I'm trying to get the option item selected in a form select element using Codeigniter...
I have a controller named results with this code in it
//get form data
if($_SERVER['REQUEST_METHOD'] == "POST"){
$data['searchdata'] = array(
"ionum" => $this->input->post('ionum'),
"thisdb" => $this->input->post('thisdb')
);
}
which loads into a view, the 'ionum' is a text input which I can retrieve, the 'thisdb' is the select, I get no results for it...how do I pull that?
Ensure your html looks like:
<form action="<?= site_url('mycontroller/myfunction');?>" method='post'>
<input type='text' name='ionum'/>
<select name='thisdb'>
<option value='db1'>DB1</option>
<option value='db2'>DB2</option>
</select>
</form>
Then in your controller, you would write:
class Mycontroller extends CI_Controller{
function myfunction(){
$p = $this->input->post();
if($p){
//you can now access the ionum and thisdb... try echo
echo $p['ionum'];
echo $p['thisdb'];
}
}
}
It is unnecessary to run the if($_SERVER['REQUEST_METHOD'] == "POST") conditional. Just check if $p exists as above.
Related
In Codeigniter, the following code is typically used for a page that has a form. But the first time a user lands on the page and a form validation fails gets routed through the same path.
As this example shows, the flash data will trigger. even if the user just land on the page and have not submit any form yet.
I am trying to echo a new class name to some input field to highlight them if validation fails. but currently it highlights the field on first load as well.
I am aware I can echo a validation_error or form_error. is there a way to echo a generic message that is not tied to a field-name and only after submission fails
// rules and other stuff above
if ($this->form_validation->run() == FALSE){
$this->session->set_flashdata('errorClass',"is-invalid");
$this->load->view('defaultOrFalse');
}else{
$this->load->view('success');
}
//view file
<input class=" <?php $this->session->flashdata('errorClass') ; ?>">
Basically I am trying to get bootstrap 4's input validation to show up
https://getbootstrap.com/docs/4.0/components/forms/#server-side
I don't know your exact setup but you can do logic like the following:
<?php
class Some_controller extends CI_Controller {
// controller/search/{$term}
public function some_method($term = null) {
// where some_field is some field in your form
// that gets posted on submit
if ($this->input->post('some_field')) {
// or if (isset($_POST)) {
if ($this->form_validation->run() == FALSE) {
$this->session->set_flashdata('errorClass', "is-invalid");
$this->load->view('defaultOrFalse');
} else {
$this->load->view('success');
}
} else {
// default view
}
}
}
?>
For your second question:
<h5>Username</h5>
<?php echo form_error('username'); ?>
<input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" <?php if (!empty(form_error('username'))) { echo "class='error'"; } ?> />
Can also make a helper and use instead of form_error to check if field has error for your class (haven't verified this works but it should).
/**
* Checks if form validation field by name
* has error
*
* #param string $field Name of field
* #return boolean
*/
function field_has_error($field) {
$CI = &get_instance();
$CI->load->library('form_validation');
$arr = $CI->form_validation->error_array();
if (isset($arr[$field])) {
return true;
}
return false;
}
Usage:
<?php if (field_has_error('username')) { echo "class='error'"; } ?> />
I am creating a form using Phalcon that has a checkbox on it. I use this code to create the checkbox in my PagesForm.php file
$this->add(new Check('usesLayout'));
and then in my view I have
{{ form.render("usesLayout") }}
However, if the checkbox is unchecked then Phalcon complains about usesLayout is required.
The html code produced by the view is
<input type="checkbox" id="usesLayout" name="usesLayout" value="1" checked="checked" />
What is the correct way to create a Phalcon form with a checkbox so that it accepts it both checked and unchecked?
Desired outcome
After looking back at a form made when using CakePHP the html output is
<input type="hidden" name="usesLayout" id="usesLayout_" value="0" />
<input type="checkbox" name="usesLayout" id="usesLayout" value="1" checked="checked" />
This works fine, so I am looking for something similar to this.
Current Workaround
After modifying the code in the final response to this question I have this workaround currently (I use this instead of Phalcon\Forms\Element\Check)
namespace Armaware\InBrowserDev\Forms\Element;
use Phalcon\Forms\Element\Check as PhalconCheck;
class Check extends PhalconCheck
{
/**
* Renders the element widget returning html
*
* #param array|null $attributes Element attributes
*
* #return string
*/
public function render($attributes = null)
{
$attrs = array();
if (!is_null($attributes)) {
foreach ($attributes as $attrName => $attrVal) {
if (is_numeric($attrName) || in_array($attrName, array('id', 'name', 'placeholder'))) {
continue;
}
$attrs[] = $attrName .'="'. $attrVal .'"';
}
}
$attrs = ' '. implode(' ', $attrs);
$id = $this->getAttribute('id', $this->getName());
$name = $this->getName();
$checked = '';
if ($this->getValue()) {
$checked = ' checked';
}
return <<<HTML
<input type="hidden" id="{$id}_" name="{$name}" value="0" />
<input type="checkbox" id="{$id}" name="{$name}" value="1"{$attrs}{$checked} />
HTML;
}
}
public Phalcon\Forms\ElementInterface setDefault (unknown $value) inherited from Phalcon\Forms\Element
Sets a default value in case the form does not use an entity or there is no value available for the element in _POST
Source.
Looks like your declaration of form can look like this:
$controls[] = (new Check('usesLayout', ['value' => '1']))
->setLabel('Should I use layout?')
->setDefault('0') // or `false` in case it's not filtered
->addFilter('bool'); // filtering to boolean value
Not tested, but probably will do. You can always try to make this trick with handling this in beforeValidation() method of form, but have no space to test it right now and am not risking on failurable solution here.
Somewhat new to Laravel(4.2) and I'm having issues with pagination on my search function. So far I've been able to successfully carry out a search, though in the rare cases it actually goes over onto a second page it resets to simply "?page=2"
Below is the code for the form.
{{ Form::open(array('method' => 'post', 'name' => 'all', 'novalidate' => 'novalidate')) }}
<input type="text" name="srch_lname" class="input-large" value="{{ Input::old('srch_lname', Session::get('srch_lname')) }}" />
<input type="text" name="srch_fname" class="input-large" value="{{ Input::old('srch_fname', Session::get('srch_fname')) }}" />
.
.
.
<?php echo $employees->links(); ?>
And the controller handling the search.
public function getIndex() {
$srch_lname = Session::get('srch_lname');
$srch_fname = Session::get('srch_fname');
$employees = vEmployees::co()->restrictions()
->where('lastname', 'LIKE', $srch_lname . '%')
->where('firstname', 'LIKE', $srch_fname . '%')
->orderBy('lastname')
->orderBy('firstname')
->paginate(10);
return View::make('index')
->with('employees', $employees)
->with('title', 'Users')
->with('pagetitle', 'Employees')
->with('pagedescription', '')
}
public function postIndex() {
if (Input::has('btnSearch')) {
return Redirect::to('/employees')->with('search', 1)
->with('srch_lname', Input::get('srch_lname'))
->with('srch_fname', Input::get('srch_fname'))
I've been trying some other solutions found throughout SO though it either ends up causing issues or bringing me back to the same problem.
Any sort of push in the right direction would be awesome!
Append the search data to the pagination links()
<?php echo $employees->appends(array("srch_lname" => ...))->links(); ?>
http://laravel.com/docs/4.2/pagination#appending-to-pagination-links
I have have a view in which there's a form that manages products (either add new product or -if an id passed- editing an existing one). If an id is passed then the form action should be eg 'admin/product/manage/5', if no id passed then it should be like this 'admin/product/manage'.
<?php echo form_open('admin/product/manage/{optional product id}', array('class' => 'ajax-form')); ?>
I have also created and this route:
$route['admin/product/manage'] = "admin/product/manage";
$route['admin/product/manage/(:num)'] = "admin/product/manage/$1";
How can I make my form action work correctly? is it possible to put inside the action the route somehow??
This is my Controller:
public function manage($id = NULL){
//fetch a single product to edit or create a new one
if (isset($id) === true) {
$data['prod'] = $this->product_model->get($id);
$data['vers'] = $this->product_version_model->get_by('product_id',$id);
} else {
$data['prod'] = $this->product_model->make_new();// this returns $product->product_name = ''; in order to be empty the input field and not throughing errors
}
$this->product_model->save_product();
$this->product_version_model->save_version();
// load the view
$this->layout->view('admin/products/manage', $data);
}
This is my view:
<?php echo form_open('admin/product/manage', array('class' => 'ajax-form')); ?>
<p>
<label for="product_name">Product *</label>
<input type="text" name="product_name" value="<?php echo set_value('product_name', $prod->product_name); ?>" />
<?php echo form_error('product_name'); ?>
</p>
<?php echo form_close() . PHP_EOL; ?>
You need to declare both possible routes in order of importance, so:
$route['admin/product'] = "admin/product/manage";
$route['admin/product/(:num)'] = "admin/product/manage/$1";
From the Codeigniter Docs:
Routes will run in the order they are defined. Higher routes will always take precedence over lower ones.
Edit:
According to the changes you have made to your question I can say the following:
First of all isset() returns boolean only, so you don't need the type check "=== true". isset($id) is sufficient.
In order to have your form action set to the id you need to include it either in a hidden field or in the action itself.
So for example:
$action_id = (isset($id) ? '/'.$id : ''); // Using ternary operators here
echo form_open('admin/product/manage'.$action_id, array('class' => 'ajax-form'));
and add the id to the view data in your controller:
$data['id'] = $id;
As a side note: In order to comply with SoC (Separation of Concerns) you'd prepare all data in your controller (with e.g. models all having their own task) and pass the processed data to the view instead of partially generating data in the view itself.
I am trying to add some form to my component, but I am not shure what naming conventions must be applied to work it correctly.
Currently I have a working form - it displays fields stored in XML file and loads data from database to it. However, when i try to submit this form (edit or add new records), it doesn't work. After pressing submit (save() method) it just redirects me and displays that record was edited successfuly but it wasn't. When I try to edit existing record, after pressing submit nothing happens and when I try to add new record, it just adds empty/blank record.
So I was doing a little debug and discovered, that problem is in the JController::checkEditId() method. It always returns false which means that JControllerForm::save() returns false as well and that's why it doesn't save it correctly. HTML code of form is correct and I can access the data by using global array $_POST.
I suspect that this problem is because of naming conventions in methods loadFormData, getForm of JModelAdmin class. I am not sure how to name that form.
So here is my code related to this problem:
Subcontroller for displaying the form - controllers/slideshowform.php
class SlideshowModelSlideshowForm extends JModelAdmin{
public function getForm($data = array(), $loadData = true){
return $this->loadForm('com_slideshow.slideshowform', 'editform', array('load_data' => $loadData, 'control' => 'jform'));
}
protected function loadFormData(){
$data = JFactory::getApplication()->getUserState('com_slideshow.edit.slideshowform.data', array());
if (empty($data))
{
$data = $this->getItem();
}
return $data;
}
public function getTable($table = "biometricslideshow"){
return parent::getTable($table);
}
}
views/slideshowform/view.html.php
class SlideshowViewSlideshowForm extends JView{
public function display($tmpl = null){
if (count($errors = $this->get('Errors')))
{
JError::raiseError(500, implode('<br />', $errors));
return false;
}
$this->form = $this->get('form');
$this->item = $this->get('item');
JToolBarHelper::save('slideshowform.save');
parent::display();
}
}
views/slideshowform/tmpl/default.php
<?php
defined('_JEXEC') or die('Restricted access');
JHtml::_('behavior.tooltip');
?>
<form method="post" action="<?php echo JRoute::_("index.php?option=com_slideshow&id=".(int) $this->item->id)?>" name="adminForm" id="slideshow-form">
<fieldset class="adminform">
<legend>Edit slide</legend>
<table>
<input type="hidden" name="task" value="">
<?php echo JHtml::_('form.token'); ?>
<?php
foreach($this->form->getFieldset() as $field){
?>
<tr><td><?php echo $field->label ?></td><td><?php echo $field->input ?></td></tr>
<?php
}
?>
</table>
</fieldset>
</form>
Can someone take o look, please?
you have to add controller SlideshowControllerSlideshowForm and code save method. In there you have to validate the form data and call SlideshowModelSlideshowForm->save event, then redirect with success/failure message.