Table 1:
AccountId, ReferenceId, Name, (lots of other columns)
Table 2:
AccountId, ReferenceId, (other columns)
How can I do a select to get the following:
AccountId, ReferenceId, [Count(*) in Table2 where accountId and reference ID match.]
1, AB, 1
1, AC, 0
2, AD, 4
2, EF, 0
etc
Guessing a join, but that gives me values, not a count?
Tried adding a count, but get errors?
SELECT T1.AccountId,
T1.ReferenceId,
COUNT(T2.ReferenceId) AS Cnt
FROM Table1 T1
LEFT JOIN Table2 T2
ON T1.AccountId = T2.AccountId
AND T1.ReferenceId = T2.ReferenceId
GROUP BY T1.AccountId,
T1.ReferenceId
Something like:
SELECT t1.AccountId, t1.ReferenceId, COUNT(t2.AccountId)
FROM Table1 t1
LEFT JOIN Table2 t2 ON t1.AccountId = t2.AccountId AND
t1.ReferenceId = t2.ReferenceId
GROUP BY t1.AccountId, t1.ReferenceId
should work. The trick is to group by both key values so you can aggregate over other values. In this case you want to simply count values from other rows (you could also sum or average values from the grouped-by rows.).
sample data
declare #tbl1 table (AccountId INT, ReferenceId int, Name varchar(20))
declare #tbl2 table (AccountId INT, ReferenceId int)
insert into #tbl1 select 1, 10, 'White'
insert into #tbl1 select 2, 20, 'Green'
insert into #tbl1 select 3, 30, 'Black'
insert into #tbl1 select 3, 40, 'Red'
insert into #tbl2 select 1, 10
insert into #tbl2 select 1, 10
insert into #tbl2 select 2, 20
insert into #tbl2 select 3, 30
Query
select t.AccountId, t.ReferenceId, t.Name
,(select COUNT(*) from #tbl2 t2
where t.AccountId = t2.AccountId
and t.ReferenceId = t.ReferenceId) as countt
from #tbl1 t
SELECT t1.AccountId, t1.ReferenceId, COUNT(t2.AccountId)
FROM Table1 t1 LEFT JOIN Table2 t2
ON (t1.AccountId=t2.AccountId AND t1.ReferenceId=t2.ReferenceId)
GROUP BY Table1.AccountId, Table1.ReferenceId
Related
I have a table that has account number, end of month valid from and end of month valid to columns.
What I need is a table that has account number and a column that has all the end of month dates of when the account was live, inclusive of end of month valid to. The Current Table looks like this
New table will need to be like this
I have tried using a calendar table and an CTE table type query but have had no success.
Any help would be great.
This can be achieved using Using multiple comma separated CTEs in a statement
Query
with t0 (i) AS (select 0 union all select 0 union all select 0 union all select 0 union all select 0 union all select 0),
t1 (i) AS (select 0 from t0 a inner join t0 b on a.i = b.i),
n (i) AS (select row_number()over(order by i) from t1),
Account_details (Account_number,valid_from,valid_to,mth,Live_date)As(
select Account_number,valid_from,valid_to, datediff(month,valid_from,valid_to ) mth, valid_from"Live_date"
from tbl1
union all
select Account_number,valid_from,valid_to, datediff(month,valid_from,valid_to ) mth, EOMONTH (dateadd(month,n.i,valid_from)) "Live_date"
from tbl1
inner join n on 1=1 and n.i between 1 and datediff(month,valid_from,valid_to )
)
select *
from Account_details
where Account_details.Account_number =1
order by Account_details.Account_number
Output
CTE Table t0, t1 and n will generate numbers. This is a best way to generate rows without any data.
Then the CTE table Account_details is used to pull data from the table.
Based on sql on the msdn thread how to get month end date between two dates.
DECLARE #Old AS Table (AccountNumber INT, ValidFrom DATE, ValidTo DATE)
DECLARE #New AS Table (AccountNumber INT, LiveDate DATE)
INSERT INTO #old
SELECT 1, '20130630', '20131130' UNION ALL
SELECT 2, '20130630', '20131231' UNION ALL
SELECT 3, '20120430', '20120531' UNION ALL
SELECT 4, '20170331', '20171130'
SELECT TOP 100 * FROM #old
DECLARE #AccountNumber INT, #ValidFrom DATE, #ValidTo DATE
DECLARE #Cursor CURSOR
SET #Cursor = CURSOR FOR
SELECT AccountNumber, ValidFrom, ValidTo
FROM #old
OPEN #Cursor
FETCH NEXT INTO #Cursor FROM #AccountNumber, #ValidFrom, #ValidTo
WHILE ##FETCH_STATUS = 0
BEGIN
;WITH cteEndMonthDates (MonthEndDate)
AS
(
SELECT eomonth(#ValidFrom) AS MonthEndDate
UNION ALL
SELECT eomonth( dateadd(day, 1, MonthEndDate)) AS MonthEndDate
FROM cteEndMonthDates
WHERE MonthEndDate < eomonth(#ValidTo)
)
INSERT INTO #new (AccountNumber, LiveDate)
SELECT #AccountNumber, MonthEndDate
FROM cteEndMonthDates
FETCH NEXT FROM #Cursor INTO #AccountNumber, #ValidFrom, #ValidTo
END
CLOSE #Cursor
DEALLOCATE #Cursor
SELECT * FROM #New
Edit: Or without the cursor
DECLARE #Old AS Table (AccountNumber INT, ValidFrom DATE, ValidTo DATE)
DECLARE #New AS Table (AccountNumber INT, LiveDate DATE)
INSERT INTO #old
SELECT 1, '20130630', '20131130' UNION ALL
SELECT 2, '20130630', '20131231' UNION ALL
SELECT 3, '20120430', '20120531' UNION ALL
SELECT 4, '20170331', '20171130' UNION ALL
SELECT 5, '20180430', '20190131' UNION ALL
SELECT 6, '20160430', '20180531'
SELECT TOP 100 * FROM #old
;WITH cteEndMonthDates (AccountNumber, MonthEndDate)
AS
(
SELECT AccountNumber, eomonth(ValidFrom) AS MonthEndDate
FROM #Old
UNION ALL
SELECT x.AccountNumber, eomonth( dateadd(day, 1, MonthEndDate)) AS MonthEndDate
FROM cteEndMonthDates x
JOIN #Old o ON o.AccountNumber = x.AccountNumber
WHERE MonthEndDate < eomonth(ValidTo)
)
SELECT AccountNumber, MonthEndDate
FROM cteEndMonthDates
order by AccountNumber, MonthEndDate
This should work.
;WITH Span AS (
SELECT
AccountNumber,
ValidFrom AS Valid
FROM dbo.Input
UNION ALL
SELECT
AccountNumber,
DATEADD(DAY, 1, Span.Valid) AS Valid
FROM Span
WHERE DATEADD(DAY, 1, Span.Valid) <= (SELECT ValidTo FROM dbo.Input WHERE AccountNumber = Span.AccountNumber)
)
SELECT * FROM Span
ORDER BY Span.AccountNumber, Span.Valid
OPTION (MAXRECURSION 0);
I have 2 columns 1) id (int) and 2) Date. I want to select id on max date. Grouping results in returning both id's/more than one id. Instead i only want to retrieve id on max date .
I am sure there is easier way to do this however below should work fine.
-- create sample data
create table #temp(ID int, courseID int, end_date datetime)
go
insert into #temp
select 1 , 11 , getdate()
union
select 1, 12, getdate()-20
union
select 1, 13, getdate()-40
union
select 2, 13, getdate()-70
union
select 2, 14, getdate()-80
-- create temp table to calculate correct date
select id, max(end_date) as correctDate
into #temp2
from #temp
group by id
-- final desired outup
select #temp2.id , #temp.courseID
from #temp2
inner join #temp
on #temp2.id = #temp.id
and #temp2.correctDate = #temp.end_date
-- drop temp tables
drop table #temp
drop table #temp2
give me a shout if you have any questions
Simpler alternative
-- create sample data
create table #temp(id int, courseID int, end_date datetime)
go
insert into #temp
select
1 , 11 , getdate()
union
select
1, 12, getdate()-20
union
select
1, 13, getdate()-40
union
select
2, 13, getdate()-70
union
select
2, 14, getdate()-80
SELECT * FROM(
SELECT DENSE_RANK() OVER(PARTITION BY id ORDER BY end_date DESC ) sira, id,courseID,end_date FROM #temp
) t WHERE sira = 1
-- drop temp tables
drop table #temp
drop table #temp2
I need to get a tree of related nodes given a certain node, but not necessary top node. I've got a solution using two CTEs, since I am struggling to squeeze it all into one CTE :). Might somebody have a sleek solution to avoid using two CTEs? Here is some code that I was playing with:
DECLARE #temp AS TABLE (ID INT, ParentID INT)
INSERT INTO #temp
SELECT 1 ID, NULL AS ParentID
UNION ALL
SELECT 2, 1
UNION ALL
SELECT 3, 2
UNION ALL
SELECT 4, 3
UNION ALL
SELECT 5, 4
UNION ALL
SELECT 6, NULL
UNION ALL
SELECT 7, 6
UNION ALL
SELECT 8, 7
DECLARE #startNode INT = 4
;WITH TheTree (ID,ParentID)
AS (
SELECT ID, ParentID
FROM #temp
WHERE ID = #startNode
UNION ALL
SELECT t.id, t.ParentID
FROM #temp t
JOIN TheTree tr ON t.ParentID = tr.ID
)
SELECT * FROM TheTree
;WITH Up(ID,ParentID)
AS (
SELECT t.id, t.ParentID
FROM #temp t
WHERE t.ID = #startNode
UNION ALL
SELECT t.id, t.ParentID
FROM #temp t
JOIN Up c ON t.id = c.ParentID
)
--SELECT * FROM Up
,TheTree (ID,ParentID)
AS (
SELECT ID, ParentID
FROM Up
WHERE ParentID is null
UNION ALL
SELECT t.id, t.ParentID
FROM #temp t
JOIN TheTree tr ON t.ParentID = tr.ID
)
SELECT * FROM TheTree
thanks
Meh. This avoids using two CTEs, but the result is a brute force kludge that hardly qualifies as "sleek" as it won’t be efficient if your table is at all sizeable. It will:
Recursively build all possible hierarchies
As you build them, flag the target NodeId as you find it
Return only the targeted tree
I threw in column “TreeNumber” on the off-chance the TargetId appears in multiple hierarchies, or if you’d ever have multiple values to check in one pass. “Depth” was added to make the output a bit more legible.
A more complex solution like #John’s might do, and more and subtler tricks could be done with more detailed table sturctures.
DECLARE #startNode INT = 4
;WITH cteAllTrees (TreeNumber, Depth, ID, ParentID, ContainsTarget)
AS (
SELECT
row_number() over (order by ID) TreeNumber
,1
,ID
,ParentID
,case
when ID = #startNode then 1
else 0
end ContainsTarget
FROM #temp
WHERE ParentId is null
UNION ALL
SELECT
tr.TreeNumber
,tr.Depth + 1
,t.id
,t.ParentID
,case
when tr.ContainsTarget = 1 then 1
when t.ID = #startNode then 1
else 0
end ContainsTarget
FROM #temp t
INNER JOIN cteAllTrees tr
ON t.ParentID = tr.ID
)
SELECT
TreeNumber
,Depth
,ID
,ParentId
from cteAllTrees
where TreeNumber in (select TreeNumber from cteAllTrees where ContainsTarget = 1)
order by
TreeNumber
,Depth
,ID
Here is a technique where you can select the entire hierarchy, a specific node with all its children, and even a filtered list and how they roll.
Note: See the comments next to the DECLAREs
Declare #YourTable table (id int,pt int,name varchar(50))
Insert into #YourTable values
(1,null,'1'),(2,1,'2'),(3,1,'3'),(4,2,'4'),(5,2,'5'),(6,3,'6'),(7,null,'7'),(8,7,'8')
Declare #Top int = null --<< Sets top of Hier Try 2
Declare #Nest varchar(25) = '|-----' --<< Optional: Added for readability
Declare #Filter varchar(25) = '' --<< Empty for All or try 4,6
;with cteP as (
Select Seq = cast(1000+Row_Number() over (Order by name) as varchar(500))
,ID
,pt
,Lvl=1
,name
From #YourTable
Where IsNull(#Top,-1) = case when #Top is null then isnull(pt,-1) else ID end
Union All
Select Seq = cast(concat(p.Seq,'.',1000+Row_Number() over (Order by r.name)) as varchar(500))
,r.ID
,r.pt
,p.Lvl+1
,r.name
From #YourTable r
Join cteP p on r.pt = p.ID)
,cteR1 as (Select *,R1=Row_Number() over (Order By Seq) From cteP)
,cteR2 as (Select A.Seq,A.ID,R2=Max(B.R1) From cteR1 A Join cteR1 B on (B.Seq like A.Seq+'%') Group By A.Seq,A.ID )
Select Distinct
A.R1
,B.R2
,A.ID
,A.pt
,A.Lvl
,name = Replicate(#Nest,A.Lvl-1) + A.name
From cteR1 A
Join cteR2 B on A.ID=B.ID
Join (Select R1 From cteR1 where IIF(#Filter='',1,0)+CharIndex(concat(',',ID,','),concat(',',#Filter+','))>0) F on F.R1 between A.R1 and B.R2
Order By A.R1
I'm working on a sql query that should 'coalesce' the records from 2 tables, i.e. if the record exists in table2, it should take that one, otherwise it should fall back to the values in table1.
In the example, table1 and table2 have just 2 fields (id an description), but obviously in reality there could be more.
Here's a small test case:
create table table1 (id int, description nvarchar(50))
create table table2 (id int, description nvarchar(50))
insert into table1 values (1, 'record 1')
insert into table1 values (2, 'record 2')
insert into table1 values (3, 'record 3')
insert into table2 values (1, 'record 1 modified')
insert into table2 values (2, null)
The result of the query should look like this:
1, "record 1 modified"
2, null
3, "record 3"
Here's what I came up with.
select
case when table2.id is not null then
table2.id else table1.id
end as Id,
case when table2.id is not null then
table2.description
else
table1.description
end as Description
-- etc for other fields
from table1
left join table2 on table1.id = table2.id
Is there a better way to achieve what I want? I don't think I can use coalesce since that would not select a null value from table2 if the corresponding value in table1 is not null.
How about:
SELECT t2.ID, t2.Description
FROM table2 t2
UNION ALL
SELECT t1.ID, t1.Description
FROM table1 t1
WHERE NOT EXISTS (SELECT *
FROM table2 t2
WHERE t2.ID = t1.ID)
The above query gets all the records from table 2 (including the case where description is NULL but the ID is populated), and only the records from table 1 where they don't exist in table 2.
Here's an alternative:
SELECT table2.*
FROM table1
RIGHT JOIN table2
ON table1.id = table2.id
UNION
SELECT table1.*
FROM table1
FULL OUTER join table2
ON table1.id = table2.id
WHERE table1.id NOT IN (SELECT id FROM table2)
--and table2.id not in (select id from table1)
You can add in that last line if you don't want ids that are only in table2. Otherwise I guess Stuart Ainsworth's solution is better (i.e. drop all the joins)
http://sqlfiddle.com/#!3/03bab/12/0
I have two tables of records that I need to find all of the matches. The tables are based on different Primary Key identifiers, but the data points are exactly the same. I need a fast query that can show me records that are duplicated from the first table to the second. Here is an example of what I am trying to do:
DECLARE #Table1 TABLE (ID INT, Value INT)
DECLARE #Table2 TABLE (ID INT, Value INT)
INSERT INTO #Table1 VALUES (1, 500)
INSERT INTO #Table1 VALUES (2, 500)
INSERT INTO #Table2 VALUES (3, 500)
INSERT INTO #Table2 VALUES (4, 500)
SELECT MAX(x.T1ID)
,MAX(x.T2ID)
FROM (
SELECT T1ID = t1.ID
,T2ID = 0
,t1.Value
FROM #Table1 t1
UNION ALL
SELECT T1ID = 0
,T2ID = t2.ID
,t2.Value
FROM #Table2 t2
) x
GROUP BY x.Value
HAVING COUNT(*) >= 2
The problem with this code is that it returns record 2 in table 1 correlated to record 4 in table 2. I really need it to return record 1 in table 1 correlated to record 3 in table 2. I tried the following:
SELECT MIN(x.T1ID)
,MIN(x.T2ID)
FROM (
SELECT T1ID = t1.ID
,T2ID = 0
,t1.Value
FROM #Table1 t1
UNION ALL
SELECT T1ID = 0
,T2ID = t2.ID
,t2.Value
FROM #Table2 t2
) x
GROUP BY x.Value
HAVING COUNT(*) >= 2
This code does not work either. It returns 0,0.
Is there a way to return the MIN value greater than 0 for both tables?
Might answer my own question. This seems to work. Are there any reasons why I would not do this?
SELECT MIN(t1.ID)
,MIN(t2.ID)
FROM #Table1 t1
INNER JOIN #Table2 t2 ON t1.Value = t2.Value
GROUP BY t1.Value
If you want to see the records in table1 that have matches in table2 then
select *
from #Table1 T1
where exists (select * from #Table2 T2
where T1.ID=T2.ID
-- you would put the complete join clause that defines a match here
)