Zend Framework: How to render a different action? - zend-framework

Question

I have two actions that are essentially identical, but need different URLs. Normally I would use _forward() to render the other action:
class MyController extends Zend_Controller_Action
{
public function actionOneAction()
{
$this->_forward('action-two');
}
public function actionTwoAction()
{
$this->view->foobar = 'foobar';
}
}
However, I have some code the is happening in preDispatch() that I only want to execute once:
class MyController extends Zend_Controller_Action
{
public function preDispatch()
{
//execute this only once before actionOne or actionTwo, but not both
}
public function actionOneAction()
{
$this->_forward('action-two'); //this won't work because preDispatch() will get called a second time
}
public function actionTwoAction()
{
$this->view->foobar = 'foobar';
}
}
So I thought maybe I could simply call the function directly, like this:
class MyController extends Zend_Controller_Action
{
public function preDispatch()
{
//execute this only once before actionOne or actionTwo, but not both
}
public function actionOneAction()
{
$this->actionTwoAction(); //execute the same code as actionTwoAction()
}
public function actionTwoAction()
{
$this->view->foobar = 'foobar';
}
}
But now Zend Framework is complaining about not being able to find the action-one.phtml view script. I don't want to render actionOne's view script. I want to render actionTwo's view script. What do I need to do?

Answer 1

Using render() seems to do the trick:
public function actionOneAction()
{
$this->actionTwoAction(); //execute the same code as actionTwoAction()
$this->render('action-two'); //renders the same view as actionTwoAction()
}