I have three tables:
CREATE TABLE person
(id int,
name char(50))
CREATE TABLE eventtype
(id int,
description char(50))
CREATE TABLE event
(person_id int,
eventtype_id int,
duration int)
What I want is a single query which gives me a list of the total duration of each eventtype for each person, including all zero entries. E.g. if there are 10 people and 15 different eventtypes, there should be 150 rows returned, irrespective of the contents of the event table.
I can get an outer join to work between two tables (e.g. durations for all eventtypes), but not with a second outer join.
Thanks!
You'll have to add a CROSS APPLY to the mix to get the non-existing relations.
SELECT q.name, q.description, SUM(q.Duration)
FROM (
SELECT p.Name, et.description, Duration = 0
FROM person p
CROSS APPLY eventtype et
UNION ALL
SELECT p.Name, et.description, e.duration
FROM person p
INNER JOIN event e ON e.person_id = p.id
INNER JOIN eventtype et ON et.id = e.eventtypeid
) q
GROUP BY
q.Name, q.description
You can cross join person and eventtype, and then just join the result to the event table:
SELECT
p.Name,
et.Description,
COALESCE(e.duration,0)
FROM
person p
cross join
eventtype et
left join
event e
on
p.id = e.person_id and
et.id = e.eventtype_id
A cross join is one where, for each row in the left table, it's joined to every row in the right table.
If you want a row for every combination of person and eventtype, that suggets a CROSS JOIN. To get the duration we need to join to event, but this needs to be an OUTER join since there might not always be a row. Your use of "total" suggests there there could be more than one event for a given combination of person and event, so we'll need a SUM in there as well.
Sample data:
insert person values ( 1, 'Joe' )
insert person values ( 2, 'Bob' )
insert person values ( 3, 'Tim' )
insert eventtype values ( 1, 'Cake' )
insert eventtype values ( 2, 'Pie' )
insert eventtype values ( 3, 'Beer' )
insert event values ( 1, 1, 10 )
insert event values ( 1, 2, 10 )
insert event values ( 1, 2, 5 )
insert event values ( 2, 1, 10 )
insert event values ( 2, 2, 7 )
insert event values ( 3, 2, 8 )
insert event values ( 3, 3, 16 )
insert event values ( 1, 1, 10 )
The query:
SELECT
PET.person_id
, PET.person_name
, PET.eventtype_id
, PET.eventtype_description
, ISNULL(SUM(E.duration), 0) total_duration
FROM
(
SELECT
P.id person_id
, P.name person_name
, ET.id eventtype_id
, ET.description eventtype_description
FROM
person P
CROSS JOIN eventtype ET
) PET
LEFT JOIN event E ON PET.person_id = E.person_id
AND PET.eventtype_id = E.eventtype_id
GROUP BY
PET.person_id
, PET.person_name
, PET.eventtype_id
, PET.eventtype_description
Output:
person_id person_name eventtype_id eventtype_description total_duration
----------- ----------- ------------ --------------------- --------------
1 Joe 1 Cake 20
1 Joe 2 Pie 15
1 Joe 3 Beer 0
2 Bob 1 Cake 10
2 Bob 2 Pie 7
2 Bob 3 Beer 0
3 Tim 1 Cake 0
3 Tim 2 Pie 8
3 Tim 3 Beer 16
Warning: Null value is eliminated by an aggregate or other SET operation.
(9 row(s) affected)
Related
I have table with self-related foreign keys and can not get how I can receive firs child or descendant which meet condition. My_table structure is:
id
parent_id
type
1
null
union
2
1
group
3
2
group
4
3
depart
5
1
depart
6
5
unit
7
1
unit
I should for id 1 (union) receive all direct child or first descendant, excluding all groups between first descendant and union. So in this example as result I should receive:
id
type
4
depart
5
depart
7
unit
id 4 because it's connected to union through group with id 3 and group with id 2 and id 5 because it's connected directly to union.
I've tried to write recursive query with condition for recursive part: when parent_id = 1 or parent_type = 'depart' but it doesn't lead to expected result
with recursive cte AS (
select b.id, p.type_id
from my_table b
join my_table p on p.id = b.parent_id
where b.id = 1
union
select c.id, cte.type_id
from my_table c
join cte on cte.id = c.parent_id
where c.parent_id = 1 or cte.type_id = 'group'
)
Here's my interpretation:
if type='group', then id and parent_id are considered in the same group
id#1 and id#2 are in the same group, they're equals
id#2 and id#3 are in the same group, they're equals
id#1, id#2 and id#3 are in the same group
If the above is correct, you want to get all the first descendent of id#1's group. The way to do that:
Get all the ids in the same group with id#1
Get all the first descendants of the above group (type not in ('union', 'group'))
with recursive cte_group as (
select 1 as id
union all
select m.id
from my_table m
join cte_group g
on m.parent_id = g.id
and m.type = 'group')
select mt.id,
mt.type
from my_table mt
join cte_group cg
on mt.parent_id = cg.id
and mt.type not in ('union','group');
Result:
id|type |
--+------+
4|depart|
5|depart|
7|unit |
Sounds like you want to start with the row of id 1, then get its children, and continue recursively on rows of type group. To do that, use
WITH RECURSIVE tree AS (
SELECT b.id, b.type, TRUE AS skip
FROM my_table b
WHERE id = 1
UNION ALL
SELECT c.id, c.type, (c.type = 'group') AS skip
FROM my_table c
JOIN tree p ON c.parent_id = p.id AND p.skip
)
SELECT id, type
FROM tree
WHERE NOT skip
ffI have a json array stored in my postgres database. The first table "Orders" looks like this:
order_id, basket_items_id
1, {1,2}
2, {3}
3, {1,2,3,1}
Second table "Items" looks like this:
item_id, price
1,5
2,3
3,20
Already tried to load data with multiple sql and select of different jsonb record, but this is not a silver bullet.
SELECT
sum(price)
FROM orders
INNER JOIN items on
orders.basket_items_id = items.item_id
WHERE order_id = 3;
Want to get this as output:
order_id, basket_items_id, price
1, 1, 5
1, 2, 3
2, 3, 20
3, 1, 5
3, 2, 3
3, 3, 20
3, 1, 5
or this:
order_id, sum(price)
1, 8
2, 20
3, 33
demo:db<>fiddle
SELECT
o.order_id,
elems.value::int as basket_items_id,
i.price
FROM
orders o, jsonb_array_elements_text(basket_items_id) as elems
LEFT JOIN items i
ON i.item_id = elems.value::int
ORDER BY 1,2,3
jsonb_array_elements_text expands the jsonb array into one row each element. With this you are able to join against your second table directly
Since the expanded array gives you text elements you have to cast them into integers using ::int
Of course you can GROUP and SUM aggregate this as well:
SELECT
o.order_id,
SUM(i.price)
FROM
orders o, jsonb_array_elements_text(basket_items_id) as elems
LEFT JOIN items i
ON i.item_id = elems.value::int
GROUP BY o.order_id
ORDER BY 1
Is your orders.basket_items_id column of type jsonb or int[]?
If the type is jsonb you can use json_array_elements_text to expand the column:
SELECT
o.order_id,
o.basket_item_id,
items.price
FROM
(
SELECT
order_id,
jsonb_array_elements_text(basket_items_id)::int basket_item_id
FROM
orders
) o
JOIN
items ON o.basket_item_id = items.item_id
ORDER BY
1, 2, 3;
See this DB-Fiddle.
If the type is int[] (array of integers), you can run a similar query with the unnest function:
SELECT
o.order_id,
o.basket_item_id,
items.price
FROM
(
SELECT
order_id,
unnest(basket_items_id) basket_item_id
FROM
orders
) o
JOIN
items ON o.basket_item_id = items.item_id
ORDER BY
1, 2, 3;
See this DB-fiddle
I have two tables: ItemCategories and Items. ItemCategories list the categories for items and contain language dependent text strings. The CultureCode column determines which language the text belongs to.
ItemCategories
ID Name CultureCode
1 Food 'en-us'
2 Clothing 'en-us'
3 Computers 'en-us'
4 Books 'en-us'
1 Essen 'de-de'
2 Kleidung 'de-de'
3 Rechner 'de-de'
4 Bücher 'de-de'
Items
ID CategoryID1 CategoryID2
4 1 NULL
5 NULL 2
6 3 4
7 NULL NULL
The Items table lists each item and the values under the CategoryID1 and CategoryID2 refer to the ID field in CategoryItems. The values of CategoryID1 and CategoryID2 can be both null , both set to an ID or just one of them set to an ID value.
I need to create an SQL (T-SQL) that returns the ID from Items along with its correspond Name from ItemCategories when the CultureCode is set to a specific language. So if my CultureCode is set to 'en-us', the results should be:
ID CategoryID1 CategoryID2 CategoryName1 CategoryName2
4 1 NULL Food Null
5 NULL 2 null Clothing
6 3 4 Computers Books
7 NULL NULL null null
This is what I have so far:
Select I.*
From Items I
Left Join ItemCategories IC On (IC.ID = I.CategoryID1) Or (IC.ID = I.CategoryID2)
where (IC.CultureCode = 'en-us') Or (IC.CultureCode is null)
But this is not giving me the results I want.
Sounds like you need to split your LEFT JOIN into two separate LEFT JOINs:
SELECT I.ID, I.CategoryID1, I.CategoryID2, CategoryName1 = IC1.Name, CategoryName2 = IC2.Name
FROM Items I
LEFT JOIN ItemCategories IC1 ON IC1.ID = I.CategoryID1 AND IC1.CultureCode = 'en-us'
LEFT JOIN ItemCategories IC2 ON IC2.ID = I.CategoryID2 AND IC2.CultureCode = 'en-us';
Give a try and let me know your results/Comments.
CREATE TABLE ItemCategories
(
ID INT
,Name VARCHAR(50)
,CultureCode VARCHAR(5)
)
GO
INSERT INTO ItemCategories VALUES(1 ,'Food ' , 'en-us')
INSERT INTO ItemCategories VALUES(2 ,'Clothing' , 'en-us')
INSERT INTO ItemCategories VALUES(3 ,'Computers' , 'en-us')
INSERT INTO ItemCategories VALUES(4 ,'Books' , 'en-us')
INSERT INTO ItemCategories VALUES(1 ,'Essen' , 'de-de')
INSERT INTO ItemCategories VALUES(2 ,'Kleidung' , 'de-de')
INSERT INTO ItemCategories VALUES(3 ,'Rechner' , 'de-de' )
INSERT INTO ItemCategories VALUES(4 ,'Bücher ' , 'de-de')
CREATE TABLE Items
(
ID INT
,CategoryID1 INT
,CategoryID2 INT
)
GO
INSERT INTO Items VALUES (4 , 1 , NULL)
INSERT INTO Items VALUES (5 , NULL , 2 )
INSERT INTO Items VALUES (6 , 3 , 4 )
INSERT INTO Items VALUES (7 , NULL , NULL)
Select I.*,IC.Name,IT.Name
From Items I
left join ItemCategories IC ON (IC.ID = I.CategoryID1) AND IC.CultureCode = 'en-us'
left join ItemCategories IT On (It.ID = I.CategoryID2) AND IT.CultureCode = 'en-us'
You can do it in two ways:
Use subqueries:
Select
I.ID,
(SELECT TOP 1 ID FROM ItemCategories IC WHERE IC.ID=I.CategoryID1 AND IC.CultureCode = 'en-us') AS CategoryID1,
(SELECT TOP 1 ID FROM ItemCategories IC WHERE IC.ID=I.CategoryID2 AND IC.CultureCode = 'en-us') AS CategoryID2,
(SELECT TOP 1 Name FROM ItemCategories IC WHERE IC.ID=I.CategoryID1 AND IC.CultureCode = 'en-us') AS CategoryName1,
(SELECT TOP 1 Name FROM ItemCategories IC WHERE IC.ID=I.CategoryID2 AND IC.CultureCode = 'en-us') AS CategoryName2
From Items I
Or, split query into 2 joins
SELECT DISTINCT I.*, IC1.Name AS CategoryName1, IC2.Name AS CategoryName2
FROM Items I
LEFT JOIN ItemCategories IC1 ON I.CategoryID1=IC1.ID
LEFT JOIN ItemCategories IC2 ON I.CategoryID2=IC2.ID
WHERE (IC1.CultureCode IS NULL OR IC1.CultureCode = 'en-us') AND (IC2.CultureCode IS NULL OR IC2.CultureCode = 'en-us');
I have a table TaggedData with the following fields and data
ID GroupID Tag MyData
** ******* *** ******
1 Texas AA01 Peanut Butter
2 Texas AA15 Cereal
3 Ohio AA05 Potato Chips
4 Texas AA08 Bread
I have a second table of BlockedTags as follows:
ID StartTag EndTag
** ******** ******
1 AA00 AA04
2 AA15 AA15
How do I select from this to return all data matching a given GroupId but NOT in any blocked range (inclusive)? For the data given if the GroupId is Texas, I don't want to return Cereal because it matches the second range. It should only return Bread.
I did try left joins based queries but I'm not even that close.
Thanks
create table TaggedData (
ID int,
GroupID varchar(16),
Tag char(4),
MyData varchar(50))
create table BlockedTags (
ID int,
StartTag char(4),
EndTag char(4)
)
insert into TaggedData(ID, GroupID, Tag, MyData)
values (1, 'Texas', 'AA01', 'Peanut Butter')
insert into TaggedData(ID, GroupID, Tag, MyData)
values (2, 'Texas' , 'AA15', 'Cereal')
insert into TaggedData(ID, GroupID, Tag, MyData)
values (3, 'Ohio ', 'AA05', 'Potato Chips')
insert into TaggedData(ID, GroupID, Tag, MyData)
values (4, 'Texas', 'AA08', 'Bread')
insert into BlockedTags(ID, StartTag, EndTag)
values (1, 'AA00', 'AA04')
insert into BlockedTags(ID, StartTag, EndTag)
values (2, 'AA15', 'AA15')
select t.* from TaggedData t
left join BlockedTags b on t.Tag between b.StartTag and b.EndTag
where b.ID is null
Returns:
ID GroupID Tag MyData
----------- ---------------- ---- --------------------------------------------------
3 Ohio AA05 Potato Chips
4 Texas AA08 Bread
(2 row(s) affected)
So, to match on given GroupID you change the query like that:
select t.* from TaggedData t
left join BlockedTags b on t.Tag between b.StartTag and b.EndTag
where b.ID is null and t.GroupID=#GivenGroupID
I Prefer the NOT EXISTS simply because it gives you more readability, usability and better performance usually in large data (several cases get better execution plans):
would be like this:
SELECT * from TaggedData
WHERE GroupID=#GivenGroupID
AND NOT EXISTS(SELECT 1 FROM BlockedTags WHERE Tag BETWEEN StartTag ANDEndTag)
I have two tables in a database. The first table tblTracker contains many columns, but the column of particular interest is called siteAdmin and each row in that column can contain multiple loginIDs of 5 digits like 21457, 21456 or just one like 21444. The next table users contains columns like LoginID, fname, and lname.
What I would like to be able to do is take the loginIDs contained in tblTracker.siteAdmin and return fname + lname from users. I can successfully do this when there is only one loginID in the row such as 21444 but I cannot figure out how to do this when there is more than one like 21457, 21456.
Here is the SQL statement I use for when there is one loginID in that column
SELECT b.FName + '' '' + b.LName AS siteAdminName,
FROM tblTracker a
LEFT OUTER JOIN users b ON a.siteAdmin= b.Login_Id
However this doesn't work when it tries to join a siteAdmin with more than one LoginID in it
Thanks!
I prefer the number table approach to split a string in TSQL
For this method to work, you need to do this one time table setup:
SELECT TOP 10000 IDENTITY(int,1,1) AS Number
INTO Numbers
FROM sys.objects s1
CROSS JOIN sys.objects s2
ALTER TABLE Numbers ADD CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number)
Once the Numbers table is set up, create this split function:
CREATE FUNCTION [dbo].[FN_ListToTable]
(
#SplitOn char(1) --REQUIRED, the character to split the #List string on
,#List varchar(8000)--REQUIRED, the list to split apart
)
RETURNS TABLE
AS
RETURN
(
----------------
--SINGLE QUERY-- --this will not return empty rows
----------------
SELECT
ListValue
FROM (SELECT
LTRIM(RTRIM(SUBSTRING(List2, number+1, CHARINDEX(#SplitOn, List2, number+1)-number - 1))) AS ListValue
FROM (
SELECT #SplitOn + #List + #SplitOn AS List2
) AS dt
INNER JOIN Numbers n ON n.Number < LEN(dt.List2)
WHERE SUBSTRING(List2, number, 1) = #SplitOn
) dt2
WHERE ListValue IS NOT NULL AND ListValue!=''
);
GO
You can now easily split a CSV string into a table and join on it:
select * from dbo.FN_ListToTable(',','1,2,3,,,4,5,6777,,,')
OUTPUT:
ListValue
-----------------------
1
2
3
4
5
6777
(6 row(s) affected)
Your can now use a CROSS APPLY to split every row in your table like:
DECLARE #users table (LoginID int, fname varchar(5), lname varchar(5))
INSERT INTO #users VALUES (1, 'Sam', 'Jones')
INSERT INTO #users VALUES (2, 'Don', 'Smith')
INSERT INTO #users VALUES (3, 'Joe', 'Doe')
INSERT INTO #users VALUES (4, 'Tim', 'White')
INSERT INTO #users VALUES (5, 'Matt', 'Davis')
INSERT INTO #users VALUES (15,'Sue', 'Me')
DECLARE #tblTracker table (RowID int, siteAdmin varchar(50))
INSERT INTO #tblTracker VALUES (1,'1,2,3')
INSERT INTO #tblTracker VALUES (2,'2,3,4')
INSERT INTO #tblTracker VALUES (3,'1,5')
INSERT INTO #tblTracker VALUES (4,'1')
INSERT INTO #tblTracker VALUES (5,'5')
INSERT INTO #tblTracker VALUES (6,'')
INSERT INTO #tblTracker VALUES (7,'8,9,10')
INSERT INTO #tblTracker VALUES (8,'1,15,3,4,5')
SELECT
t.RowID, u.LoginID, u.fname+' '+u.lname AS YourAdmin
FROM #tblTracker t
CROSS APPLY dbo.FN_ListToTable(',',t.siteAdmin) st
LEFT OUTER JOIN #users u ON st.ListValue=u.LoginID --to get all rows even if missing siteAdmin
--INNER JOIN #users u ON st.ListValue=u.LoginID --to remove rows without any siteAdmin
ORDER BY t.RowID,u.fname,u.lname
OUTPUT:
RowID LoginID YourAdmin
----------- ----------- -----------
1 2 Don Smith
1 3 Joe Doe
1 1 Sam Jones
2 2 Don Smith
2 3 Joe Doe
2 4 Tim White
3 5 Matt Davis
3 1 Sam Jones
4 1 Sam Jones
5 5 Matt Davis
7 NULL NULL
7 NULL NULL
7 NULL NULL
8 3 Joe Doe
8 5 Matt Davis
8 1 Sam Jones
8 15 Sue Me
8 4 Tim White
(18 row(s) affected)