1) user launch application
2) user press button
3) button loads http://domain.com/mypage/?item=123
How do you trigger http://domain.com/?item=123, without opening the actual page in the browser?
NSURLConnection is the answer.
Not 100% sure of what the question is, but you could use a UIWebView. Load that UIWebView in the app with the URL and you should be good to go.
Hope this helps!
NSString* str = [NSString stringWithContentsOfURL:[NSURL URLWithString:#"http://domain.com/?item=123"] usedEncoding:NULL error:NULL]
I have used a UIWebView set to "hidden". It probably is not the most efficient way but if you normally use UIWebViews and Interface Builder then it is easy. You can also use the webview delegate methods to watch it.
On second thought - use the NSURL String method above but put it in a new thread.
Related
Some help please,
I am putting a web app together and I am stuck on a few things.
I have tabviewcontrollers which load different uiwebviews.
Each time I navigate on the app and re-click the tab it remains where I was on that page is there a way to re-load it so it always goes from the orginal ur (not just a refresh)?
Any advice on the best way to handle this would be appreciated.
Thank you
Steve
Load the request in your view controller's viewWillAppear: method.
When you want to refresh, use
[webView reload]
or for if you want t reload with a specific url
NSURL *theURL = [NSURL URLWithString:#"http://urltoreload.html"];
[webView loadRequest:[NSURLRequest requestWithURL:theURL]];
I'm making an iPhone app using xcode, but whenever the homepage (localHTML) is visited using the backbutton, the list item stays highlighted. My solution to this is to refresh the page whenever the localHTML is visited. Can anyone suggest an easy way of detecting when the url matches localHTML (should I use isFileURL?) Thanks for your help. Also, the list was made with javascript or else I would use deselectRowAtIndexPath.
This is what I came up with, but it doesn't work
-(IBAction)backbutton{
[webView goBack];
NSString *currentURL = webView.request.URL.absoluteString;
if (currentURL = "whatever the file path is") {
[webView reload];
}
is this a valid way to accomplish this? is there a way to get my localhtml's file path by using nslog?
Have you tried having a delay after going back, then refreshing?
eg. after
[webView goBack];
have a delay now using nstimer
then
[webView reload];
For legal reasons, I'm obligated to show Terms of Service in my application, a PDF on an external server. What I believe would be easiest to do would be to create a UIBarButton item and then create an IBAction that launches the link in Safari.
So I create a button:
IBOutlet UIBarButtonItem *legal;
Then I make it into a nonatomic property and synthesize it in my implementation file, right? I go on to create an IBAction:
-(IBAction)legalButtonPressed:(id)sender;
I go into my implementation file, and here's where the issue comes. When it comes to defining those actions, I become confused. As I am new to iOS development, I could use some guidance. I don't know how to force the link into safari in the action. Any help would be greatly appreciated!
Thanks!
IBOutlet and IBActions are used for Interface Builder connections. If you have your UIBarButtonItem on a xib file, you can connect its action to the controller by right clicking in the files owner object. The same with the outlet.
Once you have the action in the controller connected to the button in the xib file, (I see no need to get an outlet here), you just implement the method as follows:
-(IBAction)legalButtonPressed:(id)sender {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: #"http://yourdomain.com/legal.pdf"]];
}
this will automatically open safari with the given url
Take a look at UIApplication's documentation, it has a openURL method you might find useful.
Another option is to include your legal text in a UITextView.
Example:
By clicking Join you agree to company's
Terms of Service, found here: http://www.site.com/tos.html and
Privacy Policy, found here: http://www.site.com/privacy.html
Make sure Link Detection is turned on in the UITextView and it will automatically recognize URLs. Any clicks on those URLs will automatically launch Safari.
Although you can do this approach (i.e. launch the link in Safari). I would suggest that you try to keep the user as much as possible in your app. I am guessing this LEGAL TERMS is a HTML doc?
You can do that using UIWebView. Init a webView and do this -
NSURL *url = [NSURL URLWithString:webAddress];
NSURLRequest *req = [NSURLRequest requestWithURL:url];
[webView loadRequest:req];
This will open the url in your app only! You can make the UIWebView open up as a modal window or in many other ways...
In one of my apps I reuse a webview. Each time the user enters a certain view on reload cached data to the webview using the method :-
- (void)loadData:(NSData *)data MIMEType:(NSString *)MIMEType textEncodingName:(NSString *)encodingName baseURL:(NSURL *)baseURL
and I wait for the callback call
- (void) webViewDidFinishLoad:(UIWebView *)webView.
In the mean time I hide the webview and show a 'loading' label.
Only when I receive webViewDidFinishLoad do I show the webview.
Many times what happens I see the previous data that was loaded to the webview for a brief second before the new data I loaded kicks in.
I already added a delay of 0.2 seconds before showing the webview but it didn't help.
Instead of solving this by adding more time to the delay does anyone know how to solve this issue or maybe clear old data from a webview without release and allocating it every time?
Thanks malaki1974, in my case I wasn't using a modal view.
When I sat with an Apple engineer on WWDC 2010 and asked him this question his answer was simply: "Don't reuse UIWebViews, that's not how they were ment to be used."
Since then I make sure to calls this set of lines before allocating a new UIWebView
[self.myWebView removeFromSuperview];
self.myWebView.delegate = nil;
[self.myWebView stopLoading];
[self.myWebView release];
That solved the issue.
Clear the contents of the webview before you try to load new content
[self loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:#"about:blank"]]];
First, the UIWebView renders it contents in a background thread. Even when you receive webViewDidFinishLoad: it might not be completely done. Specially if it is an ajax-intense page that comes from the network.
You say you are hiding the view. I wonder if that means that the webview delays its drawing completely. What you could try is to move the UIWebView offscreen or obscure it with another view. Maybe that will change it's drawing behaviour.
If you do not need an interactive UIWebView then you can also consider to do it completely offscreen in a separate UIWindow and then create an image from that UIWebView's layer.
That's what I do, and it works:
[_webView stringByEvaluatingJavaScriptFromString:#"document.open();document.close();"];
Try loading a local file that is blank or has a loading graphic when you hide it, rather than just loading new content when you show it. Since the file is local it will be quick and even if the new page takes a while to load it will have either blank or loading expected behavior.
If you got controll over the html. You can communicate back to objective-c when the document is ready. Like so in jQuery:
function messageNative (name, string) {
var iframe = document.createElement("IFRAME");
iframe.setAttribute("src", "appscheme://" + name + "/" + string);
document.documentElement.appendChild(iframe);
iframe.parentNode.removeChild(iframe);
iframe = null;
}
$(function() {
messageNative('webview', 'ready');
});
And then in UIWebView's delegate method webView:shouldStartLoadWithRequest:navigationType: wait for the request with url equal to "appscheme://webview/ready". Then you should know: the document is loaded and ready for display. Then all that is missing is a simple fade-in or something like that :)
I am working on an iPhone app, and would like to be able to click on a link that is in UITableView. When the Link, and only the link is selected I want the Safari app to be opened to the selected link. Any suggestions on how to do this? Thanks so much!
There are multiple solutions to your problem.
If the links are the only object in the cell, then you could just make call the didSelectRowAtIndexPath:(NSIndexPath *)indexPath function of UITableView to gather the link from your array of table data, and then use
[[UIApplication sharedApplication] openURL:myURL];
to open the URL.
Alternatively you could create your own UITableCell subclass that contains a custom button (instead of a rounded rect button) that has no image or background (only text) so that it has the appearance of a link (you could even color the text blue, and underline it...). When the user clicks the button, your handler function would then call the same openURL function as above.
The above method works best if you have multiple items in each cell (which is why you would have to create a custom cell...
A naive approach would be to embed a tiny UIWebView into each cell. UIWebView has a delegate that lets you know when a link is clicked which you can implement to launch the Safari or navigate to a new controller hosting a full screen UIWebView.
This approach might be too resource intensive and I haven't tried it myself but if it does work it would offer a lot of flexibility. Would love to know the results if you try it.
To launch a link in safari use:
NSURL *url = [NSURL URLWithString:#"http://stackoverflow.com"];
if (![[UIApplication sharedApplication] openURL:url]) {
NSLog(#"%#%#", #"Failed to open url:", [url description]);
}
Is the link in its own row in the UITableView? If so, then you can handle it within didSelectRowAtIndexPath when the appropriate row is clicked.