PowerShell's Get-ADGroupMember cmdlet returns members of a specific group. Is there a cmdlet or property to get all the groups that a particular user is a member of?
I fixed my mistake: Get-Member should be Get-ADGroupMember.
Get-ADPrincipalGroupMembership will do this.
Get-ADPrincipalGroupMembership username | select name
name
----
Domain Users
Domain Computers
Workstation Admins
Company Users
Company Developers
AutomatedProcessingTeam
Single line, no modules necessary, uses current logged user:
(New-Object System.DirectoryServices.DirectorySearcher("(&(objectCategory=User)(samAccountName=$($env:username)))")).FindOne().GetDirectoryEntry().memberOf
Kudos to this vbs/powershell article: http://technet.microsoft.com/en-us/library/ff730963.aspx
A more concise alternative to the one posted by Canoas, to get group membership for the currently-logged-on user.
I came across this method in this blog post: http://www.travisrunyard.com/2013/03/26/auto-create-outlook-mapi-user-profiles/
([ADSISEARCHER]"samaccountname=$($env:USERNAME)").Findone().Properties.memberof
An even better version which uses a regex to strip the LDAP guff and leaves the group names only:
([ADSISEARCHER]"samaccountname=$($env:USERNAME)").Findone().Properties.memberof -replace '^CN=([^,]+).+$','$1'
More details about using the [ADSISEARCHER] type accelerator can be found on the scripting guy blog: http://blogs.technet.com/b/heyscriptingguy/archive/2010/08/24/use-the-powershell-adsisearcher-type-accelerator-to-search-active-directory.aspx
Old school way from CMD:
net user mst999 /domain
(GET-ADUSER –Identity USERNAME –Properties MemberOf | Select-Object MemberOf).MemberOf
This should provide you the details for current user. Powershell not needed.
whoami /groups
If you cannot get Get-ADPrincipalGroupMembership to work for you could try logging in as that user then use.
$id = [Security.Principal.WindowsIdentity]::GetCurrent()
$groups = $id.Groups | foreach-object {$_.Translate([Security.Principal.NTAccount])}
$groups | select *
While there are many excellent answers here, there is one which I was personally looking for that was missing. Once I figured it out - I thought I should post it in case I want to find it later, or it actually manages to help someone else at some point:
Get-ADPrincipalGroupMembership username | Format-Table -auto
A second approach for presenting this is to specify the individual columns you are interested in eg:
Get-ADPrincipalGroupMembership username | select name, GroupScope, GroupCategory
This gives all the AD groups the username belongs to - but also presents all of the default properties of each group formatted nicely as a table.
The key benefit this gives you is you can see at a glance which are distribution lists, & which are Security groups. You can further see at a glance which are Universal, which are DomainLocal & which are Global.
Why would you care about this last bit?
Universal group is a security or distribution group that contains
users, groups, and computers from any domain in its forest as
members. You can give universal security groups rights and
permissions on resources in any domain in the forest.
Global group is a group that can be used in its own domain, in member
servers and in workstations of the domain, and in trusting domains.
In all those locations, you can give a global group rights and
permissions and the global group can become a member of local groups.
However, a global group can contain user accounts that are only from
its own domain.
Domain local group is a security or distribution group that can
contain universal groups, global groups, other domain local groups
from its own domain, and accounts from any domain in the forest. You
can give domain local security groups rights and permissions on
resources that reside only in the same domain where the domain local
group is located.
Get-Member is not for getting user's group membership. If you want to get a list of groups a user belongs to on the local system, you can do so by:
$query = "ASSOCIATORS OF {Win32_Account.Name='DemoUser1',Domain='DomainName'} WHERE ResultRole=GroupComponent ResultClass=Win32_Account"
Get-WMIObject -Query $query | Select Name
In the above query, replace DemoUser1 with the username you want and the DomainName with either your local computer name or domain name.
Get group membership for a user:
$strUserName = "Primoz"
$strUser = get-qaduser -SamAccountName $strUserName
$strUser.memberof
See Get Group Membership for a User
But also see Quest's Free PowerShell Commands for Active Directory.
[Edit: Get-ADPrincipalGroupMembership command is included in Powershell since v2 with Windows 2008 R2. See kstrauss' answer below.]
Get-Member is a cmdlet for listing the members of a .NET object. This has nothing to do with user/group membership. You can get the current user's group membership like so:
PS> [System.Security.Principal.WindowsIdentity]::GetCurrent().Groups |
Format-Table -auto
BinaryLength AccountDomainSid Value
------------ ---------------- -----
28 S-1-5-21-... S-1-5-21-2229937839-1383249143-3977914998-513
12 S-1-1-0
28 S-1-5-21-... S-1-5-21-2229937839-1383249143-3977914998-1010
28 S-1-5-21-... S-1-5-21-2229937839-1383249143-3977914998-1003
16 S-1-5-32-545
...
If you need access to arbitrary users' group info then #tiagoinu suggestion of using the Quest AD cmdlets is a better way to go.
I wrote a PowerShell function called Get-ADPrincipalGroupMembershipRecursive. It accepts the DSN of a user, computer, group, or service account. It retrieves an initial list of groups from the account's memberOf attribute, then recursively checks those group's memberships. Abbreviated code is below. Full source code with comments can be found here.
function Get-ADPrincipalGroupMembershipRecursive( ) {
Param(
[string] $dsn,
[array]$groups = #()
)
$obj = Get-ADObject $dsn -Properties memberOf
foreach( $groupDsn in $obj.memberOf ) {
$tmpGrp = Get-ADObject $groupDsn -Properties memberOf
if( ($groups | where { $_.DistinguishedName -eq $groupDsn }).Count -eq 0 ) {
$groups += $tmpGrp
$groups = Get-ADPrincipalGroupMembershipRecursive $groupDsn $groups
}
}
return $groups
}
# Simple Example of how to use the function
$username = Read-Host -Prompt "Enter a username"
$groups = Get-ADPrincipalGroupMembershipRecursive (Get-ADUser $username).DistinguishedName
$groups | Sort-Object -Property name | Format-Table
No need for long scripts when it is a simple one liner..
QUEST Command
(Get-QADUser -Identity john -IncludedProperties MemberOf | Select-Object MemberOf).MemberOf
MS AD Command
(GET-ADUSER –Identity john –Properties MemberOf | Select-Object MemberOf).MemberOf
I find the MS AD cmd is faster but some people like the Quest ones better..
Steve
Use:
Get-ADPrincipalGroupMembership username | select name | export-CSV username.csv
This pipes output of the command into a CSV file.
First, import the ActiveDirectory module:
Import-Module ActiveDirectory
Then issue this command:
Get-ADGroupMember -Identity $group | foreach-object {
Write-Host $_.SamAccountName
}
This will display the members of the specified group.
It is just one line:
(get-aduser joe.bloggs -properties *).memberof
end of :)
The below works well:
get-aduser $username -Properties memberof | select -expand memberof
If you have a list of users:
$list = 'administrator','testuser1','testuser2'
$list | `
%{
$user = $_;
get-aduser $user -Properties memberof | `
select -expand memberof | `
%{new-object PSObject -property #{User=$user;Group=$_;}} `
}
Get-QADUser -SamAccountName LoginID | % {$_.MemberOf } | Get-QADGroup | select name
Get-ADUser -Filter { memberOf -RecursiveMatch "CN=Administrators,CN=Builtin,DC=Fabrikam,DC=com" } -SearchBase "CN=Administrator,CN=Users,DC=Fabrikam,DC=com" -SearchScope Base
## NOTE: The above command will return the user object (Administrator in this case) if it finds a match recursively in memberOf attribute.
I couldn't get the following to work for a particular user:
Get-ADPrincipalGroupMembership username
It threw an error that I was not willing to troubleshoot.
I did however come up with a different solution using Get-ADUser. I like it a bit better because if you don't know the account name then you can get it based off of a wildcard on the user's actual name. Just fill in PartOfUsersName and away it goes.
#Get the groups that list of users are the member of using a wildcard search
[string]$UserNameLike = "*PartOfUsersName*" #Use * for wildcards here
[array]$AccountNames = $(Get-ADUser -Filter {Name -like $UserNameLike}).SamAccountName
ForEach ($AccountName In $AccountNames) {
Write-Host "`nGETTING GROUPS FOR" $AccountName.ToUpper() ":"
(Get-ADUser -Identity $AccountName -Properties MemberOf|select MemberOf).MemberOf|
Get-ADGroup|select Name|sort name
}
Huge props to schmeckendeugler and 8DH for getting me to this solution. +1 to both of you.
To get it recursive, you can use:
<#
.SYNOPSIS
Get all the groups that a user is MemberOf.
.DESCRIPTION
This script retrieves all the groups that a user is MemberOf in a recursive way.
.PARAMETER SamAccountName
The name of the user you want to check #>
Param (
[String]$SamAccountName = 'test',
$DomainUsersGroup = 'CN=Domain Users,CN=Users,DC=domain,DC=net'
)
Function Get-ADMemberOf {
Param (
[Parameter(ValueFromPipeline)]
[PSObject[]]$Group,
[String]$DomainUsersGroup = 'CN=Domain Users,CN=Users,DC=grouphc,DC=net'
)
Process {
foreach ($G in $Group) {
$G | Get-ADGroup | Select -ExpandProperty Name
Get-ADGroup $G -Properties MemberOf| Select-Object Memberof | ForEach-Object {
Get-ADMemberOf $_.Memberof
}
}
}
}
$Groups = Get-ADUser $SamAccountName -Properties MemberOf | Select-Object -ExpandProperty MemberOf
$Groups += $DomainUsersGroup
$Groups | Get-ADMemberOf | Select -Unique | Sort-Object
Studying all comments presented gave me a starting point (thanks for such) but left me with several unresolved issues. As result here is my answer. The code snippet provided does a little more than what is asked for but it provides helpful debugging info.
[array] $script:groupsdns = #()
function Get-ADPrincipalGroupMembershipRecursive()
{
Param( [string] $dn, [int] $level = 0, [array] $groups = #() )
#if(($groupsdns | where { $_.DistinguishedName -eq $dn }).Count -ne 0 ) { return $groups } # dependency on next statement
#$groupsdns += (Get-ADObject $dn -Properties MemberOf) # Get-ADObject cannot find an object with identity
if ($script:groupsdns.Contains($dn)) { return $groups }
$script:groupsdns += $dn
$mo = $Null
$mo = Get-ADObject $dn -Properties MemberOf # Get-ADObject cannot find an object with identity
$group = ($dn + " (" + $level.ToString())
if ($mo -eq $Null) { $group += "!" }
$group += ")"
$groups += $group
foreach( $groupdn in $mo.MemberOf )
{
$groups = Get-ADPrincipalGroupMembershipRecursive -dn $groupdn -level ($level+1) -groups $groups
}
if ($level -le 0)
{
$primarygroupdn = (Get-ADUser -Identity $dn -Properties PrimaryGroup).PrimaryGroup
$groups = Get-ADPrincipalGroupMembershipRecursive -dn $primarygroupdn -level ($level+1) -groups $groups
}
return $groups
}
$adusergroups = Get-ADPrincipalGroupMembershipRecursive -dn $aduser.DistinguishedName
$adusergroups | ft -AutoSize | `
Out-File -Width 512 Get-ADPrincipalGroupMembershipRecursive.txt #-Append #-Wrap # | Sort-Object -Property Name
When you do not have privileges to consult other member groups but you do have the privilege to consult group members, you can do the following to build a map of which user has access to which groups.
$groups = get-adgroup -Filter * | sort name | select Name
$users = #{}
foreach($group in $groups) {
$groupUsers = #()
$groupUsers = Get-ADGroupMember -Identity $group.Name | Select-Object SamAccountName
$groupUsers | % {
if(!$users.ContainsKey($_.SamAccountName)){
$users[$_.SamAccountName] = #()
}
($users[$_.SamAccountName]) += ($group.Name)
}
}
For LOCAL users and groups (ie not in Active Directory), and if you don't want to, or aren't allowed to, or can't install RSAT and/or Install-WindowsFeature RSAT-AD-PowerShell and/or import-module activedirectory then here's a pure, pre-installed powershell (5.1+) way to do it.
(Note: Get-LocalGroup* used below are only available Powershell v5.1 and above. "...v5.1 was released along with the Windows 10 Anniversary Update on August 2, 2016, and in Windows Server 2016. ...[F]or Windows 7, Windows Server 2008, Windows Server 2008 R2, Windows Server 2012, and Windows Server 2012 R2 [it] was released on January 19, 2017." (wikipedia))
$username = "user002"
Get-LocalGroup | ForEach-Object {
# the usernames are returned in the string form "computername\username"
if (Get-LocalGroupMember -Group $_ | Where-Object name -like "*\$username") {
$_.name
}
}
Example output:
Administrators
Users
Import-Module ActiveDirectory
Get-ADUser -SearchBase "OU=Users,DC=domain,DC=local" -Filter * | foreach-object {
write-host "User:" $_.Name -foreground green
Get-ADPrincipalGroupMembership $_.SamAccountName | foreach-object {
write-host "Member Of:" $_.name
}
}
Change the value of -SearchBase to reflect the OU you need to list the users from :)
This will list all of the users in that OU and show you which groups they are a member of.
Get-ADPrincipalGroupMembership USERLOGON | select name
This is the simplest way to just get the names:
Get-ADPrincipalGroupMembership "YourUserName"
# Returns
distinguishedName : CN=users,OU=test,DC=SomeWhere
GroupCategory : Security
GroupScope : Global
name : testGroup
objectClass : group
objectGUID : 2130ed49-24c4-4a17-88e6-dd4477d15a4c
SamAccountName : testGroup
SID : S-1-5-21-2114067515-1964795913-1973001494-71628
Add a select statement to trim the response or to get every user in an OU every group they are a user of:
foreach ($user in (get-aduser -SearchScope Subtree -SearchBase $oupath -filter * -Properties samaccountName, MemberOf | select samaccountName)){
Get-ADPrincipalGroupMembership $user.samaccountName | select name}
Almost all above solutions used the ActiveDirecotry module which might not be available by default in most cases.
I used below method. A bit indirect, but served my purpose.
List all available groups
Get-WmiObject -Class Win32_Group
And then list the groups the user belongs to
[System.Security.Principal.WindowsIdentity]::GetCurrent().Groups
Comparison can then be done via checking through the SIDs. This works for the logged in user. Please correct me if I am wrong. Completely new to PowerShell, but had to get this done for a work commitment.
With user input and fancy output formatting:
[CmdletBinding(SupportsShouldProcess=$True)]
Param(
[Parameter(Mandatory = $True)]
[String]$UserName
)
Import-Module ActiveDirectory
If ($UserName) {
$UserName = $UserName.ToUpper().Trim()
$Res = (Get-ADPrincipalGroupMembership $UserName | Measure-Object).Count
If ($Res -GT 0) {
Write-Output "`n"
Write-Output "$UserName AD Group Membership:"
Write-Output "==========================================================="
Get-ADPrincipalGroupMembership $UserName | Select-Object -Property Name, GroupScope, GroupCategory | Sort-Object -Property Name | FT -A
}
}
Putting this here for future reference. I'm in the midst of an email migration. I need to know each user account and its respective group membership, and also I need to know each group and its respective members.
I'm using the code block below to output a CSV for each user's group membership.
Get-ADUser -Filter * |`
ForEach-Object { `
$FileName = $_.SamAccountName + ".csv" ; `
$FileName ; `
Get-ADPrincipalGroupMembership $_ | `
Select-Object -Property SamAccountName, name, GroupScope, GroupCategory | `
Sort-Object -Property SamAccountName | `
Export-Csv -Path $FileName -Encoding ASCII ; `
}
The export process for the groups and their respective members was a little convoluted, but the below works. The output filenames include the type of group. Therefore, the email distribution groups I need are/should be the Universal and Global Distribution groups. I should be able to just delete or move the resulting TXT files I don't need.
Get-ADGroup -Filter * | `
Select-Object -Property Name, DistinguishedName, GroupScope, GroupCategory | `
Sort-Object -Property GroupScope, GroupCategory, Name | `
Export-Csv -Path ADGroupsNew.csv -Encoding ASCII
$MyCSV = Import-Csv -Path .\ADGroupsNew.csv -Encoding ASCII
$MyCSV | `
ForEach-Object { `
$FN = $_.GroupScope + ", " + $_.GroupCategory + ", " + $_.Name + ".txt" ; `
$FN ; `
Get-ADGroupMember -Identity $_.DistinguishedName | `
Out-File -FilePath $FN -Encoding ASCII ; $FN=""; `
}
Related
Was wondering if you could help me with script.
This script would search a specific OU (let's say Disabled Users OU) and display all the AD groups
all users are part of, the output to a CSV file showing Usernames and AD group names.
I have got a command that will display all AD groups of a user but I have to keep changing the username:
Get-ADPrincipalGroupMembership username_withoutdomain | select name
I have a script that requires the username entered and will display the AD group membership.
do {
write-host -NoNewline "Type username: "
$user = read-host
if ($user -eq "") { break }
(get-aduser $user -Properties memberof).memberof |
get-adgroup |
select -exp name
} while ($true)
I also know it is possible to do this via command prompt:
net userusername
Thanks for all assistance.
You can query all users under an OU by using the -SearchBase parameter, from there you can enumerate each user and then enumerate each group the user is a memberOf to generate your report:
$base = 'OU=disabledUsers,DC=domain,DC=com'
Get-ADUser -Filter * -SearchBase $base -Properties memberOf |
ForEach-Object {
foreach($group in $_.memberOf) {
[pscustomobject]#{
User = $_.Name
SamAccountName = $_.SamAccountName
MemberOf = $group -replace '^CN=|(?<!\\),.+'
}
}
} | Export-Csv path\to\report.csv -NoTypeInformation
As Santiago already stated you can query your OU with the -SearchBase.
And because the user and the group membership can not be queried with one command you have to create a table as Santiago points with [pscustomobject]#{...}
When I was running a daily report on users and their group membership I was running the script:
function Get-ADUserGroups{
#$Domain = 'Domain_name'
$users= Get-AdUser -Filter * -Properties SamAccountName, DisplayName, Description -ResultPageSize 500 |
select SamAccountName, DisplayName, Description
$users|
ForEach-Object{
$p=[ordered]#{
UserName=$_.SamAccountName
FullName=$_.DisplayName
User_Description=$_.Description
GroupName=$null
Group_Description=$null
}
Get-ADPrincipalGroupMembership $_.SamAccountName |
ForEach-Object{
$p.GroupName=$_.Name
Get-ADGroup $_ -Properties description |
ForEach-Object{
New-Object PsObject -Property $p
}
}
}
}
Get-ADUserGroups | Export-Csv -Path "Your_Path\Groups.csv" -Delimiter "|" -Encoding UTF8 -NoTypeInformation
I am trying to get a CSV output of all the users in the 'VPN Users' group that are also in the 'Domain Users' group. I'd like it to give their name and then their group membership. Each member should only be in the VPN group. I am looking to identify who is in both groups.
To achieve this I have first exported a list of the users in the VPN Group to a CSV which works fine. Second part of the code is meant to go through the list of users in the CSV from that AD group and export an output as a CSV containing the users and their group membership which isn't working for me. For each user in the CSV it returns the error: Get-ADUser : Cannot find an object with identity: '"User001_vpn"'.....
I'm not sure if the way I'm going about it is the best way to achieve the task in hand or if any of you might be able to help me make it work? It seems like Get-ADUser isn't finding the users from the CSV.
#Retrieves list of users that are in the VPN Users group and exports them into a CSV
(Get-ADGroupMember "VPN Users" -Recursive | Get-ADUser -Properties * |
Select-Object SamAccountName |
ConvertTo-Csv -NoTypeInformation) |
Select-Object -Skip 1 |
Set-Content -Path "C:\Documents\VPN Users Report\VPNUsers.csv”
Get-Content “C:\Documents\VPN Users Report\VPNUsers.csv” | Get-ADUser | ForEach{
$user = $_
$groups = Get-ADPrincipalGroupMembership $user
$groups | %{ New-Object PSObject -Property #{ User = $user.SamAccountName; Group = $_.SamAccountName } }
} | Export-Csv "C:\VPN Users Report\Results\Output.csv"
I believe the problem is with the quotes, since you are using ConvertTo-Csv while retrieving the users, all user SamAccountNames will be quoted.
Afterwards you read this csv file using Get-Content, not Import-Csv, so the quotes will not be removed and you have user names like "User001_vpn" instead of User001_vpn
You do not have to use this 'in-between' cvs at all and on second thought, you can leave out Get-ADUser too unless you want other properties from these users than what Get-ADGroupMember already returns (i.e. distinguishedName, name, objectClass, objectGUID, SamAccountName, SID)
Try
# Retrieves list of users that are in the VPN Users group
(Get-ADGroupMember "VPN Users" -Recursive | Where-Object { $_.objectClass -eq 'user' }).SamAccountName | ForEach-Object {
foreach ($group in (Get-ADPrincipalGroupMembership -Identity $_)) {
[PsCustomObject]#{
User = $_
Group = $group.SamAccountName
}
}
} | Export-Csv "C:\VPN Users Report\Results\Output.csv" -NoTypeInformation
I have added Where-Object { $_.objectClass -eq 'user' }, because the Get-ADGroupMember cmdlet can return users, groups, and/or computer objects
As per your latest comment:
If you want more properties from the user, you need Get-ADUser, which by default returns objects with these properties:
DistinguishedName, Enabled, GivenName, Name, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
If you still need more, like for instance the users email address, you need to ask for it by adding -Properties EmailAddress
# demo to include the users first and last name
Get-ADGroupMember "VPN Users" -Recursive | Where-Object { $_.objectClass -eq 'user' } | ForEach-Object {
$user = Get-ADUser -Identity $_.DistinguishedName
foreach ($group in (Get-ADPrincipalGroupMembership -Identity $user.DistinguishedName)) {
[PsCustomObject]#{
User = $user.SamAccountName
FirstName = $user.GivenName
LastName = $user.Surname
Group = $group.SamAccountName
}
}
} | Export-Csv "C:\VPN Users Report\Results\Output.csv" -NoTypeInformation
I propose an alternative to Theo's helpful answer letting LDAP handle the filtering of users.
The result of this query would be those users which are members of GroupX and members of GroupY:
$groupX = (Get-ADGroup 'VPN Users').DistinguishedName
$groupY = (Get-ADGroup 'Domain Users').DistinguishedName
Get-ADUser -LDAPFilter "(&(memberOf=$groupX)(memberOf=$groupY))"
If you were looking for indirect members of one of the groups or both groups, meaning, possible members of nested groups in those groups you could use memberOf:1.2.840.113556.1.4.1941:. Example:
Get-ADUser -LDAPFilter "(&(memberOf:1.2.840.113556.1.4.1941:=$groupX)(memberOf=$groupY))"
Would bring all members (recursive) of GroupX which are also direct members of GroupY.
hoping to get a little help here – I looked around the site but didn’t see anything quite like this (please direct me if there IS and I missed it).
I need to incorporate a new step in our user offboarding process, which would remove them from any AD Distribution Lists. I would like to set this up as a scheduled task to run once a night against two OU’s where the inactivated user accounts can be found.
I’d like to run this by pointing it at the USERS instead of the OU where the Distro Lists live, because I suspect that we’ll ultimately get the request to remove these users from OTHER types of group as well.
This snippet will remove AD Distro Lists from a single user, but leave all other types of AD groups alone:
# GroupCategory 0 = Distro List
# GroupCategory 1 = Security Group
# GroupScope 0 = DomainLocal
# GroupScope 1 = Global
# GroupScope 2 = Universal
$user = "userlogon"
Get-ADPrincipalGroupMembership -Identity $user|
Where {$_.GroupCategory -eq 0} |
ForEach {Remove-ADPrincipalGroupMembership -Identity $user -MemberOf $_ -Confirm:$false}
THIS snippet will look at an OU and return some info (just my example for using a variable with -searchbase):
$OUs = 'OU=PendingDeletion,OU=Users,DC=Stuff,DC=Place,DC=net','OU=HoldForReview,OU=Users,DC=Stuff,DC=Place,DC=net'
$OU | ForEach {Get-ADGroup -Filter * -Properties ManagedBy -SearchBase $_ } |
Select Name, ManagedBy |
Sort -Property Name
Out-GridView
BUT – Does it hold together that in order to complete my objective, I would do something like this?! I'm a bit out of my depth here, any advice for a re-write is appreciated:
$OUs = 'OU=PendingDeletion,OU=Users,DC=Stuff,DC=Place,DC=net','OU=HoldForReview,OU=Users,DC=Stuff,DC=Place,DC=net'
$user = "*"
$OUs | ForEach {
Get-ADPrincipalGroupMembership -Identity $user|
Where {$_.GroupCategory -eq 0} |
ForEach {Remove-ADPrincipalGroupMembership -Identity $user -MemberOf $_ -Confirm:$false}
}
There’s always a couple of ways to do stuff in PoSh, so I’m sure there’s a less-complicated way to do the same thing. If anyone has a different approach please feel free to suggest an alternative.
Thanks for taking a look!
So it sounds like you need three loops.
First, you will need to loop over the OU list to get the Users. We'll store the user objects in $Users
$OUs = 'OU=PendingDeletion,OU=Users,DC=Stuff,DC=Place,DC=net','OU=HoldForReview,OU=Users,DC=Stuff,DC=Place,DC=net'
$Users = ForEach ($OU in $OUs) {
Get-ADUser -Filter * -SearchBase $OU
}
Next loop over the users to get the groups that you want to remove. Then loop over the groups to remove each one.
ForEach ($User in $Users) {
Get-ADPrincipalGroupMembership -Identity $user |
Where-Object {$_.GroupCategory -eq 0} |
ForEach-Object {
Remove-ADPrincipalGroupMembership -Identity $user -MemberOf $_
}
}
I think I'd take this a little differently, by getting the group membership of all users, then grouping by AD group, and processing each group that way. Seems like it would be a lot fewer calls to AD. So I'd start out getting all of the users, just like BenH, except I would include their MemberOf property. Then I'd build a list of potential groups and filter down to just the Distribution Lists. I'd make a Hashtable of those as the keys, and make the value an array of each user that is in that group. Then loop through that removing the value of each from the associated key.
$OUs = 'OU=PendingDeletion,OU=Users,DC=Stuff,DC=Place,DC=net','OU=HoldForReview,OU=Users,DC=Stuff,DC=Place,DC=net'
$Users = ForEach ($OU in $OUs) {
Get-ADUser -Filter * -SearchBase $OU -Properties MemberOf
}
$UsersByGroup = #{}
ForEach($Group in ($Users.MemberOf | Select -Unique | Get-ADGroup | Where{ $_.GroupCategory -eq 0 })) {
$UsersByGroup.Add($Group.DistinguishedName,($Users | Where{ $Group.DistinguishedName -in $_.MemberOf}))
}
$UsersByGroup.Keys | ForEach{
Remove-ADGroupMember -Identity $_ -Members $UsersByGroup[$_] -Confirm:$false
}
This script works without error now, but the problem is that when several groups in the searchbase are found, the script will add all users from all groups to the cross forest target groups.
So for example:
ForestAGroup1 = contains 2 users
ForestAGroup2 = contains 2 users
::runs script::
now...
ForestBGroup1 = contains 4 users
ForestBGroup2 = contains 4 users
The ForestBGroup1/2 needs to contain the same identical users as ForestAGroup1/2.
Here is the script for reference:
$creds = Get-Credential
$Groups = Get-ADGroup -Properties * -Filter * -SearchBase "OU=TEST,OU=Shop Print Groups,OU=User,OU=domain Groups,DC=domainA,DC=com" | export-csv c:\temp\test.csv
$Groups = Get-ADGroup -Properties * -Filter * -SearchBase "OU=TEST,OU=Shop Print Groups,OU=User,OU=domain Groups,DC=domainA,DC=com"
Foreach($G In $Groups)
{
#Display group members and group name
Write-Host $G.Name
Write-Host "-------------"
$G.Members
#Add members to domainB group
$domainGMembers = import-csv C:\temp\test.csv | ForEach-Object -Process {Get-ADGroupMember -Identity $_.CN} | Select-Object samaccountname | export-csv c:\temp\gmembers.csv
$domainDNUser = import-csv C:\temp\gmembers.csv | ForEach-Object -Process {Get-ADUser $_.samaccountname -Server "domainA.com" -properties:Distinguishedname}
import-csv C:\temp\gmembers.csv | ForEach-Object -Process {Add-ADGroupMember -Server "domainB.com" -Identity $G.Name -Members $domainDNUser -Credential $creds -Verbose}
}
What are you doing?
You export to csv, but still try to save it to a variable
You search twice
You add all members from ALL groups in TEST-OU to every group in domainB
You waste time on saving and reading data that you already have in memory
You search for the user-object to get SamAccountName when you already have something ten times better, the DN. Then you use that SamAccountName to find the DN.
Try this (untested):
$creds = Get-Credential
$Groups = Get-ADGroup -Properties Members -Filter * -SearchBase "OU=TEST,OU=Shop Print Groups,OU=User,OU=domain Groups,DC=domain,DC=com"
Foreach($G In $Groups)
{
#Display group members and group name
Write-Host $G.Name
Write-Host "-------------"
$G.Members
#Add members to domainB group
$G.Members |
Get-ADUser -Server fairfieldmfg.com |
ForEach-Object { Add-ADGroupMember -Server "domainB.com" -Identity $G.Name -Members $_ -Credential $creds -Verbose }
}
I used a foreach-loop to run the Add-ADGroupMember because it usually fails in the middle of a group of members if it finds on the already is a member, but if we add them one at a time you get around that (or you could do a search and exclude those already in the group).
You may want to add -ErrorAction SilentlyContinue to Add-ADGroupMember to ignore those errors when you know the script works as it should.
I got a list of 150+ users and I want to know which group they have membership for?
I just started using PS. I can query for 1 user, but not for a list of users. Would like
to know exact command??? I got :
(get-aduser -identity "username" -properties memberof |select-object memberof).memberof > c:\temp\ss.csv
Read your user list into an array and check if your AD users are contained in that array:
$userlist = Get-Content 'C:\your\userlist.txt'
Get-ADUser -Filter '*' -Properties memberof | Where-Object {
$userlist -contains $_.SamAccountName
} | ForEach-Object {
$username = $_
$groups = $_ | Select-Object -Expand memberof |
ForEach-Object { (Get-ADGroup $_).Name }
"{0}: {1}" -f $username, ($groups -join ', ')
} | Out-File 'c:\temp\ss.csv'
Replace SamAccountName as appropriate if the user list doesn't contain the account names of the users.