pygtk - spinbutton: output-signal - callback

I use a spinbutton in my application to let the user choose a number between -1 and 100. In my application -1 means Infinity. So I want to show the text "Infinity", if the user selects the value -1. This is my code:
def spin_output(spin):
digits = int(spin.props.digits)
value = spin.props.value
if value < 0:
spin.props.text = "Infinity" # u"\u221E"
else:
spin.props.text = '{0:.{1}f}'.format(value, digits)
return True
self.my_spin.connect('output', spin_output)
When the "Infinity"-value is selected and the user presses the "up"-button the value changes to 100 instead of 0.
When i replace "Infinity" with u"\u221E" and the user presses the "up"-button while it is selected, the value changes to 1.
What I want is, that the user can select the values in that order: Infinity, 0, 1, ...
What is my mistake?
I thought that only the underlying adjustment is changed when the user changes the value and my function is only used to show the current value.

What's happening is that the spin button is interpreting the string "infinity" as a string entered by the user, and trying to parse it as a value. The gtk.Scale widgets offer a signal called format-value which is used to display custom values just like you're trying to do, but I don't see a similar signal for the spin button.
Here is something using a scale that might do what you want:
#!/usr/bin/env python
import gtk
def scale_output(scale, value):
if value < 0:
return "Infinity" # u"\u221E"
return "{0}".format(int(value))
window = gtk.Window(gtk.WINDOW_TOPLEVEL)
adjustment = gtk.Adjustment(-1, -1, 100, 1, 1)
scale = gtk.HScale(adjustment)
window.set_default_size(300, 100)
window.add(scale)
scale.connect('format-value', scale_output)
window.connect('destroy', gtk.main_quit)
window.show_all()
gtk.main()

Ok, i found a solution. I wrote the counterpart for the output-signal-handler ... the input-signal-handler :-)
def parallel_spin_input(spin, new_value):
text = spin.get_text()
if text == u"\u221E":
value = -1
else:
try:
value = float(text)
except ValueError:
return -1
p = ctypes.c_double.from_address(hash(new_value))
p.value = value
return True
self.parallel_spin.connect('input', parallel_spin_input)
This seems to work well ;-)

Related

Libreoffice calc - how to write a same value into a range

I know how to 'select' a range in LO (7.2.4.1) Calc BASIC ....
ThisComponent.CurrentController.ActiveSheet.getCellRangeByName("D1:H6")
But how to write a value, e.g. "1", into that range using BASIC?
myRange = ThisComponent.CurrentController.ActiveSheet.getCellRangeByName("D1:H6")
myRange.Value = 1
Gives an "property or method not found" error. But I can't find any properties or values to go after Range to allow me to do what I want. Flailing around and trying
myRange.setValue = 1
myRange.writeValue = 1
myRange.setString = "1"
and numerous other variants don't work either.
Would really appreciate the solution. Thanks.
You can edit the value of an individual cell, but not the entire range. You will have to iterate over all the cells in the range one at a time, changing the value of each of them.
Sub Set1ToD1H6
myRange = ThisComponent.CurrentController.ActiveSheet.getCellRangeByName("D1:H6")
For i = 0 To myRange.getRows().getCount()-1
For j = 0 To myRange.getColumns().getCount()-1
myRange.getCellByPosition(j, i).setValue(1)
Next j
Next i
End Sub
But since the read-write operation to a cell is comparable in time to the read-write operation to a whole range, it is preferable to use another method - to prepare data in an array and write from it to a range in one operation:
Sub Set1ToRange
myRange = ThisComponent.CurrentController.ActiveSheet.getCellRangeByName("D1:H6")
dataOfRange = myRange.getData()
For i = LBound(dataOfRange) To UBound(dataOfRange)
For j = LBound(dataOfRange(i)) To UBound(dataOfRange(i))
dataOfRange(i)(j) = 1
Next j
Next i
myRange.setData(dataOfRange)
End Sub
(For your example, this will be approximately 30 times faster, for a larger range the time winnings will be even more significant)
The .getData() and .setData() methods work on numeric range values. To work with text strings (and numbers), use .getDataArray() and .setDataArray(), for working with cell formulas use .getFormulaArray() and .setFormulaArray()

Get Row and Column number from "ThisComponent.CurrentSelection" in libreoffice calc basic

I have this code where I can get which one is the current selected cell and use it to modify its value:
theSelection = ThisComponent.CurrentSelection
theSelection.setString("some value")
Now I want to move to the next column to the right, if it was Microsoft excel VBA I could just use something like theSelection.Offset(0,1) but that's not the case. So I'm doing some workarounds of course:
nextCell = oActiveSheet.getCellByPosition( ???currentColumn + 1, ???currentRow)
ThisComponent.CurrentController.select( nextCell )
I just want to know the simplest way to replace these ??? to the actual values of the theSelection var to move to the next column to the right.
I also tried this:
nextCell = oActiveSheet.getCellByPosition( column() + 1, row())
But I don't know why it is always returning column() = 1 and row() = 1 in regardless of which is the value of the CurrentSelection. Thanks in advance for the help.
Get the cell address.
Sub ChangeAndThenGoToCellToRightOfSelection
oActiveSheet = ThisComponent.getCurrentController().getActiveSheet()
oSels = ThisComponent.getCurrentSelection()
If oSels.supportsService("com.sun.star.sheet.SheetCell") Then
'A single cell is selected.
oSels.setString("some value")
address = oSels.getCellAddress()
nextCell = oActiveSheet.getCellByPosition(address.Column + 1, address.Row)
ThisComponent.CurrentController.select(nextCell)
End If
End Sub
To see what an object can do, use an introspection tool such as XrayTool or MRI.

how to create a program on python that can input a number from a user and classify it as either prime or composite

I'm stuck at a point where the computer has to check for all remainders of the number which has been given by the user. Am I supposed to use a For loop for this if yes then how?
Thank you.
yes, you need to use for loop, below function will give you how you can use for loop to check whether number is prime or not.
def prime(n):
flag = 0
for i in range(2,(n/2)+2):
if n%i==0:
flag = 1
return "composite"
if flag==0:
return "prime"
def prime_or_composite(num):
div = 2
while True:
if num == div:
print("It is a prime number!")
break
elif num % div = 0:
print("It is a composite number!")
break
else:
div += 1
This works if the input number is an integer bigger than 2.

SSRS Expression works as cell value expression, but not as background color value expression

I have an SSRS report with a matrix in it, where I needed to display the Growth Percentage in a column group compared to the previous column value. I managed this by using custom code...
DIM PreviousColValue AS Decimal
Dim RowName AS String = ""
Public Function GetPreviousColValue(byval Val as Decimal, byval rwName as string) as Decimal
DIM Local_PreviousColValue AS Decimal
IF RowName <> rwName THEN
RowName = rwName
PreviousColValue = val
Local_PreviousColValue = 0
ELSE
Local_PreviousColValue = (Val - PreviousColValue)/PreviousColValue
PreviousColValue = val
END IF
Return Local_PreviousColValue
End Function
..and then using this as the value expression in the cell..
=Round(Code.GetPreviousColValue(ReportItems!Textbox8.Value,Fields!BusinessUnit.Value)*100,0,system.MidpointRounding.AwayFromZero)
So far so good, this produces the expected value. Now I need to use this expression in a background color expression to get a red/yellow/green but in that capacity it fails.
The background color expression looks like this: =IIF(ROUND(Code.GetPreviousColValue(ReportItems!Textbox9.Value,Fields!Salesperson.Value)*100,0,System.MidpointRounding.AwayFromZero)<=-5,"Red"
,IIF(ROUND(Code.GetPreviousColValue(ReportItems!Textbox9.Value,Fields!Salesperson.Value)*100,0,System.MidpointRounding.AwayFromZero) >=5,"Green"
,"Yellow"))
When I run the report the background color expression only ever returns yellow. As a test I pasted the background color expression in as the cell value and ran it again. Results in the image below
I get no build or run time errors so I'm not sure why this does not work.
After some more searching I found a better Custom Code solution than what I was using to get the Growth Percentage in a column group compared to the previous column value. Besides being simpler to read this version has an added benefit: You can dynamically hide the growth percentage column for your first instance of the column group (because it will always be zero or null) and still get the right values in the 2nd/3rd/4th instance of the column group.
Public Function GetDeltaPercentage(ByVal PreviousValue, ByVal CurrentValue) As Object
If IsNothing(PreviousValue) OR IsNothing(CurrentValue) Then
Return Nothing
Else if PreviousValue = 0 OR CurrentValue = 0 Then
Return Nothing
Else
Return (CurrentValue - PreviousValue) / PreviousValue
End If
End Function
The new function is called like so
=Code.GetDeltaPercentage(Previous(Sum(<expression or dataset field>),"Group ByColumn"), Sum(<expression or dataset field>))
Re: the original question - why does my cell value expression not work when used as the background color expression - I took an easy out and just referenced the cell value.
=IIF(ROUND(Me.Value*100,0,System.MidpointRounding.AwayFromZero)<=-5,"Red"
,IIF(ROUND(Me.Value*100,0,System.MidpointRounding.AwayFromZero) >=5,"Green"
,"Yellow"))

How would I use recursion to create an array of extra change($100, 50, 20, 10, 5, 1) MATLAB

How would I correctly make a recursive call within every if-statement to get the change of money? Im specifically focusing on the "change" variable.Thanks
TEST CASE 1-------------------------------------------------------------------------------
<>> [change,flag] = makeChangeRecursive(2,100)
change =
50
20
20
5
2
1
flag =
1
My code is the following
function [change,flag] = makeChangeRecursive(cost,paid)
if extra > 0
flag = true;
elseif extra == 0
change = 0;
flag = true;
return
elseif cost > paid;
flag = false;
change = [];
warning('That''s not enough to buy that item.');
return
end
if extra >= 100
change = [change; makeChangeRecursive(cost,paid - change )];
paid =paid-100;
elseif extra >= 50
change = [change; 50];
paid =paid-50;
elseif
This continues for all dollar values.
Let's take a look at your first case:
if extra >= 100
change = [change; makeChangeRecursive(cost,paid - change )];
paid =paid-100;
elseif ...
The first time we call your function, the variable change doesn't have anything in it. In fact, it will never have anything in it at the beginning of the function call because you don't pass it in as a parameter or give it a value prior to this line. So putting change on the right-hand side of the assignment will give you an error.
But that's okay, because that's not what you want to do anyway. You want to build change up from the beginning.
In addition, change is a list of values. We want to pass the recursive calls a single value, paid after updating its value.
Let's build this up step by step:
if extra >= 100
If this is true, we want subtract 100 from the amount paid (what we pass in to the recursive call) and add 100 to our list of change. Let's do the first part:
paid = paid - 100;
As I said, we want to update paid first because we're going to use this value in the recursive call, which happens next, along with adding our new change value to the list:
change = [100; makeChangeRecursive(cost, paid)];
elseif ...
And so on for the remainder of the change values. I'm sure you can take care of the rest of them now by yourself.
I also noticed that you didn't assign a value to extra. This might have been just a cut-and-paste error, but you need to make sure that you have that at the beginning of your function.