Is it possible to get the values of just rows 10 through 20? If so how?
If you're using SQL Server 2005 or greater, check out the ROW_NUMBER function: http://msdn.microsoft.com/en-us/library/ms186734.aspx
One way is to do something like the following...
SELECT * FROM (
SELECT TOP x * FROM (
SELECT TOP y fields
FROM table
WHERE conditions
ORDER BY table.field ASC) as foo
ORDER by field DESC) as bar
ORDER by field ASC
x is the number of rows you want returned and y is x+offset.
http://josephlindsay.com/archives/2005/05/27/paging-results-in-ms-sql-server/
Hey, by the asnwer of joelt about row_number(). I did it.
Its like this:
SELECT allianceId, position, points from (select ROW_NUMBER() over (Order by Points DESC) as position, points, allianceId from Alliance) as somethingx where position >= #alliancePosition - 5 and position <= #alliancePosition + 5;
Related
I have a query. this query is calculated percentage for every product. I created a virtual column on this query this columns name is 'yüzde'. After that, i want to transfer yüzde columns to another column in another table with update query if product ids are same.
I think I need to write a stored procedure. How can I do that?
SELECT [ProductVariantId] ,
count([ProductVariantId]) as bedensayısı,
count([ProductVariantId]) * 100.0 / (SELECT Top 1 Count(*) as Total
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
Group by [ProductVariantId]
order by Total Desc) as yüzde
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
group by [ProductVariantId]
order by yüzde desc
you don't really need a SP, you can do it in-line, using CTE for instance, something along these lines:
; with tabyuzde as
(
SELECT [ProductVariantId] ,
count([ProductVariantId]) as bedensayısı,
count([ProductVariantId]) * 100.0 / (SELECT Top 1 Count(*) as Total
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
Group by [ProductVariantId]
order by Total Desc) as yüzde
FROM [Live_ADL].[dbo].[_INV_ProductCombinationAttributes]
Where Size LIKE '%[^0-9]%' and [StockQuantity]>0
group by [ProductVariantId]
)
update x
set othertablevalue=yüzde
from
othertable x
join tabyuzde t on x.ProductVariantId=t.ProductVariantId
I have a table named raw_data with the following data
as You can see id 1 and 2 share the same values in field desa, kecamatan and kabupaten, also id 3,4,5.
So basically I want to select all rows that is not followed by the same previous values. expected result would be:
I know it's easy to do this in any programming languages such as PHP, but I need this in postgresql. is this doable? Thanks in Advance.
Assuming higher id denotes latest row, if a row with same all three columns is present not together and you don't want to filter it out as it doesn't have same values as previous row (order by id or created_date), then you can make use of analytic lag() function:
select *
from (
select
t.*,
case
when desa = lag(desa) over (order by id)
and kecamatan = lag(kecamatan) over (order by id)
and kabupaten = lag(kabupaten) over (order by id)
then 0 else 1
end flag
from your_table t
) t where flag = 1;
I'm currently doing this group by to retrieve the max date :
SELECT A, MAX(B) FROM X GROUP BY A
This is perfectly working. However, when I try to retrieve the second highest value, I'm totally lost.
If anyone has an idea...
Try this:
SELECT X.A,
MAX(X.B)
FROM YourTable X
JOIN
(
SELECT
X1.A,
MAX(X1.B)
FROM YourTable X1
GROUP BY X1.A
) X1 ON X1.A = X.A
AND X.B < X1.B
GROUP BY X.A
Basically this says get the max of all the ones that are less than the max.
You can use the ranking function ROW_NUMBER in a cte:
WITH CTE AS
(
SELECT A,
MaxB = MAX(B)OVER(PARTITION BY A),
RN = ROW_NUMBER() OVER (PARTITION BY A ORDER By B DESC)
FROM dbo.X
)
SELECT A, MaxB
FROM CTE
WHERE RN <= 2
This will return the two highest values for each group (if that is what you want).
You're columns are rather ambiguous, but if A is max_date then, B is some other value you wish to sort by, then one way to do it could be:
SELECT A FROM X ORDER BY B DESC LIMIT 2
Which will give you 2 rows with the second highest displayed first.
I am wondering if there is some easy way, a function, or other method to return data from a query with the following results.
I have a SQL Express DB 2008 R2, a table that contains numerical data in a given column, say col T.
I am given a value X in code and would like to return up to three records. The record where col T equals my value X, and the record before and after, and nothing else. The sort is done on col T. The record before may be beginning of file and therefore not exist, likewise, if X equals the last record then the record after would be non existent, end of file/table.
The value of X may not exist in the table.
This I think is similar to get a range of results in numerical order.
Any help or direction in solving this would be greatly appreciated.
Thanks again,
It might not be the most optimal solution, but:
SELECT T
FROM theTable
WHERE T = X
UNION ALL
SELECT *
FROM
(
SELECT TOP 1 T
FROM theTable
WHERE T > X
ORDER BY T
) blah
UNION ALL
SELECT *
FROM
(
SELECT TOP 1 T
FROM theTable
WHERE T < X
ORDER BY T DESC
) blah2
DECLARE #x int = 100
;WITH t as
(
select ROW_NUMBER() OVER (ORDER BY T ASC) AS row_nm,*
from YourTable
)
, t1 as
(
select *
from t
WHERE T = #x
)
select *
from t
CROSS APPLY t1
WHERE t.row_nm BETWEEN t1.row_nm -1 and t1.row_nm + 1
Imagine a table with [ID, Name, Position, Price]
Currently the table has ALL the records with Position=0 and each record has a different price value.
What is the quickest way to update that Position and set its value unique and based on the Price, where the record with the lowest price is Position=1, the second lowest is Position=2 ...and so on?
thanks in advanced.
You could use row_number to number rows. A subquery is required to refer to the row number by alias:
update yt
set Position = rn
from (
select row_number() over (order by Price desc) as rn
, *
from YourTable
) yt
Working example at SE Data.