I want to globally replace the string foo with the string bar, using sed. This should only be done for lines which do NOT start with the string ##Input.
I can't get it to work. I tried things like this but reached a point where I'm not sure if I know what I'm doing:
sed -i '/^##Input/ s/foo/bar/g' myfile
Please help!
You just need to negate the match using !:
sed -i '/^##Input/! s/foo/bar/g' myfile
You got to escape # as in \#.
An ugly answer for an ugly request (i.e. they get what they asked for):
echo \{
for file in *.json; do
sed -n '/^[\{\}]/! s/\([^\,]\)$/\1,/; /^[\{\}]/!p' $file
done
echo \{
Related
in a text file (on linux system) I have this string:
O\WIN_INFRASTRUKTUR{Windows Fabrik}\FIM{Forefront Identity Manager(Benutzer)}\EXTRA{}
Now, I want to replace the O\WIN_INFRASTRUKTUR{Windows Fabrik}, but I don't know what is standing in {}. It could be empty or text in it.
I try this, but without success:
sed -e 's/O\\WIN_INFRASTRUKTUR{[a-zA-Z0-9]}/O\\WIFI{}/g'
And that must be the Result:
O\WIFI{}\FIM{Forefront Identity Manager(Benutzer)}\EXTRA{}
Could anyone help me?
use the delimiter as end of your pattern, here it is } so take a class excluding this, any occurrence than your delimiter with [^}]*}
sed -e 's/O\\WIN_INFRASTRUKTUR{[^}]*}/O\\WIFI{}/g' YourFile
sed -e 's/WIN_INFRASTRUKTUR{[^}]*}/WIFI{}/g' <filename>
Thanks, it will be sucessful, but what is, if I want to have this result:
O\WIFI{}\EXTRA{}.
It doesn't matter if I do this:
sed -e 's/O\\WIN_INFRASTRUKTUR{[^}]*}\\FIM{[^}]*}/O\\WIFI{}/g'
than I get only this result: O\WIFI{}
sed is still giving me headaches, so a little help is extremely appreciated.
In a file I have a string like:
SOME_TEXT="variables"
What I want to accomplish is to add a piece of text (variable) to either the end or the begging of the string for that text.
I tried to use variations of:
sed -i '/^SOME_TEXT="/ s/$/ SOME_TEXT="new text'/' filename
but that is failing, so clearly the quota for the string I want to add to is messing up the syntax.
LE:
A variation further is that I have a variable that I want to use as the replace in that syntax, so I have this:
sed -i "s/^SOME_TEXT="/SOME_TEXT=" $variable/" file
This actually produces this output, as it picks up incorrectly the opening/closing quotas:
SOME_TEXT = text_variable" initial text continuation
So how can I properly close the trailing quota so that I can use the variable after it?
I used
sed 's/^SOME_TEXT="/SOME_TEXT="new text/' filename
and it showed:
SOME_TEXT="new textvariables"
Is that what you want?
Escape the '"' characters with a '\' so that they don't terminate your regex string.
sed -i "s/^TEXT=\"/TEXT=\" $variable/"
I have a file that I need to append to certain lines.
I can get the line numbers and have been able to use sed to print the entry but not to append the entry.
All I need to do is something like
sed -n '$VAR s/$/,nosuid/' > to_file
Just can not get the syntax down.
Thank you.
Try doing this :
sed "$VAR s/$/,nosuid/" > to_file
Like Etan Reisner said in the comments, the quotes should be double quotes.
This might work for you:
sed -n $VAR's/$/,nosuid/' > to_file
I think the title says it all, I'm looking for a one-liner to remove lines of a file in which a specific character, let's say /, appears more than x times - 5, for instance.
Start:
/Bo/byl/apointe
S/ta/ck/ov/er/flo/w
M/oon/
Expected result:
/Bo/byl/apointe
M/oon/
Thank you for your suggestions !
You can use gsub function of awk. gsub return number of successful substitution made. So you can use that as reference to identify number of occurrences of particular character.
awk 'gsub(/\//,"&")<5' file
Updated Based on Ed Morton's suggestion.
This might work for you (GNU sed):
sed 's|/|&|5;T;d' file
All you need is:
awk -F/ 'NF<6' file
Look:
$ cat file
/Bo/byl/apointe
S/ta/ck/ov/er/flo/w
M/oon/
$ awk -F/ 'NF<6' file
/Bo/byl/apointe
M/oon/
I believe sed would be sufficient here. You'll want to look into //d and supply the correct condition. I'm going to try something and update when I have better ideas, you should too :)
Once you find it sed -i /{blah}/d will be enough to change it in the file, but you might want to run it without the -i and pipe it through less first to confirm it's doing what you think it's doing.
This would do :
sed -r '/(\/.*){5}\//d' file
I have a data file that needs to have several uniq identifiers stripped of hyphens.
So I have:
(Special_Section "data-values")
and I want to have it replaced with:
(Special_Section "datavalues")
I wanted to use a simple sed find/replace, but the data and values are different each time. Preferably, I'd run this in-place since the file has a lot of other information I want to keep in tact.
Does sed or awk have a way to remove the hyphen from the matched portion only?
Currently I can match with: sed -i 's/Special_Section "[a-zA-Z0-9]*-[a-zA-Z0-9]*"/&/g *myfiles*
But I would like to then run s/-// on & if it's possible.
You seems to be using GNU sed, so something like this might work:
sed -ri '
s/(Special_Section [^-]*)-([^)]*)/\1\2/g
' <your_filename_glob>
does this work?
sed -i '/(Special_Section ".*-.*")/{s/-//}' yourFile
Close - scan for the lines and then substitute on those that match:
sed -i '/Special_Section "[a-zA-Z0-9]*-[a-zA-Z0-9]*"/s/\( "[a-zA-Z0-9]*\)-\([a-zA-Z0-9]*\)"/\1\2/' *myfiles*
You can split that over several lines to avoid the scroll bar in SO:
sed -i '/Special_Section "[a-zA-Z0-9]*-[a-zA-Z0-9]*"/{
s/\( "[a-zA-Z0-9]*\)-\([a-zA-Z0-9]*\)"/\1\2/
}' *myfiles*
And on further thoughts, you can also do:
sed -i 's/\(Special_Section "[a-zA-Z0-9]*\)-\([a-zA-Z0-9]*"\)/\1\2/' *myfiles*
This is more compact. You can add the g qualifier if you need it. Both solutions use the special \(...\) notation to capture parts of the regular expression.