how can I insert value into my sqlite3 database table? - iphone

Question

I am writing a simple query as below
const char *sql = "insert into abc(name) values ('Royal')";
and this will insert each time 'Royal' into my 'name', so now I want to take input from user each time as names of hotel and wants to save them instead of 'Royal', so what should I do?
If you are not clear to my question, you may as me again,,,,,

Answer 1

this code is very simple for insert the value in sqlite3 table
-(void)writeValueInSettings:(NSMutableArray *)arrayvalue
{
if(sqlite3_open([databasePath UTF8String],&myDatabase)==SQLITE_OK)
{
database *objectDatabase=[[database alloc]init];
NSString *stringvalue2=[objectDatabase countValue];
[objectDatabase release];
NSLog(#"opened");
NSString *sql1;
sql1=[[NSString alloc] initWithFormat:#"insert into setting values('%i','%i','%i','%#','%i','%i','%#','%i','%i','%i','%i','%i','%i','%#');",intvalue1,
[[arrayvalue objectAtIndex:0] intValue],[[arrayvalue objectAtIndex:1] intValue],[arrayvalue objectAtIndex:2],[[arrayvalue objectAtIndex:3] intValue],[[arrayvalue objectAtIndex:4]intValue ],[arrayvalue objectAtIndex:5],[[arrayvalue objectAtIndex:6]intValue],[[arrayvalue objectAtIndex:7]intValue ],[[arrayvalue objectAtIndex:8] intValue],[[arrayvalue objectAtIndex:9] intValue],[[arrayvalue objectAtIndex:10]intValue ],[[arrayvalue objectAtIndex:11]intValue],[arrayvalue objectAtIndex:12]];
char *err1;
if (sqlite3_exec(myDatabase,[sql1 UTF8String],NULL,NULL,&err1)==SQLITE_OK)
{
NSLog(#"value inserted:");
UIAlertView *alert=[[UIAlertView alloc]initWithTitle:#"Attention" message:#"You inserted successfully" delegate:self cancelButtonTitle:nil otherButtonTitles:#"Ok", nil];
[alert show];
[alert release];
}
[sql1 release];
sqlite3_close(myDatabase);
}
}

Answer 2

you need to connect to a database
- (sqlite3 *)database {
if (nil == db) {
NSString *path = <path to your database>;
int res = sqlite3_open([path UTF8String], &db);
if (res != SQLITE_OK){
// handle the error.
db = nil;
return nil;
}
}
return db;
}
then you can call this with the query
-(void)executeQuery:(NSString *)query{
sqlite3_stmt *statement;
if (sqlite3_prepare_v2([self database], [query UTF8String], -1, &statement, NULL) == SQLITE_OK) {
sqlite3_step(statement);
}else{
// handle the error.
}
sqlite3_finalize(statement);
}
-(void)dealloc {
//close database connection
sqlite3_close(db);
db = nil;
[super dealloc];
}

Answer 3

-(NSArray *) executeSelect:(NSString *)query {
//Data search block****************************************
char *zErrMsg;
char **result;
int nrow, ncol;
sqlite3_get_table(
[self database], /* An open database */
[query UTF8String], /* SQL to be executed */
&result, /* Result written to a char *[] that this points to */
&nrow, /* Number of result rows written here */
&ncol, /* Number of result columns written here */
&zErrMsg /* Error msg written here */
);
NSMutableArray *returnArray = [NSMutableArray arrayWithCapacity:3];
for (int i=0; i<nrow; i++){
[returnArray addObject:[NSString stringWithUTF8String:result[ncol + i]]];
}
sqlite3_free_table(result);
return returnArray;
}

Answer 4

Hi
if Your getting user inputs in userinput textfield
NSString *qry=[NSString stringwithformat:#"insert into abc(name) values (\"%#\")",userinput.text];
const char *sql = [qry UTF8string];
sqlite3 *contactDB;
const char *dbpath = [databasePath UTF8String]; // Convert NSString to UTF-8
if (sqlite3_open(dbpath, &contactDB) == SQLITE_OK)
{
if (sqlite3_exec(contactDB, sql_stmt, NULL, NULL, &errMsg) == SQLITE_OK)
{ // SQL statement execution succeeded
}
} else {
//Failed to open database
}