How do I capture the first line from a NSString object?
I currently am assigning the entire NSString object to the title of my textView, but only want to assign the first line of the string. My current code like this this:
self.textView.text = [[managedObject valueForKey:#"taskText"] description];
You want
self.textView.text = [[[[managedObject valueForKey: #"taskText"] description] componentsSeparatedByString: #"\n"] objectAtIndex:0];
http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html
If you’re targeting iOS 4.0 and later, you can use -[NSString enumerateLinesUsingBlock:]:
__block NSString *firstLine = nil;
NSString *wholeText = [[managedObject valueForKey:#"taskText"] description];
[wholeText enumerateLinesUsingBlock:^(NSString *line, BOOL *stop) {
firstLine = [[line retain] autorelease];
*stop = YES;
}];
self.textView.text = firstLine;
An alternative approach which is probably the most efficient and straightforward:
NSString* str = [[managedObject valueForKey:#"taskText"] description];
self.textView.text = [str substringWithRange:[str lineRangeForRange:NSMakeRange(0, 0)]];
Related
I have a string like: "mocktail, wine, beer"
How can I convert this into: "mocktail", "wine", "beer"?
the following gives you the desired result:
NSString *_inputString = #"\"mocktail, wine, beer\"";
NSLog(#"input string : %#", _inputString);
NSLog(#"output string : %#", [_inputString stringByReplacingOccurrencesOfString:#", " withString:#"\", \""]);
the result is:
input string : "mocktail, wine, beer"
output string : "mocktail", "wine", "beer"
You need to use:
NSArray * components = [myString componentsSeparatedByString: #", "];
NSString *string = #"mocktail, wine, beer";
//remove whitespaces
NSString *trimmedString = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//get array of string
NSArray *array = [trimmedString componentsSeparatedByString:#","];
NSMutableArray *newArray = [[NSMutableArray alloc] init];
for (NSString *trimmedString in array) {
NSString *newString = [NSMutableString stringWithFormat:#"'%#'", trimmedString];
[newArray addObject:newString];
}
//merge new strings
NSString *finalString = [NSString stringWithFormat:#"%#", [newArray objectAtIndex:0]];
for (NSInteger i = 1; i < [newArray count]; i++) {
finalString = [NSString stringWithFormat:#"%#, %#", finalString, [newArray objectAtIndex:i]];
}
Without knowing spesifically about iOS or objective-c, I assume you could use a split function.
In almost any higher level programming language there is such a function.
Try:
Objective-C split
This gets you an array of Strings. You can then practically do with those what you want to do, e.g. surrounding them with single quotes and appending them back together. :D
I have problem with string. The string shows: ~00000000:termometr2: +26.9 st.C and I want to use only this part: +26.9 st.C in my textfield.text.
Thanks
NSString *fullStr = #"00000000:termometr2: +26.9 st.C";
NSArray *parts = [fullStr componentsSeparatedByString:#" "];
textField.text =[NSString stringWithFormat:#"%#",[parts objectAtIndex:1]];
it might help you:
NSArray *_array = [yourString componentsSeparatedByString:#":"];
[myTextField setText:[_array lastObject]]; // or any other component you want
Just do it this way, using the method stringByReplacingOccurrencesOfString: withString::
NSString *originalString = #"~00000000:termometr2: +26.9 st.C";
NSString *filteredString = [originalString stringByReplacingOccurrencesOfString:#"~00000000:termometr2: " withString:#""];
how can I display 5 raise to 1/3 in iphone i.e I want 1/3 written above 5 can anyone help please
I Found this solution, hope so it would be helpful for you.
x to the power of y in a UILabel could be easy. Just replace your indices with unicode superscript characters... I use the following method to turn an integer into a string with superscript characters.
+(NSString *)convertIntToSuperscript:(int)i
{
NSArray *array = [[NSArray alloc] initWithObjects:#"⁰", #"¹", #"²", #"³", #"⁴", #"⁵", #"⁶", #"⁷", #"⁸", #"⁹", nil];
if (i >= 0 && i <= 9) {
NSString *myString = [NSString stringWithFormat:#"%#", [array objectAtIndex:i]];
[array release];
return myString;
}
else {
NSString *base = [NSString stringWithFormat:#"%i", i];
NSMutableString *newString = [[NSMutableString alloc] init];
for (int b = 0; b<[base length]; b++) {
int temp = [[base substringWithRange:NSMakeRange(b, 1)] intValue];
[newString appendString:[array objectAtIndex:temp]];
}
[array release];
NSString *returnString = [NSString stringWithString:newString];
[newString release];
return returnString;
}
}
Try this NSString *cmsquare=#"cm\u00B2";
It will display cm².
Yes you can do that but you need custom UILabel, either Make it by yourself or Get it Open Source..
I am having an array like fallowing,
NSArray*array = [NSArray arrayWithObjects:#"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
Now,i am having the string like fallowing,
NSString*str = #"1.3";
Now i will send the str .Then it needs to find that str in array and it need to return the index of object where that text found.Means i need index 2 has to come as output.Can anyone share the code please.Thanks in advance.
Here is an example using blocks, notice the method: hasPrefix:
NSArray *array = [NSArray arrayWithObjects:#"1.1 problem1", #"1.2 problem2", #"1.3 problem3", #"1.4 problem4", nil];
NSString *str = #"1.3";
NSUInteger index = [array indexOfObjectPassingTest:
^(id obj, NSUInteger idx, BOOL *stop) {
return [obj hasPrefix:str];
}];
NSLog(#"index: %lu", index);
NSLog output:
index: 2
First a comment,
NSString *str = 1.3;
does not create an NSString object. You should instead have
NSString *str = #"1.3";
To search the NSArray, you will either have to change the string to the exact string in the array or search the NSString as well. For the former, simply do
float num = 1.3;
NSString *str = [NSString stringWithFormat:#"%.1f problem%d",num,(num*10)%10];
[array indexOfObject:str];
You can get fancier using NSPredicates as well.
Try
NSString *searchString = [str stringByAppendingFormat: #" problem%#", [str substringFromIndex: 2]];
NSUInteger index = [array indexOfObject: searchString];
Or (because you somehow like oneliners):
[array indexOfObject: [[array filteredArrayUsingPredicate: [NSPredicate predicateWithFormat: #"SELF beginswith %#", str]] objectAtIndex: 0]];
The simplest way is to enumerate through values of array and check substrings:
NSArray *array = [NSArray arrayWithObjects: #"1.1 something", #"1.2 something else", #"1.3 out of left field", #"1.4 yet another!", nil];
NSString *str = #"1.33";
int i = -1;
int index = -1;
for (NSString *arrayString in array) {
i++;
if ([arrayString rangeOfString: str].location != NSNotFound) {
index = i;
break;
}
}
NSLog(#"Index: %d", index);
Not optimal but will work.
I have an NSString *str, having value #"I like Programming and gaming."
I have to remove "I" "like" & "and" from my string so it should look like as "Programming gaming"
How can I do this, any Idea?
NSString *newString = #"I like Programming and gaming.";
NSString *newString1 = [newString stringByReplacingOccurrencesOfString:#"I" withString:#""];
NSString *newString12 = [newString1 stringByReplacingOccurrencesOfString:#"like" withString:#""];
NSString *final = [newString12 stringByReplacingOccurrencesOfString:#"and" withString:#""];
Assigned to wrong string variable edited now it is fine
NSLog(#"%#",final);
output : Programming gaming
NSString * newString = [#"I like Programming and gaming." stringByReplacingOccurrencesOfString:#"I" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"like" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"and" withString:#""];
NSLog(#"%#", newString);
More efficient and maintainable than doing a bunch of stringByReplacing... calls in series:
NSSet* badWords = [NSSet setWithObjects:#"I", #"like", #"and", nil];
NSString* str = #"I like Programming and gaming.";
NSString* result = nil;
NSArray* parts = [str componentsSeparatedByString:#" "];
for (NSString* part in parts) {
if (! [badWords containsObject: part]) {
if (! result) {
//initialize result
result = part;
}
else {
//append to the result
result = [NSString stringWithFormat:#"%# %#", result, part];
}
}
}
It is an old question, but I'd like to show my solution:
NSArray* badWords = #[#"the", #"in", #"and", #"&",#"by"];
NSMutableString* mString = [NSMutableString stringWithString:str];
for (NSString* string in badWords) {
mString = [[mString stringByReplacingOccurrencesOfString:string withString:#""] mutableCopy];
}
return [NSString stringWithString:mString];
Make a mutable copy of your string (or initialize it as NSMutableString) and then use replaceOccurrencesOfString:withString:options:range: to replace a given string with #"" (empty string).