I use this code to set a label with a location string
locationString = [[NSString alloc] initWithFormat:#"%#%# - %# %#%#",
thoroughfare,subThoroughfare,postalCode,
locality,countryCode];
locationLabel.text = locationString;
where thoroughfare, subThoroughfare, postalCode, locality,countryCode are obtained from a placemark.
Now, I'd like to visualize this string according the current locale. Have I specify a string format for each locale in which I'm interested or there is a simpler way to obtain this?
Thanks,
Fran
you can use following function
-(void) setLocation:(NSString *)latitude withLongitude:(NSString *)longitude {
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
CLLocation *location = [[CLLocation alloc] initWithLatitude:[latitude doubleValue] longitude:
longitude doubleValue]];
CLGeocodeCompletionHandler completionHandler = ^ (NSArray *placemarks, NSError *error){
if (error){
NSLog(#"error in fetching location <%#>",error);
return ;
}
if ( placemarks && placemarks.count >0){
CLPlacemark *mark = [placemarks objectAtIndex:0];
NSString *addresstring = [[mark addressDictionary] objectForKey:#"FormattedAddressLines"] componentsJoinedByString:#","];
*//fetched addressDictionary for key FormattedAddressLines*
}
The addressDictionary property of the placemark object should resolve in part the problem with its FormattedAddressLines array.
Related
I am to reverse Geo Code Latitude and Longitude of some location and want to get address of that location. I have done it through google web service but it takes time.
I want to know if there is some other good and efficient approach.
Currently calling this service,
NSString * getAddress = [NSString stringWithFormat:#"http://maps.googleapis.com/maps/api/geocode/json?latlng=%#,%#&sensor=true",Lattitude,Longitude];
You can use CLGeocoder:
[self.geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error){
CLPlacemark *placemark = placemarks[0];
NSLog(#"Found %#", placemark.name);
}];
This will still take time though, since both methods use web services to convert lat / long into a place
Try This code .
geoCoder = [[CLGeocoder alloc]init];
[self.geoCoder reverseGeocodeLocation: locationManager.location completionHandler:
//Getting Human readable Address from Lat long,,,
^(NSArray *placemarks, NSError *error) {
//Get nearby address
CLPlacemark *placemark = [placemarks objectAtIndex:0];
//String to hold address
NSString *locatedAt = [[placemark.addressDictionary valueForKey:#"FormattedAddressLines"] componentsJoinedByString:#", "];
//Print the location to console
NSLog(#"I am currently at %#",locatedAt);
}];
Have a look at GLGeocoder. Specifically reverseGeocodeLocation:completionHandler:
You can use Apple's CLGeocoder (part of CoreLocation). Specifically, the – reverseGeocodeLocation:completionHandler: method which will return a dictionary of address data for the given coordinates.
Have a look at this tutorial, or, if just want something to copy quickly: NSArray *addressOutput;
CLLocation *currentLocation;
//assumes these instance variables
// Reverse Geocoding
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error) {
NSLog(#"Found placemarks: %#, error: %#", placemarks, error);
if (error == nil && [placemarks count] > 0) {
NSMutableArray *tempArray = [[NSMutableArray alloc] initWithCapacity:[placemarks count]];
for (CLPlacemark *placemark in placemarks) {
[tempArray addObject:[NSString stringWithFormat:#"%# %#\n%# %#\n%#\n%#",
placemark.subThoroughfare, placemark.thoroughfare,
placemark.postalCode, placemark.locality,
placemark.administrativeArea,
placemark.country]];
}
addressOutput = [tempArray copy];
}
else {
addressOutput = nil;
NSLog(#"%#", error.debugDescription);
}
}];
Based off the code in the tutorial.
If you to not want to use google API, try this code - basically transforms latitude and longitude inputs into ZIPs (can be adjusted to adresses).
pip install uszipcode
# Import packages
from uszipcode import SearchEngine
search = SearchEngine(simple_zipcode=True)
from uszipcode import Zipcode
import numpy as np
#define zipcode search function
def get_zipcode(lat, lon):
result = search.by_coordinates(lat = lat, lng = lon, returns = 1)
return result[0].zipcode
#load columns from dataframe
lat = df_shooting['Latitude']
lon = df_shooting['Longitude']
#define latitude/longitude for function
df = pd.DataFrame({'lat':lat, 'lon':lon})
#add new column with generated zip-code
df['zipcode'] = df.apply(lambda x: get_zipcode(x.lat,x.lon), axis=1)
#print result
print(df)
#(optional) save as csv
#df.to_csv(r'zip_codes.csv')
I am developing iOS app, in which i want to find all locations within a some radius.
Is there any way in objective-c that will allow me to specify a fixed radius and a location, and that will tell me which locations are within that radius ?
I have done some researching and i got this code snippet,
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:locationManager.location
completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(#"reverseGeocodeLocation:completionHandler: Completion Handler called!");
if (error)
{
NSLog(#"Geocode failed with error: %#", error);
return;
}
CLLocationDistance radius = 30;
CLLocation* target = [[CLLocation alloc] initWithLatitude:51.5028 longitude:0.0031];
NSArray *locationsWithinRadius = [placemarks objectsAtIndexes:
[placemarks indexesOfObjectsPassingTest:
^BOOL(id obj, NSUInteger idx, BOOL *stop) {
return [(CLLocation*)obj distanceFromLocation:target] < radius;
}]];
NSLog(#"locationsWithinRadius=%#",locationsWithinRadius);
}];
but it gets crashes and shows error:
Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[CLPlacemark distanceFromLocation:]:
Am i going on right way ? is this a way, to find all locations from my specified locations ?
Thanks in advance.
EDIT:
NSArray *testLocations = #[[[CLLocation alloc] initWithLatitude:19.0759 longitude:72.8776]];
CLLocationDistance maxRadius = 3000; // in meters
CLLocation *targetLocation = [[CLLocation alloc] initWithLatitude:newLocation.coordinate.latitude longitude:newLocation.coordinate.longitude]; //Current location coordinate..
NSPredicate *predicate = [NSPredicate predicateWithBlock:^BOOL(CLLocation *testLocation, NSDictionary *bindings) {
return ([testLocation distanceFromLocation:targetLocation] <= maxRadius);
}];
NSArray *closeLocations = [testLocations filteredArrayUsingPredicate:predicate];
NSLog(#"closeLocations=%#",closeLocations);
When i log my closeLocations array it shows null(Empty) value. Coordinate which i provided in testLocations is near to my current location.
What you're trying to do in your code is geocoding, this is the process of translating coordinates to addresses and isn't what you want to do. Instead you need to more basic coordinate bounding. You could use the distanceFromLocation: method in your code above and just iterate through your coordinates, converting them into CLLocation objects (if they aren't already) and then checking the distance to your center point.
Rather than using indexesOfObjectsPassingTest, I'd probably use filteredArrayUsingPredicate and a predicate created with predicateWithBlock to do your distance check (unless you actually want the indices for some reason).
NSArray *testLocations = #[ [[CLLocation alloc] initWithLatitude:11.2233 longitude:13.2244], ... ];
CLLocationDistance maxRadius = 30; // in meters
CLLocation *targetLocation = [[CLLocation alloc] initWithLatitude:51.5028 longitude:0.0031];
NSPredicate *predicate = [NSPredicate predicateWithBlock:^BOOL(CLLocation *testLocation, NSDictionary *bindings) {
return ([testLocation distanceFromLocation:targetLocation] <= maxRadius);
}];
NSArray *closeLocations = [testLocations filteredArrayUsingPredicate:predicate];
I was wondering if anyone knew how to get a list of addresses around a longitude and latitude?
I've been using the following code but it always yields one address:
[self.geocoder reverseGeocodeLocation: currentLocation completionHandler:
^(NSArray *placemarks, NSError *error) {
for (int i = 0; i < placemarks.count; i++)
{
CLPlacemark *placemark = [placemarks objectAtIndex:i];
if (placemark.addressDictionary != nil)
{
Location *aLocation = [[Location alloc] init];
aLocation.locationName = [placemark.addressDictionary valueForKey:#"Name"];
aLocation.locationAddress = [placemark.addressDictionary valueForKey:#"City"];
aLocation.currentLocation = placemark.location;
[self.tableData addObject:aLocation];
}
}
[self.locationsTableView reloadData];
}];
I'm not sure if Core Location's geocoded is intended to do that.
Google allows for this kind of search but with limits with their Places API. That being said, you can do a search for something like "Pizza" and get results within a radius.
For more info look at: https://developers.google.com/places/documentation/
You can use their API to query based on a lat/long with a search query and radius to get results looking like what you're after.
Good luck!
First change your latitude and longitude value (and check may be your code is right) becoze in map, some coordinate does not provide full information.
following provide code for if some coordinate does not provide full information then how can give you condition for get specific CITY(or other Infor) name.
Here getReverseGeocode method call by [self getReverseGeocode];
- (void) getReverseGeocode
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
if(currentLatLong.count > 0)
{
CLLocationCoordinate2D myCoOrdinate;
myCoOrdinate.latitude = LatValue;
myCoOrdinate.longitude = LangValue;
CLLocation *location = [[CLLocation alloc] initWithLatitude:myCoOrdinate.latitude longitude:myCoOrdinate.longitude];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error)
{
if (error)
{
NSLog(#"failed with error: %#", error);
return;
}
if(placemarks.count > 0)
{
NSString *MyAddress = #"";
NSString *city = #"";
if([placemark.addressDictionary objectForKey:#"FormattedAddressLines"] != NULL)
MyAddress = [[placemark.addressDictionary objectForKey:#"FormattedAddressLines"] componentsJoinedByString:#", "];
else
MyAddress = #"Address Not founded";
if([placemark.addressDictionary objectForKey:#"SubAdministrativeArea"] != NULL)
city = [placemark.addressDictionary objectForKey:#"SubAdministrativeArea"];
else if([placemark.addressDictionary objectForKey:#"City"] != NULL)
city = [placemark.addressDictionary objectForKey:#"City"];
else if([placemark.addressDictionary objectForKey:#"Country"] != NULL)
city = [placemark.addressDictionary objectForKey:#"Country"];
else
city = #"City Not founded";
NSLog(#"%#",city);
NSLog(#"%#", MyAddress);
}
}];
}
}
I have a view controller that pulls the users latitude and longitude coordinates from the app delegate. This works well, but I also need the user's city, state, and time zone. I know I should use CLGeocoder for this (please see last chunk of code), but don't know how to put it together. I'd just need NSStrings of the city, state, and timezone. Anyone have any pointers or an example? Thank you!
In my App Delegate, I use CCLocationManager to get the Coordinates like this:
- (NSString *)getUserCoordinates
{
NSString *userCoordinates = [NSString stringWithFormat:#"latitude: %f longitude: %f",
locationManager.location.coordinate.latitude,
locationManager.location.coordinate.longitude];
locationManager = [[CLLocationManager alloc] init];
locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move
locationManager.desiredAccuracy = kCLLocationAccuracyHundredMeters; // 100 m
[locationManager startUpdatingLocation];
return userCoordinates;
}
- (NSString *)getUserLatitude
{
NSString *userLatitude = [NSString stringWithFormat:#"%f",
locationManager.location.coordinate.latitude];
return userLatitude;
}
- (NSString *)getUserLongitude
{
NSString *userLongitude = [NSString stringWithFormat:#"%f",
locationManager.location.coordinate.longitude];
return userLongitude;
}
In my View Controller, I get the user's Latitude and Longitude as an NSString with this:
NSString *userLatitude =[(PDCAppDelegate *)[UIApplication sharedApplication].delegate
getUserLatitude];
NSString *userLongitude =[(PDCAppDelegate *)[UIApplication sharedApplication].delegate
getUserLongitude];
I would like to get the city, state, and timezone. I understand I need CLGeocoder, but can't figure out how to meld it together:
CLGeocoder * geoCoder = [[CLGeocoder alloc] init];
[geoCoder reverseGeocodeLocation:newLocation completionHandler:^(NSArray *placemarks,
NSError *error) {
for (CLPlacemark * placemark in placemarks) {
NSString *locality = [placemark locality];
}
}
A couple things, Brandon:
1) CLLocationManager might not give you an instant response to your request for coordinates. You should set your view controller as a CLLocationManager delegate and then when the location update comes in (which will be in the locationManager:didUpdateLocations: method), then you can run your CLGeocoder method.
2)
Which I wrote to look like this:
- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
NSLog( #"didUpdateLocation!");
NSLog( #"latitude is %# and longitude is %#", [self getUserLatitude], [self getUserLongitude]);
CLGeocoder * geoCoder = [[CLGeocoder alloc] init];
[geoCoder reverseGeocodeLocation:locationManager.location completionHandler:^(NSArray *placemarks, NSError *error) {
for (CLPlacemark * placemark in placemarks) {
NSString * addressName = [placemark name];
NSString * city = [placemark locality]; // locality means "city"
NSString * administrativeArea = [placemark administrativeArea]; // which is "state" in the U.S.A.
NSLog( #"name is %# and locality is %# and administrative area is %#", addressName, city, administrativeArea );
}
}];
}
Getting the location's timezone is a bit trickier. I bet there's an API or some sample code to get it within iOS, but it's not a part of the CLPlacemark API.
Form a CLLocation from latitude and longitude double value. Then feed that location to reverseGeocodeLocation:completionHandler:
Also note that the method reverseGeocodeLocation:completionHandler: is asynchronous.
You can also use, CLLocationManagerDelegate's locationManager:didUpdateHeading:
to asynchronously update if there is an Location available, which is better.
Anyway following your approach, just modifying some of your code from AppDelegate
- (double)getUserLatitude
{
return retrun locationManager.location.coordinate.latitude;
}
- (double)getUserLongitude
{
retrun locationManager.location.coordinate.longitude;
}
-(CLLocationManager*) getLocationManager
{
return locationManager;
}
Now Form a Location object
double latt = [(PDCAppDelegate *)[UIApplication sharedApplication].delegate getUserLatitude];
double longt = [(PDCAppDelegate *)[UIApplication sharedApplication].delegate getUserLongitude];
CLLocation loc = [[CLLocation alloc] initWithLatitude:latt longitude:longt]
or you can directly get the location object from CLLocationManager
CLLocation loc = [(PDCAppDelegate *)[UIApplication sharedApplication].delegate getLocationManager].location;
Then you can use your code feeding the location to reverseGeocodeLocation:completionHandler: and Get the CLPlaceMark
[geoCoder reverseGeocodeLocation:loc completionHandler:^(NSArray *placemarks,
NSError *error) {
for (CLPlacemark * placemark in placemarks) {
NSString *locality = [placemark locality];
NSString * name = [placemark name];
NSString *country = [placemark country];
/*you can put these values in some member vairables*/
m_locality = [placemark locality];
m_name = [placemark name];
m_country = [placemark country];
}
}
While I don't have a solution for the timezone issue (I agree with others who've answered this question - look for a non-Apple API), I thought I'd provide an answer in Swift, for those who are curious:
func provideGeocodedStringForLocation(location: CLLocation, withCompletionHandler completionHandler: (String) -> ()) {
let geocoder = CLGeocoder()
geocoder.reverseGeocodeLocation(location) { (placemarks: [CLPlacemark]?, error: NSError?) -> Void in
guard let placemarks = placemarks where placemarks.count > 0 && error == nil else {
if let error = error { print(error.localizedDescription) }
completionHandler("Earth")
return
}
let city = placemarks[0].locality ?? ""
let state: String
if let adminArea = placemarks[0].administrativeArea {
state = ", \(adminArea)"
} else {
state = ""
}
completionHandler("\(city)\(state)") // produces output similar to "Boulder, CO"
}
}
// get the lat/long from your UIAppDelegate subclass
let latitude = CLLocationDegrees("40.0176")
let longitude = CLLocationDegrees("-105.28212")
let location = CLLocation(latitude: latitude, longitude: longitude)
provideGeocodedStringForLocation(location) { print($0) }
I got timezone name from placemark description. And it works for ios 8 and higher.
You can check this link for how to get time zone
My iphone app supposed to resolve address based on latitude and longitude of the user.
reverseGeocodeLocation works fine, but results are in english.
Is there a way to localize the results to other languages?
couldnt find any information about it at apple or anywhere else.
The code I use is:
CLGeocoder *geocoder = [[[CLGeocoder alloc] init] autorelease];
CLLocation *location = [[[CLLocation alloc]
initWithLatitude:coord.latitude longitude:coord.longitude] autorelease];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error) {
NSLog(#"reverseGeocodeLocation:completionHandler: Completion Handler called!");
if (error){
NSLog(#"Geocode failed with error: %#", error);
[self displayError:error];
return;
}
if(placemarks && placemarks.count > 0)
{
//do something
CLPlacemark *topResult = [placemarks objectAtIndex:0];
NSString *addressTxt = [NSString stringWithFormat:#"%# %#,%# %#",
[topResult subThoroughfare],[topResult thoroughfare],
[topResult locality], [topResult administrativeArea]];
}
}
i found how to localize country name, maybe it'll help:
CLPlacemark *placemark;
NSString *identifier = [NSLocale localeIdentifierFromComponents: [NSDictionary dictionaryWithObject: placemark.ISOcountryCode forKey: NSLocaleCountryCode]];
NSLocale *usLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US"];
NSString *country = [usLocale displayNameForKey: NSLocaleIdentifier value: identifier];
insert any country id instead #"en_US"
Solution for Swift 4, iOS 11
You can force to get geocoding results in chosen locale language by setting argument: preferredLocale: Locale.init(identifier: "en_US").
CLGeocoder().reverseGeocodeLocation(location, preferredLocale: Locale.init(identifier: "en_US"), completionHandler: {(placemarks, error) -> Void in
print(location)
if error != nil {
print("Reverse geocoder failed with error" + error!.localizedDescription)
return
}
if placemarks!.count > 0 {
let pm = placemarks![0]
print(pm.administrativeArea!, pm.locality!)
}
else {
print("Problem with the data received from geocoder")
}
})
Mattt Thompson has a great writeup on using a method from the AddressBookUI.framework for localizing addresses on his site NSHipster. He also has a formatting library on github which contains a class for doing this type of localization which uses the AddressBookUI.framework approach he has described.
Since iOS11, apple provides us with another API which can set locale to print localized language.
- (void)reverseGeocodeLocation:(CLLocation *)location preferredLocale:(nullable NSLocale *)locale
completionHandler:(CLGeocodeCompletionHandler)completionHandler API_AVAILABLE(macos(10.13), ios(11.0), watchos(4.0), tvos(11.0));