I have models of my tables and would like to do a join using a model as opposed to to a table.
For example, instead of:
$select = $this->select()
->from(array('p' => 'products'),
array('product_id', 'product_name'))
->join(array('l' => 'line_items'),
'p.product_id = l.product_id',
->limit(20, 10);
where I specify the table names and columns I want to join, can I not use my models?
$select = $this->select()
->from(array('p' => 'products'),
array('product_id', 'product_name'))
->join(array('l' => Model_Table1::tableName()),
'p.product_id = l.product_id',
->limit(20, 10);
no ... u cann't join two model ... these are class which can be include .. so u can only use these class in controller or can include in another model too ... according to application or requirement
I don't see why not, if your model has a static variable with the name and a static function to return the variable:
protected static $table = 'dbname';
public static function tableName() {
return self::$table;
}
Is it worth it though? Is the table name ever going to change?
You must set integrity check is false. Like this
$select = $this->select()
->setIntegrityCheck(false)
->from(array('p' => 'products'),
array('product_id', 'product_name'))
->join(array('l' => 'line_items'),
'p.product_id = l.product_id',
->limit(20, 10);
Related
With relationship and joins I'm trying get the latest post of each customer.
But I don't really get it to work. I get error:
Column already exists: 1060 Duplicate column name 'custID'
Based on my searching both here and Google it could have been for * but I have removed so all table columns is specified by name so I don't get why I get column already exists?
$db = $this->getDbTable();
// create sub query
$subSql = $db->select()
->setIntegrityCheck(false)
->from(array('s1' => 'sales'), array('s1.custID', 's1.saledate'))
->joinLeft(array('s2' => 'sales'), 's1.custID = s2.custID AND s1.saledate < s2.saledate', array('s2.custID', 's2.saledate'))
->where('s2.custID IS NULL')
->limit(1);
//main query
$sql = $db->select()
->setIntegrityCheck(false)
->from(array('customers' => 'customers'), array("customers.custID"))
->joinLeft(array('sale_tmp' => new Zend_Db_Expr('(' . $subSql . ')')), "customers.custID = sale_tmp.custID", array('sale_tmp.custID'));
//echo $sql->assemble();
//exit;
$resultSet = $db->fetchAll($sql);
return $resultSet;
Since two of your tables have the field custID, there is a conflict about how to populate the custID value in your joined table.
You need to provide a column-alias for one of them. The signature of the joinLeft() method is:
joinLeft($table, $condition, [$columns])
The third argument $columns can be a straight integer-indexed array of columns (as you are using) or it can be an associative array whose values are the columns, but whose keys are the column-aliases.
So perhaps try something like:
// create sub query
// add alias for the custID field
$subSql = $db->select()
->setIntegrityCheck(false)
->from(array('s1' => 'sales'), array('s1.custID', 's1.saledate'))
->joinLeft(array('s2' => 'sales'), 's1.custID = s2.custID AND s1.saledate < s2.saledate', array('sales_custID' => 's2.custID', 's2.saledate'))
->where('s2.custID IS NULL')
->limit(1);
// main query
// add alias for custID field
$sql = $db->select()
->setIntegrityCheck(false)
->from(array('customers' => 'customers'), array("customers.custID"))
->joinLeft(array('sale_tmp' => new Zend_Db_Expr('(' . $subSql . ')')), "customers.custID = sale_tmp.custID", array('temp_custID' => sale_tmp.custID'));
hi i have aproblem in my code, I want generate a list of user but this have a group and need just a group of user.
the error say:
Error: SQLSTATE[42P01]: Undefined table: 7 ERROR: missing FROM-clause entry for table "Grupo"
this is my code:
public function add()
{
$this->loadModel('SoyaProveedor');
$this->loadModel('Soya');
$this->set('oleaginosas', $this->Soya->find('list', array(
'fields'=> array('id','username'),
'conditions' => array('Grupo.categoria' => 'Soya' , 'Grupo.subcategoria' => 'Productor de Oleaginosas')
)));
if ($this->request->is('post')) {
$this->request->data['SoyaProveedor']['nombre'] = strtoupper($this->request->data['SoyaProveedor']['nombre']);
$this->request->data['SoyaProveedor']['codigo'] = strtoupper($this->request->data['SoyaProveedor']['codigo']);
if ($this->SoyaProveedor->save($this->request->data)) {
$this->Session->setFlash(__('La Información fue Guardada.'));
return $this->redirect(array('action' => 'index'));
}
}
}
the sql query of the cake generate it:
SQL Query: SELECT "Soya"."id" AS "Soya__id", "Soya"."username" AS
"Soya__username" FROM "public"."users" AS "Soya" WHERE
"Grupo"."categoria" = 'Soya' AND "Grupo"."subcategoria" = 'Productor
de Oleaginosas'
You need the grupos table to be joined in the query, your query in the question has no joins. There are a number of simple solutions.
Define recursive.
Recursive is a very coarse control of what joins and queries are executed, by default find('list') has a recursive value of -1.
-1 means no joins, which is why there is no join in the resultant query. Setting it to a value of 0 adds a join to the main query for all hasOne and belongsTo associations.
Be wary of using/relying on recursive as it's very easy to generate queries with joins you don't need - and/or triggering many subsequent queries for related data (if set to a value larger than 0).
However this find call:
$data = $this->Soya->find('list', array(
'fields'=> array('Soya.id','Soya.username'),
'recursive' => 0, // added
'conditions' => array(
'Grupo.categoria' => 'Soya' ,
'Grupo.subcategoria' => 'Productor de Oleaginosas'
)
));
Should result in this query (If the Soya model has a belongsTo association to Grupo):
SELECT
"Soya"."id" AS "Soya__id",
"Soya"."username" AS "Soya__username"
FROM
"public"."users" as "Soya"
LEFT JOIN
"public"."Grupos" as "Grupo" on ("Soya"."grupo_id" = "Grupo"."id")
...
Possibly more joins
...
WHERE
"Grupo"."categoria" = 'Soya'
AND
"Grupo"."subcategoria" = 'Productor de Oleaginosas'
Or Use containable
The containable behavior allows better control of what queries are executed. Given the info in the question to use it that means:
<?php
class Soya extends AppModel {
// Assumed from information in the question
public $useTable = 'users';
public $belongsTo = array('Grupo');
// added
public $actsAs = array('Containable');
}
Will permit you to do the following in your controller:
$data = $this->Soya->find('list', array(
'fields'=> array('Soya.id','Soya.username'),
'contain' => array('Grupo'), // added
'conditions' => array(
'Grupo.categoria' => 'Soya' ,
'Grupo.subcategoria' => 'Productor de Oleaginosas'
)
));
Which will generate the following query (exactly one join):
SELECT
"Soya"."id" AS "Soya__id",
"Soya"."username" AS "Soya__username"
FROM
"public"."users" as "Soya"
LEFT JOIN
"public"."Grupos" as "Grupo" on ("Soya"."grupo_id" = "Grupo"."id")
WHERE
"Grupo"."categoria" = 'Soya'
AND
"Grupo"."subcategoria" = 'Productor de Oleaginosas'
Link your models together using associations: CakePHP Associations
Alternatively you can use custom sql-statemens using join e.g.:
$db = $this->getDataSource();
$result = $db->fetchAll(
"SELECT Soya.id AS Soya__id, Soya.username AS Soya__username FROM public.users AS Soya
join Grupo on Grupo.id = Soya.groupo_id
WHERE Grupo.categoria = ? AND Grupo.subcategoria = ?",
array('Soya', 'Productor de Oleaginosas')
);
$this->set('oleaginosas', $result);
I am a Yii Beginner and I am currently working on a Tagging system where I have 3 tables:
Issue (id,content,create_d,...etc)
Tag (id,tag)
Issue_tag_map (id,tag_id_fk,issue_id_fk)
In my /Views/Issue/_form I have added a MultiComplete Extension to retrieve multiple tag ids and labels,
I have used an afterSave function in order to directly store the Issue_id and the autocompleted Tag_ids in the Issue_tag_map table, where it is a HAS_MANY relation.
Unfortunately Nothing is being returned.
I wondered if there might be a way to store the autocompleted Tag_ids in a temporary attribute and then pass it to the model's afterSave() function.
I have been searching for a while, and this has been driving me crazy because I feel I have missed a very simple step!
Any Help or advices of any kind are deeply appreciated!
MultiComplete in Views/Issue/_form:
<?php
echo $form->labelEx($model, 'Tag');
$this->widget('application.extension.MultiComplete', array(
'model' => $model,
'attribute' => '', //Was thinking of creating a temporary here
'name' => 'tag_autocomplete',
'splitter' => ',',
'sourceUrl' => $this->createUrl('Issue/tagAutoComplete'),
// Controller/Action path for action we created in step 4.
// additional javascript options for the autocomplete plugin
'options' => array(
'minLength' => '2',
),
'htmlOptions' => array(
'style' => 'height:20px;',
),
));
echo $form->error($model, 'issue_comment_id_fk');
?>
AfterSave in /model/Issue:
protected function afterSave() {
parent::afterSave();
$issue_id = Yii::app()->db->getLastInsertID();
$tag; //here I would explode the attribute retrieved by the view form
// an SQL with two placeholders ":issue_id" and ":tag_id"
if (is_array($tag))
foreach ($tag as $tag_id) {
$sql = "INSERT INTO issue_tag_map (issue_id_fk, tag_id_fk)VALUES(:issue_id,:tag_id)";
$command = Yii::app()->db->createCommand($sql);
// replace the placeholder ":issue_id" with the actual issue value
$command->bindValue(":issue_id", $issue_id, PDO::PARAM_STR);
// replace the placeholder ":tag_id" with the actual tag_id value
$command->bindValue(":tag_id", $tag_id, PDO::PARAM_STR);
$command->execute();
}
}
And this is the Auto Complete sourceUrl in the Issue model for populating the tags:
public static function tagAutoComplete($name = '') {
$sql = 'SELECT id ,tag AS label FROM tag WHERE tag LIKE :tag';
$name = $name . '%';
return Yii::app()->db->createCommand($sql)->queryAll(true, array(':tag' => $name));
actionTagAutoComplete in /controllers/IssueController:
// This function will echo a JSON object
// of this format:
// [{id:id, name: 'name'}]
function actionTagAutocomplete() {
$term = trim($_GET['term']);
if ($term != '') {
$tags = issue::tagAutoComplete($term);
echo CJSON::encode($tags);
Yii::app()->end();
}
}
EDIT
Widget in form:
<div class="row" id="checks" >
<?php
echo $form->labelEx($model, 'company',array('title'=>'File Company Distrubution; Companies can be edited by Admins'));
?>
<?php
$this->widget('application.extension.MultiComplete', array(
'model' => $model,
'attribute' => 'company',
'splitter' => ',',
'name' => 'company_autocomplete',
'sourceUrl' => $this->createUrl('becomEn/CompanyAutocomplete'),
'options' => array(
'minLength' => '1',
),
'htmlOptions' => array(
'style' => 'height:20px;',
'size' => '45',
),
));
echo $form->error($model, 'company');
?>
</div>
Update function:
$model = $this->loadModel($id);
.....
if (isset($_POST['News'])) {
$model->attributes = $_POST['News'];
$model->companies = $this->getRecordsFromAutocompleteString($_POST['News']
['company']);
......
......
getRecordsFromAutocompleteString():
public static cordsFromAutocompleteString($string) {
$string = trim($string);
$stringArray = explode(", ", $string);
$stringArray[count($stringArray) - 1] = str_replace(",", "", $stringArray[count($stringArray) - 1]);
$criteria = new CDbCriteria();
$criteria->select = 'id';
$criteria->condition = 'company =:company';
$companies = array();
foreach ($stringArray as $company) {
$criteria->params = array(':company' => $company);
$companies[] = Company::model()->find($criteria);
}
return $companies;
}
UPDATE
since the "value" porperty is not implemented properly in this extension I referred to extending this function to the model:
public function afterFind() {
//tag is the attribute used in form
$this->tag = $this->getAllTagNames();
parent::afterFind();
}
You should have a relation between Issue and Tags defined in both Issue and Tag models ( should be a many_many relation).
So in IssueController when you send the data to create or update the model Issue, you'll get the related tags (in my case I get a string like 'bug, problem, ...').
Then you need to parse this string in your controller, get the corresponding models and assigned them to the related tags.
Here's a generic example:
//In the controller's method where you add/update the record
$issue->tags = getRecordsFromAutocompleteString($_POST['autocompleteAttribute'], 'Tag', 'tag');
Here the method I'm calling:
//parse your string ang fetch the related models
public static function getRecordsFromAutocompleteString($string, $model, $field)
{
$string = trim($string);
$stringArray = explode(", ", $string);
$stringArray[count($stringArray) - 1] = str_replace(",", "", $stringArray[count($stringArray) - 1]);
return CActiveRecord::model($model)->findAllByAttributes(array($field => $stringArray));
}
So now your $issue->tags is an array containing all the related Tags object.
In your afterSave method you'll be able to do:
protected function afterSave() {
parent::afterSave();
//$issue_id = Yii::app()->db->getLastInsertID(); Don't need it, yii is already doing it
foreach ($this->tags as $tag) {
$sql = "INSERT INTO issue_tag_map (issue_id_fk, tag_id_fk)VALUES(:issue_id,:tag_id)";
$command = Yii::app()->db->createCommand($sql);
$command->bindValue(":issue_id", $this->id, PDO::PARAM_INT);
$command->bindValue(":tag_id", $tag->id, PDO::PARAM_INT);
$command->execute();
}
}
Now the above code is a basic solution. I encourage you to use activerecord-relation-behavior's extension to save the related model.
Using this extension you won't have to define anything in the afterSave method, you'll simply have to do:
$issue->tags = getRecordsFromAutocompleteString($_POST['autocompleteAttribute'], 'Tag', 'tag');
$issue->save(); // all the related models are saved by the extension, no afterSave defined!
Then you can optimize the script by fetching the id along with the tag in your autocomplete and store the selected id's in a Json array. This way you won't have to perform the sql query getRecordsFromAutocompleteString to obtain the ids. With the extension mentioned above you'll be able to do:
$issue->tags = CJSON::Decode($_POST['idTags']);//will obtain array(1, 13, ...)
$issue->save(); // all the related models are saved by the extension, the extension is handling both models and array for the relation!
Edit:
If you want to fill the autocomplete field you could define the following function:
public static function appendModelstoString($models, $fieldName)
{
$list = array();
foreach($models as $model)
{
$list[] = $model->$fieldName;
}
return implode(', ', $list);
}
You give the name of the field (in your case tag) and the list of related models and it will generate the appropriate string. Then you pass the string to the view and put it as the default value of your autocomplete field.
Answer to your edit:
In your controller you say that the companies of this model are the one that you added from the Autocomplete form:
$model->companies = $this->getRecordsFromAutocompleteString($_POST['News']
['company']);
So if the related company is not in the form it won't be saved as a related model.
You have 2 solutions:
Each time you put the already existing related model in you autocomplete field in the form before displaying it so they will be saved again as a related model and it won't disapear from the related models
$this->widget('application.extensions.multicomplete.MultiComplete', array(
'name' => 'people',
'value' => (isset($people))?$people:'',
'sourceUrl' => array('searchAutocompletePeople'),
));
In your controller before calling the getRecordsFromAutocompleteString you add the already existing models of the model.
$model->companies = array_merge(
$model->companies,
$this->getRecordsFromAutocompleteString($_POST['News']['company'])
);
$select->joinRight(array('i' => '(SELECT * FROM images ORDER BY image_id)'),'i.ad_id = '. $main .'.id',$imarray);
Like that doesn't work. Subquery getting inside quotes.
Like that:
RIGHT JOIN `(SELECT * FROM images ORDER BY image_id)` AS `i` ON i.ad_id = a.id
Thanks ;)
Use
$select->joinRight(
array('i' => new Zend_Db_Expr('(SELECT * FROM images ORDER BY image_id)')),
'i.ad_id = '. $main .'.id',
$imarray
);
I feel This is easier to read and navigate...
$sub = $this->select()
->setIntegrityCheck(false)
->from(array('i' => 'images'), array('*'))
->order('i.image_id');
$select = $this->select()
->setIntegrityCheck(false)
->from(array('m' => 'MAIN_TABLE'), array('*'))
->joinRight(array('i' => $sub), 'i.ad_id = m.id', array('*'));
return $this->select($select);
This is my first time using Zend Framework for an application and i don't know if I completely have by head around Models.
I have four tables: shopping_cart, product, product_unit, distributor.
shopping cart has an cart_id, product_id, unit_id and dist_id (shopping cart joins on the other tables with their corresponding id).
Before Zend I would create a class like this:
class ShoppingCart
{
function getItems()
{
$sql ="select * from shopping_cart, product, product_unit, distributor
where
shopping_cart.product_id = product.id AND
shopping_cart.unit_id = product_unit.id AND
shopping_cart.dist_id = distributor.id AND
cart_id = xxx";
$items = $this->db->getAll($sql);
}
One query to get all the information from the joined tables.
When I set up the relationship mapping in Zend_Db_Table_Abstract:
My Shopping Cart Model:
class Application_Model_ShoppingCart
{
function __construct()
{
$this->ShoppingCartTable = new Application_Model_DbTable_ShoppingCart();
}
function getItems()
{
$cart_items = $this->ShoppingCartTable->getItems($this->GetCartId());
return $cart_items;
}
}
class Application_Model_DbTable_ShoppingCart extends Zend_Db_Table_Abstract
{
protected $_name = 'shopping_cart';
protected $_rowClass = 'Application_Model_DbTable_ShoppingCart_Item';
protected $_referenceMap = array(
'Product' => array(
'columns' => 'product_id',
'refTableClass' => 'Application_Model_DbTable_Product',
'refColumns' => 'id'
),
'Distributor' => array(
'columns' => 'dist_id',
'refTableClass' => 'Application_Model_DbTable_Distributor',
'refColumns' => 'id'
),
'Unit' => array(
'columns' => 'unit_id',
'refTableClass' => 'Application_Model_DbTable_ProductUnit',
'refColumns' => 'id'
)
);
public function getItems($cart_id)
{
$where = $this->getAdapter()->quoteInto('cart_id = ?', $cart_id);
return $this->fetchAll($where);
}
}
In my controller:
$this->_shoppingCartModel = new Application_Model_ShoppingCart();
$items = $this->_shoppingCartModel->getItems();
IN my view :
foreach($this->items AS $item)
{
$item_product = $item->findParentRow('Application_Model_DbTable_Product');
$item_dist = $item->findParentRow('Application_Model_DbTable_Distributor');
$item_unit = $item->findParentRow('Application_Model_DbTable_ProductUnit');
}
when I have ten items in my cart the db profiler shows over sixty queries (WHOA) to view the cart items ( information across all four tables are displayed - product name, unit description, distributor name).
For each item it queries the shopping_cart, then querys the product table, then the product unit, then the distributor_table.
Is there a way to have this run as one query joining all the tables via Zend_Db_Table_Abstract relationships?
Will I have to go back to using db adapter in the my Application_Model_ShoppingCart class?
I want to abstract all data access to the table models (Application_Model_DbTable_ShoppingCart) and not have the Application_Model_ShoppingCart tied to a db handler.
Thanks in advance for advice, I love the Zend Framework but models are still hard for me to understand given the different conflicting ways people talk about using them.
In short, no, unfortunately it's not possible to get a set of table rows together with their relationships in a single query.
It's just that all methods dealing with relationships are defined for a row, not for a table.
But at least, you can form your sql with Zend_Db_Table_Select instead of writing it all manually.
Upd: Your code for fetching ShoppingCarts, in my opinion, should belong to the table (DbTable_ShoppingCart). So, the code you provided in the beginning could be transformed to the following:
class Application_Model_DbTable_ShoppingCart extends Zend_Db_Table_Abstract {
public function getItem($cart_id) {
$select = $this->select()
->from( array('sc' => 'shopping_cart'), array(Zend_Db_Select::SQL_WILDCARD) )
->join( array('p' => 'product'), 'sp.product_id = p.id', array(Zend_Db_Select::SQL_WILDCARD) )
->join( array('pu' => 'product_unit'), 'sp.unit_id = pu.id', array(Zend_Db_Select::SQL_WILDCARD) )
->join( array('d' => 'distributor'), 'sp.dist_id = d.id', array(Zend_Db_Select::SQL_WILDCARD) )
->where('sp.cart_id = ?', $cart_id)
->setIntegrityCheck(false);
return $this->fetchAll($select);
}
}