UIButton in UIView in UITableView = can't click the button - iphone

Question

If I add the button straight everything goes fine. I'd really like to add it inside a view and still be able to click it. Here's the code:
UIView *containerView =
[[[UIView alloc]
initWithFrame:CGRectMake(0, 0, 300, 60)]
autorelease];
UIButton *footerButton = [UIButton buttonWithType:UIButtonTypeCustom];
footerButton.frame = CGRectMake(10, 10, 300, 40);
[footerButton addTarget:self action:#selector(click) forControlEvents:UIControlEventTouchUpInside];
[containerView addSubview:footerButton];

Answer 1

Did you set the footer height to the height of the view you are adding to it? I had a similar problem when I returned a UIView containing a UIButton in the method viewForFooterInSection. The footer height was not large enough until I updated the heightForFooterInSection method. For example:
- (CGFloat)tableView:(UITableView *)tableView heightForFooterInSection:(NSInteger)section
{
return containerView.bounds.size.height;
}

Answer 2

All works fine! In your TableViewController do:
- (void)viewDidLoad {
[super viewDidLoad];
UIView *containerView = [[[UIView alloc] initWithFrame:CGRectMake(0, 0, 300, 60)] autorelease];
UIButton *footerButton = [UIButton buttonWithType:UIButtonTypeCustom];
footerButton.frame = CGRectMake(10, 10, 300, 40);
[footerButton addTarget:self action:#selector(click) forControlEvents:UIControlEventTouchUpInside];
[containerView addSubview:footerButton];
[footerButton setTitle:#"Touch me!" forState:UIControlStateNormal];
containerView.backgroundColor = [UIColor colorWithWhite:0.5 alpha:0.5];
self.tableView.tableFooterView = containerView;
}
- (void)click {
NSLog(#"I am here!");
}

Answer 3

This #selector(click) looks a little odd. I would have thought your click function would like something like:
- (void)click:(id)sender;
If that's what you have then you need to add the colon #selector(click:) to make the signatures match.