I have a page of nested ULs and LIs, I need to get the last LI of each UL, so I'm doing:
$('li:last-child')
this works great.
But I need to extend this so it gets the last child LI of each UL, where the LI doesn't have a given class (x). For example:
<ul>
<li class="x">1</li>
<li>2</li>
<li class="x">3</li>
<li>4</li>
<li>5</li>
<li class="x">
6
<ul>
<li class="x">7</li>
<li>8</li>
<li class="x">9</li>
<li>10</li>
<li>11</li>
<li class="x">12</li>
<li class="x">13</li>
</ul>
</li>
</ul>
I need to return LI 5 and 11 (as these are the last children within their parent ul that don't have .x)
How can I do this elegantly?
Use the map()(docs) method to create a jQuery object by iterating over the <ul> elements, and returning the last child <li> element without an x class.
Example: http://jsfiddle.net/e2Da7/2/
var lastLisNoX = $('ul').map(function() {
return $(this).children('li:not(.x)').get(-1);
});
EDIT: Updated my jsFiddle example with the HTML that was posted in the question.
Filter out the elements with a class.
$('li:not(.x):last-child')
If the classes are different amongst the li elements, that is if all the elements are not class="x" then something like
$('li[class=""]:last-child')
Related
I have to write a specific selector in jQuery it has to choose all elements in numeric list (with given class "a") which has class "b" and no links inside. And them give them certain class(which give them certain formatting).
So for example for such list:
<ol class="a">
<li>List element</li>
<li class="b">List element</div></li>
<li class="b">List element</a></li>
</ol>
Only the last element should get that class.
Though when I tried to do it like this:
$('ol.a li.b:not(a)').addClass('someclass');
then the second element gets that class too.
I also tried to do this with space before ":not(a)", but this way nothing get that class.
Is this what you're looking for? I think I understood what you were asking. Please let me know if it's not so I can amend my answer. :)
Essentially 'ol.a li.b:not(:has(a))' means to search for an ordered list with a class of a, with any descendent li item with a class of b that doesn't have any children that are an anchor a.
const nonLinks = $('ol.a li.b:not(:has(a))');
nonLinks.addClass("red");
.red {
color: red;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ol class="a">
<li>First</li>
<li class="b">Second Element</li>
<li class="b">Shouldn't Be Included</li>
</ol>
HTML:
<div id="my-id">
<li class="list_element">
<div class="my_class"></div>
</li>
<li class="list_element">
<div class="another_class"></div>
</li>
<li class="list_element">
<div class="class3"></div>
</li>
</div>
What I want to do with behat/mink:
$page = $this->getSession()->getPage();
$selector = $page->find('css', "#my-id .my_class"); //here I need anchor element located near to .my_class div.
I don't know in which one .list_element .my_class div is. I know only anchor is next to .my_class element. Which selector should I use in the find() function?
Try one of these:
#my-id .my_class ~ a
#my-id .my_class + p
#my-id .list_element a
This is too basic question.Please see more here w3schools
<ul class="parent">
<li class="abc">1</li>
<li class="abc">2</li>
</ul>
How to select li which have the same class as other?
$('./ul[#class="parent"]/li[contains(text(),"1")]') This is a way you can select any li using text function
This will also work:
$('//ul[#class="parent"]/li[1]') #Targets the first "<li>".
$('//ul[#class="parent"]/li[2]') #Targets the second "<li>".
Can I execute that line of code
nav = request().path().toString()
inside of scala template like index.scala.html
I would like to have that code to check on witch side is user and to mark it on menu
using code like this in main.scala.html:
<li class="#("active".when(nav == "contact"))">
Contacts
</li>
I would recommend you different approach, create tag - resuable template, which takes Integer as an argument,
it will render menu and mark as an active different menuitem depends on value.
#(menuItem: Int)
<ul >
<li #if(menuItem==1){ class="active" } >
////
</li>
<li #if(menuItem==2){ class="active" }>
</li>
<li #if(menuItem==3){ class="active" }>
///
</li>
</ul>
from your contact page and any other page, call this tag with corresponding value, #views.html.tags.menu(1)
You can define variables like that if that is your question. If it is not your question than please try to explain your problem in more detail.
#nav = { #request().path().toString() }
I would like to generate ID's for an HTML list.
The list is generated dynamically from the database.
I cant use a for loop or the list.zipWithIndex function because my logic contains a few loops for the generation of the list already, in which the counter needs to be incremented too. I also tried it with the defining function, but its not allowed to reasign values like this: #{id = id + 1}
Whats the best way to accomplish the generation of Id's?
Thats part of the template (uniqueId needs to be replaced with an integer):
<div id="tree">
<ul>
<li id="uniqueId">
<a class="dashboard" href="/">Dashboard</a>
</li>
<li id="uniqueId">
<b>Products</b>
<ul id="uniqueId">
#for(cat <- Application.allCategories()) {
<li id="uniqueId">
<a class="name" href="#routes.Categories.getd(cat.id).url">#cat.name</a>
<ul>
#for(prod <- Application.allProducts()) {
<li id="uniqueId">
<a class="name" href="#routes.Product.getById(prod.id).url">#prod.name</a>
</li>
#*more code and the closing tags...*#
Use just ... object's id prefixed to make it unique, example for first listing:
#for(cat <- Application.allCategories()) {
<li id="cat_#cat.id">
for second:
#for(prod <- Application.allProducts()) {
<li id="prod_#prod.id">
or if the same product can be displayed in several categories prefix it with cat.id as well:
#for(cat <- Application.allCategories()) {
<li id="cat_#cat.id">
#for(prod <- Application.allProducts()) {
<li id="prod_#(cat.id)_#(prod.id)">