Use iconv API in C - unicode

Question

I try to convert a sjis string to utf-8 using the iconv API. I compiled it already succesfully, but the output isn't what I expected.
My code:
void convertUtf8ToSjis(char* utf8, char* sjis){
iconv_t icd;
int index = 0;
char *p_src, *p_dst;
size_t n_src, n_dst;
icd = iconv_open("Shift_JIS", "UTF-8");
int c;
p_src = utf8;
p_dst = sjis;
n_src = strlen(utf8);
n_dst = 32; // my sjis string size
iconv(icd, &p_src, &n_src, &p_dst, &n_dst);
iconv_close(icd);
}
I got only random numbers. Any ideas?
Edit:
My input is
char utf8[] = "\xe4\xba\x9c"; //亜
And output should be:
0x88 0x9F
But is in fact:
0x30 0x00 0x00 0x31 0x00 ...

Answer 1

I was unable to duplicate the problem. The only thing I can suggest is to be careful about your allocations.
Code:
#include <iconv.h>
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
void convertUtf8ToSjis(char* utf8, char* sjis){
...
}
int main(int argc, char *argv[])
{
char utf8[] = "\xe4\xba\x9c";
char *sjis;
sjis = malloc(32);
convertUtf8ToSjis(utf8, sjis);
int i;
for (i = 0; sjis[i]; i++)
{
printf("%02x\n", (unsigned char)sjis[i]);
}
free(sjis);
}
Output:
$ gcc t.c
$ ./a.out
88
9f