh, I see what the problem is now. Thought you were printing the structure itself. Misread that.