18.11.2009 10:32:00
I want the value in between the above tag(created) to be inserted into the sqlite db for which i have taken a column of type timestamp....
how can i store this value in that column??
please advise...
Well, it depends in which format you want to save it in your database.
If you want to save it in the string form, then save it directly by making an object. But, use the datatype of string type.
Another option is to save it using the date datatype, seeing as sqlite doesn't have a dedicated date/time datatype.
Use a formatter to set the date format:
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"dd-MM-YYYY HH:MM:SS"];
Then make Date object, and save it.
You should replace dots by hyphens and place months, days and year parts in correct order.
According to sqlite docs these are the date and time accepted formats:
YYYY-MM-DD
YYYY-MM-DD HH:MM
YYYY-MM-DD HH:MM:SS
YYYY-MM-DD HH:MM:SS.SSS
YYYY-MM-DDTHH:MM
YYYY-MM-DDTHH:MM:SS
YYYY-MM-DDTHH:MM:SS.SSS
HH:MM
HH:MM:SS
HH:MM:SS.SSS
now
DDDDDDDDDD
Two options here (if you want sorting, which I assume you do):
Add as a string, but re-order the fields from highest to lowest. After that, it's a simple matter to sort via text. This is the slower option.
2009.11.18 10:32:00
Convert to a UNIX timestamp, I.E. seconds since Jan 1st, 1970. This is the fastest option.
1261153920
It is then simple to pull it out using date and time functions.
Note that SQLite does not have a date/time data type.
Make object for date
then use this
[date timeIntervalSinceDate:objDate];
this give time interval beetween the date and objDate. two dates(date and objDate) for finding timeInterval.
Save this by convert it into string.
Related
I store the date in an SQLlite database as a long and want to view it in a ListView. At the moment I have the Database, a content provider, a loadermanager and a custom adapter. At the moment I'm using the custom adapter to format the data. However, there may be other possibilites, so I'm interested what is best practice.
An alternative, assuming that saving it as a long meets the recognised time string formats as per :-
Time Strings A time string can be in any of the following formats (e.g. the very last one):
YYYY-MM-DD
YYYY-MM-DD HH:MM
YYYY-MM-DD HH:MM:SS
YYYY-MM-DD HH:MM:SS.SSS
YYYY-MM-DDTHH:MM
YYYY-MM-DDTHH:MM:SS
YYYY-MM-DDTHH:MM:SS.SSS
HH:MM
HH:MM:SS
HH:MM:SS.SSS
now
DDDDDDDDDD
SQL As Understood By SQLite - Date And Time Functions
would be to extract the data in the required display format.
For example consider the following :-
DROP TABLE IF EXISTS mydata;
CREATE TABLE IF NOT EXISTS mydata (mydatetime INTEGER);
INSERT INTO mydata VALUES(1092941466); -- <<<<<<<<<< 2004-08-19 18:51:06
SELECT *, datetime(mydatetime,'unixepoch'), strftime('%d/%m/%Y %H:%M:%S week %W of Year %Y',mydatetime,'unixepoch') FROM mydata;
The result would be :-
Reading the link above should indicate the flexibility of this approach.
I'm new to Firestore and since it doesn't seem like it has a native createdAt/updatedAt as part of a document, I'm creating them when I create the new document. Using a straight up Date() as the value for my initial dictionary that I save to Firestore obviously gives me a localized date/time – UTC -500, for example.
Firestore stores this as November 19, 2018 at 5:14:54 PM UTC-5
Is there a specific date format that Firestore likes in order to save something as a Timestamp and so that I will be able to sort on it later?
I tried using "yyyy-MM-dd HH:mm:ss Z" as the dateFormat from just printing out the value of Date() in a Playground. Would love some help here. Thanks!
A Timestamp object doesn't have a date format. It's just a measurement of a number of seconds since Unix epoch, plus some number of nanoseconds. It does not accept a formatted time. If you have a formatted time, you will have to parse it to get a Timestamp object in return.`
The date format you're seeing in the console is just the way the console is choosing to format it. If you want to format a Timestamp for display, you'll need to do that yourself.
I have this date "2018-05-30T16:19:58.016Z" coming from my Angular app.
In Spring, the field date is as follows :
#JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'")
private Date date;
The date is well stored, but with this format YYYY-MM-dd.
Is there anything that I'm missing ?
MySql date type can't hold data with timestamp. It has to be datetime in order to contain date time with timestamp data.
You probably have to specify the date format going out to the storage, as #JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'") only specifies the date format for parsing the date into the Date object. Even if your Date has all of the seconds and timezone information, the default Date toString() is still
Formats a date in the date escape format yyyy-mm-dd.
according to the Java 8 docs. So if you are using that, it would most likely drop all that extra information on conversion.
You can look at this Convert java.util.Date to String for information on how to get a Date to a formatted String.
So I have one big file (13 million rows) and date formatted as:
2009-04-08T01:57:47Z. Now I would like to split it into 2 columns now,
one with just date as dd-MM-yyyy and other with time only hh:MM.
How do I do it?
You can simply use tMap and parseDate/formatDate to do what you want. It is neither necessary nor recommended to implement your own date parsing logic with regexes.
First of all, parse the timestamp using the format yyyy-MM-dd'T'HH:mm:ss'Z'. Then you can use the parsed Date to output the formatted date and time information you want:
dd-MM-yyyy for the date
HH:mm for the time (Note: you mixed up the case in your question, MM stands for the month)
If you put that logic into a tMap:
you will get the following:
Input:
timestamp 2009-04-08T01:57:47Z
Output:
date 08-04-2009
time 01:57
NOTE
Note that when you parse the timestamp with the mentioned format string (yyyy-MM-dd'T'HH:mm:ss'Z'), the time zone information is not parsed (having 'Z' as a literal). Since many applications do not properly set the time zone information anyway but always use 'Z' instead, so this can be safely ignored in most cases.
If you need proper time zone handling and by any chance are able to use Java 7, you may use yyyy-MM-dd'T'HH:mm:ssXXX instead to parse your timestamp.
I'm guessing Talend is falling over on the T and Z part of your date time stamp but this is easily resolved.
As your date time stamp is in a regular pattern we can easily extract the date and time from it with a tExtractRegexFields component.
You'll want to use "^([0-9]{4}-[0-9]{2}-[0-9]{2})T([0-9]{2}:[0-9]{2}):[0-9]{2}Z" as your regex which will capture the date in yyyy-MM-dd format and the time as mm:HH (you'll want to replace the date time field with a date field and a time field in the schema).
Then to format your date to your required format you'll want to use a tMap and use TalendDate.formatDate("dd-MM-yyyy",TalendDate.parseDate("yyyy-MM-dd",row7.date)) to return a string in the dd-MM-yyyy format.
I am trying to get the date from SQLite. I am getting timestamp in coredata, but I need to see the date. What is the command to get the timestamp converted into YYYY-MM-DD format? My query is:
SELECT ZDATE FROM ZWEATHER
Zdate is datetime.
You may be looking for the DATE() function, as seen in the SQLite manual:
SELECT date(ZDATE);
The first thing to understand is that SQLite has no date type. It has no time type either.
It only offers some time functions. The page Piskvor links to is what you need. You enter the date and/or time in your database as a string following one of a few formats available:
YYYY-MM-DD
YYYY-MM-DD HH:MM
YYYY-MM-DD HH:MM:SS
YYYY-MM-DD HH:MM:SS.SSS
YYYY-MM-DDTHH:MM
YYYY-MM-DDTHH:MM:SS
YYYY-MM-DDTHH:MM:SS.SSS
HH:MM
HH:MM:SS
HH:MM:SS.SSS
Or as a floating point value representing the Julian day number.