Imagine I have a UIView and to that I add 2 UIButtons.
I find that I can put a finger on one button, then, holding the first, I can touch the 2nd button with another finger. Both buttons will show their UIControlStateHighlighted images.
Is there a way to stop the 2nd touch working? I thought that multipleTouchEnabled = NO was the answer, but seems not!
Any ideas?
use a property of UIButton called exclusiveTouch
-(IBAction)button1Pressed {
button2.enabled = NO;
}
-(IBAction)button2Pressed {
button1.enabled = NO;
}
For touch down.
Then for touch up inside and touch up outside.
-(IBAction)button1Lifted {
button2.enabled = YES;
}
-(IBAction)button1Lifted {
button2.enabled = YES;
}
when you tab on 1st button, in Button's IBAction method,make a user interaction of a 2nd button disabled.(On 1st line)
and in last line of 1st button IBAction code, make 2nd button user interaction enabled.(on last line). set IBAction to touchDown.
& vice-versa.
add this property to each button\n
button.exclusiveTouch=YES;
Related
I'd like to detect swipe on the entire screen, however, the screen contains UIButtons, and if the user taps one of these buttons, I want the Touch Up Inside event to be triggered.
I've create a UIView on the top of my screen, and added a UIPanGestureRecognizer on it to detect the swipe, but now I need to pass the gesture through that view when I detect that it's a tap rather than a swipe.
I know how to differentiate the gestures, but I've no idea on how to pass it to the view below.
Can anyone help on that? Thanks!
Thanks for your answer. The link helped me to solve part of my problem.
I've set the buttons as subviews of my gestureRecognizer view and I can now start a swipe from one of the buttons (and continue to use the buttons as well). I managed to prevent the buttons to go to the "down" state by using the following code :
UIPanGestureRecognizer *swipe = [[UIPanGestureRecognizer alloc] initWithTarget:self action:#selector(swipeDetected:)];
swipe.maximumNumberOfTouches = 1;
swipe.delaysTouchesBegan =YES;
swipe.cancelsTouchesInView = YES;
[self.gestureRecognitionView addGestureRecognizer:swipe];
there is a BOOL property of UIGestureRecognizer cancelsTouchesInView. default is yes. set it to NO , and the touches will pass thru to the UIView
also have a look at the solution for this question
If you want to prevent the recognizer from receiving the touch at all, UIGestureRecognizerDelegate has a method gestureRecognizer:shouldReceiveTouch: you can use:
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
// don't override any other recognizers
if (gestureRecognizer != panRecognizer) {
return YES;
}
CGPoint touchedPoint = [touch locationInView:self.someButton];
return CGRectContainsPoint(self.someButton.bounds, touchedPoint) == NO;
}
I have small view with a UITextField in it. I want to make the view hidden by default. when a button clicked it should show the view and the elements in main view below this sub view must be scrolled down. Any idea? I'm attaching the screenshots
Set the UITextView as hidden from InterfaceBuilder (you can set it from code too).
After this attach this action handler to the UIButton.
- (IBAction)showTextBar
{
[textView setHidden:False];
return;
}
This will show the textBar. If you want to show some other elements then you can add them in this method. Also you can make this method like a toggle. click once to show the elements, click again to hide them.
Inside the action u can also use
textView.hidden = NO;
As for the scrolling use a UIScrollView something like
[_scrollView setContentOffset:CGPointMake(0,_textView.center.y+168) animated:YES];
//Alternate between hide and show when button is clicked
-(IBAction)showTextBar
{
if(textview.hidden)
{
[textView setHidden:False];
}
else
{
[textView setHidden:True];
}
}
I've got a view containing subviews of various types on it. At one point, I would like to disable all interactions with the view and subviews, and register instead taps from a gesture recognizer I place on the whole view:
tapGestureRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:revealController action:#selectorrdoSomething:)];
tapGestureRecognizer.cancelsTouchesInView = YES;
While it sort of works, the view below still interacts to all the touches. I then tried adding:
tapGestureRecognizer.delaysTouchesBegan = YES;
tapGestureRecognizer.delaysTouchesEnded = YES;
It now works EXCEPT - when I tap over a UITextField, this receives the touch INSTEAD of the gesture recognizer. Why is this, how can I stop it? Any help is much appreciated :)
Sounds like what you want to do is set the view you don't want receiving the touches .userInteractionEnabled property to FALSE. Or I am misunderstanding something.
yourView.userInteractionEnabled = FALSE;
In My view there is reset button .i need userinteraction disabled except for that button .how can i do that can any one share the code.thanks in advance?
btn1 is your button, self.view - your view
for (UIView *view in self.view.subviews)
view.userInteractionEnabled=NO;
btn1.userInteractionEnabled=YES;
For all the elements there is a property userinteractionenabled. Set it to false
yourelement.userInteractionEnabled = NO;
Also place your UIButton on top of your view hierachy.
Other option is to place a tranparent UIButton on your entire view and your UIButton on top of this view. This way only your UIButton is touch enalbed. Other touches would be taken in by the transparent button which does nothing.
Sligthly better approach, define a "magic value" that will help you :
#define kDontDisableUserInteraction 3928473
then set this value as the tag of your button you don't want disabled:
[resetButton setTag:kDontDisableUserInteraction];
you can now create a function in your superview's class :
- (void)setInterfaceEnabled:(BOOL)newEnabled {
for (UIView *subview in self.subviews) {
if (subView.tag != kDontDisableUserInteraction)
continue;
subView.userInteractionEnabled = newEnabled;
}
}
That allows you to create other non-disableable buttons simply by giving them the right tag (which can be whatever int value you want, not only 3928473, depends on your #define).
I have many UIButtons within a UIScrollView. Those UIButtons have actions attached to them in Touch Down Repeat. My problem is my scroll view doesn't scroll when I touch a button then scroll, but it works fine if I touch outside of the button.
How can I allow my scroll view to scroll even though a button is pressed?
As long as you have the Cancellable Content Touches in Interface Builder set it should work. You can also set it in code:
scrollView.canCancelContentTouches = YES;
So view.canCancelContentTouches = YES works OK if you don't also have delaysContentTouches set to YES. If you do though, the buttons won't work at all. What you need to do is subclass the UIScrollView (or UICollectionView/UITableView) and implement the following:
Objective-C
- (BOOL)touchesShouldCancelInContentView:(UIView *)view {
if ([view isKindOfClass:UIButton.class]) {
return YES;
}
return [super touchesShouldCancelInContentView:view];
}
Swift 2
override func touchesShouldCancelInContentView(view: UIView) -> Bool {
if view is UIButton {
return true
}
return super.touchesShouldCancelInContentView(view)
}
Use a UITapGestureRecognizer with delaysTouchesBegan as a property set to true.