stringByReplacingCharactersInRange don't replace It's Append ! - iphone

I Spent 5 hours try to figure a way for that..i'm trying to do a hangman app for iphone and the method below is the method that should be called when the player chooses a character and it match the chosen word..
-(void)replaceTheHiddenTextWithNewText:(NSString*)character{
NSString *fullTextField = fullText.text;
int textCount = [hiddenText.text length];
NSString *theRiddle;
for (int i = textCount-1 ; i>=0; i--) {
NSString *hiddenTextField = [[NSMutableString alloc] initWithString:hiddenText.text];
NSString *aChar=[fullTextField substringWithRange:NSMakeRange(i/3,1)];
if ([aChar isEqualToString:#" "]) {
theRiddle= [hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:#" "];
}else if ([aChar isEqualToString:character]) {
theRiddle =[hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:aChar];
}else{
theRiddle = [hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:#"_"];
}
hiddenTextField = theRiddle;
}
hiddenText.text=theRiddle;
}
the problem is stringByReplacingCharactersInRange doesn't replace the character, it appends it to the underscore what am I doing wrong here?
Best Regards,
M Hegab

Just played around with your code. It does not work, but stringByReplacingCharactersInRange is not your problem.
Your game logic doesn't work like it should. Get a pen and a sheet of paper and "manually" loop through your for loop to see that this must be wrong.
Next time, if you've stared at code for half an hour, take a pen. This will save you at least 4 hours :-)
There are some issues with your code. Assume Kartoffelkäfer is the word you are looking for, and the user enters the letter f.
for (int i = textCount-1 ; i>=0; i--) {
NSString *hiddenTextField = [[NSMutableString alloc] initWithString:hiddenText.text];
// you are creating this string in every loop from the text of a (I guess) UITextField.
// I don't know what the content of this text is but I guess it is suppossed to be `______________`
// in every loop you replace the word where you replaced the _ with the correct letter with the string from the textfield.
// Btw, you are leaking this string.
NSString *aChar=[fullTextField substringWithRange:NSMakeRange(i/3,1)];
// Kartoffelkäfer has 14 chars so i is 13. And 13/3 is 4. And the character at index 4 is o
// In the next loop i is 12. And 12/3 is 4, too.
// next three loops will give you index 3. Then you get three times index 2, and so one.
// you never reach the letter f, anyway.
if ([aChar isEqualToString:#" "]) {
theRiddle= [hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:#" "];
}else if ([aChar isEqualToString:character]) {
theRiddle =[hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:aChar];
}else{
theRiddle = [hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:#"_"];
// You should not replace a unmatched character with a _ . Because already matched letters would be overwritten.
}
hiddenTextField = theRiddle;
}
I assumed that the content of hiddenText.text is #"______"
and the content of fullText.text is #"Kartoffelkäfer". So hiddentext is the exact length as the fullText.
What I had to change to get this to work:
NSString *theRiddle;
NSString *hiddenTextField = [[[NSMutableString alloc] initWithString:hiddenText.text] autorelease];
for (int i = textCount-1 ; i>=0; i--) {
NSString *aChar=[fullTextField substringWithRange:NSMakeRange(i,1)];
if ([aChar isEqualToString:#" "]) {
theRiddle= [hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:#" "];
}else if ([aChar isEqualToString:character]) {
theRiddle =[hiddenTextField stringByReplacingCharactersInRange:NSMakeRange(i, 1) withString:aChar];
}
else {
theRiddle = hiddenTextField;
}
hiddenTextField = theRiddle;
}
hiddenText.text=theRiddle;
Far away from good code, but I tried to change your code as little as possible.

Related

Regex pattern and/or NSRegularExpression a bit too slow searching over very large file, can it be optimized?

In an iOS framework, I am searching through this 3.2 MB file for pronunciations: https://cmusphinx.svn.sourceforge.net/svnroot/cmusphinx/trunk/pocketsphinx/model/lm/en_US/cmu07a.dic
I am using NSRegularExpression to search for an arbitrary set of words that are given as an NSArray. The search is done through the contents of the large file as an NSString. I need to match any word that appears bracketed by a newline and a tab character, and then grab the whole line, for example if I have the word "monday" in my NSArray I want to match this line within the dictionary file:
monday M AH N D IY
This line starts with a newline, the string "monday" is followed by a tab character, and then the pronunciation follows. The entire line needs to be matched by the regex for its ultimate output. I also need to find alternate pronunciations of the words which are listed as follows:
monday(2) M AH N D EY
The alternative pronunciations always begin with (2) and can go as high as (5). So I also search for iterations of the word followed by parentheses containing a single number bracketed by a newline and a tab character.
I have a 100% working NSRegularExpression method as follows:
NSArray *array = [NSArray arrayWithObjects:#"friday",#"monday",#"saturday",#"sunday", #"thursday",#"tuesday",#"wednesday",nil]; // This array could contain any arbitrary words but they will always be in alphabetical order by the time they get here.
// Use this string to build up the pattern.
NSMutableString *mutablePatternString = [[NSMutableString alloc]initWithString:#"^("];
int firstRound = 0;
for(NSString *word in array) {
if(firstRound == 0) { // this is the first round
firstRound++;
} else { // After the first iteration we need an OR operator first.
[mutablePatternString appendString:[NSString stringWithFormat:#"|"]];
}
[mutablePatternString appendString:[NSString stringWithFormat:#"(%#(\\(.\\)|))",word]];
}
[mutablePatternString appendString:#")\\t.*$"];
// This results in this regex pattern:
// ^((change(\(.\)|))|(friday(\(.\)|))|(monday(\(.\)|))|(saturday(\(.\)|))|(sunday(\(.\)|))|(thursday(\(.\)|))|(tuesday(\(.\)|))|(wednesday(\(.\)|)))\t.*$
NSRegularExpression * regularExpression = [NSRegularExpression regularExpressionWithPattern:mutablePatternString
options:NSRegularExpressionAnchorsMatchLines
error:nil];
int rangeLocation = 0;
int rangeLength = [string length];
NSMutableArray * matches = [NSMutableArray array];
[regularExpression enumerateMatchesInString:string
options:0
range:NSMakeRange(rangeLocation, rangeLength)
usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop){
[matches addObject:[string substringWithRange:result.range]];
}];
[mutablePatternString release];
// matches array is returned to the caller.
My issue is that given the big text file, it isn't really fast enough on the iPhone. 8 words take 1.3 seconds on an iPhone 4, which is too long for the application. Given the following known factors:
• The 3.2 MB text file has the words to match listed in alphabetical order
• The array of arbitrary words to look up are always in alphabetical order when they get to this method
• Alternate pronunciations start with (2) in parens after the word, not (1)
• If there is no (2) there won't be a (3), (4) or more
• The presence of one alternative pronunciation is rare, occurring maybe 1 time in 8 on average. Further alternate pronunciations are even rarer.
Can this method be optimized, either by improving the regex or some aspect of the Objective-C? I'm assuming that NSRegularExpression is already optimized enough that it isn't going to be worthwhile trying to do it with a different Objective-C library or in C, but if I'm wrong here let me know. Otherwise, very grateful for any suggestions on improving the performance. I am hoping to make this generalized to any pronunciation file so I'm trying to stay away from solutions like calculating the alphabetical ranges ahead of time to do more constrained searches.
****EDIT****
Here are the timings on the iPhone 4 for all of the search-related answers given by August 16th 2012:
dasblinkenlight's create NSDictionary approach https://stackoverflow.com/a/11958852/119717: 5.259676 seconds
Ωmega's fastest regex at https://stackoverflow.com/a/11957535/119717: 0.609593 seconds
dasblinkenlight's multiple NSRegularExpression approach at https://stackoverflow.com/a/11969602/119717: 1.255130 seconds
my first hybrid approach at https://stackoverflow.com/a/11970549/119717: 0.372215 seconds
my second hybrid approach at https://stackoverflow.com/a/11970549/119717: 0.337549 seconds
The best time so far is the second version of my answer. I can't mark any of the answers best, since all of the search-related answers informed the approach that I took in my version so they are all very helpful and mine is just based on the others. I learned a lot and my method ended up a quarter of the original time so this was enormously helpful, thank you dasblinkenlight and Ωmega for talking it through with me.
Since you are putting the entire file into memory anyway, you might as well represent it as a structure that is easy to search:
Create a mutable NSDictionary words, with NSString keys and NSMutableArray values
Read the file into memory
Go through the string representing the file line-by-line
For each line, separate out the word part by searching for a '(' or a '\t' character
Get a sub-string for the word (from zero to the index of the '(' or '\t' minus one); this is your key.
Check if the words contains your key; if it does not, add new NSMutableArray
Add line to the NSMutableArray that you found/created at the specific key
Once your are finished, throw away the original string representing the file.
With this structure in hand, you should be able to do your searches in time that no regex engine would be able to match, because you replaced a full-text scan, which is linear, with a hash look-up, which is constant-time.
** EDIT: ** I checked the relative speed of this solution vs. regex, it is about 60 times faster on a simulator. This is not at all surprising, because the odds are stacked heavily against the regex-based solution.
Reading the file:
NSBundle *bdl = [NSBundle bundleWithIdentifier:#"com.poof-poof.TestAnim"];
NSString *path = [NSString stringWithFormat:#"%#/words_pron.dic", [bdl bundlePath]];
data = [NSString stringWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];
NSMutableDictionary *tmp = [NSMutableDictionary dictionary];
NSUInteger pos = 0;
NSMutableCharacterSet *terminator = [NSMutableCharacterSet characterSetWithCharactersInString:#"\t("];
while (pos != data.length) {
NSRange remaining = NSMakeRange(pos, data.length-pos);
NSRange next = [data
rangeOfCharacterFromSet:[NSCharacterSet newlineCharacterSet]
options:NSLiteralSearch
range:remaining
];
if (next.location != NSNotFound) {
next.length = next.location - pos;
next.location = pos;
} else {
next = remaining;
}
pos += (next.length+1);
NSString *line = [data substringWithRange:next];
NSRange keyRange = [line rangeOfCharacterFromSet:terminator];
keyRange.length = keyRange.location;
keyRange.location = 0;
NSString *key = [line substringWithRange:keyRange];
NSMutableArray *array = [tmp objectForKey:key];
if (!array) {
array = [NSMutableArray array];
[tmp setObject:array forKey:key];
}
[array addObject:line];
}
dict = tmp; // dict is your NSMutableDictionary ivar
Searching:
NSArray *keys = [NSArray arrayWithObjects:#"sunday", #"monday", #"tuesday", #"wednesday", #"thursday", #"friday", #"saturday", nil];
NSMutableArray *all = [NSMutableArray array];
NSLog(#"Starting...");
for (NSString *key in keys) {
for (NSString *s in [dict objectForKey:key]) {
[all addObject:s];
}
}
NSLog(#"Done! %u", all.count);
Try this one:
^(?:change|monday|tuesday|wednesday|thursday|friday|saturday|sunday)(?:\([2-5]\))?\t.*$
and also this one (using positive lookahead with list of possible first letters):
^(?=[cmtwfs])(?:change|monday|tuesday|wednesday|thursday|friday|saturday|sunday)(?:\([2-5]\))?\t.*$
and at the end, a version with some optimization:
^(?=[cmtwfs])(?:change|monday|t(?:uesday|hursday)|wednesday|friday|s(?:aturday|unday))(?:\([2-5]\))?\t.*$
Here is my hybrid approach of dasblinkenlight's and Ωmega's answers, which I thought I should add as an answer as well at this point. It uses dasblinkenlight's method of doing a forward search through the string and then performs the full regex on a small range in the event of a hit, so it exploits the fact that the dictionary and words to look up are both in alphabetical order and benefits from the optimized regex. Wish I had two best answer checks to give out! This gives the correct results and takes about half of the time of the pure regex approach on the Simulator (I have to test on the device later to see what the time comparison is on the iPhone 4 which is the reference device):
NSMutableArray *mutableArrayOfWordsToMatch = [[NSMutableArray alloc] initWithArray:array];
NSMutableArray *mutableArrayOfUnfoundWords = [[NSMutableArray alloc] init]; // I also need to know the unfound words.
NSUInteger pos = 0;
NSMutableString *mutablePatternString = [[NSMutableString alloc]initWithString:#"^(?:"];
int firstRound = 0;
for(NSString *word in array) {
if(firstRound == 0) { // this is the first round
firstRound++;
} else { // this is all later rounds
[mutablePatternString appendString:[NSString stringWithFormat:#"|"]];
}
[mutablePatternString appendString:[NSString stringWithFormat:#"%#",word]];
}
[mutablePatternString appendString:#")(?:\\([2-5]\\))?\t.*$"];
// This creates a string that reads "^(?:change|friday|model|monday|quidnunc|saturday|sunday|thursday|tuesday|wednesday)(?:\([2-5]\))?\t.*$"
// We don't want to instantiate the NSRegularExpression in the loop so let's use a pattern that matches everything we're interested in.
NSRegularExpression * regularExpression = [NSRegularExpression regularExpressionWithPattern:mutablePatternString
options:NSRegularExpressionAnchorsMatchLines
error:nil];
NSMutableArray * matches = [NSMutableArray array];
while (pos != data.length) {
if([mutableArrayOfWordsToMatch count] <= 0) { // If we're at the top of the loop without any more words, stop.
break;
}
NSRange remaining = NSMakeRange(pos, data.length-pos);
NSRange next = [data
rangeOfString:[NSString stringWithFormat:#"\n%#\t",[mutableArrayOfWordsToMatch objectAtIndex:0]]
options:NSLiteralSearch
range:remaining
]; // Just search for the first pronunciation.
if (next.location != NSNotFound) {
// If we find the first pronunciation, run the whole regex on a range of {position, 500} only.
int rangeLocation = next.location;
int searchPadding = 500;
int rangeLength = searchPadding;
if(data.length - next.location < searchPadding) { // Only use 500 if there is 500 more length in the data.
rangeLength = data.length - next.location;
}
[regularExpression enumerateMatchesInString:data
options:0
range:NSMakeRange(rangeLocation, rangeLength)
usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop){
[matches addObject:[data substringWithRange:result.range]];
}]; // Grab all the hits at once.
next.length = next.location - pos;
next.location = pos;
[mutableArrayOfWordsToMatch removeObjectAtIndex:0]; // Remove the word.
pos += (next.length+1);
} else { // No hits.
[mutableArrayOfUnfoundWords addObject:[mutableArrayOfWordsToMatch objectAtIndex:0]]; // Add to unfound words.
[mutableArrayOfWordsToMatch removeObjectAtIndex:0]; // Remove from the word list.
}
}
[mutablePatternString release];
[mutableArrayOfUnfoundWords release];
[mutableArrayOfWordsToMatch release];
// return matches to caller
EDIT: here is another version which uses no regex and shaves a little bit more time off of the method:
NSMutableArray *mutableArrayOfWordsToMatch = [[NSMutableArray alloc] initWithArray:array];
NSMutableArray *mutableArrayOfUnfoundWords = [[NSMutableArray alloc] init]; // I also need to know the unfound words.
NSUInteger pos = 0;
NSMutableArray * matches = [NSMutableArray array];
while (pos != data.length) {
if([mutableArrayOfWordsToMatch count] <= 0) { // If we're at the top of the loop without any more words, stop.
break;
}
NSRange remaining = NSMakeRange(pos, data.length-pos);
NSRange next = [data
rangeOfString:[NSString stringWithFormat:#"\n%#\t",[mutableArrayOfWordsToMatch objectAtIndex:0]]
options:NSLiteralSearch
range:remaining
]; // Just search for the first pronunciation.
if (next.location != NSNotFound) {
NSRange lineRange = [data lineRangeForRange:NSMakeRange(next.location+1, next.length)];
[matches addObject:[data substringWithRange:NSMakeRange(lineRange.location, lineRange.length-1)]]; // Grab the whole line of the hit.
int rangeLocation = next.location;
int rangeLength = 750;
if(data.length - next.location < rangeLength) { // Only use the searchPadding if there is that much room left in the string.
rangeLength = data.length - next.location;
}
rangeLength = rangeLength/5;
int newlocation = rangeLocation;
for(int i = 2;i < 6; i++) { // We really only need to do this from 2-5.
NSRange morematches = [data
rangeOfString:[NSString stringWithFormat:#"\n%#(%d",[mutableArrayOfWordsToMatch objectAtIndex:0],i]
options:NSLiteralSearch
range:NSMakeRange(newlocation, rangeLength)
];
if(morematches.location != NSNotFound) {
NSRange moreMatchesLineRange = [data lineRangeForRange:NSMakeRange(morematches.location+1, morematches.length)]; // Plus one because I don't actually want the line break at the beginning.
[matches addObject:[data substringWithRange:NSMakeRange(moreMatchesLineRange.location, moreMatchesLineRange.length-1)]]; // Minus one because I don't actually want the line break at the end.
newlocation = morematches.location;
} else {
break;
}
}
next.length = next.location - pos;
next.location = pos;
[mutableArrayOfWordsToMatch removeObjectAtIndex:0]; // Remove the word.
pos += (next.length+1);
} else { // No hits.
[mutableArrayOfUnfoundWords addObject:[mutableArrayOfWordsToMatch objectAtIndex:0]]; // Add to unfound words.
[mutableArrayOfWordsToMatch removeObjectAtIndex:0]; // Remove from the word list.
}
}
[mutableArrayOfUnfoundWords release];
[mutableArrayOfWordsToMatch release];
Looking at the dictionary file you provided, I'd say that a reasonable strategy could be reading in the data and putting it into any sort of persistent data store.
Read through the file and create objects for each unique word, with n strings of pronunciations (where n is the number of unique pronunciations). The dictionary is already in alphabetical order, so if you parsed it in the order that you're reading it you'd end up with an alphabetical list.
Then you can do a binary search on the data - even with a HUGE number of objects a binary search will find what you're looking for very quickly (assuming alphabetical order).
You could probably even keep the whole thing in memory if you need lightning-fast performance.

Deleting a number digit by digit on a calculator screen

I want to delete a number digit by digit on the calculator screen but am only being able to delete the full number . Is there any method ?
-(IBAction)cancelInput:(float)result1{
NSString *myString = [[NSNumber numberWithFloat:result] stringValue];
int str=[myString length]-1;
NSString *newstring = [[NSNumber numberWithInt:str] stringValue];
calculatorScreen.text= [NSString stringWithFormat:newstring];
//NSLog(#"%d ",str);
}
Here you go,
NSString *myString = [[NSNumber numberWithFloat:result] stringValue];
myString = [myString substringToIndex:[myString length]-1];
calculatorScreen.text= myString;
int str=[myString length]-1 will only return the length of your string, say if your number is 9876, it will return 3(4-1) and your newstring will be 3.If you want to delete the last character you have to create substring of myString.
string = [string substringToIndex:[string length] - 1];
-(IBAction)backPressed:(UIButton *)sender
{
self.display.text=[self.display.text substringToIndex:[self.display.text length]-1];
if ( [self.display.text isEqualToString:#""] || [self.display.text isEqualToString:#"-"])
{
self.display.text =#"0";
}
}
This is the core function for the button. I took the liberty to add in the if feature so that it could handle some of the basic issues. As usual, replace display with your primary label. The If function help to counter check that your label does not become empty " " or have a negative sign "-" and will automatically replace it with "0", similar to clear in that aspect. in which you can run the clear method instead. But use
self.display.text =#"0";
for better clarification instead.
Use this code for it:
else if([character isEqualToString:(NSString*) Delete])
{
NSInteger index_of_char_to_remove=[_display length]-1;
if(index_of_char_to_remove>=0)
{
[_display deleteCharactersInRange:NSMakeRange(index_of_char_to_remove, 1)];
last_character_is_operator=NO;
}
}
When press 'C' it will checked this condition and delete the data one by one

swipe directions and loop text string

Help me... I'm stuck. I'm trying to make simple game something like angry bird swipe. I don't know how to code this. I have two labels and swipe move code (up, down,left or right, any directions).
I want to transfer label1.text ("333333777777555555888888") on label2.text with shorter number ("3758"). So I can make Artificial Intelligence game better.
How do I do this?
Here's the code.
for (NSValue *point_value in TouchRecord) {
CGPoint current_point = [point_value CGPointValue];
NSUInteger idx = [self subregionIndexContainingPoint:current_point];
//collect string on label2
NSString *numValue = [[NSString alloc] initWithFormat:#"%d", idx];
label1.text = [label1.text stringByAppendingString:numValue];
}
Thanks.
I'm not entirely sure this is what you want but I think it is.
To shorten the string so that there are only one of each number use this function.
+(NSString*) removeDuplicateNumbersFromString:(NSString*)first{
//if first is "1112222334445" the return value of this function would be "12345"
NSString *end = [NSString stringWithString:#""]; //the return string
char last; //will track changes in numbers
for (int i = 0; i < [first length]; i++) {
char charAtIndex = [first characterAtIndex:i];
if (last != charAtIndex) {
//if the last character is different than the current character
//set the current character as last, and add that character to the return string
last = charAtIndex;
end = [end stringByAppendingFormat:#"%c",last];
}
}
NSLog(#"First:%#, End:%#",first,end); //prints out the start/end strings
return end;
}

How to know the length of NSString that fits a UILabel with fixed size?

I know NSString has methods that determine the frame size for it, using NSString UIKit Additions, sizeWithFont......
How about the other way around? I mean if I have a fixed frame size, how do I know how many characters or words for a NSString that can fit into it?
If I know this, I can cut off the NSString easily.
thanks
It might not be the most elegant solution, but you could do something like this:
- (NSString *)string:(NSString *)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont *)font {
if ([sourceString sizeWithFont:font].width <= width)
return sourceString;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [sourceString length]; i++) {
[string appendString:[sourceString substringWithRange:NSMakeRange(i, 1)]];
if ([string sizeWithFont:font].width > width) {
if ([string length] == 1)
return nil;
[string deleteCharactersInRange:NSMakeRange(i, 1)];
break;
}
}
return string;
}
Then call it like this:
NSString *test = #"Hello, World!";
CGFloat width = 40.0;
UIFont *font = [UIFont systemFontOfSize:[UIFont labelFontSize]];
NSString *reducedString = [self string:test reducedToWidth:width withFont:font];
NSLog(#"%#", reducedString);
You cannot know/determine the number of characters that fits in a UILabel with fixed width because some characters are smaler than others, eg l and m.
There are two options:
Use Mono-Space-Fonts (each character has also a fixed width). Then determine the width for one char in your font with your font-size and calculate the number of chars
Allow any number of characters and check on insert if the inserted characters fit.
You have to know what behaviour you want to have. What should happen if there is text that does not fit. If you only want to truncate (like the solution of mortenfast does) then just use UILineBreakModeTailTruncation for the lineBreakMode-property of your UILabel (there are more options, like TruncateHead, Clip, Word Wrap)
Or you just just use the lineBreak property and set it to NSLineBreakByCharWrapping and move on with your life. https://stackoverflow.com/a/29088337/951349
Thanks #Morten. I've updated the sample code to handle word separation. It also eliminates extra spaces in between words. It has not been tested in the field, but my tests have, thus far, proven OK. Please update at your leisure if you find improvements or bug/glitch fixes.
-(NSString*)string:(NSString*)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont*)font {
// if full string is within bounds, simply return the full string
if( [sourceString sizeWithFont:font].width <= width ) return sourceString;
// break up string into words. if <= 1 word, return original string
NSArray* words = [sourceString componentsSeparatedByString:#" "];
NSInteger numWords = [words count];
if( numWords <= 1 ) return sourceString;
// our return var. we populate as we go
NSMutableString* str = [NSMutableString string];
// temp var to test with before adding to return string
NSMutableString* strTemp = [NSMutableString string];
// string to hold word LESS spaces
NSString* strWordTemp = nil;
// the word we're currently on
NSInteger numWord = 0;
// whether we need to add a space (when not last word)
Boolean addSpace = NO;
// loop through our words....
for( NSString* strWord in words ) {
// which word we're on
numWord++;
// eliminate white space
strWordTemp = [strWord stringByReplacingOccurrencesOfString:#" " withString:#""];
// if this word is empty or was a space(s), skip it
if( [strWordTemp isEqualToString:#""] ) continue;
// append to temp string
[strTemp appendString:strWordTemp];
// if we're still within the bounds...
if( [strTemp sizeWithFont:font].width <= width ) {
// default = no extra space
addSpace = NO;
// if we're not the last word, add a space & check for length
if( numWord < numWords ) {
[strTemp appendString:#" "];
// if adding space made it too long, then just don't add it!
if( [strTemp sizeWithFont:font].width > width ) {
// it was too long with space, so we'll just add word
[str appendString:strWordTemp];
break;
}
// otherwise, it's OK to add the space
else addSpace = YES;
}
// append to return string and continue
[str appendFormat:#"%#%#", strWordTemp, ( addSpace ? #" " : #"" )];
}
// otherwise, we're done
else break;
}
// return our result
return str;
}

How to count '\n' in an UITextView

I got a headache trying to count returns (\n) in my UITextView. As you'll soon realise, I'm a bloody beginner and here is my theory of what I've come up with, but there are many gaps...
- (IBAction)countReturns:(id)sender {
int returns;
while ((textView = getchar()) != endOfString [if there is such a thing?])
{
if (textView = getchar()) == '\n') {
returns++;
}
}
NSString *newText = [[NSString alloc] initWithFormat:#"Number of returns: %d", returns];
numberReturns.text = newText;
[newText release];
}
I checked other questions on here, but people are usually (in my eyes) lost in some details which I don't understand. Any help would be very much appreciated! Thanks for your patience.
You can simply
UITextView *theview; //remove this line, and change future theview to your veiw
NSString *thestring; //for storing a string from your view
int returnint = 0;
thestring = [NSString stringWithFormat:#"%#",[theview text]];
for (int temp = 0; temp < [thestring length]; temp++){ //run through the string
if ([thestring characterAtIndex: temp] == '\n')
returnint++;
}
NSArray *newlines = [textView.text componentsSeparatedByString:#"\n"];
int returns = ([newlines count]-1)
Should work. Keep in mind this isn't such a great idea if you have a gia-normous string, but it's quick, dirty and easy to implement.
there are a lot of ways to do that. Here is one:
NSString *str = #"FooBar\n\nBaz...\n\nABC\n";
NSString *tmpStr = [str stringByReplacingOccurrencesOfString:#"\n" withString:#""];
NSInteger count = [str length] - [tmpStr length];
NSLog(#"Count: %d", count);