Here's my problem. Suppose I have a table called persons containing, among other things, fields for the person's name and national identification number, with the latter being optional. There can be multiple rows for each actual person.
Now suppose I want to select exactly one row for each actual person. For the purposes of the application, two rows are considered to refer to the same person if a) their ID numbers match, or b) their names match and the ID number of one or both is NULL. SELECT DISTINCT is no good here: I cannot do a DISTINCT ON (name, id) because then two rows with the same name where the ID of one is NULL wouldn't match (which is incorrect, they should be considered the same). I cannot do a DISTINCT ON (name) because then rows with the same name but different IDs would match (again incorrect, they should be considered different). And I cannot do a DISTINCT ON (id) because then all the rows where ID is NULL would be considered the same (obviously incorrect).
Is there any way to redefine the way PostgreSQL compares rows to determine whether or not they're identical? I guess the default behaviour for DISTINCT ON (name, id) would be something like IF a.name = b.name AND a.id = b.id THEN IDENTICAL ELSE DISTINCT. I'd like to redefine it to something like IF a.id = b.id OR (a.name = b.name AND (a.id IS NULL OR b.id IS NULL)) THEN IDENTICAL ELSE DISTINCT.
It's pretty late and I might have missed something obvious, so other suggestions on how to achieve what I want would also be welcome. Anything to enable me to select distinct rows based on more complex criteria than a simple list of columns. Thanks in advance.
With Window Functions
--
-- First, SELECT those names with NULL national IDs not shadowed by the same
-- name with a national ID. Each one is a unique person.
--
SELECT name, id
FROM persons
WHERE NOT EXISTS (SELECT 1
FROM persons p
WHERE p.name = persons.name AND p.id IS NOT NULL)
--
-- Second, collapse each national ID into the "first" row with that ID,
-- whatever the name. Each ID is a unique person.
--
UNION ALL
SELECT name, id
FROM (SELECT name, id, ROW_NUMBER() OVER (PARTITION BY id)
FROM persons
WHERE id IS NOT NULL) d
WHERE d.row_number = 1;
Without Window Functions
Replace the above UNION with a GROUP BY the first (MIN()) name for each non-NULL id:
...
UNION ALL
SELECT MIN(name) AS name, id
FROM persons
WHERE id IS NOT NULL
GROUP BY id
It seems like the main problem is the layout of your database. I don't know the details of your specific application, but having multiple rows and null IDs for the same person is usually a bad idea. If possible you may want to consider creating a separate table for any of the information that requires multiple rows, with persons only containing one row per person and a unique identifier for each row.
But, if you can't do that... I don't think just a distinct is going to solve this problem.
What's the problem with:
select distinct name, id
from persons
where id is not null
Do you have some persons that have a name, but not an ID? Or do you need some specific data from the other rows?
Here's another problem: if there are two rows with the same name and null IDs, and multiple people with the same name and different IDs, how do you know which person the null rows match?
Related
I have a table in which objects have ids and they have names. The ids are correct by definition, the names are almost always correct, but sometimes dirty incoming data causes names to be null or even wrong.
So I do a query like
SELECT id, name, AGGR1(a) as a, AGGR2(b) as b, AGGR3(c) as c
FROM my_table
WHERE d = 3
GROUP BY id
I'd like to have name in the results, but of course the above is wrong. I'd have to group on id, name, in which case what should be one row sometimes becomes more than one -- say, id 2 has names 'John' (correct), 'Jon' (no, but only 1%), or NULL (also a small fraction).
Is there a construct or idiom in postgresql that lets me select what a human looking at the list would say is obviously the consensus name?
(I hear our postgres installation is finally being upgraded soon, if that matters here.)
sample output, in case prose wasn't clear
SELECT id, name, COUNT(id) as c
FROM my_table
WHERE d = 3
GROUP BY id
id name c
2 John 2000
2 Jon 3
2 (NULL) 5
vs
id name c
2 John 2008
You can get the names with
WITH names as (
SELECT
id,
name,
ROW_NUMBER() OVER (PARTITION BY id ORDER BY COUNT(1) DESC) as rn
FROM my_table
GROUP BY id, name
)
SELECT id, name
FROM names
WHERE rn=1;
and then do your calculations by id only, joining names from this query.
This might be partly a design question (new to PostgreSQL) as well.
I have three tables - Users, Groups and User_Group. User_Group represents a combination of 1 user_id being linked to 0..X Group IDs.
The tables are as simple as you think (for now, building out this thing):
User: ID, Name, ....
Group: ID, Name, ...
User_Group: UserID, GroupID int[], ...
So right now, the GroupID field in User_Group is an Integer array. UserID 1 has a value of {1,2,10,19,28} for example.
Goal:
In my UI, I need to represent that list as the group names (ie: {Group1, Group2, Group10, Group19, Group28}).
So, because I am new to PostgreSQL, I'm researching and a couple ideas pop into my mind - unnest, ANY and array replacement. All scream performance issues to me, but I might be wrong (this is the design question, is it smart to store array?)
My query right now:
select
u.*,
g.group_ids
from users u
left join user_group g
on u.id = g.user_id
Piece I'm trying to figure out how to push into:
select ug.group_id
from (select unnest(group_ids) group_id FROM user_group) as ug
left join groups g
on g.id = ug.group_id
This will just result in (obviously) an additional row for each group ID the person is associated with.
Which is the best way to do this?
( Personally I would have a column on Users table as Groups (int array) but your choice is fine too).
It would look like (I used table and field names off the top of my head, slightly modified than yours):
select u.*, g.Name as GroupName
from users u
left join usergroups ug on ug.UserId = u.UserId
left join groups g on g.groupId = ANY( ug.groups );
Update: I might have misunderstood your need. Maybe you meant this:
select u.*,
(select string_agg(g.name,',')
from groups g
inner join usergroups ug on ug.groupId = g.GroupId
where ug.UserId = u.UserID and
g.groupId = ANY( ug.groups )) as Groups
from users u;
There, you have a one-to-many relationship:
User (1)->(*) Groups
This kind of relation doesn't need an intermediary table for the link definition. The one-to-many relation use to have a foreign key in the child table (in this case is Groups).
The result will be:
User: id, name
Group: id, name, user_id
And you can add a constraint to the database as: ALTER TABLE user ADD CONSTRAINT fk_user FOREIGN KEY (user_id) REFERENCES group;
I have a lookup table for institution id, name, address and another table for course details.
In each course record there will be two columns pointing primary and secondary institution ids.
My select query should look like ->
Select course_id,
name,
primary_Institution_id,
Primary_Institution_name,
primary_Institution_address,
Secondary _Institution_id,
Secondary _Institution_name,
Secondary_Institution_address
from [JOIN MAY BE]
where course_id in ('1223','34234','43432')
How to achieve this? I have no control over the tables and I can only select from them and cannot modify their structure.
If you are trying to ask how to do the join, it might look something like this
Select c.course_id,
c.name,
c.primary_Institution_id,
i.name as primary_Institution_name,
i.address as primary_Institution_address
c.secondary_Institution_id
k.name as Secondary _Institution_name,
k.address as Secondary_Institution_address
from courses as c
join institutions as i
on i.id = c.primary_Institution_id
left
join institutions as k
on i.id = c.secondary_Institution_id
where course_id in ('1223','34234','43432')
This assumes that the first institution id is mandatory (never null) so the join is implied as an inner join, but that perhaps the second might be optional (null allowed) so it uses a left join, in case there is nothing to match to.
It's possible I'm stupid, but I've been querying and checking for hours and I can't seem to find the answer to this, so I apologize in advance if the post is redundant... but I can't seem to find its doppelganger.
OK: I have a PostGreSQL db with the following tables:
Key(containing two fields in which I'm interested, ID and Name)
and a second table, Key.
Data contains well... data, sorted by ID. ID is unique, but each Name has multiple ID's. E.G. if Bill enters the building this is ID 1 for Bill. Mary enters the building, ID 2 for Mary, Bill re-enters the building, ID 3 for Bill.
The ID field is in both the Key table, and the DATA table.
What I want to do is... find
The MAX (e.g. last) ID, unique to EACH NAME, and the Data associated with it.
E.g. Bill - Last Login: ID 10. Time: 123UTC Door: West and so on.
So... I'm trying the following query:
SELECT
*
FROM
Data, Key
WHERE
Key.ID = (
SELECT
MAX (ID)
FROM
Key
GROUP BY ID
)
Here's the kicker, there's about... something like 800M items in these tables, so errors are... time consuming. Can anyone help to see if this query is gonna do what I expect?
Thanks so much.
To get the maximum key for each name . . .
select Name, max(ID) as max_id
from data
group by Name;
Join that to your other table.
select *
from key t1
inner join (select Name, max(ID) as max_id
from data
group by Name) t2
on t1.id = t2.max_id
(I don't think I have titled this question correctly - but I don't know how to describe it)
Here is what I am trying to do:
Let's say I have a Person table that has a PersonID field. And let's say that a Person can belong to many Groups. So there is a Group table with a GroupID field and a GroupMembership table that is a many-to-many join between the two tables and the GroupMembership table has a PersonID field and a GroupID field. So far, it is a simple many to many join.
Given a list of GroupIDs I would like to be able to write a query that returns all of the people that are in ALL of those groups (not any one of those groups). And the query should be able to handle any number of GroupIDs. I would like to avoid dynamic SQL.
Is there some simple way of doing this that I am missing?
Thanks,
Corey
select person_id, count(*) from groupmembership
where group_id in ([your list of group ids])
group by person_id
having count(*) = [size of your list of group ids]
Edited: thank you dotjoe!
Basically you are looking for Persons for whom there is no group he is not a member of, so
select *
from Person p
where not exists (
select 1
from Group g
where not exists (
select 1
from GroupMembership gm
where gm.PersonID = p.ID
and gm.GroupID = g.ID
)
)
You're basically not going to avoid "dynamic" SQL in the sense of dynamically generating the query at query time. There's no way to hand a list around in SQL (well, there is, table variables, but getting them into the system from C# is either impossible (2005 & below) or else annoying (2008)).
One way that you could do it with multiple queries is to insert your list into a work table (probably a process-keyed table) and join against that table. The only other option would be to use a dynamic query such as the ones specified by Jonathan and hongliang.