How to search the iphone address book for a specific phone number? - iphone

Question

I am developing an app that connects to another iphone using bonjour. One of its features is when I connect to the other device it will automatically check if I have the other persons phone number. So my problem is how do I check my address book for the phone number provided by the other device?

Answer 1

Here's an example extracted from one of my address book methods. I wasn't searching by phone number but this gives you an idea have how to move forward with what you need:
- (void) scanAddressBookSample
{
NSUInteger i;
NSUInteger k;
ABAddressBookRef addressBook = ABAddressBookCreate();
NSArray *people = (NSArray *) ABAddressBookCopyArrayOfAllPeople(addressBook);
if ( people==nil )
{
NSLog(#"NO ADDRESS BOOK ENTRIES TO SCAN");
CFRelease(addressBook);
return;
}
for ( i=0; i<[people count]; i++ )
{
ABRecordRef person = (ABRecordRef)[people objectAtIndex:i];
//
// Phone Numbers
//
ABMutableMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
CFIndex phoneNumberCount = ABMultiValueGetCount( phoneNumbers );
for ( k=0; k<phoneNumberCount; k++ )
{
CFStringRef phoneNumberLabel = ABMultiValueCopyLabelAtIndex( phoneNumbers, k );
CFStringRef phoneNumberValue = ABMultiValueCopyValueAtIndex( phoneNumbers, k );
CFStringRef phoneNumberLocalizedLabel = ABAddressBookCopyLocalizedLabel( phoneNumberLabel ); // converts "_$!<Work>!$_" to "work" and "_$!<Mobile>!$_" to "mobile"
// Find the ones you want here
//
NSLog(#"-----PHONE ENTRY -> %# : %#", phoneNumberLocalizedLabel, phoneNumberValue );
CFRelease(phoneNumberLocalizedLabel);
CFRelease(phoneNumberLabel);
CFRelease(phoneNumberValue);
}
}
[people release];
CFRelease(addressBook);
}

Answer 2

-(void)createQuickAccessContacts{
NSMutableDictionary contactDictionary= [[NSMutableDictionary alloc]init];
CFArrayRef all = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex n = ABAddressBookGetPersonCount(addressBook);
NSDate *date=[NSDate date];
for( int i = 0 ; i < n ; i++ )
{
ABRecordRef ref = CFArrayGetValueAtIndex(all, i);
ABMultiValueRef phones = (ABMultiValueRef)ABRecordCopyValue(ref, kABPersonPhoneProperty);
for(CFIndex j = 0; j < ABMultiValueGetCount(phones); j++)
{
CFStringRef phoneNumberRef = ABMultiValueCopyValueAtIndex(phones, j);
NSString *phoneNumber = (__bridge NSString *)phoneNumberRef;
[contactDictionary setObject:(__bridge id)(ref) forKey:phoneNumber];
}
}
NSLog(#" Time taken %f for %i contacts",[[NSDate date] timeIntervalSinceDate:date],[contactDictionary count]);
}
This takes like 0.5 sec for 2.5k contacts to fill
then you can find the contact using number
ABRecordRef ref= [contactDictionary objectForKey:#"89xxxxxxx"];
its super fast takes like 0.000x seconds

Answer 3

Use This. this is my code.
NSLog(#"=====Make People Array with Numbers. Start.");
peopleWithNumber = [[NSMutableDictionary alloc] init];
for (int i=0; i < [people count]; i++) {
NSInteger phoneCount = [self phoneCountAtIndex:i];
if (phoneCount != 0) {
NSMutableArray *phoneNumbers = [[NSMutableArray alloc] init];
for (int j=0 ; j < phoneCount ; j++) {
[phoneNumbers addObject:[self phoneNumberAtIndex:i phoneIndex:j]];
}
[peopleWithNumber addEntriesFromDictionary:
[NSDictionary dictionaryWithObjectsAndKeys:
[NSArray arrayWithArray:phoneNumbers], [self fullNameAtIndex:i], nil]];
}
}
NSLog(#"=====Make People Array with Numbers. End.\n");
search method. it would be faster than using array
"NSArray *people = (NSArray *) ABAddressBookCopyArrayOfAllPeople(addressBook);"
- (NSArray *)searchNamesByNumber:(NSString *)number {
NSString *predicateString = [NSString stringWithFormat:#"%#[SELF] contains '%#'",#"%#",number];
NSPredicate *searchPredicate = [NSPredicate predicateWithFormat:predicateString,peopleWithNumber,number];
NSArray *names = [[peopleWithNumber allKeys] filteredArrayUsingPredicate:searchPredicate];
return names;
}