Hi am starting off with Zend Framework and have a question about action helpers. My first application is a simple authentication system (following a tutorial from a book). The registration and authentication seems to work fine but the redirect doesn't.
I have a customer controller that has this among others:
class CustomerController extends Zend_Controller_Action
{
// some code here......
public function authenticateAction()
{
$request = $this->getRequest();
if (!$request->isPost()) {
return $this->_helper->redirector('login');
}
// Validate
$form = $this->_forms['login'];
if (!$form->isValid($request->getPost())) {
return $this->render('login');
}
if (false === $this->_authService->authenticate($form->getValues())) {
$form->setDescription('Login failed, please try again.');
return $this->render('login');
}
return $this->_helper->redirector('index');
}
the authenticate url is http://localhost/customer/authenticate and this seems to work fine but it does not redirect. After authentication I get a blank page which looks like its taking me to the index and just sits there. I tried using '/index' instead but that did not help either. Do I need to do anything special to make the redirector helper work? I have a logout action which behaves the same.
You should call
$this->_helper->redirector('index');
without the return.
I found out there may be a problem with my setup. The code above is perfect, works on another computer.
Related
Im trying to style my login page. My login url is website/Security/login. Im trying to locate the 'login' piece of the url. What have i done wrong below?
public function DisplayPageType() {
$param = $this->request->param('Action');
if ($param === 'login')
{
return 'Login';
}
Thanks
I think that won't work since the controller during render is the Page_Controller and not the Security controller. So the $Action param is not equal to login. It could be index, I'm not sure.
If you just want to check if you're in the login page, you can add this to your Page_Controller:
public function getIsLoginPage()
{
return $_REQUEST['url'] == '/Security/login';
}
Then in your template:
<body class="<%if $IsLoginPage %>login-page<% end_if %>">
A bit dirty but it's the quickest way I know.
Another way is to leverage SilverStripe's legacy support. You can add a css file called tabs.css at mysite/css/tabs.css. If this file exists, SilverStripe will include this in the page.
You can also create templates that SilverStripe will automatically use if they exist:
themes/<theme_name>/Security.ss - If you want your login page to use an entirely different layout.
themes/<theme_name>/Layout/Security_login.ss - If you want to change just the content part (the $Layout section)
I hope this helps.
#gpbnz is right, the $Action param is not equal to login, it actually returns null as accessing $this->request from the Page_Controller when accessing the Security/login returns a NullHTTPRequest.
To get the action, you will want to get the current controller using Controller::curr(). It is then as simple as calling getAction on this controller.
To confirm that the action isn't from a random controller that happens to have an action called login, you can check the instanceof the controller like so: Controller::curr() instanceof Security
This check will still allow it to work for any controller that extends Security though which may/may not happen depending on the project.
I would stick away from actually reading the URL for the information manually though as that can create issues with maintainability in the future.
To bring this to a nice little function:
public function isLoginPage()
{
$controller = Controller::curr();
return $controller instanceof Security && $controller->getAction() == 'login';
}
Otherwise #gpbnz had a good suggestion of using the template system to your advantage for overriding not only the styles but the HTML around it.
I use dektrium user registration form.
registration link generates domain.com/user/register link
but it's not base user model, this module is located inside vendor/dektrium folder.
Now in base controllers folder I have UsersController with view action.
and after finishing registration I want to start view action of UsersController to view users page.
This is registration module code
public function actionRegister()
{
if (!$this->module->enableRegistration) {
throw new NotFoundHttpException;
}
$model = $this->module->manager->createRegistrationForm();
if ($model->load(\Yii::$app->request->post()) && $model->register()) {
return $this->redirect(array('users/'.$model->username));
}
return $this->render('register', [
'model' => $model
]);
}
As you can see I've put there this code
return $this->redirect(array('users/'.$model->username));
Which is supposed to take user to it's own page at domain.com/users/username.
But unfortunatelly url is forming in the following way
domain.com/user/users/username
How can I fix this problem and direct user to domain.com/users/username page ?
Add an extra / in front of the users redirect. it should be
return $this->redirect(array('/users/'.$model->username));
Or you should actually create the url the proper way, that would be the best way to do this, but I do not know the way you have your rules set up so I cannot help you there. I am just guessing here but it should be:
return $this->redirect(array('users/view, 'username' => $model->username));
In this way you are using your url manager, not just hardcoding the url. In the future if you decide to change the link it will be much easier (replace just the url line in your config) and not go in files to change it.
I'm using the SignMeUp Plugin for user registration in CakePHP 2.0 (whose homepage seems to be down atm).
For the most part, everything works perfectly fine, except that I'm getting the following seemingly unrelated error whenever a function uses $this->Email->send() :
Trying to get property of non-object
[CORE\Cake\View\Helper\PaginatorHelper.php, line 111]
The line is:
public function beforeRender($viewFile) {
$this->options['url'] = array_merge($this->request->params['pass'],
$this->request->params['named']);
Not sure how that is actually related to the email, so I'm at a loss as to what can possibly cause this error, as the emails are actually being sent no problem.
An example function in the plugin would be:
protected function __sendActivationEmail($userData) {
$this->__setUpEmailParams($userData);
$this->__parseEmailSubject('activation', $userData);
if ($this->__setTemplate(Configure::read('SignMeUp.activation_template'))) {
if ($this->Email->send()) {
return true;
}
}
}
I personally see nothing wrong with this either... Not sure what else could possibly be causing this error. If someone of you has any kind of idea, that would really be appreciated!
BTW: If I set debug to 0, I get a blank page after the function executes instead of a proper redirect, so that's not a solution.
I had the same problem because I included the paginator as helper:
public $helpers = array('Time','Paginator');
In CakePHP 2.0 the Paginator is always included and for some reason there seems to be a conflict with the sendMail if you include the helper in the controller. So if you delete the Paginator from the helpers list it should work without error.
One of the application I am developing using Zend Framework requires the user's profile page to be accessed via website.com/username, while other pages should be accessed by website.com/controller_name/action_name
I am not too sure how can this be achieved, however, I feel this can be done with some tweaks in the .htaccess file.
Can someone here please help me out?
Many thanks in advance
As suggested before, you can use a custom route that will route single level requests. However, this will also override the default route. If you're using modules, this will no longer work example.com/<module>.
I have done this before but only for static pages. I wanted this:
example.com/about
instead of this:
example.com/<some-id>/about
while maintaining the default route so this still works
example.com/<module>
example.com/<controller>
The way I did this was using a plugin to test if my request could be dispatched. If the request could not be dispatched using the default route, then I would change the request to the proper module to load my page. Here is a sample plugin:
class My_Controller_Plugin_UsernameRoute extends Zend_Controller_Plugin_Abstract
{
public function preDispatch(Zend_Controller_Request_Abstract $request)
{
$dispatcher = Zend_Controller_Front::getInstance()->getDispatcher();
if (!$dispatcher->isDispatchable($request)) {
$username = $request->getControllerName();
$request->setModuleName('users');
$request->setControllerName('dashboard');
$request->setActionName('index');
$request->setParam('username', $username);
/** Prevents infinite loop if you make a mistake in the new request **/
if ($dispatcher->isDispatchable($request)) {
$request->setDispatched(false);
}
}
}
}
What about using Zend_Controller_Router_Route, look here the link http://framework.zend.com/manual/en/zend.controller.router.html#zend.controller.router.routes.standard.variable-requirements
I'm trying to centralise my redirects (based on authentication and various other states) into a front controller plugin. So far I've tried:
$this->setRequest(new Zend_Controller_Request_Http('my_url'));
at various points in the plugin (i.e. from routeStartup to dispatchLoopShutdown) and also:
$this->setResponse(new Zend_Controller_Response_Http('my_url'));
Can anyone offer some assistance on this, or point me in the direction of a tutorial?
The easiest way would be to use ZF's Redirect ActionHelper
$r = Zend_Controller_Action_HelperBroker::getStaticHelper('redirector');
$r->gotoUrl('/some/url')->redirectAndExit();
Alternatively instantiate it without the HelperBroker
$r = new Zend_Controller_Action_Helper_Redirector;
$r->gotoUrl('/some/url')->redirectAndExit();
The ActionHelper provides an API solely concerned about redirecting through a number of methods, like gotoRoute, gotoUrl, gotoSimple, which you can use depending on your desired UseCase.
Internally, the ActionHelper uses the APIs of Response and Router to do the redirect though, so you can also use their methods directly, e.g.
$request->setModuleName('someModule')
->setControllerName('someController')
->setActionName('someAction');
or
$response->setRedirect('/some/url', 200);
Further reading:
http://devzone.zend.com/article/3372-Front-Controller-Plugins-in-Zend-Framework
http://framework.zend.com/manual/en/zend.controller.actionhelpers.html
http://framework.zend.com/manual/en/zend.controller.response.html
http://framework.zend.com/manual/en/zend.controller.plugins.html
http://framework.zend.com/apidoc/core
http://framework.zend.com/svn/framework/standard/trunk/library/Zend/Controller/
If you are looking to redirect if the user is not logged it, the first parameter of dispatchLoopStartup() is a handle to the request object.
public function dispatchLoopStartup(Zend_Controller_Request_Abstract $request)
{
if(!Zend_Auth::getInstance()->hasIdentity())
{
$request->setControllerName('auth');
$request->setActionName('login');
// Set the module if you need to as well.
}
}
If you want to redirect in the index page then this should suffice.
public function preDispatch(Zend_Controller_Request_Abstract $request)
{
if(!Zend_Auth::getInstance()->hasIdentity())
{
$baseUrl = new Zend_View_Helper_BaseUrl();
$this->getResponse()->setRedirect($baseUrl->baseUrl());
}
}
If you want to redirect somewhere else then just change the parameter in the setRedirect() function
Thanks!
:)