Invalid receiver type int - iphone

I cant seem to find what would be the problem here...
NSArray *oneMove;
oneMove = [[bestMoves objectAtIndex:i] componentsSeparatedByString:#","];
int from, to;
int temp = [[oneMove objectAtIndex:0] intValue];
from = [temp intValue]/100; //"Invalid receiver type int"
to = [temp intValue]%100; //"Invalid receiver type int"
NSLog(#"%d, %d", from, to);
The thing is: it works and 'from' and 'to' get the right values but i get warnings at the indicated lines...
anyone knows why and how to fix that? (dont like them warnings when compiling ;) )

temp is already int value, no NSNumber. So you cannot send an [temp intValue] message to it.
Just use
from = temp / 100;
to = temp % 100;
Edit: Here is code that proves it works:
NSArray *bestMoves = [NSArray arrayWithObject:#"499,340,124"]; // Example data
NSArray *oneMove = [[bestMoves objectAtIndex:0] componentsSeparatedByString:#","];
int from, to;
int temp = [[oneMove objectAtIndex:0] intValue];
from = temp/100; // Code change
to = temp%100; // Code change
NSLog(#"%d, %d", from, to);
Output is as expected 4, 99.

Related

NSMutableArray integer storage

I am trying to store numbers inside the NSMutableArray, and have wrapped them like so:
-(IBAction)opUp:(id)sender{
opBool = YES;
opNum = [sender tag];
[numArray addObject:[NSNumber numberWithLong:number2]];
[opArray addObject:[NSNumber numberWithInt:opNum]];
number1 = 0;
number2 = 0;
opNum = 0;
NSLog(#"Operand %i", opNum);
NSLog(#"%i, %i", numArray.count, opArray.count);
}
But when I call them later using this:
final2 = [numArray objectAtIndex:i];
operthing = [opArray objectAtIndex:i];
I get this error message:
operthing equals 111526320
'operthing' is not supposed to go beyond 20.
Can someone help me with this?
Thanks.
operthing = [[opArray objectAtIndex:i] intValue];

How to sort an array with alphanumeric values?

I have an array which contains strings like frame_10#3x.png , frame_5#3x.png,frame_19#3x.png etc.
So I want to sort this array according to the number after the underscore i.e. the correct sequence will be frame_5#3x.png,frame_10#3x.png,frame_19#3x.png.
I tried to use the following method but no result:
NSInteger firstNumSort(id str1, id str2, void *context) {
int num1 = [str1 integerValue];
int num2 = [str2 integerValue];
if (num1 < num2)
return NSOrderedAscending;
else if (num1 > num2)
return NSOrderedDescending;
return NSOrderedSame;
}
Please suggest how to do this sorting for array.
NSArray *sry_img = [[NSArray alloc] initWithObjects:#"frame_18#3x.png",#"frame_17#3x.png",#"frame_1222#3x.png",#"frame_10#3x.png",#"frame_3#3x.png",#"frame_4#3x.png",#"frame_4#3x.png",#"frame_1#3x.png",#"frame_4#3x.png",#"frame_4#3x.png",nil];
NSArray *sortedStrings = [sry_img sortedArrayUsingSelector:#selector(localizedStandardCompare:)];
NSLog(#"%#",sortedStrings);
Enjy .......
But
localizedStandardCompare:, added in 10.6, should be used whenever file names or other strings are presented in lists and tables where Finder-like sorting is appropriate. The exact behavior of this method may be tweaked in future releases, and will be different under different localizations, so clients should not depend on the exact sorting order of the strings.
you want to do something like:
NSArray *components1 = [str1 componentsSeparatedByString:#"_"];
NSArray *components2 = [str2 componentsSeparatedByString:#"_"];
NSString *number1String = [components1 objectAtIndex:([components1 count] - 1])];
NSString *number2String = [components2 objectAtIndex:([components2 count] - 1])];
return [number1String compare:number2String];
I am not sure if my solution is the best possible approach but it can solve your problem for the time being :) .
1) First I have written a function to get the numbers before # character in your string and then I implemented simple SELECTION SORT algo to sort the array using this functions.
- (NSString*)getSubStringForString:(NSString*)value {
// First we will cut the frame_ string
NSMutableString *trimmedString = [NSMutableString stringWithString:[value substringWithRange:NSMakeRange(6, [value length]-6)]];
// New String to contain the numbers
NSMutableString *newString = [[NSMutableString alloc] init];
for (int i = 0; i < [trimmedString length] ; i++) {
NSString *singleChar = [trimmedString substringWithRange:NSMakeRange(i, 1)];
if (![singleChar isEqualToString:#"#"]) {
[newString appendString:singleChar];
} else {
break;
}
}
return newString;
}
This is the selection Implementation of the algo for sorting. The main logic is in the for loop. You can copy the code in viewDidLoad method to test.
NSMutableArray *array = [[NSMutableArray alloc] initWithObjects:#"frame_10#3x.png",#"frame_5#3x.png",
#"frame_3#3x.png", #"frame_19#3x.png",
nil];
NSLog(#"Values before Sort: %#", array);
int iPos;
int iMin;
for (iPos = 0; iPos < [array count]; iPos++)
{
iMin = iPos;
for (int i = iPos+1; i < [array count]; i++)
{
if ([[self getSubStringForString:[array objectAtIndex:i]] intValue] >
[[self getSubStringForString:[array objectAtIndex:iMin]] intValue]) {
iMin = i;
}
}
if ( iMin != iPos )
{
NSString *tempValue = [array objectAtIndex:iPos];
[array replaceObjectAtIndex:iPos withObject:[array objectAtIndex:iMin]];
[array replaceObjectAtIndex:iMin withObject:tempValue];
}
}
NSLog(#"Sorted Values: %#", array);
I hope that it can atleast keep you going. :)
You can try this-
NSString *str1 = [[[[str1 componentsSeparatedByString:#"frame_"] objectAtIndex:1] componentsSeparatedByString:#"#3x.png"] objectAtIndex:0];
int num1 = [str1 integerValue];

Can we assign exact string value to an int value in iphone sdk

In my application I have a value like "25:30" in NSString and I want to assign this value to int value.
If I do like:
int j = [stringval intValue];
hence I got the value "25" to my int value but I want the full value.
Is it possible?
If you mean 25.30 then you need floats, use CGFloat j = [stringval floatValue];
If that is supposed to be minutes & seconds, use NSDateFormatter's dateFromString:.
You can try this
NSString *new = #"25:30";
NSArry *data = [new componentsSeparatedByString:#":"];
int first = [[data objectAtIndex:0] intValue]; \\\ 25
int second = [[data objectAtIndex:1] intValue]; \\\ 30

Xcode Gives Strange Output From NSArray

When I run this code, the output is some 1084848 to the console. I can't figure out why such odd output... here is the code.
#import <Foundation/Foundation.h>
int main (int argc, const char * argv[])
{
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
NSMutableArray *array = [[NSMutableArray alloc] init];
int someNumber = 3;
[array addObject:[NSNumber numberWithInt:someNumber]];
NSLog(#"%i" , [array objectAtIndex:0]);
[pool drain];
return 0;
}
the "%i" format specifier expects an integer, not an Object.
Try NSLog(#"%i" , [[array objectAtIndex:0] intValue]);
XCode is probably giving you a warning on this line: something like "Conversion specifies type 'int', but argument has type 'id'".
Here's the pseudocode of your program:
//
// Inside of your main function....
//
// Set up the Autorelease pool and then create an array
//
// Declare an int
//
// Add the int to an array, while wrapping it in an NSNumber
//
// Log the value of the first object in the array, using the int formatter
//
// Clean up and return
//
You are logging the first object in the array, but NSArray cannot hold a primitive that's not wrapped in an Objective-C object.
To better understand your code, try changing these lines of code:
int someNumber = 3;
[array addObject:[NSNumber numberWithInt:someNumber]];
Expand them a little. Try this:
int someNumber = 3;
NSNumber *aNumber = [NSNumber numberWithInt:someNumber];
[array addObject:aNumber];
So, you've correctly wrapped the int in an NSNumber, but you're not unwrapping it. You need to ask your NSNumber for the int that it holds like so:
[[array objectAtIndex:0] intValue];
Or, to do the logging in one line:
NSLog(#"%i" , [[array objectAtIndex:0] intValue]);
The characters "%i" is called a "formatter". Different kinds of values require different formatters. When you are using an Objective-C object, you use "%#". For an NSInteger or int, you'd use %i. For a float, you'd use "%f". The point is that you need to either unwrap that number, or use the Objective-C formatter for strings.
A quick note about that weird value you were getting earlier: That's a memory address in RAM. It's the closest thing you're going to get when you use an incorrect formatter. In some cases, using the wrong formatter will cause an EXC_BAD_ACCESS. You were "lucky" and got a weird value instead of a dead program. I suggest learning about strings and formatters before you move on. It will make your life a lot easier.
When you use %i for integer values then you should give arguments as integer as below
NSLog(#"%i" , [[array objectAtIndex:0] intValue]);
But when you want object to be displayed then you must use %# which identifies object in general case as below:
NSLog(#"%#", array);

Convert char to int to NSString

I am writing some code to allow users to answer multiple choice questions. So I have an NSArray of values [#"value1", #"value2", ..]
I want to display them as:
A) value1
B) value2
The code I have is
for(int i = i; i < [values count]; i = i+1) {
NSString *displayValue = [[NSString alloc] initWithString:<NEED HELP HERE>];
displayValue = [displayValue stringByAppendingString:#") "];
displayValue = [displayValue stringByAppendingString:[values objectAtIndex:i];
}
The question I have is if there is where I have put , how could I convert i to the right ASCII character (A, B, C, etc) and initialize the string with that value
NSString *displayValue = [NSString stringWithFormat:#"%c",'A'-1+i];
and to get the whole string at once, use:
NSString *displayValue = [NSString stringWithFormat:#"%c) %#",'A'-1+i,
[values objectAtIndex:i]];
(ps. if you alloc an object, you must also release or autorelease, or you will "leak" memory)
Look at NSString:initWithFormat method, along with the String Programming Guide.