remove first image with interval - iphone

Question

I am using...
[self addChild:self.blue_action];
[self schedule:#selector(updateTimer1:) interval:1.0f];
Via this line, I want to show an image in the any position and after some time that image will remove, through '[self removeChild: self.blue_action cleanUp:Yes];'
-(void)updateTimer1:(id)sender {
if(time_1 == 0) {
NSLog(#"time value ");
[self removeChild:self.blue_action cleanup:YES];
[self schedule: #selector(updateTimer1:) interval:0.10];
}
else {
--time_1;
}
}

Answer 1

In this case the updateTimer1:(id)sender method was already scheduled.
To schedule this again you obvious must unscheduled this method by [self unschedule:_cmd];
And it's a good practice do not remove sprite every time when you want it to disappear, try to just make it invisible self.blue_action.visible = NO

Answer 2

You want to fire method once after specific time? Action is helpful.
-(void)addBlueAction {
[self addChild:self.blue_action];
[self runAction:[CCSequence actions:
[CCDelayTime actionWithDuration:1],
[CCCallFunc actionWithTarget:self
selector:#selector(removeBlueAction)],
nil]];
}
-(void)removeBlueAction {
[self removeChild:self.blue_action cleanup:YES];
}
If your app's target is for after iOS 4.0, you can use Blocks.
-(void)addBlueAction {
[self addChild:self.blue_action];
[self runAction:[CCSequence actions:
[CCDelayTime actionWithDuration:1],
[CCCallBlock actionWithBlock:^{
[self removeChild:self.blue_action cleanup:YES];
}],
nil]];
}