NSString To NSSArray - iphone

How Can we Store An group OF NSString Objects to an Single Array.....
starting from index = 0;

NSArray *array = [NSArray arrayWithObjects:string1, string2, string3, nil];
or
NSMutableArray *array = [NSMutableArray array];
[array addObject:string1];
[array addObject:string2];
pick one, or improve your question if I've misunderstood you.

An example:
NSArray *myStringArray = [NSArray arrayWithObjects:#"String", #"Another String", #"Last string", nil];

NSArray *myStringArray = [NSArray arrayWithObjects: string1, string2, string3, ..., stringn, nil];

Related

How to compare two MutableArrays and display the unmatched value in iphone? [duplicate]

This question already has answers here:
Compare 2 nsmutablearray and get different object to third array in ios
(4 answers)
Closed 9 years ago.
I have two MutableArray values like.
NSMutableArray *array=[[NSMutableArray alloc]initWithObjects:#"Apple", #"Orange", #"Grapes", #"Banana", nil];
NSMutableArray *array1=[[NSMutableArray alloc]initWithObjects:#"Apple", #"Orange", #"Grapes", nil];
Now i have to compare that two Mutable arrays and display that unmatched object "Banana" into one string.
I am fresher to iOS so, anybody would send me the code for that problem.
Thanks in Advance.
As others have suggest, NSSet is probably your best bet. However, given that *array is mutable, you could simply remove the objects from it contained in *array1
NSMutableArray *array=[[NSMutableArray alloc]initWithObjects:#"Apple", #"Orange", #"Grapes", #"Banana", nil];
NSMutableArray *array1=[[NSMutableArray alloc]initWithObjects:#"Apple", #"Orange", #"Grapes", nil];
[array removeObjectsInArray:array1];
NSLog(#"array: %#", array); // array: ( Banana )
// if you require result as a string
NSString *objectsAsString = [array componentsJoinedByString:#", "];
NSLog(#"objects as string: %#", objectsAsString); // objects as string: Banana
for(int i=0;i<[array count];i++)
{
NSString *str1 = [array objectAtIndex:i];
for(int j=0;j<[array1 count];j++)
{
NSString *str2 = [array1 objectAtIndex:j];
if([str1 isEqualToString:str2])
{
//do something which you want i.e add the values to some other array
}
}
}
You should probably use NSSet for this purpose
NSSet *set1 = [NSSet setWithObjects:#"a", #"s", #"d", #"f", nil];
NSSet *set2 = [NSSet setWithObjects:#"a", #"s", nil];
NSMutableSet *notInSet1 = [NSMutableSet setWithSet:set2];
[notInSet1 minusSet:set1];
NSMutableSet *notInSet2 = [NSMutableSet setWithSet:set1];
[notInSet2 minusSet:set2];
NSMutableSet *symmetricDifference = [NSMutableSet setWithSet:notInSet1];
[symmetricDifference unionSet:notInSet2];
NSArray *array1 = [[NSArray alloc] initWithObjects:#"a",#"b",#"c",nil];
NSArray *array2 = [[NSArray alloc] initWithObjects:#"a",#"d",#"c",nil];
NSMutableArray *ary_result = [[NSMutableArray alloc] init];
NSMutableArray *ary_resultUnmatched = [[NSMutableArray alloc] init];
for(int i = 0;i<[array1 count];i++)
{
for(int j= 0;j<[array2 count];j++)
{
if([[array1 objectAtIndex:i] isEqualToString:[array2 objectAtIndex:j]])
{
[ary_result addObject:[array1 objectAtIndex:i]];
} else {
[ary_resultUnmatched addObject:[array1 objectAtIndex:i]];
}
}
}
NSLog(#"%#",ary_result);//it will print a,c
NSLog(#"%#",ary_resultUnmatched);//it will print b,d
so in else condition you'll have your un matched values

How to join an NSArray output to an NSString separated with commas

I'm using the following code to try to join the array output into an NSString.
NSArray *array1 = [NSArray arrayWithObjects:[item objectForKey:#"id"], nil];
NSString *joinedString = [array1 componentsJoinedByString:#","];
NSLog(#"joinedString is %#", joinedString);
I would like this to output the joined string as: joined string is 55,56,57,66,88... etc... at the moment the output is:
2013-03-05 13:13:17.052 [63705:907] joinedString is 55
2013-03-05 13:13:17.056 [63705:907] joinedString is 56
2013-03-05 13:13:17.060 [63705:907] joinedString is 57
2013-03-05 13:13:17.064 [63705:907] joinedString is 66
You are probably running the join method inside a loop.
I suppose this is what you want.
NSMutableArray * array1 = [NSMutableArray array]; // create a Mutable array
for(id item in items){
[array1 addObject:[item objectForKey:#"id"]]; // Add the values to this created mutable array
}
NSString *joinedString = [array1 componentsJoinedByString:#","];
NSLog(#"joinedString is %#", joinedString);
You can do it as,
take for example
NSArray *array=#[#"A",#"B",#"C"];
NSString *string=[array componentsJoinedByString:#","];
NSLog(#"%#",string);
Output is :
A,B,C
What ever you are writing that one correct may be problem in [item objectForKey:#"id"] once check this one other all are fine.
NSMutableArray *array = [[NSMutableArray alloc]
initWithObjects:#"55",#"56",#"57",#"58", nil];
NSString *joinedString = [array componentsJoinedByString:#","];
NSLog(#"%#",joinedString);
I have been commenting on a couple of the answers here and found that most of the answers are just giving the code provided as the answer to solve this code, and the reason for that is because the code provided (See Provided code) works perfectly fine.
(Provide by question asker)
NSArray *array1 = [NSArray arrayWithObjects:[item objectForKey:#"id"], nil];
NSString *joinedString = [array1 componentsJoinedByString:#","];
NSLog(#"joinedString is %#", joinedString);
As the user hasn't provided how the item NSDictionary is created I am assuming that an NSArray has been created which contains some NSDictionaries
NSArray *array = [[NSArray alloc] initWithObjects:[NSDictionary dictionaryWithObjectsAndKeys:#"55", #"id", nil],
[NSDictionary dictionaryWithObjectsAndKeys:#"65", #"id", nil],
[NSDictionary dictionaryWithObjectsAndKeys:#"75", #"id", nil],
[NSDictionary dictionaryWithObjectsAndKeys:#"65", #"id", nil],
nil];
The problem is with the code that hasn't been provide, because we know that item is an NSDictionary we know that [item objectForKey:#"id"] doesn't return an individual items it returns an NSArray of ids. So based on if it was an NSArray it would log something like joinedString is (55, 56, 57...)". We also know that it can't just be a string as we would also only have one value than so it would log some thing like this joinedString is 55, and again this isn't what is wanted so. the only way to get what has been provided would be to have something like this
for(NSDictionary *item in array) {
NSArray *array1 = [NSArray arrayWithObjects:[item objectForKey:#"id"], nil];
NSString *joinedString = [array1 componentsJoinedByString:#","];
NSLog(#"joinedString is %#", joinedString);
}
So if this is the case than the way to resolve this would be to do
NSMutableArray *array1 = [NSMutableArray array];
for(NSDictionary *item in array) {
[array1 addObject:[item objectForKey:#"id"]];
}
// Note that this doesn't need to be in a for loop `componentsJoinedByString:` only needs to run once.
NSString *joinedString = [array1 componentsJoinedByString:#","];
NSLog(#"joinedString is %#", joinedString);
The output of this would be (As user wants)
joinedString is 55,65,75,65
Once the question asker provides the missing code I will correct his to answer based on there code but until then I am assuming.
EDIT:
First Check [item objectForKey:#"id"] it is proper or not ??
And Then use following code :
NSArray *array1 = [NSArray arrayWithObjects:[item objectForKey:#"id"], nil];
NSString *commaSpStr;
commaSpStr = [array1 componentsJoinedByString:#", "];
NSLog(#"%#", commaSpStr);
You are recreating array1 everytime. Create an instance variable of array1, insert [item objectForKey:#"id"] value to it and you will see joinedString will be updated.
NSMutableArray *arr = [[NSMutableArray alloc] init];
for (NSDictionary *item in array) {
[arr addObject:[item objectForKey:#"id"]];
}
NSString *joinedStr = [arr componentsJoinedByString:#","];

Using a nested NSMutableDictionary

simple question, I need to structure data in the following format:
UserID:
1 {
Name = Bob
Surname = Hope
}
2 {
...
I can used an NSMutableDictionary to add a single layer with keys, but I am unable to create a child associate with a certain key.
I have tried creating a mutable dictionary and assigning that to a key:
NSMutableDictionary *dic = [[NSMutableDictionary alloc] init];
NSArray *keys = [[NSArray alloc] initWithObjects:#"Name", #"Surname", nil];
NSArray *details = [[NSArray alloc] initWithObjects:#"Bob",#"Hope", nil];
NSDictionary *person = [[NSMutableDictionary alloc] initWithObjects:details forKeys:keys];
[dic setValue:#"1" forKey:#"id"];
[[dic objectForKey:#"id"] setDictionary: person];
I think it is better to use an array of dictionaries, each dictionary representing a user.
NSMutableArray *users= [[NSMutableArray alloc] init];
NSArray *keys = [[NSArray alloc] initWithObjects:#"Name", #"Surname", nil];
NSArray *details = [[NSArray alloc] initWithObjects:#"Bob",#"Hope", nil];
NSDictionary *person = [[NSMutableDictionary alloc] initWithObjects:details forKeys:keys];
[users addObject:person];
u can also set the objects for dictionary in this way
[dic setObject:person forKey:#"id"];

-[__NSCFString objectForKey:]: unrecognized selector sent to instance

// Configure the cell.
cell.textLabel.text = [[self.drinks objectAtIndex:indexPath.row] objectForKey:#"Name"];
return cell;
The above code is generating this exception. What could be causing this and how can I fix it?
My Understand from Your question
You have array of drinks like
Drink *d1 = [[Drink alloc] init]
d1.name = #"Drink1";
d1.price = [NSNumber numberWithFloat:25.0];
Drink *d2 = [[Drink alloc] init]
d2.name = #"Drink2";
d2.price = [NSNumber numberWithFloat:35.0];
OR
NSArray *values1 = [NSArray arrayWithObjects:#"Drink1",[NSNumber numberWithFloat:25.0], nil];
NSArray *keys1 = [NSArray arrayWithObjects:#"Name",#"price", nil];
NSDictionary *d1 = [[NSDictionary alloc] initWithObjects:values1 forKeys:keys1];
NSArray *values2 = [NSArray arrayWithObjects:#"Drink2",[NSNumber numberWithFloat:55.0], nil];
NSArray *keys2 = [NSArray arrayWithObjects:#"Name",#"price", nil];
NSDictionary *d2 = [[NSDictionary alloc] initWithObjects:values1 forKeys:keys1];
self.drinks = [NSArray arrayWithObjects:d1,d2, nil];
[d1 release];
[d2 release];
From the above case
cell.textLabel.text = [[self.drinks objectAtIndex:indexPath.row] objectForKey:#"Name"];
the above statement is correct
You are getting exception means, You are inserting the objects into drinks array, that supports Key Value Pairs data and that is String Data.
I hope you are having like this
self.drinks = [NSArray arrayWithObjects:#"Drink1",#"Drink2", nil];
In this above case you have to go with
cell.textLabel.text = [self.drinks objectAtIndex:indexPath.row];
first try to determine what object is self.drinks,
then you can go finer depending if is an array with dictionaries?
do a log
[self.drinks objectAtIndex:0]
what do you see?

Objective-C - Concatenating strings separated by pipes

I would like to loop through an array strings and add them to an NSString in the following way:
NSMutableArray *emailsArray = [[NSMutableArray alloc] initWithObjects:#"One", #"Two", #"Three", nil];
for (id email in emailsArray {
NSString *emails = ??;
}
So the final NSString should be the following:
NSString *emails = #"One|Two|Three";
Use [emailsArray componentsJoinedByString:#"|"] for this.
Sample:
NSMutableArray *emailsArray = [[NSMutableArray alloc] initWithObjects:#"One", #"Two", #"Three", nil];
NSString *emails = [emailsArray componentsJoinedByString:#"|"];
Here you'll have emails = #"One|Two|Three".