Switch Case in T-SQL In where Clause - tsql

Why this doesn't work? Please help.
SELECT X
FROM Y
WHERE Z >= 5
AND A IN (CASE #someParameter when 1 THEN (5) ELSE (4,5) END)
Where as below works
SELECT X
FROM Y
WHERE Z >= 5
AND A = (CASE #someParameter when 1 THEN 5 ELSE 4 END)


You could accomplish that without case, like:
WHERE Z >= 5
AND (
#SomeParameter = 1 AND A = 5
OR
#SomeParameter <> 1 AND A IN (4,5)
)


You can have select statement instead of mentioning numbers directly. I ahven't tried executing it. But the idea is to get the required number set by using select query inside your brackets.
SELECT X
FROM Y
WHERE Z >= 5
AND A IN (CASE #someParameter when 1 THEN (SELECT 4) ELSE (SELECT 4 UNION SELECT 5) END)


You can't return a set, range, or table (or anything else you want to call multiple values) from a CASE statement. That (4,5) expression is just not allowed. My advice instead is to build these values as a small lookup table you can select from.


SELECT X
FROM Y
WHERE Z >= 5
AND
CASE #someParameter
when 1 THEN A = 5
ELSE (A = 4 OR A = 5)
END
Note: I haven't tried this syntax. My guess is that this should work.

Related

Sum two columns values in same table on postgresql query

SELECT c.period,
c.idsr_incident_id_id,
c.idsr_disease_id_id,
CASE WHEN idsr_incident_id_id = 1 OR idsr_incident_id_id = 3 THEN SUM(c.data_value::integer) ELSE 0 END AS cases,
CASE WHEN idsr_incident_id_id = 2 OR idsr_incident_id_id = 4 THEN SUM(c.data_value::integer) ELSE 0 END AS deaths
FROM veoc_idsr_weekly_national_report c
LEFT JOIN veoc_idsr_diseases b ON b.id = c.idsr_disease_id_id
LEFT JOIN veoc_idsr_reported_incidents j ON j.id = c.idsr_incident_id_id
WHERE c.idsr_incident_id_id >= 1 AND c.idsr_incident_id_id <= 4 AND idsr_disease_id_id = 10 AND period ='2019W30'
GROUP BY c.period, c.idsr_incident_id_id, c.idsr_disease_id_id, c.data_value;`enter code here`
Below my query results:
I want to sum the cases and the death value columns since the period and disease_id is the same. I think my problem is on the Group By section but I cant solve it. If it means i must remove the incident_id column to get the totals it will still be fine.

Please, try with below query where sum of function place replaced:
SELECT c.period,
c.idsr_disease_id_id,
SUM(CASE WHEN idsr_incident_id_id = 1 OR idsr_incident_id_id = 3 THEN (c.data_value::integer) ELSE 0 END) AS cases,
SUM(CASE WHEN idsr_incident_id_id = 2 OR idsr_incident_id_id = 4 THEN (c.data_value::integer) ELSE 0 END) AS deaths
FROM veoc_idsr_weekly_national_report c
LEFT JOIN veoc_idsr_diseases b ON b.id = c.idsr_disease_id_id
LEFT JOIN veoc_idsr_reported_incidents j ON j.id = c.idsr_incident_id_id
WHERE c.idsr_incident_id_id >= 1 AND c.idsr_incident_id_id <= 4 AND idsr_disease_id_id = 10 AND period ='2019W30'
GROUP BY c.period, c.idsr_disease_id_id;

T-SQL Two counts with different where clause

I want to count values on a table with different where clauses and wondering if there is a better way of doing it.
In this code i count one value.
SELECT v.name, count(v.value) AS v1
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value = 1
GROUP BY v.name
I also want to count all rows with value = 2
my way of doing it is like this with a sub select.
SELECT v.name, count(v.value) AS v1, (SELECT v2.name, count(v2.value)
FROM dbo.table as v2
WHERE v2.organisationID = 2
AND v2.datecreated > '2018-01-01'
AND v2.datecreated < '2018-05-01'
AND v2.value = 2
GROUP BY v2.name) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value = 1
GROUP BY v.name
The table contains > 100 millions rows so I really want the fastest way. I use clustered columnstore index on the table.
Is there some way of doing it whitout sub-select.
Pseudo code:
SELECT v.name, count(v.value where v.value=1) AS v1, count(v.value where v.value=2) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
GROUP BY v.name

Yes, just use a CASE expression:
SELECT v.name,
SUM(CASE WHEN v.value = 1 THEN 1 ELSE 0 END) AS v1,
SUM(CASE WHEN v.value = 2 THEN 1 ELSE 0 END) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value IN (1,2)
GROUP BY v.name
;

DB2 SQL, cant define column as

I have some SQLthat is part of that is a section of a with statement
And I keep getting an error that "NEWID" is not valid in the context where it is used sqlstate 42703.
Update: The error has been comming from the group by clause using a having function I didnt put in the original code as I thought it wasnt the issue.So I updated the code to show the full version.
Does anyone know what the problem is with the statement?
HATSTABLE1 (HATId, NewID) as (
select HA.HATId as "ID",
round(
cast(
sum(
case when HA.ID = 4 or
HA.ID < 0
then 1 else 0 end
) AS FLOAT
) / count(*) * 100,
2
) AS NewID
from Hats T
join Heads HD on
T.ID=HD.HatID
group by T.ID
having NewID >1

try it
with tmp as (
select T.HATId as "ID",
sum(case when T.ID = 4 or HA.ID < 0 then 1 else 0 end) as sum1,
count(*) as nb
from Hats T
group by T.HATId
)
select HATId, round(cast(sum1 as decimal)/ nb * 100, 2) NewID
from tmp

Check for equal amounts of negative numbers as positive numbers

I have a table with two columns: intGroupID, decAmount
I want to have a query that can basically return the intGroupID as a result if for every positive(+) decAmount, there is an equal and opposite negative(-) decAmount.
So a table of (id=1,amount=1.0),(1,2.0),(1,-1.0),(1,-2.0) would return back the intGroupID of 1, because for each positive number there exists a negative number to match.
What I know so far is that there must be an equal number of decAmounts (so I enforce a count(*) % 2 = 0) and the sum of all rows must = 0.0. However, some cases that get by that logic are:
ID | Amount
1 | 1.0
1 | -1.0
1 | 2.0
1 | -2.0
1 | 3.0
1 | 2.0
1 | -4.0
1 | -1.0
This has a sum of 0.0 and has an even number of rows, but there is not a 1-for-1 relationship of positives to negatives. I need a query that can basically tell me if there is a negative amount for each positive amount, without reusing any of the rows.
I tried counting the distinct absolute values of the numbers and enforcing that it is less than the count of all rows, but it's not catching everything.
The code I have so far:
DECLARE #tblTest TABLE(
intGroupID INT
,decAmount DECIMAL(19,2)
);
INSERT INTO #tblTest (intGroupID ,decAmount)
VALUES (1,-1.0),(1,1.0),(1,2.0),(1,-2.0),(1,3.0),(1,2.0),(1,-4.0),(1,-1.0);
DECLARE #intABSCount INT = 0
,#intFullCount INT = 0;
SELECT #intFullCount = COUNT(*) FROM #tblTest;
SELECT #intABSCount = COUNT(*) FROM (
SELECT DISTINCT ABS(decAmount) AS absCount FROM #tblTest GROUP BY ABS(decAmount)
) AS absCount
SELECT t1.intGroupID
FROM #tblTest AS t1
/* Make Sure Even Number Of Rows */
INNER JOIN
(SELECT COUNT(*) AS intCount FROM #tblTest
)
AS t2 ON t2.intCount % 2 = 0
/* Make Sure Sum = 0.0 */
INNER JOIN
(SELECT SUM(decAmount) AS decSum FROM #tblTest)
AS t3 ON decSum = 0.0
/* Make Sure Count of Absolute Values < Count of Values */
WHERE
#intABSCount < #intFullCount
GROUP BY t1.intGroupID
I think there is probably a better way to check this table, possibly by finding pairs and removing them from the table and seeing if there's anything left in the table once there are no more positive/negative matches, but I'd rather not have to use recursion/cursors.

Create TABLE #tblTest (
intA INT
,decA DECIMAL(19,2)
);
INSERT INTO #tblTest (intA,decA)
VALUES (1,-1.0),(1,1.0),(1,2.0),(1,-2.0),(1,3.0),(1,2.0),(1,-4.0),(1,-1.0), (5,-5.0),(5,5.0) ;
SELECT * FROM #tblTest;
SELECT
intA
, MIN(Result) as IsBalanced
FROM
(
SELECT intA, X,Result =
CASE
WHEN count(*)%2 = 0 THEN 1
ELSE 0
END
FROM
(
---- Start thinking here --- inside-out
SELECT
intA
, x =
CASE
WHEN decA < 0 THEN
-1 * decA
ELSE
decA
END
FROM #tblTest
) t1
Group by intA, X
)t2
GROUP BY intA

Not tested but I think you can get the idea
This returns the id that do not conform
The not is easier to test / debug
select pos.*, neg.*
from
( select id, amount, count(*) as ccount
from tbl
where amount > 0
group by id, amount ) pos
full outer join
( select id, amount, count(*) as ccount
from tbl
where amount < 0
group by id, amount ) neg
on pos.id = neg.id
and pos.amount = -neg.amount
and pos.ccount = neg.ccount
where pos.id is null
or neg.id is null
I think this will return a list of id that do conform
select distinct(id) from tbl
except
select distinct(isnull(pos.id, neg.id))
from
( select id, amount, count(*) as ccount
from tbl
where amount > 0
group by id, amount ) pos
full outer join
( select id, amount, count(*) as ccount
from tbl
where amount < 0
group by id, amount ) neg
on pos.id = neg.id
and pos.amount = -neg.amount
and pos.ccount = neg.ccount
where pos.id is null
or neg.id is null

Boy, I found a simpler way to do this than my previous answers. I hope all my crazy edits are saved for posterity.
This works by grouping all numbers for an id by their absolute value (1, -1 grouped by 1).
The sum of the group determines if there are an equal number of pairs. If it is 0 then it is equal, any other value for the sum means there is an imbalance.
The detection of evenness by the COUNT aggregate is only necessary to detect an even number of zeros. I assumed that 0's could exist and they should occur an even number of times. Remove it if this isn't a concern, as 0 will always pass the first test.
I rewrote the query a bunch of different ways to get the best execution plan. The final result below only has one big heap sort which was unavoidable given the lack of an index.
Query
WITH tt AS (
SELECT intGroupID,
CASE WHEN SUM(decAmount) > 0 OR COUNT(*) % 2 = 1 THEN 1 ELSE 0 END unequal
FROM #tblTest
GROUP BY intGroupID, ABS(decAmount)
)
SELECT tt.intGroupID,
CASE WHEN SUM(unequal) != 0 THEN 'not equal' ELSE 'equals' END [pair]
FROM tt
GROUP BY intGroupID;
Tested Values
(1,-1.0),(1,1.0),(1,2),(1,-2), -- should work
(2,-1.0),(2,1.0),(2,2),(2,2), -- fail, two positive twos
(3,1.0),(3,1.0),(3,-1.0), -- fail two 1's , one -1
(4,1),(4,2),(4,-.5),(4,-2.5), -- fail: adds up the same sum, but different values
(5,1),(5,-1),(5,0),(5,0), -- work, test zeros
(6,1),(6,-1),(6,0), -- fail, test zeros
(7,1),(7,-1),(7,-1),(7,1),(7,1) -- fail, 3 x 1
Results
A pairs
_ _____
1 equal
2 not equal
3 not equal
4 not equal
5 equal
6 not equal
7 not equal

The following should return "disbalanced" groups:
;with pos as (
select intGroupID, ABS(decAmount) m
from TableName
where decAmount > 0
), neg as (
select intGroupID, ABS(decAmount) m
from TableName
where decAmount < 0
)
select distinct IsNull(p.intGroupID, n.intGroupID) as intGroupID
from pos p
full join neg n on n.id = p.id and abs(n.m - p.m) < 1e-8
where p.m is NULL or n.m is NULL
to get unpaired elements, select satement can be changed to following:
select IsNull(p.intGroupID, n.intGroupID) as intGroupID, IsNull(p.m, -n.m) as decAmount
from pos p
full join neg n on n.id = p.id and abs(n.m - p.m) < 1e-8
where p.m is NULL or n.m is NULL

Does this help?
-- Expected result - group 1 and 3
declare #matches table (groupid int, value decimal(5,2))
insert into #matches select 1, 1.0
insert into #matches select 1, -1.0
insert into #matches select 2, 2.0
insert into #matches select 2, -2.0
insert into #matches select 2, -2.0
insert into #matches select 3, 3.0
insert into #matches select 3, 3.5
insert into #matches select 3, -3.0
insert into #matches select 3, -3.5
insert into #matches select 4, 4.0
insert into #matches select 4, 4.0
insert into #matches select 4, -4.0
-- Get groups where we have matching positive/negatives, with the same number of each
select mat.groupid, min(case when pos.PositiveCount = neg.NegativeCount then 1 else 0 end) as 'Match'
from #matches mat
LEFT JOIN (select groupid, SUM(1) as 'PositiveCount', Value
from #matches where value > 0 group by groupid, value) pos
on pos.groupid = mat.groupid and pos.value = ABS(mat.value)
LEFT JOIN (select groupid, SUM(1) as 'NegativeCount', Value
from #matches where value < 0 group by groupid, value) neg
on neg.groupid = mat.groupid and neg.value = case when mat.value < 0 then mat.value else mat.value * -1 end
group by mat.groupid
-- If at least one pair within a group don't match, reject
having min(case when pos.PositiveCount = neg.NegativeCount then 1 else 0 end) = 1

You can compare your values this way:
declare #t table(id int, amount decimal(4,1))
insert #t values(1,1.0),(1,-1.0),(1,2.0),(1,-2.0),(1,3.0),(1,2.0),(1,-4.0),(1,-1.0),(2,-1.0),(2,1.0)
;with a as
(
select count(*) cnt, id, amount
from #t
group by id, amount
)
select id from #t
except
select b.id from a
full join a b
on a.cnt = b.cnt and a.amount = -b.amount
where a.id is null
For some reason i can't write comments, however Daniels comment is not correct, and my solution does accept (6,1),(6,-1),(6,0) which can be correct. 0 is not specified in the question and since it is a 0 value it can be handled eather way. My answer does NOT accept (3,1.0),(3,1.0),(3,-1.0)
To Blam: No I am not missing
or b.id is null
My solution is like yours, but not exactly identical

Summing From Consecutive Rows

Assume we have a table and we want to do a sum of the Expend column so that the summation only adds up values of the same Week_Name.
SN Week_Name Exp Sum
-- --------- --- ---
1 Week 1 10 0
2 Week 1 20 0
3 Week 1 30 60
4 Week 2 40 0
5 Week 2 50 90
6 Week 3 10 0
I will assume we will need to `Order By' Week_Name, then compare the previous Week_Name(previous row) with the current row Week_name(Current row).
If both are the same, put zero in the SUM column.
If not the same, add all expenditure, where Week_Name = Week_Name(Previous row) and place in the Sum column. The final output should look like the table above.
Any help on how to achieve this in T-SQL is highly appreciated.

Okay, I was eventually able to resolve this issue, praise Jesus! If you want the exact table I gave above, you can use GilM's response below, it is perfect. If you want your table to have running Cumulatives, i.e. Rows 3 shoud have 60, Row 5, should have 150, Row 6 160 etc. Then, you can use my code below:
USE CAPdb
IF OBJECT_ID ('dbo.[tablebp]') IS NOT NULL
DROP TABLE [tablebp]
GO
CREATE TABLE [tablebp] (
tablebpcCol1 int PRIMARY KEY
,tabledatekey datetime
,tableweekname varchar(50)
,expenditure1 numeric
,expenditure_Cummulative numeric
)
INSERT INTO [tablebp](tablebpcCol1,tabledatekey,tableweekname,expenditure1,expenditure_Cummulative)
SELECT b.s_tablekey,d.PK_Date,d.Week_Name,
SUM(b.s_expenditure1) AS s_expenditure1,
SUM(b.s_expenditure1) + COALESCE((SELECT SUM(s_expenditure1)
FROM source_table bs JOIN dbo.Time dd ON bs.[DATE Key] = dd.[PK_Date]
WHERE dd.PK_Date < d.PK_Date),0)
FROM source_table b
INNER JOIN dbo.Time d ON b.[Date key] = d.PK_Date
GROUP BY d.[PK_Date],d.Week_Name,b.s_tablekey,b.s_expenditure1
ORDER BY d.[PK_Date]
;WITH CTE AS (
SELECT tableweekname
,Max(expenditure_Cummulative) AS Week_expenditure_Cummulative
,MAX(tablebpcCol1) AS MaxSN
FROM [tablebp]
GROUP BY tableweekname
)
SELECT [tablebp].*
,CASE WHEN [tablebp].tablebpcCol1 = CTE.MaxSN THEN Week_expenditure_Cummulative
ELSE 0 END AS [RunWeeklySum]
FROM [tablebp]
JOIN CTE on CTE.tableweekname = [tablebp].tableweekname

I'm not sure why your SN=6 line is 0 rather than 10. Do you really not want the sum for the last Week? If having the last week total is okay, then you might want something like:
;WITH CTE AS (
SELECT Week_Name,SUM([Expend.]) as SumExpend
,MAX(SN) AS MaxSN
FROM T
GROUP BY Week_Name
)
SELECT T.*,CASE WHEN T.SN = CTE.MaxSN THEN SumExpend
ELSE 0 END AS [Sum]
FROM T
JOIN CTE on CTE.Week_Name = T.Week_Name
Based on the requst in the comment wanting a running total in SUM you could try this:
;WITH CTE AS (
SELECT Week_Name, MAX(SN) AS MaxSN
FROM T
GROUP BY Week_Name
)
SELECT T.SN, T.Week_Name,T.Exp,
CASE WHEN T.SN = CTE.MaxSN THEN
(SELECT SUM(EXP) FROM T T2
WHERE T2.SN <= T.SN) ELSE 0 END AS [SUM]
FROM T
JOIN CTE ON CTE.Week_Name = T.Week_Name
ORDER BY SN