Intercept URL and opening URL in Safari - iphone

Question

I have intercepted URL opening by doing the following:
- (BOOL)openURL:(NSURL *)url{
URLViewController * web = [[URLViewController alloc] init];
web.url = url;
UINavigationController * nav = [[UINavigationController alloc] initWithRootViewController:web];
[nav.navigationBar setTintColor:[UIColor blackColor]];
[nav setModalPresentationStyle:UIModalPresentationFormSheet];
[self.detailViewController presentModalViewController:nav animated:NO];
[web release];
[nav release];
return YES;
}
I have a UITextView in which detects URL and when clicking on the URL it opens up the link in a ModalViewController. Full detail on what's going on can be seen here. Now the issue is, what if I want to open a URL in safari, is it still possible?

Answer 1

You should add an override flag indicating whether you want to exercise control or not.
#interface MyApplication : UIApplication {
}
-(BOOL)openURL:(NSURL *)url withOverride:(BOOL)override;
#end
#implementation MyApplication
-(BOOL)openURL:(NSURL *)url withOverride:(BOOL)override {
if ( !override ) {
return [super openURL:url];
}
if ([self.delegate openURL:url]) {
return YES;
} else {
return [super openURL:url];
}
}
-(BOOL)openURL:(NSURL *)url{
return [self openURL:url withOverride:YES];
}
#end
So now all calls that you want to bypass can be sent like this.
[[MyApplication sharedApplication] openURL:url withOverride:NO];
Original Answer
This is what you should do. Put it before the return YES; statement.
if ( [super canOpenURL:aURL] ) {
return [super openURL:aURL];
}